Tensor Network Theory: A formalization blueprint

26 Mixed States: Renormalization of Matrix Product Operators

Starting from the MPO, MPDO, and LPDO notation of Chapter 23, this chapter studies renormalization fixed points for density-operator chains. Following the order of the mixed-state analysis in [ CPGSV16 , Section 4 ] , the discussion first states the local renormalization condition and then records its comparison with the pure-state formalism. It next passes to zero correlation length, purification fixed points, mutual information, and saturation of the area law. The source definitions of simple tensors and Gibbs states of nearest-neighbor commuting Hamiltonians precede the simple local and commuting structures. The boundary-theory interlude of the source is outside the present MPO development. The general case and its algebraic characterization continue in Chapter 27.

26.1 Preliminaries for physical renormalization

We first collect the transfer-map, channel, and physical-closure notions used to state the mixed-state renormalization condition. The renormalization fixed point of [ CPGSV16 , Definition 4.1 ] is stated in the next section.

Definition 26.1.1 MPO transfer-map idempotence
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An MPO tensor \(M\) has transfer-map idempotence if

\begin{align} \mathcal{E}_M\circ \mathcal{E}_M& =\mathcal{E}_M. \notag \end{align}
Definition 26.1.2 Completely positive map in rectangular Kraus form
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A linear map \(\mathcal S\) between matrix algebras is completely positive in rectangular Kraus form if there are finitely many operators \(A_i:H\to K\) such that

\begin{align} \mathcal S(X)& =\sum _i A_iXA_i^\dagger . \notag \end{align}

No trace-preservation normalization is imposed.

Lemma 26.1.3 Agreement with square-map complete positivity
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When the input and output matrix algebras agree, rectangular Kraus complete positivity is equivalent to the square-map notion of complete positivity.

Lemma 26.1.4 Basic properties of rectangular Kraus complete positivity

A map in rectangular Kraus form sends positive semidefinite matrices to positive semidefinite matrices. Every trace-preserving completely positive Kraus map is a completely positive Kraus map.

Lemma 26.1.5 Sum of rectangular Kraus maps
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The sum of two completely positive maps in rectangular Kraus form is completely positive in rectangular Kraus form.

Proof

Concatenating Kraus families for the two summands gives a Kraus family for their sum.

Definition 26.1.6 Trace-preserving completely positive map
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A linear map \(\mathcal{S}\) between matrix algebras is trace-preserving completely positive if it has a Kraus form \(\mathcal{S}(X)=\sum _i A_iXA_i^\dagger \) with \(\sum _i A_i^\dagger A_i=I\). The Kraus operators may be rectangular, so the input and output dimensions need not agree.

Theorem 26.1.7 Trace preservation completes a Kraus channel

A completely positive map in rectangular Kraus form that preserves the matrix trace is trace-preserving completely positive.

Proof

If \((A_i)_i\) is a Kraus family, trace preservation and cyclicity give \(\operatorname{tr}((\sum _i A_i^\dagger A_i)X)=\operatorname{tr}(X)\) for every \(X\). Nondegeneracy of the trace pairing implies \(\sum _i A_i^\dagger A_i=\mathbb {1}\).

Theorem 26.1.8 Trace preservation from a Kraus resolution
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Every trace-preserving completely positive map in rectangular Kraus form preserves the matrix trace.

Proof

If \(\mathcal S(X)=\sum _a A_aXA_a^\dagger \) and \(\sum _a A_a^\dagger A_a=I\), cyclicity gives

\begin{align} \operatorname{tr}\mathcal S(X) & =\sum _a\operatorname{tr}(A_aXA_a^\dagger ) =\operatorname{tr}\left(\left(\sum _a A_a^\dagger A_a\right)X\right) =\operatorname{tr}X. \notag \end{align}
Lemma 26.1.9 Positivity preservation for Kraus maps
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If \(\mathcal S\) is trace-preserving completely positive and \(X\geq 0\), then \(\mathcal S(X)\geq 0\).

Lemma 26.1.10 Identity map is trace-preserving completely positive
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The identity map \(\operatorname{id}(X)=X\) is trace-preserving completely positive, with single Kraus operator \(A_0=I\).

Proof

Take \(r=1\) and \(A_0=I\); then \(\operatorname{id}(X)=IXI^\dagger =X\) and \(A_0^\dagger A_0=I\).

Theorem 26.1.11 Conjugation by an isometry is trace-preserving completely positive
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Let \(H\) and \(K\) be finite-dimensional complex vector spaces, and let \(V:H\to K\) satisfy \(V^\dagger V=I_H\). Then the map

\begin{align} \Phi _V:\operatorname{End}_{\mathbb {C}}(H)& \longrightarrow \operatorname{End}_{\mathbb {C}}(K), \notag \\ \Phi _V(X)& =VXV^\dagger , \notag \end{align}

is trace-preserving and completely positive. This is the general one-isometry form of the local basis change used in [ CPGSV16 , Appendix C.2, lines 1439 and 1520 ] .

Proof

Take the sole Kraus operator to be \(V\). Its resolution of the identity is precisely \(V^\dagger V=I_H\).

Definition 26.1.12 Single-Kraus map
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For a rectangular matrix \(V:H\to K\), define the linear map

\begin{align} \Phi _V(X)& =VXV^\dagger . \notag \end{align}
Lemma 26.1.13 Evaluation of the single-Kraus map
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For every matrix \(X\), one has \(\Phi _V(X)=VXV^\dagger \).

Theorem 26.1.14 The single-Kraus map of an isometry is a channel

If \(V^\dagger V=I_H\), then \(\Phi _V\) is trace-preserving and completely positive.

Lemma 26.1.15 A single-Kraus map is completely positive

For every rectangular operator \(V:H\to K\), the map \(X\mapsto VXV^\dagger \) is completely positive.

Definition 26.1.16 Matrix reindexing along an equivalence
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Let \(e:I\simeq J\) be an equivalence of index sets. The associated matrix reindexing is the linear map \(R_e:\mathbb {C}^{I\times I}\to \mathbb {C}^{J\times J}\) determined by

\begin{align} [R_e(X)]_{j,j'} & =X_{e^{-1}(j),e^{-1}(j')}. \notag \end{align}
Theorem 26.1.17 Equivalence reindexing is trace-preserving completely positive

For every equivalence \(e:I\simeq J\) between finite index sets, the reindexing map \(R_e\) is trace-preserving and completely positive.

Proof

Let \(P_e:\mathbb {C}^I\to \mathbb {C}^J\) be the permutation matrix of \(e\). Then \(R_e(X)=P_eXP_e^\dagger \) and \(P_e^\dagger P_e=I_{\mathbb {C}^I}\). The claim follows from the preceding isometry lemma.

Lemma 26.1.18 Composition of trace-preserving completely positive maps
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The composition of two trace-preserving completely positive maps is again trace-preserving completely positive. If \(\mathcal{S}\) has Kraus operators \(A_i\) and \(\mathcal{T}\) has Kraus operators \(B_j\), then \(\mathcal{S}\circ \mathcal{T}\) has Kraus operators \(A_iB_j\).

Proof

The Kraus form of the composite and its resolution of the identity are

\begin{align} (\mathcal{S}\circ \mathcal{T})(X) & =\sum _{i,j}(A_iB_j)X(A_iB_j)^\dagger , \notag \\ \sum _{i,j}(A_iB_j)^\dagger (A_iB_j) & =\sum _j B_j^\dagger \left(\sum _i A_i^\dagger A_i\right)B_j =\sum _j B_j^\dagger B_j=I. \notag \end{align}
Lemma 26.1.19 Composition of completely positive rectangular Kraus maps
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The composition of two completely positive rectangular Kraus maps is completely positive. If the two families are \((A_i)_i\) and \((B_j)_j\), the composite family is \((A_iB_j)_{i,j}\).

Theorem 26.1.20 Tensor extension preserves trace-preserving complete positivity

Let \(\mathcal S:\operatorname{End}_{\mathbb {C}}(H)\to \operatorname{End}_{\mathbb {C}}(K)\) be trace-preserving and completely positive, and let \(R\) be another finite-dimensional space. Then

\begin{align} \mathcal S\otimes \operatorname{id}_R: \operatorname{End}_{\mathbb {C}}(H\otimes R)& \longrightarrow \operatorname{End}_{\mathbb {C}}(K\otimes R), \notag \\ \operatorname{id}_R\otimes \mathcal S: \operatorname{End}_{\mathbb {C}}(R\otimes H)& \longrightarrow \operatorname{End}_{\mathbb {C}}(R\otimes K) \notag \end{align}

are trace-preserving and completely positive.

Proof

The first assertion is the tensor-extension closure theorem. For the second, let \(\tau _H:R\otimes H\simeq H\otimes R\) and \(\tau _K:K\otimes R\simeq R\otimes K\) be the canonical factor swaps. Then

\begin{align} \operatorname{id}_R\otimes \mathcal S & =\mathcal R_{\tau _K}\circ (\mathcal S\otimes \operatorname{id}_R)\circ \mathcal R_{\tau _H}, \notag \end{align}

where \(\mathcal R_\tau \) denotes reindexing both matrix coordinates along \(\tau \). Both reindexing maps are trace-preserving and completely positive, so closure under composition proves the claim. No choice of Kraus family is needed for this preservation statement.

Definition 26.1.21 Rectangular Kraus map
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Let \(I\) be a finite index set, let \(J\) be an arbitrary index set, and let \((A_a\in \mathbb {C}^{J\times I})_a\) be a finite family of matrices. Its rectangular Kraus map is

\begin{align} \Phi _A(X)& =\sum _a A_aXA_a^\dagger . \notag \end{align}
Theorem 26.1.22 Rectangular Kraus resolution

Let \((A_a:H\to K)_a\) be a finite family of rectangular operators. If \(\sum _a A_a^\dagger A_a=I_H\), then \(X\mapsto \sum _a A_aXA_a^\dagger \) is trace-preserving and completely positive.

Proof

The displayed family is already a Kraus representation, and the assumed identity is precisely its trace-preserving normalization.

Lemma 26.1.23 A rectangular Kraus family is completely positive

Every finite rectangular Kraus family defines a completely positive map, without a resolution-of-identity assumption.

Theorem 26.1.24 Relabeling a rectangular Kraus family
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If \(e:I\simeq I'\) and \(A'_b=A_{e^{-1}(b)}\), then \(\Phi _{A'}=\Phi _A\).

Proof

Reindexing the finite sum gives \(\sum _{b\in I'}A_{e^{-1}(b)}XA_{e^{-1}(b)}^\dagger =\sum _{a\in I}A_aXA_a^\dagger \).

Definition 26.1.25 Orthogonally controlled Kraus map

Let \(H=\bigoplus _k H_k\) and \(K=\bigoplus _k K_k\). For each \(k\), let \((A_{k,a}:H_k\to K_k)_a\) be a finite family of operators, and let \(\widetilde A_{k,a}:H\to K\) agree with \(A_{k,a}\) on \(H_k\) and vanish on every other summand. The orthogonally controlled Kraus map is

\begin{align} \mathcal C(X) & =\sum _{k,a}\widetilde A_{k,a}X\widetilde A_{k,a}^\dagger . \notag \end{align}

In particular, \(\mathcal C(X)_{kl}=0\) for \(k\ne l\). This is the sector control in the definitions of \(\mathcal T_1\) and \(\mathcal S_1\) in [ CPGSV16 , Appendix C.2, lines 1523–1535 and 1548–1555 ] .

Theorem 26.1.26 Diagonal blocks of an orthogonally controlled map

Let \(X_{kk}:H_k\to H_k\) denote the \(k\)th diagonal block of \(X\). Then

\begin{align} \mathcal C(X)_{kk} & =\sum _a A_{k,a}X_{kk}A_{k,a}^\dagger =\Phi _{A_k}(X_{kk}). \notag \end{align}
Proof

If \(j\ne k\), then every zero-extended Kraus operator satisfies \([\widetilde A_{j,a}X\widetilde A_{j,a}^\dagger ]_{(k,b),(k,c)}=0\). Hence only the \(j=k\) terms survive, and \([\mathcal C(X)]_{kk}=\sum _a A_{k,a}X_{kk}A_{k,a}^\dagger \).

Theorem 26.1.27 Off-diagonal blocks of an orthogonally controlled map

If \(k\ne l\), then \(\mathcal C(X)_{kl}=0\).

Proof

For every \((j,a)\) and \(k\ne l\), the zero-extended operator satisfies \([\widetilde A_{j,a}X\widetilde A_{j,a}^\dagger ]_{(k,b),(l,c)}=0\). Therefore \([\mathcal C(X)]_{kl}=\sum _{j,a}0=0\).

Theorem 26.1.28 Orthogonal control preserves trace-preserving complete positivity

Suppose that for every \(k\) the sectorwise Kraus family resolves the identity, \(\sum _a A_{k,a}^\dagger A_{k,a}=I_{H_k}\). Then the orthogonally controlled map \(\mathcal C\) is trace-preserving and completely positive.

Proof

Each embedded operator has support in one summand, and therefore

\begin{align} \sum _{k,a}\widetilde A_{k,a}^\dagger \widetilde A_{k,a} & =\bigoplus _k\left(\sum _a A_{k,a}^\dagger A_{k,a}\right) =\bigoplus _k I_{H_k}=I_H. \notag \end{align}

Apply Theorem 26.1.22 to the combined rectangular Kraus family \((\widetilde A_{k,a})_{k,a}\).

Definition 26.1.29 Right partial trace
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For a matrix \(X\) on \(A\otimes B\), the right partial trace is the linear map from matrices on \(A\otimes B\) to matrices on \(A\) given by

\begin{align} [\operatorname{tr}_B(X)]_{ij} & =\sum _k X_{(i,k),(j,k)}. \notag \end{align}

After the retained and discarded subspins have been regrouped as \(A\otimes B\), this is the partial-trace ingredient of the maps \(\mathcal T_0\) and \(\mathcal S_0\) in [ CPGSV16 , Appendix C.2, lines 1521–1522 and 1547 ] .

Theorem 26.1.30 Right partial trace of a Kronecker product

For square matrices \(X\) on \(A\) and \(Y\) on \(B\), \(\operatorname{tr}_B(X\otimes Y)=\operatorname{tr}(Y)X\).

Proof

For all \(i,j\), \([\operatorname{tr}_B(X\otimes Y)]_{ij} =\sum _t X_{ij}Y_{tt}=\operatorname{tr}(Y)X_{ij}\).

Lemma 26.1.31 The right partial trace is trace-preserving completely positive

The map \(\operatorname{tr}_B\) is trace-preserving and completely positive for arbitrary finite-dimensional spaces \(A\) and \(B\).

Proof

For each basis vector \(e_k\) of \(B\), define \(V_k:A\otimes B\to A\) by \(V_k(e_i\otimes e_\ell )=\delta _{k\ell }e_i\). Then

\begin{align} \sum _k V_kXV_k^\dagger & =\operatorname{tr}_B(X), \notag \\ \sum _k V_k^\dagger V_k& =I_{A\otimes B}. \notag \end{align}

Theorem 26.1.22 applies.

Definition 26.1.32 State-preparation map
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Let \(\rho \) be a matrix on a finite-dimensional space \(B\). The state-preparation map from matrices on \(A\) to matrices on \(A\otimes B\) is

\begin{align} \mathcal P_\rho (X)& =X\otimes \rho . \notag \end{align}

This is the elementary preparation operation used in the maps \(\mathcal T_1\) and \(\mathcal S_1\) of [ CPGSV16 , Appendix C.2, lines 1527–1533 and 1551–1555 ] .

Definition 26.1.33 Preparation Kraus operators
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Let \(R=\sqrt\rho \). For an orthonormal basis \((e_j)_j\) of \(B\), define rectangular operators \(A_j:A\to A\otimes B\) by \(A_j(e_a)=e_a\otimes Re_j\).

Theorem 26.1.34 Kraus action of state preparation

If \(\rho \succeq 0\) and \(A_j(e_a)=e_a\otimes \sqrt\rho \, e_j\), then

\begin{align} \sum _j A_jXA_j^\dagger & =X\otimes \rho . \notag \end{align}
Proof

Put \(R=\sqrt\rho \). Since \(R\) is Hermitian and \(R^2=\rho \), the \(((a,s),(b,t))\) entry of the left-hand side is

\begin{align} X_{ab}\sum _jR_{sj}\overline{R_{tj}} & =X_{ab}(R^2)_{st}=X_{ab}\rho _{st}. \notag \end{align}
Theorem 26.1.35 Preparation Kraus operators resolve the identity

If \(\rho \geq 0\) and \(\operatorname{tr}(\rho )=1\), then \(\sum _j A_j^\dagger A_j=I_A\).

Proof

Since \(R\) is Hermitian and \(R^2=\rho \), the diagonal entries of the sum are \(\sum _{j,t}\overline{R_{tj}}R_{tj} =\operatorname{tr}(R^2)=\operatorname{tr}(\rho )=1\), while its off-diagonal entries vanish.

Lemma 26.1.36 Positive state preparation is completely positive

If \(\rho \geq 0\), then the map \(X\mapsto X\otimes \rho \) is completely positive. No trace normalization is required.

Lemma 26.1.37 State preparation is trace-preserving completely positive

If \(\rho \geq 0\) and \(\operatorname{tr}(\rho )=1\), then \(\mathcal P_\rho :X\mapsto X\otimes \rho \) is trace-preserving completely positive.

Proof

Theorem 26.1.34 identifies the map with the rectangular Kraus family \((A_j)_j\), and Theorem 26.1.35 gives \(\sum _j A_j^\dagger A_j=I_A\). Apply Theorem 26.1.22.

Definition 26.1.38 Physical closure maps

For an MPO tensor \(M\), a length \(N\), and a virtual operator \(X\), define the physical operator \(M_N(X)\) by

\begin{align} M_N(X)_{\boldsymbol i,\boldsymbol j} & = \operatorname{tr}\! \left(M^{i_0j_0}M^{i_1j_1}\cdots M^{i_{N-1}j_{N-1}}X\right). \notag \end{align}

This is linear in \(X\). The displayed order chooses the cut of the cyclic virtual contraction immediately before the first site, so that \(X\) follows the last site. The one- and two-site operators are constructed in [ CPGSV16 , lines 638–654 and Definition 4.1 ] . When \(M=\mathcal K\), write these operators as \(\mathcal K_N(X)\); the cases \(N=2,3\) occur in [ CPGSV16 , Proposition C.7, lines 1510–1516 ] .

Lemma 26.1.39 Periodic closure

Closing the virtual legs with the identity gives the periodic MPO operator: \(M_N(1)=\rho ^{(N)}(M)\).

Proof

For every pair of physical words \(\sigma ,\tau \),

\begin{align} M_N(1)_{\sigma ,\tau } & =\operatorname{tr}\! \left(M^{\sigma ,\tau }\cdot 1\right) =\operatorname{tr}\! \left(M^{\sigma ,\tau }\right) =\rho ^{(N)}(M)_{\sigma ,\tau }. \notag \end{align}
Theorem 26.1.40 One- and two-site physical closures

Under the canonical identifications of one-site configurations with physical indices and two-site configurations with pairs of physical indices,

\begin{align} M_1(X)_{i,j} & =\operatorname{tr}(M^{ij}X), \notag \\ M_2(X)_{(i_0,i_1),(j_0,j_1)} & =\operatorname{tr}(M^{i_0j_0}M^{i_1j_1}X). \notag \end{align}
Proof

Under these identifications, the length-one and length-two word evaluations are \(M^{ij}\) and \(M^{i_0j_0}M^{i_1j_1}\), respectively.

The general three-site physical closure has coefficients

\begin{align} M_3(X)_{(i_0,(i_1,i_2)),(j_0,(j_1,j_2))} & =\operatorname{tr}(M^{i_0j_0}M^{i_1j_1}M^{i_2j_2}X). \notag \end{align}

For \(M=\mathcal K\), this is the operator \(\mathcal K_3(X)\) in [ CPGSV16 , Proposition C.7, lines 1510–1516 ] .

Proof

The length-three word evaluation is \(M^{i_0j_0}M^{i_1j_1}M^{i_2j_2}\).

26.2 Renormalization fixed points

The following is the mixed-state fixed-point condition of [ CPGSV16 , Definition 4.1 ] . Its two local channels extend to every longer periodic chain by acting on the first one or two sites and leaving the remaining sites unchanged.

Definition 26.2.1 Renormalization fixed point via trace-preserving maps

An MPO tensor \(M\) is a renormalization fixed point if there exist two trace-preserving completely positive maps \(\mathcal{S}, \mathcal{T}\) on the physical indices such that \(\mathcal{S}[M_2(X)]=M_1(X)\) and \(\mathcal{T}[M_1(X)]=M_2(X)\) for every virtual operator \(X\), where \(M_1(X)_{ij}=\operatorname{tr}(M^{ij}X)\) and \(M_2(X)_{(i_1i_2)(j_1j_2)} =\operatorname{tr}(M^{i_1j_1}M^{i_2j_2}X)\) are the one- and two-site physical operators obtained by closing one or two tensors with \(X\). This condition is distinct from idempotence of the doubled-index transfer map for general mixed states. Its source zero-correlation-length consequence concerns the physical-trace transfer and is proved below. This is [ CPGSV16 , Definition 4.1, line 657 ] . On the open coefficient tensors the two maps have types:

\begin{tenkzcd}[maps, species={channel},
        column sep=10mm, row sep=8mm]
      \tnpic[inline, physical=updown]{
        \tn[mpo]{M}
      } &
      \tnpic[inline, physical=updown]{
        \tn[mpo]{M} & \tn[mpo]{M}
      } \\
      \tnpic[inline, physical=updown]{
        \tn[mpo]{M} & \tn[mpo]{M}
      } &
      \tnpic[inline, physical=updown]{
        \tn[mpo]{M}
      }
      \tnarrow[from={(1,1)}, to={(1,2)}, species=channel]{\mathcal T}
      \tnarrow[from={(2,1)}, to={(2,2)}, species=channel]{\mathcal S}
    \end{tenkzcd}
Definition 26.2.2 Initial-coordinate regroupings
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Let \(R_1\) identify an \((N+1)\)-tuple with its first coordinate and the remaining \(N\)-tuple. Let \(R_2\) identify an \((N+2)\)-tuple with its first two coordinates and the remaining \(N\)-tuple.

Definition 26.2.3 Renormalization maps on a longer ring

Let \(N\) count the sites that are left unchanged. For physical maps \(\mathcal T:M_d\to M_{d^2}\) and \(\mathcal S:M_{d^2}\to M_d\), define

\begin{align} \widehat{\mathcal T}_N & =\mathcal T\otimes \operatorname{id}_{d^N}, \notag \\ \widehat{\mathcal S}_N & =\mathcal S\otimes \operatorname{id}_{d^N}, \notag \end{align}

using \(R_1\) and \(R_2\). Thus \(N=0\) leaves no spectator site, but the maps still act on a one-site or two-site operator; no empty ring occurs.

Lemma 26.2.4 Regrouping the first physical sites

For a physical word \(\sigma \) of length \(N+1\),

\begin{align} R_1(\sigma ) & =(\sigma _0,(\sigma _1,\ldots ,\sigma _N)), \notag \\ R_1^{-1}(i,(a_1,\ldots ,a_N)) & =(i,a_1,\ldots ,a_N). \notag \end{align}

For a physical word \(\sigma \) of length \(N+2\),

\begin{align} R_2(\sigma ) & =\bigl((\sigma _0,\sigma _1), (\sigma _2,\ldots ,\sigma _{N+1})\bigr), \notag \\ R_2^{-1}((i,j),(a_1,\ldots ,a_N)) & =(i,j,a_1,\ldots ,a_N). \notag \end{align}
Proof

All four identities hold by definition of the product-index equivalences.

Lemma 26.2.5 Localized renormalization maps are channels

If \(\mathcal S\) and \(\mathcal T\) are trace-preserving completely positive, then so are \(\widehat{\mathcal S}_N\) and \(\widehat{\mathcal T}_N\) for every \(N\).

Proof

If \((K_j)_j\) are Kraus operators for \(\mathcal T\) with \(\sum _j K_j^\dagger K_j=I_d\), then the localized map has Kraus operators \(K_j\otimes I_{d^N}\), and

\begin{align} \sum _j(K_j\otimes I_{d^N})^\dagger (K_j\otimes I_{d^N}) & =\left(\sum _j K_j^\dagger K_j\right)\otimes I_{d^N} =I_d\otimes I_{d^N}. \notag \end{align}

The two regroupings are unitary conjugations and preserve complete positivity and the trace. The argument for \(\mathcal S\) is identical.

Suppose that \(\mathcal S[M_2(X)]=M_1(X)\) and \(\mathcal T[M_1(X)]=M_2(X)\) for every virtual operator \(X\). Then, for every \(N\) and \(X\),

\begin{align} \widehat{\mathcal S}_N[M_{N+2}(X)] & =M_{N+1}(X), \notag \\ \widehat{\mathcal T}_N[M_{N+1}(X)] & =M_{N+2}(X). \notag \end{align}

In particular, these identities hold for every periodic MPO operator. Hence the two maps supplied by a renormalization fixed point act on rings of every length as required in the proof of [ CPGSV16 , Appendix C, lines 1333–1341 ] .

Proof

For words \(u,v\) on the \(N\) spectator sites, write \(M^{u,v}\) for their virtual word evaluation and write \([Y]^{(r)}_{u,v}\) for the block of an operator \(Y\) on the first \(r\) sites. Regrouping the first site gives

\begin{align} [M_{N+1}(X)]^{(1)}_{u,v} & =M_1(M^{u,v}X). \notag \end{align}

Therefore

\begin{align} \mathcal T([M_{N+1}(X)]^{(1)}_{u,v}) & =M_2(M^{u,v}X) =[M_{N+2}(X)]^{(2)}_{u,v}. \notag \end{align}

Equality of all blocks proves the refinement identity. Interchanging \(M_1\), \(M_2\) and using \(\mathcal S[M_2(Y)]=M_1(Y)\) proves the coarsening identity. Setting \(X=1\) and using \(M_N(1)=\rho ^{(N)}(M)\) (Lemma 26.1.39) gives the periodic-ring identities

\begin{align} \widehat{\mathcal T}_N[\rho ^{(N+1)}(M)] & =\rho ^{(N+2)}(M), \notag \\ \widehat{\mathcal S}_N[\rho ^{(N+2)}(M)] & =\rho ^{(N+1)}(M). \notag \end{align}

26.3 Pure-state recovery inside the MPO formalism

Definition 26.3.1 Diagonal pure-state embedding as an MPO
#

An MPS tensor \(A=\{ A^i\} _{i=0}^{d-1}\) determines an MPO tensor by placing \(A^i\) on the diagonal in the bra and ket indices:

\begin{align} M^{ij}& =\delta _{ij}A^i. \notag \end{align}

Equivalently, \(M^{ii}=A^i\) and \(M^{ij}=0\) for \(i\ne j\).

Theorem 26.3.2 Transfer map of the diagonal pure-state embedding

The transfer map of the diagonal MPO associated to \(A\) agrees with the original MPS transfer map: \(\mathcal{E}_{A^{\mathrm{MPO}}}=\mathcal{E}_A\).

Proof

In the double sum defining \(\mathcal{E}_{A^{\mathrm{MPO}}}\), all off-diagonal terms vanish because \(M^{ij}=0\) for \(i\ne j\), while the diagonal terms are exactly \(A^iX(A^i)^\dagger \). Thus only the sum over \(i\) remains, which is the defining formula for \(\mathcal{E}_A\).

Theorem 26.3.3 Pure-state recovery of transfer-map idempotence

For an MPS tensor \(A\), the diagonal MPO embedding has idempotent transfer map if and only if \(A\) is an RFP:

\begin{align} \mathcal{E}_{A^{\mathrm{MPO}}}\circ \mathcal{E}_{A^{\mathrm{MPO}}} =\mathcal{E}_{A^{\mathrm{MPO}}} & \iff \mathcal{E}_A\circ \mathcal{E}_A=\mathcal{E}_A. \notag \end{align}
Proof

Both conditions assert idempotence of the corresponding transfer map. Theorem 26.3.2 identifies those transfer maps, so the two predicates are equivalent.

Theorem 26.3.4 Pure-state recovery of zero correlation length

For an MPS tensor \(A\), the diagonal MPO embedding has idempotent transfer map if and only if \(A\) has zero correlation length.

Proof

Combine Theorem 26.3.3 with the characterization of zero correlation length by idempotence of the MPS transfer map (Theorem 24.5.13).

26.4 Zero correlation length

Definition 26.4.1 Physical-trace transfer
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The physical-trace transfer of an MPO tensor \(M\) is the virtual matrix obtained by contracting the ket and bra physical legs of one tensor:

\begin{align} \mathcal T_M & =\sum _i M^{ii}. \notag \end{align}

This is the transfer object appearing in the zero-correlation-length condition of [ CPGSV16 , Definition 4.2, lines 736–741 ] .

Definition 26.4.2 Source zero correlation length for MPO tensors
#

An MPO tensor has source zero correlation length when, for some real number \(\lambda {\gt}0\), the following conditions hold:

\begin{align} \mathcal T_M& \ne 0, \notag \\ \mathcal T_M^2& =\lambda \, \mathcal T_M. \notag \end{align}

The nonzero condition excludes the degenerate zero transfer, and the positive scalar makes the condition invariant under rescaling of \(M\).

Theorem 26.4.3 Literal physical-trace idempotence gives source ZCL

If \(\mathcal T_M\ne 0\) and \(\mathcal T_M^2=\mathcal T_M\), then \(M\) has source zero correlation length.

Proof

This is the preceding definition with \(\lambda =1\).

\begin{align} \mathcal T_M& =\mathcal T_M^2. \notag \end{align}
\begin{tenkz}[physical=updown, trace=physical]
        \tn[mpo]{M}
    \end{tenkz} \( = \) \begin{tenkz}[physical=updown, trace=physical]
        \tn[mpo]{M} & \tn[mpo]{M}
    \end{tenkz}

This is the normalized identity in [ CPGSV16 , Definition 4.2, lines 736–741 ] ; Definition 26.4.2 permits the positive factor \(\lambda \).

Lemma 26.4.4 Normalized transfer is idempotent under source zero correlation length

If \(M\) has source zero correlation length, then there exists \(\lambda {\gt}0\) such that \(\lambda ^{-1}\mathcal T_M\) is idempotent.

Proof

From source zero correlation length, choose \(\lambda {\gt}0\) with \(\mathcal T_M^2=\lambda \, \mathcal T_M\). Then

\begin{align} (\lambda ^{-1}\mathcal T_M)^2 & =\lambda ^{-2}\mathcal T_M^2 =\lambda ^{-1}\mathcal T_M. \notag \end{align}
Definition 26.4.5 Doubled-index transfer idempotence for MPO tensors
#

An MPO tensor \(M\) satisfies the doubled-index transfer condition when its completely positive transfer map is idempotent:

\begin{align} \mathcal{E}_M\circ \mathcal{E}_M& =\mathcal{E}_M. \notag \end{align}

This is the condition obtained from the doubled-index MPS view. It is not the physical-trace condition of Definition 26.4.2.

Theorem 26.4.6 Doubled-index transfer idempotence iff MPS RFP

An MPO tensor satisfies the doubled-index transfer condition if and only if its doubled-index MPS view is a renormalization fixed point.

Proof

By Lemma 23.2.2, the transfer map of \(M\) agrees with the transfer map of its doubled-index MPS view. Thus \(\mathcal{E}_M\circ \mathcal{E}_M=\mathcal{E}_M\) holds exactly when the transfer map of that doubled-index MPS tensor is idempotent, which is the RFP condition.

Theorem 26.4.7 Renormalization fixed points have idempotent physical-trace transfer

If \(M\) is a renormalization fixed point via trace-preserving maps, then \(\mathcal T_M^2=\mathcal T_M\). This proves the zero-correlation-length component of implication (i)\(\Rightarrow \)(ii) in [ CPGSV16 , Theorem 4.9, lines 851–893 ] . The corresponding calculation appears in the proposition “RFP implies ZCL and SAL” in Appendix C, lines 1333–1340; the part establishing saturation of the area law is separate.

Proof

For every virtual matrix \(X\), the one-site and two-site closures satisfy

\begin{align} \operatorname{tr}M_1(X)& =\operatorname{tr}(\mathcal T_M X), \notag \\ \operatorname{tr}M_2(X)& =\operatorname{tr}(\mathcal T_M^2 X). \notag \end{align}

Write \(\Phi \) for the one-to-two trace-preserving map \(\mathcal T\) of Definition 26.2.1; this is distinct from the physical-trace transfer \(\mathcal T_M\). Then \(\Phi [M_1(X)]=M_2(X)\), and hence

\begin{align} \operatorname{tr}(\mathcal T_M^2 X) & =\operatorname{tr}M_2(X) =\operatorname{tr}\Phi [M_1(X)] =\operatorname{tr}M_1(X) =\operatorname{tr}(\mathcal T_M X). \notag \end{align}

Nondegeneracy of the trace pairing now gives \(\mathcal T_M^2=\mathcal T_M\).

Theorem 26.4.8 Renormalization fixed points have source zero correlation length

If \(M\) is a renormalization fixed point via trace-preserving maps and \(\mathcal T_M\ne 0\), then \(M\) has source zero correlation length.

Proof

Apply the preceding idempotence theorem and take the positive scalar in Definition 26.4.2 to be \(1\).

Theorem 26.4.9 Transfer-map idempotence iff doubled-index condition

MPO transfer-map idempotence is exactly the doubled-index transfer condition of Definition 26.4.5.

Proof

Both conditions assert \(\mathcal{E}_M\circ \mathcal{E}_M=\mathcal{E}_M\); they are definitionally identical.

Theorem 26.4.10 Transfer-map idempotence iff doubled-index MPS RFP

MPO transfer-map idempotence is equivalent to the pure-state RFP condition for the doubled-index MPS tensor.

Proof

Unfold transfer-map idempotence to its definitional equivalent, the doubled-index transfer condition, and apply Theorem 26.4.6.

26.5 Purification fixed points

Definition 26.5.1 Purifying spin–ancilla tensor
#

Given matrices \(A^{(i,k)}\) with a spin index \(i\) and an ancillary index \(k\), the associated MPS tensor on the product physical space is \(\widehat A^{(i,k)}=A^{(i,k)}\). This is the tensor whose finite-chain vector appears in the purification formula of [ CPGSV16 , lines 744–751 ] .

Definition 26.5.2 Ancillary trace of a purifying MPS

For a purifying spin–ancilla tensor \(A\), the reduced spin density matrix is defined by

\begin{align} [\rho ^{(N)}_p(A)]_{\sigma ,\tau } & = \sum _{\kappa } \psi _A(\sigma ,\kappa ) \overline{\psi _A(\tau ,\kappa )}, \notag \\ \psi _A(\sigma ,\kappa ) & = \operatorname{tr}\! \left(A^{(\sigma _0,\kappa _0)} A^{(\sigma _1,\kappa _1)} \cdots A^{(\sigma _{N-1},\kappa _{N-1})}\right). \notag \end{align}

This is the coefficient form of the ancillary trace in [ CPGSV16 , eq. (4.7), line 751 ] .

Definition 26.5.3 Single-site ancillary trace map
#

For a matrix \(X\) on the spin–ancilla space, the ancillary trace map is

\begin{align} [\operatorname{tr}_a(X)]_{ij} & = \sum _k X_{(i,k),(j,k)}. \notag \end{align}

This is the one-site trace over ancillary degrees of freedom appearing in [ CPGSV16 , lines 751 and 761–764 ] .

Theorem 26.5.4 The ancillary trace is trace-preserving completely positive

For every ancillary dimension, the one-site ancillary trace map is trace-preserving and completely positive.

Proof

This is Lemma 26.1.31 with \(A\) the spin space and \(B\) the ancillary space.

Definition 26.5.5 Global purification equation

An MPO tensor \(M\) satisfies the global purification equation with a purifying tensor \(A\) if \(\rho ^{(N)}(M)=\rho ^{(N)}_p(A)\) for every positive length \(N\). Equivalently, for every positive length \(N\),

\begin{align} \rho ^{(N)}(M) & = \operatorname{tr}_a \bigl( |\Psi ^{(N)}(A)\rangle \! \langle \Psi ^{(N)}(A)| \bigr), \notag \end{align}

as in [ CPGSV16 , line 751 ] .

Definition 26.5.6 Trace-preserving spin reduction

The spin reduction obtained by tracing the ancillary index is trace-preserving completely positive: the ancillary trace map \(\operatorname{tr}_a\) satisfies Definition 26.1.6. This is the structure described immediately after Definition 4.3 in [ CPGSV16 , lines 761–764 ] .

Corollary 26.5.7 Trace-preserving spin reduction of the ancillary trace

For every ancillary dimension, the spin reduction obtained by tracing the ancillary index is trace-preserving and completely positive.

Proof

This is exactly Theorem 26.5.4, unpacked through Definition 26.5.6.

Definition 26.5.8 Bare global purification RFP witness

An MPO tensor \(M\) has a bare global purification RFP witness if it satisfies the global purification equation for some purifying spin–ancilla tensor \(A\), and \(\widehat A\) is a pure-state renormalization fixed point: \(\mathcal{E}_{\widehat A}\circ \mathcal{E}_{\widehat A}=\mathcal{E}_{\widehat A}\). This records the displayed conditions of Definition 4.3 in [ CPGSV16 , lines 756–764 ] . It does not include the nondegeneracy implicit when the subsequent theorem speaks of density operators.

Definition 26.5.9 Bare global purification RFP
#

An MPO tensor satisfies the bare global purification RFP predicate if it has a positive-length global purification RFP witness. Equivalently, it admits a purifying tensor \(A\) such that, for every positive length \(N\),

\begin{align} \rho ^{(N)}(M) & = \operatorname{tr}_a \bigl( |\Psi ^{(N)}(A)\rangle \! \langle \Psi ^{(N)}(A)| \bigr), \notag \end{align}

and \(\widehat A\) is a pure-state renormalization fixed point. These are the displayed conditions of Definition 4.3 in [ CPGSV16 , lines 756–764 ] ; the nondegenerate tensor-level predicate is Definition 26.5.13.

Definition 26.5.10 Trace-preserving spin reduction for a purification RFP

A purification RFP is viewed together with trace-preserving spin reduction by applying Corollary 26.5.7 to the ancillary trace map appearing in its purification equation. This records the structure obtained after tracing the ancillary indices in [ CPGSV16 , lines 761–764 ] , without adding a separate hypothesis to Definition 4.3.

Lemma 26.5.11 Forgetting the recorded spin reduction

Recording the trace-preserving ancillary reduction does not change the purification RFP condition: \(\mathrm{PRFP}_{\mathrm{tp}}(M)\Longleftrightarrow \mathrm{PRFP}(M)\).

Proof

Immediate from the equivalence in Definition 26.5.10.

Definition 26.5.12 Local purification RFP condition

An MPO tensor \(M\) satisfies the local purification RFP condition if it is an LPDO whose purifying tensor \(A\), viewed as a matrix product state tensor on the combined spin–ancilla index, is a pure-state renormalization fixed point. Thus

\begin{align} M^{ij} & = \left(\sum _{k} A^{(i,k)} \otimes \overline{A^{(j,k)}}\right)_{e,e}. \notag \end{align}

This local condition is motivated by the purification tensor formula [ CPGSV16 , lines 744–747 ] , but it is a one-site tensor-level condition rather than the global finite-chain definition in Definition 26.5.5.

Definition 26.5.13 Nondegenerate purification RFP

An MPO tensor is a nondegenerate purification renormalization fixed point if it is the local ancillary contraction of a pure-state renormalization fixed point and \(\mathcal T_M=\sum _i M^{ii}\ne 0\). The nonzero condition records the nondegeneracy implicit in the density operators of [ CPGSV16 , lines 744–786 ] and excludes the zero purifying tensor.

Theorem 26.5.14 A local purification RFP generates MPDOs

Every tensor satisfying the local purification RFP condition generates matrix product density operators.

Proof

Dropping the renormalization-fixed-point condition on the purifying tensor leaves the local purification structure, so \(M\) is an LPDO; the conclusion follows from Theorem 23.3.3.

Theorem 26.5.15 Local purification RFP does not imply doubled-index idempotence

There is an MPO tensor satisfying the local purification RFP condition for which the literal transfer-map idempotence \(\mathcal{E}_M\circ \mathcal{E}_M=\mathcal{E}_M\) fails.

Proof

Take the diagonal purification at \(d=d_K=2\) and \(D=D'=1\) with amplitudes \(A=[\tfrac {1}{\sqrt2},0,0,\tfrac {1}{\sqrt2}]\). The purifying tensor is a pure-state renormalization fixed point, since \(\sum |A|^2=1\) makes its transfer map the identity. The ancilla contraction \(M^{ij}=\sum _k A^{(i,k)} \overline{A^{(j,k)}}\) gives the scalar entries \(M^{00}=M^{11}=\tfrac 12\) (off-diagonal \(0\)), so the induced transfer map is \(\tfrac 12\cdot \operatorname{id}\) and \(\mathcal{E}_M\circ \mathcal{E}_M=\tfrac 14\cdot \operatorname{id}\neq \mathcal{E}_M\). The trace contraction has dropped the leading eigenvalue from \(1\) to \(\tfrac 12\); the literal zero-correlation-length condition is therefore strictly stronger than the source’s normalized one.

Lemma 26.5.16 Physical-trace transfer of the maximally mixed witness

For the maximally mixed witness \(M_{\mathrm w}\), closing the ket and bra physical legs gives \(\mathcal T_{M_{\mathrm w}} =M_{\mathrm w}^{00}+M_{\mathrm w}^{11} =\tfrac 12+\tfrac 12=1\).

Proof

This is the direct computation of the two nonzero diagonal entries of the witness tensor.

Theorem 26.5.17 The maximally mixed witness has source zero correlation length

The maximally mixed witness \(M_{\mathrm w}\) has source zero correlation length.

Proof

Lemma 26.5.16 gives \(\mathcal T_{M_{\mathrm w}}=1\). The identity is nonzero and idempotent, so source zero correlation length holds with \(\lambda =1\).

Theorem 26.5.18 Fixed local purification: pure RFP iff normalized physical-trace idempotence

Suppose that \(M\) is the ancillary contraction of a fixed spin–ancilla tensor \(A\) through a bond identification \(e\):

\begin{align} M^{ij} & = \left(\sum _k A^{(i,k)}\otimes \overline{A^{(j,k)}}\right)_{e,e}. \notag \end{align}

Then the purification tensor \(\widehat A\) is a pure-state renormalization fixed point if and only if \(\mathcal T_M^2=\mathcal T_M\). This is the normalized tensor-level equivalence underlying the purification theorem in [ CPGSV16 , lines 744–786 ] .

Proof

Let \(K'\) be the transfer matrix of \(\widehat A\), let \(s\) interchange the two Kronecker factors, and let \(K\) denote the same Kronecker sum in the physical ordering. The local contraction gives

\begin{align} \mathcal T_M& =K_e, \notag \\ K& =(K’)_s. \notag \end{align}

Since both reindexings are bijective and commute with matrix multiplication,

\begin{align} (K’)^2=K’ \quad & \Longleftrightarrow \quad \mathcal T_M^2=\mathcal T_M. \notag \end{align}

Injectivity of the transfer-matrix representation gives

\begin{align} (K’)^2=K’ \quad & \Longleftrightarrow \quad \mathcal{E}_{\widehat A}\circ \mathcal{E}_{\widehat A} =\mathcal{E}_{\widehat A}. \notag \end{align}
Theorem 26.5.19 Physical-trace transfer is idempotent under the local purification RFP condition

If an MPO tensor \(M\) is the ancilla contraction of a pure-state renormalization fixed point, then its physical-trace transfer \(\mathcal T_M=\sum _i M^{ii}\) is idempotent: \(\mathcal T_M\mathcal T_M=\mathcal T_M\).

Proof

Apply the forward implication of Theorem 26.5.18 to the local purifying tensor and bond identification.

Theorem 26.5.20 Local purification form and transfer idempotence characterize a local purification RFP

An MPO tensor satisfies the local purification RFP condition if and only if it has a local purification and its physical-trace transfer is idempotent:

\begin{align} \mathrm{LocalPRFP}(M) \quad & \Longleftrightarrow \quad \mathrm{LPDO}(M)\ \text{and}\ \mathcal T_M^2=\mathcal T_M. \notag \end{align}
Proof

Choose the local purifying tensor and bond identification. The equivalence is Theorem 26.5.18 for that fixed purification.

Theorem 26.5.21 Nondegenerate PRFP equivalence

An MPO tensor is a nondegenerate purification renormalization fixed point if and only if it is a local purification density operator (Definition 23.3.2) and

\begin{align} \mathcal T_M& \ne 0, \notag \\ \mathcal T_M^2& =\mathcal T_M. \notag \end{align}

This is the normalized, nonzero structural characterization used in the forward PRFP-to-ZCL implication of [ CPGSV16 , lines 744–786 ] .

Proof

Combine the preceding equivalence with the nonzero clause in Definition 26.5.13.

Theorem 26.5.22 Local purification RFP with nonzero physical-trace transfer has source ZCL

Let \(M\) be the ancilla contraction of a pure-state renormalization fixed point, satisfying the local purification renormalization fixed point condition. If the physical-trace transfer \(\mathcal T_M=\sum _i M^{ii}\) is nonzero, then \(M\) has source zero correlation length.

Proof

Theorem 26.5.19 gives idempotence of the physical-trace transfer, and the nonzero hypothesis lets Theorem 26.4.3 conclude source zero correlation length with \(\lambda =1\).

Theorem 26.5.23 A nondegenerate purification RFP has source ZCL

Every nondegenerate purification renormalization fixed point has source zero correlation length.

Proof

Definition 26.5.13 supplies both the local purification RFP condition and the nonzero physical-trace transfer required by Theorem 26.5.22.

Theorem 26.5.24 The tensor purification identity yields the global purification equation

Let \(M\) be the ancilla contraction of a purifying spin–ancilla tensor \(A\) through a bond identification \(e\), so that

\begin{align} M^{ij} & = \left(\sum _{k} A^{(i,k)}\otimes \overline{A^{(j,k)}}\right)_{e,e}. \notag \end{align}

Then at every length \(N\) the matrix product operator equals the ancillary trace of the pure spin–ancilla matrix product state, \(\rho ^{(N)}(M)=\rho ^{(N)}_p(A)\). This is the coefficient form of the purification equation of [ CPGSV16 , line 751 ] .

Proof

Applying the mixed-product property \((A\otimes B)(C\otimes D)=(AC)\otimes (BD)\) repeatedly, the length-\(N\) product of the contracted tensor entries distributes over the ancillary index sum:

\begin{align} \prod _{l=0}^{N-1} \left(\sum _{k} A^{(\sigma _l,k)} \otimes \overline{A^{(\tau _l,k)}}\right) & = \sum _{\kappa \colon [N]\to [d_K]} \left(\prod _l A^{(\sigma _l,\kappa _l)}\right) \otimes \overline{ \left(\prod _l A^{(\tau _l,\kappa _l)}\right) }. \notag \end{align}

Tracing this sum and using \(\operatorname{tr}(X\otimes \overline Y)=\operatorname{tr}(X) \overline{\operatorname{tr}(Y)}\) gives the coefficient of the ancillary trace at every \(\sigma ,\tau \). The equation holds at every length, so no positive-length restriction is needed.

Theorem 26.5.25 The local purification RFP condition implies the purification RFP

Every MPO tensor satisfying the local purification renormalization fixed point condition is a purification renormalization fixed point in the sense of Definition 4.3 of [ CPGSV16 , lines 756–764 ] .

Proof

The local condition supplies a purifying tensor \(A\) that is a pure-state renormalization fixed point and whose ancilla contraction is \(M\). By Theorem 26.5.24 this contraction satisfies the global purification equation at every positive length, so the same \(A\) is a purification RFP witness.

Corollary 26.5.26 A nondegenerate purification RFP satisfies the global PRFP predicate

Every nondegenerate purification renormalization fixed point satisfies the positive-length global purification predicate of Definition 4.3 in [ CPGSV16 , lines 744–758 ] .

Proof

Forget the nonzero condition and apply Theorem 26.5.25.

Theorem 26.5.27 The bare global PRFP predicate does not imply source ZCL

There is an MPO tensor satisfying the bare positive-length global purification RFP predicate which does not have source zero correlation length.

Proof

Take the zero tensor at spin, ancillary, and bond dimensions one, purified by the zero spin–ancilla tensor. Its transfer map is idempotent and every positive-length density operator is zero, so the global purification equation holds. Its physical-trace transfer is zero, which is excluded by source zero correlation length.

Theorem 26.5.28 A nonzero global PRFP need not have source ZCL

There is an MPO tensor which is an MPDO, satisfies the positive-length global purification RFP predicate, and has nonzero physical-trace transfer, but does not have source zero correlation length.

Proof

Take one physical state and bond dimension three, with the only tensor entry

\begin{align} Q& = \begin{pmatrix} 1 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 0 & 0 \end{pmatrix}. \notag \end{align}

Since \(\operatorname{tr}(Q^N)=1\) for every \(N{\gt}0\), all positive-length MPOs equal the scalar density operator \(1\) and are purified by the scalar pure-state RFP tensor \(A=1\). At length zero the MPO is the positive scalar \(3\), so the tensor is an MPDO at every length. Its physical-trace transfer is the nonzero matrix \(Q\). However, \(Q^2=\operatorname{diag}(1,0,0)\) is not a positive scalar multiple of \(Q\), because the \((2,3)\) entry is lost on squaring. Thus source ZCL fails. The global equation cannot detect this nilpotent bond sector.

26.6 Saturation of the area law

Definition 26.6.1 Block entropy of an MPDO

For a fixed system size \(N\), a block length \(L\le N\), and an MPO tensor \(M\) such that \(\rho ^{(N)}(M)\) is positive semidefinite, let

\begin{align} \sigma ^{(N)}(M) & =\frac{\rho ^{(N)}(M)}{\operatorname{tr}[\rho ^{(N)}(M)]}, \notag \\ \rho _L^{(N)}(M) & =\operatorname{tr}_{N\setminus L}\! [\sigma ^{(N)}(M)] \notag \end{align}

denote the normalized state and the reduced state of the first \(L\) of \(N\) spins. The \(L\)-block entropy is \(S_L^{(N)}(M)=S(\rho _L^{(N)}(M))\).

Definition 26.6.2 Mutual information of an MPDO

For the same fixed system size \(N\), block length \(L\le N\), and positive semidefiniteness of \(\rho ^{(N)}(M)\), the mutual information between a block of \(L\) spins and the rest is \(I_L=S_L^{(N)}(M)+S_{N-L}^{(N)}(M)-S_N^{(N)}(M)\).

Definition 26.6.3 Saturation of the area law
#

An MPO tensor \(M\) that generates an MPDO and whose positive-length finite-chain operators \(\rho ^{(N)}(M)\) all have nonzero trace (so the normalized states are well-defined) saturates the area law if \(I_L=I_{L+1}\) for all \(1\le L{\lt}\lfloor N/2\rfloor \) and all \(N\); that is, the mutual information is constant, \(I_1=I_2=\cdots =I_{\lfloor N/2\rfloor }\). This is [ CPGSV16 , Definition 4.6, line 811 ] .

Lemma 26.6.4 Constancy on a finite interval
#

Let \(a,n\in \mathbb N\), and let \(f\) be defined on the integer interval \([0,n]\). If \(f(m)=f(m+1)\) for every \(a\le m{\lt}n\), then \(f(i)=f(j)\) for all \(i,j\in [a,n]\).

Proof

Compose the successive equalities from the smaller index to the larger.

Lemma 26.6.5 Saturation telescopes to a constant mutual information

If an MPO tensor \(M\) saturates the area law, then the mutual informations coincide, \(I_L=I_{L'}\), for all \(1\le L,L'\le \lfloor N/2\rfloor \).

Proof

The defining condition supplies \(I_m=I_{m+1}\) throughout the interval \(1\le m{\lt}\lfloor N/2\rfloor \). Apply Lemma 26.6.4.

Let the \(N\)-site operator generated by \(M\) be positive semidefinite, and let three consecutive regions have lengths \(a\), \(b\), and \(c\), with \(a+b+c\leq N\). After reindexing the reduced state of the first \(a+b+c\) sites as a tripartite state on \(A\otimes B\otimes C\), its four entropies in strong subadditivity are

\begin{align} S(ABC)& =S_{a+b+c}, & S(AB)& =S_{a+b}, \notag \\ S(B)& =S_b, & S(BC)& =S_{b+c}. \notag \end{align}
Proof

Write \(\rho ^{(k)}\) for the first-\(k\)-site reduced state, with \(\cong \) denoting equality up to a permutation of basis indices. Reindexing a matrix does not change its von Neumann entropy, giving the first equality \(S(ABC)=S_{a+b+c}\) immediately. Tracing out \(C\) leaves the first \(a+b\) sites, \(\operatorname{tr}_C(\rho _{ABC})\cong \rho ^{(a+b)}\), so \(S(AB)=S_{a+b}\). Tracing out \(A\) and \(C\) leaves the middle \(b\) sites, while tracing out \(A\) leaves the final \(b+c\) sites; translation invariance gives

\begin{align} \operatorname{tr}_{A,C}(\rho _{ABC})& \cong \rho ^{(b)}, \notag \\ \operatorname{tr}_A(\rho _{ABC})& \cong \rho ^{(b+c)}. \notag \end{align}

Hence \(S(B)=S_b\) and \(S(BC)=S_{b+c}\).

Proposition 26.6.7 Monotonicity of the mutual information

Let \(M\) generate an MPDO whose finite-chain operator \(\rho ^{(N)}(M)\) is positive semidefinite with nonzero trace. For every block length \(L\) with \(2L+1\le N\), one has \(I_L\le I_{L+1}\). The implication \(1\le L{\lt}\lfloor N/2\rfloor \Longrightarrow 2L+1\le N\) shows that this contains the range of [ CPGSV16 , Proposition 4.5, line 801 ] .

Proof

Apply strong subadditivity to the reduced state of the first \(N-L\) spins, split into three contiguous segments of lengths \(1\), \(L\), and \(N-2L-1\). Tracing the appropriate segments yields the four block entropies \(S_{N-L}\), \(S_L\), \(S_{L+1}\), and \(S_{N-L-1}\), where the cyclic invariance of \(\rho ^{(N)}(M)\) identifies the entropy of a contiguous block with that of any block of the same length. Strong subadditivity then gives \(S_{N-L}+S_L\le S_{L+1}+S_{N-L-1}\), which rearranges to \(I_L\le I_{L+1}\) after subtracting \(S_N\).

Definition 26.6.8 Parity-sensitive classical MPDO

Let \(M\) have physical dimension two and bond dimension three, with

\begin{align} M^{00}& =\operatorname{diag}(1,0,0), & M^{11}& =\operatorname{diag}(0,1,-1), \notag \\ M^{01}& =0, & M^{10}& =0. \notag \end{align}

The tensor in Definition 26.6.8 generates the positive operators

\begin{align} \rho ^{(N)} & =|0^N\rangle \! \langle 0^N| +(1+(-1)^N)|1^N\rangle \! \langle 1^N|. \notag \end{align}

Their traces are \(2+(-1)^N\). The all-zero diagonal entry of the normalized one-site reduced state is therefore one for odd \(N\) and \(1/3\) for positive even \(N\). In particular, the normalized periodic one-site reduced states do not converge as \(N\to \infty \).

Thus normalized periodic marginals need not converge under the hypotheses of [ CPGSV16 , Proposition 4.5, lines 801–806 ] . The mutual information of this same family is computed in docs/paper-gaps/cpgsv17_mpdo_mutual_information_bound.tex.

Proof

A contraction around the virtual loop vanishes unless the bra and ket configurations agree and are both constant. The all-zero configuration receives weight one. The all-one configuration receives the sum of the two virtual-sector weights, namely \(1+(-1)^N\). This gives the displayed diagonal form. Its coefficients are non-negative: the second coefficient is zero for odd \(N\) and two for even \(N\). Hence every positive-length operator is positive semidefinite, and summing its two possible diagonal entries gives the trace \(2+(-1)^N\).

After normalization, the all-zero weight is consequently one at odd lengths and \(1/3\) at positive even lengths. Tracing out all but the first site does not change this entry, since among the configurations beginning with zero only the all-zero configuration has nonzero weight. The two subsequences of one-site marginals therefore have distinct all-zero entries, so the sequence cannot converge.

Proof

At odd \(N\), the normalized state and both of its nonempty marginals are pure, so all three terms in \(I_L^{(N)}=S_L+S_{N-L}-S_N\) vanish. At even \(N\), the full state and both marginals have the same two nonzero eigenvalues \(1/3\) and \(2/3\). Each of their entropies is therefore \(h_2(1/3)\), and hence \(I_L^{(N)}=h_2(1/3)+h_2(1/3)-h_2(1/3)=h_2(1/3)\). The binary entropy is strictly positive at \(1/3\). Thus the odd and even subsequences have distinct constant values.

Definition 26.6.11 Map on the second tensor factor
#

For a linear map \(\Psi _B\) and a bipartite matrix \(\rho _{AB}\), define

\begin{align} (\operatorname{id}_A\otimes \Psi _B)(\rho _{AB}) & =\Sigma _{B'A}\bigl((\Psi _B\otimes \operatorname{id}_A) (\Sigma _{AB}(\rho _{AB}))\bigr), \notag \end{align}

where \(\Sigma \) denotes the canonical exchange of the two tensor factors.

Definition 26.6.12 Independent maps on both tensor factors
#

For linear maps \(\Phi _A\) and \(\Psi _B\), set

\begin{align} (\Phi _A\otimes \Psi _B)(\rho ) & =(\operatorname{id}_{A'}\otimes \Psi _B) ((\Phi _A\otimes \operatorname{id}_B)(\rho )). \notag \end{align}
Lemma 26.6.13 Positivity under a map on the first tensor factor

If \(\Phi _A\) is trace-preserving completely positive and \(\rho _{AB}\geq 0\), then \((\Phi _A\otimes \operatorname{id}_B)(\rho )\geq 0\).

Lemma 26.6.14 Positivity under a map on the second tensor factor

If \(\Psi _B\) is trace-preserving completely positive and \(\rho _{AB}\geq 0\), then \((\operatorname{id}_A\otimes \Psi _B)(\rho )\geq 0\).

Lemma 26.6.15 Positivity under independent maps

If \(\Phi _A\) and \(\Psi _B\) are trace-preserving completely positive and \(\rho _{AB}\geq 0\), then \((\Phi _A\otimes \Psi _B)(\rho )\geq 0\).

Theorem 26.6.16 Data processing on the first tensor factor

Let \(\rho _{AB}\) be a bipartite density operator and let \(\Phi _A\) be a trace-preserving completely positive map whose input and output matrix algebras may have different dimensions. Then \(I(A':B)_{(\Phi _A\otimes \operatorname{id}_B)(\rho )}\leq I(A:B)_\rho \).

Proof

Choose a rectangular Stinespring isometry for \(\Phi _A\). Conjugating by \(W=V_A\otimes \operatorname{id}_B\) gives \(\omega _{A'EB}=W\rho _{AB}W^\dagger \). Since \(W=V_A\otimes \operatorname{id}_B\) and \(V_A^\dagger V_A=\operatorname{id}_A\), its marginals satisfy

\begin{align} \omega _{A'E}& =V_A\rho _A V_A^\dagger , \notag \\ \omega _B& =\rho _B. \notag \end{align}

Entropy is preserved by the isometry \(W\), and also by \(V_A\) on the first marginal. Therefore

\begin{align} S(\omega _{A'EB})& =S(\rho _{AB}), \notag \\ S(\omega _{A'E})& =S(\rho _A), \notag \\ S(\omega _B)& =S(\rho _B). \notag \end{align}

Hence \(I(A'E:B)_\omega =I(A:B)_\rho \). The defining Stinespring identity is \(\operatorname{tr}_E(\omega _{A'EB})=(\Phi _A\otimes \operatorname{id}_B)(\rho _{AB})\). Strong subadditivity in the form \(I(R:A')\leq I(R:A'E)\) proves the stated inequality with \(R=B\).

Theorem 26.6.17 Data processing on the second tensor factor

Let \(\rho _{AB}\) be a bipartite density operator and let \(\Psi _B\) be a trace-preserving completely positive map whose input and output matrix algebras may have different dimensions. Then \(I(A:B')_{(\operatorname{id}_A\otimes \Psi _B)(\rho )}\leq I(A:B)_\rho \).

Proof

Exchange the two tensor factors and apply Theorem 26.6.16.

Theorem 26.6.18 Data processing for bipartite mutual information

Let \(\rho _{AB}\) be a bipartite density operator and let \(\Phi _A\) and \(\Psi _B\) be trace-preserving completely positive maps whose input and output matrix algebras may have different dimensions. Then \(I(A':B')_{(\Phi _A\otimes \Psi _B)(\rho )}\leq I(A:B)_\rho \).

Proof

Apply the two one-sided inequalities successively.

For \(N=L+K\), split a physical configuration into consecutive intervals of lengths \(L\) and \(K\), flatten each interval to a finite index, and denote the resulting bipartite form of the normalized periodic MPO by \(\sigma ^{(N)}_{L:K}\). The flattened local maps on the two factors are denoted by \(\widehat{\mathcal T}_L\) and \(\widehat{\mathcal S}_K\).

Across the consecutive cut after the first \(L\) sites, the two marginals of \(\sigma ^{(N)}_{L:N-L}\) are the reduced states on \(L\) and \(N-L\) sites, up to the standard finite-index identifications. Consequently, \(I_L(M)\) is the ordinary bipartite mutual information of \(\sigma ^{(N)}_{L:N-L}\).

Proof

The first marginal is the defining partial trace over the last \(N-L\) sites. Periodic translation invariance identifies the second marginal with the reduced state on the first \(N-L\) sites. Entropy is invariant under the finite-index identifications, and retaining the full chain leaves the normalized state unchanged.

Lemma 26.6.21 Renormalization maps transfer one site across a cut

Suppose that \(N=(a+1)+(b+2)=(a+2)+(b+1)\). The local closure equations imply

\begin{align} (\widehat{\mathcal T}_a\otimes \widehat{\mathcal S}_b) (\sigma ^{(N)}_{a+1:b+2}) & =\sigma ^{(N)}_{a+2:b+1}, \notag \\ (\widehat{\mathcal S}_a\otimes \widehat{\mathcal T}_b) (\sigma ^{(N)}_{a+2:b+1}) & =\sigma ^{(N)}_{a+1:b+2}. \notag \end{align}
Proof

Fixing the word on the second interval leaves a physical closure on the first interval, whose virtual boundary is the fixed word evaluation. Apply the appropriate global closure identity to this slice. Fixing the resulting word on the first interval gives the closure on the second interval. Cyclicity of the virtual trace identifies the two cuts of the periodic contraction. The reverse identity is the same argument with \(\mathcal S\) and \(\mathcal T\) interchanged.

Theorem 26.6.22 Conditional RFP mutual-information equality

Let \(M\) be a renormalization fixed point. If its \(N\)-site operator is positive semidefinite and has nonzero trace, then \(I(\sigma ^{(N)}_{a+1:b+2}) =I(\sigma ^{(N)}_{a+2:b+1})\). This is the channel calculation in [ CPGSV16 , Appendix C, lines 1333–1341 ] . For the forward implication proved here, the required nonzero trace follows from normalized BNT-refined horizontal form, the MPDO condition, and the renormalization maps; simplicity is not used. This horizontal hypothesis is stronger than literal CPSV canonical form.

Proof

Apply mutual-information data processing to the forward pair of local channels and to the reverse pair. The two transfer identities turn the resulting inequalities into opposite inequalities between the displayed mutual informations.

Lemma 26.6.23 Nonvanishing of positive-length BNT-refined RFP rings

Let \(M\) be in normalized BNT-refined horizontal form, generate positive semidefinite ring operators, and satisfy the local renormalization fixed-point equations. This horizontal hypothesis is stronger than literal CPSV canonical form. Then \(\operatorname{tr}\rho ^{(N)}(M)\neq 0\) for every \(N\geq 1\).

Proof

Normalized BNT-refined horizontal form gives a nonzero sector compression for one positive length. Positivity makes its trace nonzero. The fixed-point equations make the physical-trace transfer idempotent, so the trace of its positive powers is independent of the positive exponent.

Theorem 26.6.24 BNT-refined renormalization fixed points saturate the area law

Let \(M\) be a matrix product density operator in normalized BNT-refined horizontal form which satisfies the local renormalization fixed-point equations of Definition 4.1. This horizontal hypothesis is stronger than literal CPSV canonical form. Then \(M\) saturates the area law: \(I_L(M)=I_{L+1}(M)\) whenever \(1\leq L{\lt}\lfloor N/2\rfloor \). This is the normalized BNT-refined specialization of the forward implication of Proposition propsimple in Appendix C of [ CPGSV16 ] . Simplicity is among the ambient hypotheses of Theorem 4.9 but is not used in this implication.

Proof

Write the cut as \((a+1):(b+2)\). The local channels transfer one site to obtain \((a+2):(b+1)\), and data processing in both directions gives equality of the two bipartite mutual informations. The consecutive-cut identification turns this into \(I_L=I_{L+1}\). The preceding lemma supplies the normalization at every positive chain length.

Theorem 26.6.25 BNT-refined renormalization fixed points have ZCL and SAL

Let \(M\) be a matrix product density operator in normalized BNT-refined horizontal form which satisfies the local renormalization fixed-point equations of Definition 4.1. This horizontal hypothesis is stronger than literal CPSV canonical form. Then \(M\) has source zero correlation length and saturates the area law. This is the normalized-BNT-refined specialization of Proposition propsimple in Appendix C of [ CPGSV16 ] , lines 1333–1341.

Proof

The preceding nonvanishing lemma at length one rules out a zero physical-trace transfer. Trace preservation of the refinement map then gives source zero correlation length, while Theorem 26.6.24 gives saturation of the area law.

Lemma 26.6.26 Nonnegativity of block entropies
#

For a normalized positive semidefinite finite-chain operator, every block entropy is non-negative: \(0\le S_m\).

Proof

The reduced state of a block is a density matrix, and the von Neumann entropy of a density matrix is non-negative.

Lemma 26.6.27 Nonnegativity of the mutual information

Let \(M\) generate an MPDO whose finite-chain operator \(\rho ^{(N)}(M)\) is positive semidefinite with nonzero trace. For every block length \(L\le N\), one has \(0\le I_L\).

Proof

Apply strong subadditivity with a trivial middle subsystem (equivalently, subadditivity) to the bipartition of the chain into the first \(L\) and last \(N-L\) spins: \(S_N+S_0\le S_L+S_{N-L}\). Since \(S_0\ge 0\) (Lemma 26.6.26), rearranging gives \(I_L=S_L+S_{N-L}-S_N\ge S_0\ge 0\).

Lemma 26.6.28 Symmetry of the mutual information across the cut

For every block length \(L\le N\), the mutual information of the first \(L\) spins equals that of their complement: \(I_L=I_{N-L}\).

Proof

Both sides equal \(S_L+S_{N-L}-S_N\) by the symmetric definition \(I_L=S_L+S_{N-L}-S_N\), using \(N-(N-L)=L\).

Lemma 26.6.29 Positive rank of a normalized state
#

A positive semidefinite matrix of trace one has positive rank.

Proof

If its rank were zero, every eigenvalue would vanish, contradicting that their sum is the trace, which equals one.

Lemma 26.6.30 Zero entropy in rank one

A positive semidefinite matrix of trace one and rank at most one has zero von Neumann entropy.

Proof

Its rank is positive by Lemma 26.6.29, hence it is exactly one. The rank bound gives \(S\le \log 1=0\), while entropy is non-negative.

Lemma 26.6.31 Entropy of the empty block

For a normalized positive semidefinite finite-chain operator, the block entropy of the empty block vanishes: \(S_0=0\).

Proof

The reduced state of zero spins is one-dimensional, so its rank is at most one. Lemma 26.6.30 gives \(S_0=0\).

Lemma 26.6.32 Empty-block mutual information vanishes

For a normalized positive semidefinite finite-chain operator, the mutual information of the empty block vanishes: \(I_0=0\).

Proof

By definition, \(I_0=S_0+S_N-S_N=S_0\), which is zero by Lemma 26.6.31.

For a block of \(L\) spin–ancilla pairs, regroup

\begin{align} (\mathbb {C}^d\otimes \mathbb {C}^{d_K})^{\otimes L} & \cong (\mathbb {C}^d)^{\otimes L} \otimes (\mathbb {C}^{d_K})^{\otimes L} \notag \end{align}

and trace the ancillary factor. Denote this map by \(\operatorname{Tr}_{\mathrm{anc},L}\). It is the blockwise analog of the one-site ancillary trace in Definition 26.5.3.

Theorem 26.6.34 Block ancillary trace is a channel

The map \(\operatorname{Tr}_{\mathrm{anc},L}\) is trace-preserving and completely positive.

Proof

The reindexing equivalence is a channel, as is the partial trace over the ancillary factor. Their composition is therefore trace-preserving and completely positive.

Theorem 26.6.35 Coefficients of the ancillary traces

If \(X\) is an operator on a spin–ancilla block, then for \(i,j\in [d]^L\),

\begin{align} \operatorname{Tr}_{\mathrm{anc},L}(X)_{i,j} & =\sum _{\kappa \in [d_K]^L}X_{(i,\kappa ),(j,\kappa )}. \notag \end{align}

For \(i,j\in [d]^L\) and \(x,y\in [d]^K\), applying the ancillary traces to both blocks across the cut \(L\mid K\) gives

\begin{align} \bigl[(\operatorname{Tr}_{\mathrm{anc},L}\otimes \operatorname{Tr}_{\mathrm{anc},K})(X)\bigr]_{(i,x),(j,y)} & =\sum _{\kappa \in [d_K]^L}\sum _{\lambda \in [d_K]^K} X_{((i,\kappa ),(x,\lambda )),((j,\kappa ),(y,\lambda ))}. \notag \end{align}
Proof

After regrouping the spin and ancillary factors, the definition of the partial trace gives the first coefficient identity. Applying this identity to both tensor factors gives the displayed iterated sum; the two finite sums may be interchanged.

Fix a local-purification representation

\begin{align} M^{ij} & =\left(\sum _{k=0}^{d_K-1} A^{(i,k)}\otimes \overline{A^{(j,k)}}\right)_{e,e}, \notag \end{align}

with purifying MPS tensor \(\widetilde A\) of physical dimension \(d d_K\) and bond dimension \(D'\). For every \(N=L+K\), tracing all ancillary degrees of freedom gives

\begin{align} \rho ^{(N)}(M) & =\operatorname{Tr}_{\mathrm{anc},N} \left(|V^{(N)}(\widetilde A)\rangle \! \langle V^{(N)}(\widetilde A)|\right), \notag \\ \operatorname{tr}\rho ^{(N)}(M) & =\left\lVert V^{(N)}(\widetilde A)\right\rVert ^2. \notag \end{align}

Define the normalized-form purifying operator by

\begin{align} \pi _{\widetilde A}^{(N)} & :=\left\lVert V^{(N)}(\widetilde A)\right\rVert ^{-2} |V^{(N)}(\widetilde A)\rangle \! \langle V^{(N)}(\widetilde A)|, \notag \end{align}

where the inverse scalar is taken with the convention \(0^{-1}=0\). After reindexing across the cut \(L\mid K\),

\begin{align} \sigma ^{(N)}_{L:K}(M) & =\left(\operatorname{Tr}_{\mathrm{anc},L}\otimes \operatorname{Tr}_{\mathrm{anc},K}\right) \left(\left(\pi _{\widetilde A}^{(N)}\right)_{L:K}\right). \notag \end{align}

This identity also holds when the common trace vanishes, in which case both normalized-form operators are zero.

This is the finite-chain channel identity from the purification preceding equation (4) of [ WVHC08 ] , under the explicit local purification of [ CPGSV16 , Section 4.3 ] .

Proof

The coefficient formula for one block gives

\begin{align} & \operatorname{Tr}_{\mathrm{anc},N} \left(|V^{(N)}(\widetilde A)\rangle \! \langle V^{(N)}(\widetilde A)|\right)_{\sigma ,\tau } \notag \\ & \quad =\sum _{\kappa \in [d_K]^N} V^{(N)}(\widetilde A)_{(\sigma ,\kappa )} \overline{V^{(N)}(\widetilde A)_{(\tau ,\kappa )}} =\rho ^{(N)}(M)_{\sigma ,\tau }. \notag \end{align}

Trace preservation gives equality of the two normalizing traces. Splitting \(\kappa \) into its left and right restrictions changes the last sum into the two independent sums in Theorem 26.6.35, which proves the normalized identity across \(L\mid K\).

Theorem 26.6.37 LPDOs admit a block-channel representation

Let \(M\) be an LPDO. For every decomposition \(N=L+K\), there exist an ancillary dimension \(d_K\), a purifying bond dimension \(D'\), and a local-purification family \(A\). Let \(\widetilde A\) be its associated purifying MPS tensor. Then

\begin{align} \sigma ^{(N)}_{L:K}(M) & =\left(\operatorname{Tr}_{\mathrm{anc},L}\otimes \operatorname{Tr}_{\mathrm{anc},K}\right) \left(\left(\pi _{\widetilde A}^{(N)}\right)_{L:K}\right). \notag \end{align}
Proof

Choose a local-purification representation of \(M\) and apply Theorem 26.6.36 to its purifying tensor.

Theorem 26.6.38 LPDOs admit a cut-uniform block-channel representation

Let \(M\) be an LPDO. There exist an ancillary dimension \(d_K\), a purifying bond dimension \(D'\), and a local-purification family \(A\), all independent of the cut, such that for every decomposition \(N=L+K\),

\begin{align} \sigma ^{(N)}_{L:K}(M) & =\left(\operatorname{Tr}_{\mathrm{anc},L}\otimes \operatorname{Tr}_{\mathrm{anc},K}\right) \left(\left(\pi _{\widetilde A}^{(N)}\right)_{L:K}\right), \notag \end{align}

where \(\widetilde A\) is the purifying MPS tensor associated with \(A\).

Proof

Choose one local-purification representation of \(M\). For an arbitrary decomposition \(N=L+K\), apply Theorem 26.6.36 to the same purifying tensor.

Let \(M\) be an MPO tensor whose generated \(N\)-site operator is positive semidefinite. Let \(A\) be an MPS tensor of bond dimension \(D'\geq 1\) whose \(N\)-site vector is nonzero. Suppose that, across the cut \(L\mid (N-L)\), the normalized state generated by \(M\) is obtained from the normalized pure state of \(A\) by trace-preserving completely positive maps \(\Phi _L\) and \(\Phi _R\) on the two blocks:

\begin{align} \sigma ^{(N)}_{L:N-L}(M) & =(\Phi _L\otimes \Phi _R) \left(\frac{|V^{(N)}(A)\rangle \! \langle V^{(N)}(A)|}{\lVert V^{(N)}(A)\rVert ^2}\right)_{L:N-L}. \notag \end{align}

Then \(I_L(M)\leq 4\log D'\).

Proof

Write \(\sigma _A^{(N)}\) for the normalized pure state of \(A\) in the \(L\mid (N-L)\) bipartition. Then

\begin{align} I_L(M) & =I\! \left((\Phi _L\otimes \Phi _R)(\sigma _A^{(N)})\right) \leq I(\sigma _A^{(N)}) \leq 4\log D’. \notag \end{align}

The equality is the channel-image hypothesis, the first inequality is data processing, and the last inequality is Proposition 26.6.77.

Fix a local-purification representation with purifying MPS bond dimension \(D'\). If the \(N\)-site operator is positive semidefinite and its purifying pure state is nonzero, then \(I_L(M)\leq 4\log D'\) for every \(L\leq N\).

Consequently, if \(M\) is an LPDO, \(N\geq 1\), and \(\operatorname{tr}\rho ^{(N)}(M)\neq 0\), then its local-purification representation supplies a bond dimension \(D'\) satisfying this estimate. The quantity \(D'\) is the bond dimension of the purifying MPS, not the MPO bond dimension \(D\).

Proof

By Theorem 26.6.36,

\begin{align} I_L(M) & =I\! \left((\operatorname{Tr}_{\mathrm{anc},L}\otimes \operatorname{Tr}_{\mathrm{anc},N-L}) \left(\left(\pi _{\widetilde A}^{(N)}\right)_{L:N-L}\right)\right) \notag \\ & \leq I\! \left(\left(\pi _{\widetilde A}^{(N)}\right)_{L:N-L}\right) \leq 4\log D’. \notag \end{align}

The first inequality is data processing and the second is the pure-state boundary estimate. Nonvanishing of the purifying pure state implies \(D'{\gt}0\). For an LPDO, positivity follows from Theorem 23.3.3, while the trace identity in Theorem 26.6.36 transfers the nonzero-trace hypothesis to the purifying pure state.

Theorem 26.6.41 Rank of diagonal coefficients across a periodic cut

Split a periodic chain into consecutive blocks of lengths \(L\) and \(R\). For words \(x\in \{ 0,\ldots ,d-1\} ^L\) and \(y\in \{ 0,\ldots ,d-1\} ^R\), set

\begin{align} P_{x,y} & = \operatorname{tr}\! \left(M^{x_0x_0}\cdots M^{x_{L-1}x_{L-1}} M^{y_0y_0}\cdots M^{y_{R-1}y_{R-1}}\right). \notag \end{align}

Then the ordinary complex rank of \(P\) satisfies \(\operatorname{rank}_{\mathbb {C}}P\le D^2\).

Proof

For each word, write \(A_x=M^{x_0x_0}\cdots M^{x_{L-1}x_{L-1}}\) and \(B_y=M^{y_0y_0}\cdots M^{y_{R-1}y_{R-1}}\). The identity

\begin{align} P_{x,y} & =\operatorname{tr}(A_xB_y) =\sum _{a,b=0}^{D-1}(A_x)_{ab}(B_y)_{ba} \notag \end{align}

factors \(P\) through the \(D^2\)-dimensional space indexed by pairs \((a,b)\).

Theorem 26.6.42 Rank under nonzero scalar multiplication
#

Let \(K\) be a field, let \(A\) be a finite matrix over \(K\), and let \(a\in K\) be nonzero. Then \(\operatorname{rank}_{K}(aA)=\operatorname{rank}_{K}A\).

Proof

Multiplication by \(a\) identifies the column spaces, with inverse given by multiplication by \(a^{-1}\).

Theorem 26.6.43 Rank under faithful scalar extension
#

Let \(K\subseteq L\) be a faithful field extension, let \(\iota :K\hookrightarrow L\) be the inclusion, and let \(A\) be a finite matrix over \(K\). Then \(\operatorname{rank}_{L}\! \left((\iota (A_{ij}))_{ij}\right)=\operatorname{rank}_{K}A\).

Proof

For every finite selection of columns, the selected columns are linearly independent over \(K\) if and only if their scalar extensions are linearly independent over \(L\). Selecting a basis from each column space proves the two rank inequalities.

Definition 26.6.44 Joint probability distribution and marginals

Let \(X\) and \(Y\) be finite sets. A matrix \(P=(P_{x,y})_{x\in X,y\in Y}\) is a joint probability distribution if \(P_{x,y}\geq 0\) for every \(x\in X\) and \(y\in Y\), and

\begin{align} \sum _{x\in X}\sum _{y\in Y}P_{x,y} & =1. \notag \end{align}

Its row and column marginals are respectively

\begin{align} p_x& =\sum _{y\in Y}P_{x,y}, \notag \\ q_y& =\sum _{x\in X}P_{x,y}. \notag \end{align}
Definition 26.6.45 Entropy and classical mutual information

For \(t{\gt}0\), set \(h(t)=-t\log t\), and set \(h(0)=0\). The entropy of a probability distribution \(a=(a_z)_{z\in Z}\) on a finite set is \(H(a)=\sum _{z\in Z}h(a_z)\). For a joint probability distribution \(P\) with row and column marginals \(p\) and \(q\), put

\begin{align} H(P)& =\sum _{x\in X}\sum _{y\in Y}h(P_{x,y}), \notag \\ I(X:Y)_P& =H(p)+H(q)-H(P). \notag \end{align}
Lemma 26.6.46 Entropy is bounded by the logarithm of the support cardinality

Let \(p=(p_z)_{z\in Z}\) be a probability distribution on a finite set \(Z\). Define \(h(t)=-t\log t\) for \(t{\gt}0\) and \(h(0)=0\). Then

\begin{align} \sum _{z\in Z}h(p_z) & \leq \log \left\lvert \{ z\in Z:p_z\neq 0\} \right\rvert . \notag \end{align}
Proof

Let \(k=\lvert \{ z\in Z:p_z\neq 0\} \rvert \). Jensen’s inequality for the concave function \(h\), with uniform weights on the support, gives

\begin{align} \frac{1}{k}\sum _{\substack {z\in Z\\ \begin{bgroup} p_z\neq 0 \end{bgroup}}}h(p_z) & \leq h\left(\frac{1}{k} \sum _{\substack {z\in Z\\ \begin{bgroup} p_z\neq 0 \end{bgroup}}}p_z\right) =h\left(\frac{1}{k}\right) =\frac{\log k}{k}. \notag \end{align}

Multiplication by \(k\) proves the result, since values outside the support contribute \(h(0)=0\).

Theorem 26.6.47 Classical mutual information is bounded by ordinary rank

Let \(X\) and \(Y\) be finite sets and let \(P=(P_{x,y})_{x\in X,y\in Y}\) be a joint probability distribution. With natural logarithms, \(I(X:Y)_P\leq \log \operatorname{rank}_{\mathbb {R}}P\). Equivalently, with logarithms to base two, \(2^{I(X:Y)_P}\leq \operatorname{rank}_{\mathbb {R}}P\).

Proof

This is Theorem 4.1 of [ RV17 ] . If the number of nonzero rows exceeds the ordinary real rank, choose a nontrivial real linear relation among those rows. Nonnegativity forces the relation to have coefficients of both signs. Rescaling each row by \(1+\varepsilon \beta _x\) gives two endpoint distributions. For every \(y\in Y\), the row relation gives

\begin{align} \sum _x(1+\varepsilon \beta _x)P_{x,y} & =\sum _xP_{x,y} +\varepsilon \underbrace{\sum _x\beta _xP_{x,y}}_{=0} =\sum _xP_{x,y}. \notag \end{align}

Thus each endpoint preserves every column marginal, removes at least one row, and has no larger rank. Write \(h(t)=-t\log t\) for \(t{\gt}0\), with \(h(0)=0\), and put \(m=\min _x\beta _x{\lt}0{\lt}M=\max _x\beta _x\). Then

\begin{align} I(X:Y)_{P^{(\varepsilon )}} & =I(X:Y)_P+\varepsilon S(\beta ), \notag \\ S(\beta ) & =\sum _x\beta _x\left(h(p_x)-\sum _y h(P_{x,y})\right). \notag \end{align}

If \(S(\beta )\geq 0\), choose \(\varepsilon =-m^{-1}\geq 0\); otherwise choose \(\varepsilon =-M^{-1}\leq 0\). In either case \(\varepsilon S(\beta )\geq 0\), so the selected endpoint has mutual information no smaller than the original distribution. Repeating the construction leaves at most \(\operatorname{rank}_{\mathbb {R}}P\) nonzero rows. Finally, \(I(X:Y)\leq H(X)\), and the entropy of a distribution supported on \(k\) points is at most \(\log k\).

Theorem 26.6.48 Classical estimate for normalized diagonal cut coefficients

Let \(D\geq 1\), and let \(W\) be a real diagonal coefficient matrix across a periodic cut of an MPO with bond dimension \(D\). Suppose its scalar extension to \(\mathbb {C}\) is the cut matrix \(P^{\mathbb {C}}\) from Theorem 26.6.41. If \(Z{\gt}0\) and \(P=Z^{-1}W\) is a joint probability distribution, then \(I(X:Y)_P\leq 2\log D\).

Proof

Normalization does not change real rank by Theorem 26.6.42. Faithful scalar extension does not change rank by Theorem 26.6.43; hence Theorem 26.6.41 gives \(\operatorname{rank}_{\mathbb {R}}P\leq D^2\). Theorem 26.6.47 gives \(I(X:Y)_P\leq \log \operatorname{rank}_{\mathbb {R}}P\), and monotonicity of the logarithm gives the result.

Definition 26.6.49 Normalized diagonal distribution at fixed length

For a chain of length \(N=L+R\), call \(\rho ^{(N)}(M)\) diagonal if \(\rho ^{(N)}(M)_{u,v}=0\) whenever \(u\ne v\). Call \(M\) globally diagonal if \(\rho ^{(N)}(M)\) is diagonal for every \(N{\gt}0\). For configurations \(x\) and \(y\) on the two consecutive blocks, define

\begin{align} W_{x,y}& =\operatorname{Re}\rho ^{(L+R)}(M)_{(x,y),(x,y)}, \notag \\ Z& =\sum _{x,y}W_{x,y}, \notag \\ \widehat P& =Z^{-1}W. \notag \end{align}
Lemma 26.6.50 Diagonal coefficient mass and trace

For every MPO tensor \(M\) and cut lengths \(L,R\), the total diagonal coefficient mass satisfies \(Z=\operatorname{Re}\operatorname{tr}\rho ^{(L+R)}(M)\).

Proof

Pairing each configuration \(\sigma \) on \(L+R\) sites with its unique block split \((x,y)\) on \(L\) and \(R\) sites gives

\begin{align} Z & =\sum _{x,y}W_{x,y} =\sum _\sigma \operatorname{Re}\rho ^{(L+R)}(M)_{\sigma ,\sigma } =\operatorname{Re}\operatorname{tr}\rho ^{(L+R)}(M). \notag \end{align}

Let \(D\geq 1\). Suppose that \(\rho ^{(L+R)}(M)\) is diagonal and positive semidefinite, and that \(Z{\gt}0\). Then \(W_{x,y}\geq 0\), the scalar extension of \(W\) to \(\mathbb {C}\) is the diagonal cut matrix of Theorem 26.6.41, and \(\widehat P\) is a joint probability distribution. Its classical mutual information satisfies \(I(X:Y)_{\widehat P}\leq 2\log D\).

Proof

Positive semidefiniteness makes every diagonal entry real and non-negative, so \(W_{x,y}\geq 0\) and its scalar extension recovers the complex diagonal cut matrix. Since \(Z\) is the sum of the entries of \(W\), \(\sum _{x,y}\widehat P_{x,y} =Z^{-1}\sum _{x,y}W_{x,y}=1\). Thus \(\widehat P\) is a joint probability distribution. Diagonality says that these coefficients constitute the full classical finite-chain state, and Theorem 26.6.48 gives the bound.

Corollary 26.6.52 Classical estimate for a diagonal matrix product density operator

Let \(D\geq 1\), and let \(M\) generate diagonal positive semidefinite operators at every positive chain length. If \(L+R{\gt}0\) and the trace at length \(L+R\) is positive, then the classical mutual information of its normalized diagonal coefficients satisfies \(I(X:Y)\leq 2\log D\).

Proof

Global diagonality and positivity give the fixed-length hypotheses of Theorem 26.6.51. Since the chain operator is diagonal,

\begin{align} Z & =\sum _{x,y}W_{x,y} =\operatorname{Re}\operatorname{tr}\rho ^{(L+R)}(M), \notag \end{align}

so the trace positivity hypothesis supplies the required normalization.

Definition 26.6.53 Operator-Schmidt rank

For a bipartite density operator \(\rho \in M_{d_A}(\mathbb {C})\otimes M_{d_B}(\mathbb {C})\), its operator-Schmidt rank is the least integer \(r\) for which there are matrices \(A_t\in M_{d_A}(\mathbb {C})\) and \(B_t\in M_{d_B}(\mathbb {C})\) satisfying

\begin{align} \rho & =\sum _{t=1}^{r}A_t\otimes B_t. \notag \end{align}

No Hermiticity or positivity condition is imposed on the factors. This is the definition in [ DlCDN19 , Equation (1) ] ; the same formula defines the rank of an arbitrary complex bipartite matrix.

Let \(M\) be an MPO tensor of operator bond dimension \(D\), and let \(N=L+K\). Opening the two virtual bonds at the consecutive cut gives

\begin{align} \sigma ^{(N)}_{L:K} & =\sum _{a,b=0}^{D-1} X_{ab}\otimes Y_{ab}, \notag \end{align}

and

\begin{align} \operatorname {OSR}(\sigma ^{(N)}_{L:K})& \leq D^2. \notag \end{align}

For left-block words \(x,x'\) and right-block words \(y,y'\), the factors are

\begin{align} (X_{ab})_{x,x'} & =\operatorname{tr}[\rho ^{(N)}(M)]^{-1} \bigl(M^{x_0x'_0}\cdots M^{x_{L-1}x'_{L-1}}\bigr)_{ab}, \notag \end{align}

and

\begin{align} (Y_{ab})_{y,y'} & =\bigl(M^{y_0y'_0}\cdots M^{y_{K-1}y'_{K-1}}\bigr)_{ba}. \notag \end{align}

This is the identity \(\operatorname{tr}(AB)=\sum _{a,b}A_{ab}B_{ba}\), with the normalization scalar absorbed into the left factor. The algebraic decomposition does not use positivity. Since \(0^{-1}=0\), it also remains valid when the trace vanishes; a nonzero trace is needed only to interpret \(\sigma ^{(N)}_{L:K}\) as the normalized physical state.

This is the two-virtual-boundary algebraic step toward the finite mutual-information estimate in [ CPGSV16 , Proposition 4.5 ] . It does not by itself prove \(I_L\leq 4\log D\): such a conclusion would require an entropy bound in terms of the operator-Schmidt rank.

Proof

Split each closed virtual word into its left and right products. Expanding the trace over the two exposed virtual indices gives the displayed sum of \(D^2\) product matrices. The minimality property of the operator-Schmidt rank then bounds it by the number of displayed terms.

Theorem 26.6.55 Coefficient-space characterization of operator-Schmidt rank

Write \(\rho _{ij}\in M_{d_B}(\mathbb {C})\) for the blocks determined by a basis of the first factor, and define \(\mathcal R_\rho (X)=\sum _{i,j}X_{ij}\rho _{ij}\). Then

\begin{align} \operatorname {OSR}(\rho ) & =\dim \operatorname{range}\mathcal R_\rho =\dim \operatorname{span}\{ \rho _{ij}:1\leq i,j\leq d_A\} . \notag \end{align}
Proof

The range of \(\mathcal R_\rho \) is the span of the blocks. If \(\rho =\sum _{t=1}^{r}A_t\otimes B_t\), every block belongs to \(\operatorname{span}\{ B_1,\ldots ,B_r\} \), so the range dimension is at most \(r\). Conversely, choose a basis \(B_1,\ldots ,B_s\) of the block span and expand each block as \(\rho _{ij}=\sum _t(A_t)_{ij}B_t\). This gives \(\rho =\sum _{t=1}^{s}A_t\otimes B_t\), where \(s=\dim \operatorname{range}\mathcal R_\rho \).

Let \(\rho \geq 0\) be a bipartite complex matrix whose first marginal is faithful. Choose an eigenbasis in which \(\operatorname{tr}_B\rho =\operatorname{diag}(p_1,\ldots ,p_{d_A})\) with every \(p_i{\gt}0\), and define the linear map \(\Phi _\rho \) on matrix units by

\begin{align} \Phi _\rho (E_{ij}) & =\frac{\rho _{ij}}{\sqrt{p_ip_j}}. \notag \end{align}

Then \(\Phi _\rho \) is completely positive and trace preserving, \(\dim \operatorname{range}\Phi _\rho =\operatorname {OSR}(\rho )\), and application of \(\Phi _\rho \) to the first half of \(\sum _{i,j}\sqrt{p_ip_j}\, E_{ij}\otimes E_{ij}\), followed by restoring the order of the two factors, reconstructs \(\rho \).

Proof

Strict positivity of the \(p_i\) makes the entrywise input scaling invertible, so it does not change the range. Positivity of \(\rho \) gives a Kraus representation of \(\Phi _\rho \), while the displayed marginal equation gives trace preservation. Substitution on matrix units proves the reconstruction identity. This is the finite-dimensional Choi representation [ Cho75 ] with the input marginal absorbed into the canonical purification.

Remark 26.6.57 Boundedness of the mutual information
#

The proof of Proposition 4.5 of [ CPGSV16 ] invokes the uniform estimate \(I_L\leq 4\log D\) for every MPDO. Its cited argument, however, treats mixed tensor-network states obtained from local completely positive maps [ WVHC08 ] . After purifying those maps, data processing and the pure-state boundary estimate give

\begin{align} I(A:B)_{\rho } & \leq I(A:B)_{|\Psi \rangle \! \langle \Psi |} =2S(A)_{|\Psi \rangle \! \langle \Psi |} \leq 2\lvert \partial A\rvert \log D. \notag \end{align}

A periodic one-dimensional interval has two boundary bonds, and hence the last expression is \(4\log D\). A general positive MPO need not admit this local purification.

By Theorem 26.6.55, the two virtual bonds give an operator-Schmidt decomposition with at most \(D^2\) terms, but they do not bound the ordinary rank of either marginal. For example, a bond-one tensor can generate \(q^{\otimes N}\) for a full-rank one-site density matrix \(q\). Thus its \(L\)-site marginal has rank \(\operatorname{rank}(q)^L\), although its mutual information vanishes. The unrestricted estimate therefore requires a direct operator-Schmidt argument not supplied by the cited proof.

Diagonal operators cannot violate the finite-chain estimate. Indeed, Theorem 26.6.51 bounds by \(2\log D\) the classical mutual information of the normalized diagonal coefficients whenever the finite-chain operator is diagonal and positive semidefinite and has positive total mass. Thus any counterexample must have genuine quantum coherences. Theorem 26.6.56 identifies the faithful-marginal problem with a channel whose linear range has dimension \(\operatorname {OSR}(\rho )\); it does not supply the desired mutual-information inequality. The unrestricted quantum estimate remains open. The same example as Theorem 26.6.9 also makes the iterated mutual-information limit false; see docs/paper-gaps/cpgsv17_mpdo_mutual_information_bound.tex. The channel-image implication is Theorem 26.6.39, and the pure-state instance is Proposition 26.6.77 below. The locally purified case is Theorem 26.6.40.

Definition 26.6.58 Block entropy and area-law saturation for pure states

For an MPS tensor \(A\), a system size \(N\), and a block length \(L\le N\), let

\begin{align} \sigma ^{(N)}(A) & = \frac{|V^{(N)}(A)\rangle \! \langle V^{(N)}(A)|}{\| V^{(N)}(A)\| ^2}, \notag \\ \rho _L^{(N)}(A) & =\operatorname{tr}_{N\setminus L}\! [\sigma ^{(N)}(A)] \notag \end{align}

denote the normalized state and the reduced state of the first \(L\) spins. The \(L\)-block entropy is \(S_L^{(N)}(A)=S(\rho _L^{(N)}(A))\). The tensor saturates the area law if \(S_L^{(N)}(A)=S_{L+1}^{(N)}(A)\) for all \(1\le L{\lt}\lfloor N/2\rfloor \) and all \(N\). This is [ CPGSV16 , Definition 3.13, line 600 ] .

Definition 26.6.59 Purification tensor
#

For an MPS tensor \(A\) on bond space \(\mathbb {C}^D\), define the associated MPO tensor \(M\) on bond space \(\mathbb {C}^{D^2}\) by \(M^{ij}=A^i\otimes \overline{A^j}\). This is the single-ancilla purification tensor of [ CPGSV16 ] .

Lemma 26.6.60 Pure state as a purification MPDO

For an MPS tensor \(A\), the pure-state operator \(|V^{(N)}(A)\rangle \! \langle V^{(N)}(A)|\) equals the MPDO generated by the tensor \(M^{ij}=A^i\otimes \overline{A^j}\), acting on a bond space of dimension \(D^2\):

\begin{align} \rho ^{(N)}(A\otimes \bar A) & =|V^{(N)}(A)\rangle \! \langle V^{(N)}(A)|. \notag \end{align}

This is the single-ancilla case of the purification picture of [ CPGSV16 ] ; it lets the MPDO block-entropy theory apply to pure-state block entropies.

Proof

The word evaluation of the doubled tensor is the Kronecker product of the word evaluation of \(A\) and its conjugate, \(M^{\sigma ,\tau }=A^\sigma \otimes \overline{A^\tau }\), so its trace factors as \(\operatorname{tr}(M^{\sigma ,\tau }) =\operatorname{tr}(A^\sigma ) \overline{\operatorname{tr}(A^\tau )} =\overline{V^{(N)}(A)_\tau }\, V^{(N)}(A)_\sigma \), the corresponding matrix element of \(|V^{(N)}(A)\rangle \! \langle V^{(N)}(A)|\).

Lemma 26.6.61 Block entropy of the purification tensor

For an MPS tensor \(A\), system size \(N\), and block length \(L\le N\), the MPDO block entropy of the tensor \(M^{ij}=A^i\otimes \overline{A^j}\) agrees with the pure-state block entropy: \(S_L^{(N)}(M)=S_L^{(N)}(A)\).

Proof

Lemma 26.6.60 gives \(\rho ^{(N)}(M)=|V^{(N)}(A)\rangle \! \langle V^{(N)}(A)|\), hence

\begin{align} \sigma ^{(N)}(M) & = \frac{\rho ^{(N)}(M)}{\operatorname{tr}[\rho ^{(N)}(M)]} = \frac{|V^{(N)}(A)\rangle \! \langle V^{(N)}(A)|}{\| V^{(N)}(A)\| ^2} = \sigma ^{(N)}(A). \notag \end{align}

Therefore the reduced block states agree:

\begin{align} \rho _L^{(N)}(M) & = \operatorname{tr}_{N\setminus L}\! [\sigma ^{(N)}(M)] = \operatorname{tr}_{N\setminus L}\! [\sigma ^{(N)}(A)] = \rho _L^{(N)}(A). \notag \end{align}

Thus \(S_L^{(N)}(M) =S(\rho _L^{(N)}(M)) =S(\rho _L^{(N)}(A)) =S_L^{(N)}(A)\).

Lemma 26.6.62 Schmidt symmetry of the block entropy
#

For an MPS tensor \(A\) and a block length \(L\le N\), the block entropies of a block and its complement coincide: \(S_L^{(N)}(A)=S_{N-L}^{(N)}(A)\).

Proof

The reduced state of the first \(L\) spins is \(\rho _L\propto WW^\dagger \), where \(W\) is the matrix of amplitudes \(\langle u\, w|V^{(N)}(A)\rangle \) with \(u\) the first \(L\) spins and \(w\) the remaining \(N-L\). By cyclic invariance of the amplitudes, the reduced state of the complement is \(\propto \overline{W^\dagger W}\). Cyclic invariance of the entropy, \(S(WW^\dagger )=S(W^\dagger W)\), together with invariance of the entropy under entrywise conjugation of a Hermitian matrix, \(S(\overline{W^\dagger W})=S(W^\dagger W)\), gives \(S_L^{(N)}(A)=S_{N-L}^{(N)}(A)\).

Proposition 26.6.63 Pure-state area-law monotonicity

Let \(A\) be an MPS tensor with \(V^{(N)}(A)\neq 0\). For every block length \(L\) with \(2L+1\le N\), covering \(1\le L{\lt}\lfloor N/2\rfloor \), \(S_L^{(N)}(A)\le S_{L+1}^{(N)}(A)\). This is the pure-state area law of [ CPGSV16 , Section 3, line 599 ] .

Proof

Apply the block-entropy form of strong subadditivity, the inequality underlying Proposition 26.6.7, to the purification MPDO of \(A\), giving \(S_{N-L}+S_L\le S_{L+1}+S_{N-L-1}\). By the Schmidt symmetry \(S_{N-L}=S_L\) and \(S_{N-L-1}=S_{L+1}\), this reduces to \(S_L\le S_{L+1}\).

Lemma 26.6.64 Operator-Schmidt Gram is a transfer-map power

Let \(A\) be an MPS tensor of bond dimension \(D\). For a length-\(\ell \) configuration \(\sigma \) and a length-\(m\) configuration \(\tau \), write the operator-Schmidt factors as

\begin{align} (L_\ell )_{\sigma ,(a_1,a_2)} & =(A^\sigma )_{a_1a_2}, \notag \\ (R_m)_{(p_1,p_2),\tau } & =(A^\tau )_{p_2p_1}. \notag \end{align}

The \(D^2\times D^2\) Gram matrix of the left factor equals the \(\ell \)-fold transfer map evaluated on a matrix unit:

\begin{align} (L_\ell ^\dagger L_\ell )_{(a_1,a_2),(b_1,b_2)} & = \sum _{\sigma }\overline{(A^\sigma )_{a_1a_2}} (A^\sigma )_{b_1b_2} \notag \\ & = (\mathcal{E}_A^{\, \ell }(|b_2\rangle \! \langle a_2|))_{b_1,a_1}, \notag \end{align}

where the sum runs over length-\(\ell \) configurations \(\sigma \). The Gram of the right factor \(R_m\) of an \(m\)-spin complement satisfies the bond-swapped identity

\begin{align} (R_mR_m^\dagger )_{(p_1,p_2),(q_1,q_2)} & = \sum _{\tau }(A^\tau )_{p_2p_1} \overline{(A^\tau )_{q_2q_1}} \notag \\ & = (\mathcal{E}_A^{\, m}(|p_1\rangle \! \langle q_1|))_{p_2,q_2}, \notag \end{align}

where the sum runs over length-\(m\) configurations \(\tau \).

Proof

The left Gram entry is \(\sum _\sigma \overline{(A^\sigma )_{a_1a_2}}(A^\sigma )_{b_1b_2}\) by definition of \(L_\ell \). Expanding

\begin{align} \mathcal{E}_A^{\, \ell }(|b_2\rangle \! \langle a_2|) & = \sum _\sigma A^\sigma |b_2\rangle \! \langle a_2|(A^\sigma )^\dagger \notag \end{align}

and reading off the \((b_1,a_1)\) entry gives the same sum, since

\begin{align} \bigl( A^\sigma |b_2\rangle \! \langle a_2|(A^\sigma )^\dagger \bigr)_{b_1,a_1} & = (A^\sigma )_{b_1b_2} \overline{(A^\sigma )_{a_1a_2}}. \notag \end{align}

The right-factor formula is the same expansion with the two boundary bonds interchanged: the \((p,q)\) entry of \(R_mR_m^\dagger \) is \(\sum _\tau (A^\tau )_{p_2p_1}\overline{(A^\tau )_{q_2q_1}}\), which is the \((p_2,q_2)\) entry of \(\mathcal{E}_A^{\, m}(|p_1\rangle \! \langle q_1|)\).

Lemma 26.6.65 RFP collapse of the operator-Schmidt Grams

Let \(A\) be a renormalization fixed point. For every \(L\ge 1\) and \(m\ge 1\), the operator-Schmidt Grams of the \(L\)-block and of the \(m\)-site complement are the one-site Grams:

\begin{align} L_L^\dagger L_L& =L_1^\dagger L_1, \notag \\ R_mR_m^\dagger & =R_1R_1^\dagger . \notag \end{align}
Proof

By definition, a renormalization fixed point satisfies \(\mathcal{E}_A^{\, 2}=\mathcal{E}_A\), so \(\mathcal{E}_A^{\, k}=\mathcal{E}_A\) for every \(k\ge 1\). Applying Lemma 26.6.64 to the left and right Gram entries gives the two displayed identities.

Lemma 26.6.66 Pure block entropy as a bond-environment charpoly sum

Let \(A\) be an MPS tensor, let \(L\le N\), put \(m=N-L\), and write \(c=(\operatorname{tr}\rho ^{(N)})^{-1}\). Then the pure block entropy is the charpoly-root entropy sum of the \(D^2\times D^2\) bond environment:

\begin{align} S_L^{(N)}(A) & = \sum _{\lambda \in \operatorname {roots}\chi _{c\, (R_mR_m^\dagger )(L_L^\dagger L_L)}} -\operatorname{Re}(\lambda )\log \operatorname{Re}(\lambda ). \notag \end{align}

The roots are counted with algebraic multiplicity.

Proof

The reduced block state has the exact factorization

\begin{align} \rho _L^{(N)}(A) & = c\, L_L(R_mR_m^\dagger )L_L^\dagger . \notag \end{align}

Cyclic invariance of the charpoly-root entropy sum gives

\begin{align} S(c\, L_L(R_mR_m^\dagger )L_L^\dagger ) & = S(c\, (R_mR_m^\dagger )(L_L^\dagger L_L)), \notag \end{align}

which is the displayed formula.

Theorem 26.6.67 A renormalization fixed point saturates the area law

If an MPS tensor \(A\) is a renormalization fixed point, then it saturates the area law: for every chain length \(N\) and every block length \(1\le L{\lt}\lfloor N/2\rfloor \), the pure-state block entropy is constant in the block size, \(S_L^{(N)}(A)=S_{L+1}^{(N)}(A)\). The source statement is [ CPGSV16 , Proposition 3.14, lines 606–608 ] . It assumes canonical form; the theorem above is the stronger pure-state implication obtained from transfer-map idempotence alone.

Proof

Write \(c=(\operatorname{tr}\rho ^{(N)})^{-1}\). Lemma 26.6.66 computes the entropy from the bond environment:

\begin{align} S_L^{(N)}(A) & = \sum _{\lambda \in \operatorname {roots}\chi _{c\, (R_{N-L}R_{N-L}^\dagger ) (L_L^\dagger L_L)}} -\operatorname{Re}(\lambda )\log \operatorname{Re}(\lambda ). \notag \end{align}

Since \(1\le L{\lt}\lfloor N/2\rfloor \), the four lengths \(L\), \(L+1\), \(N-L\), and \(N-(L+1)\) are positive. The RFP Gram-collapse lemma gives

\begin{align} L_L^\dagger L_L & =L_1^\dagger L_1, \notag \\ L_{L+1}^\dagger L_{L+1} & =L_1^\dagger L_1, \notag \\ R_{N-L}R_{N-L}^\dagger & =R_1R_1^\dagger , \notag \\ R_{N-(L+1)}R_{N-(L+1)}^\dagger & =R_1R_1^\dagger . \notag \end{align}

Therefore the two bond environments agree:

\begin{align} (R_{N-L}R_{N-L}^\dagger )(L_L^\dagger L_L) & = (R_1R_1^\dagger )(L_1^\dagger L_1) \notag \\ & = (R_{N-(L+1)}R_{N-(L+1)}^\dagger ) (L_{L+1}^\dagger L_{L+1}). \notag \end{align}

The scalar \(c\) depends only on \(N\), so the two charpoly-root entropy sums are equal. Hence \(S_L^{(N)}(A)=S_{L+1}^{(N)}(A)\).

Theorem 26.6.68 A renormalization fixed point has a constant block-entropy chain

If an MPS tensor \(A\) is a renormalization fixed point, then all block entropies in the range \(1\le L\le \lfloor N/2\rfloor \) coincide:

\begin{align} S_1^{(N)}(A) & =S_2^{(N)}(A) =\cdots =S_{\lfloor N/2\rfloor }^{(N)}(A). \notag \end{align}

This is the explicit constant-entropy chain of the area-law saturation [ CPGSV16 , Definition 3.13, line 600 ] , under the fixed-point hypothesis.

Proof

The fixed point saturates the area law (Theorem 26.6.67), so by the telescoping of saturation (Lemma 26.6.75) the block entropies at any two lengths \(1\le L,L'\le \lfloor N/2\rfloor \) agree: \(S_L^{(N)}(A)=S_{L'}^{(N)}(A)\).

Lemma 26.6.69 Operator-Schmidt rank bound
#

For an MPS tensor \(A\) of bond dimension \(D\) and a block length \(L\le N\), the reduced state \(\rho _L^{(N)}(A)\) of the first \(L\) spins has rank at most \(D^2\).

Proof

The reduced state is \(\rho _L\propto WW^\dagger \), where the amplitude matrix

\begin{align} W(u,w) & = \langle u\, w|V^{(N)}(A)\rangle = \operatorname{tr}\! \bigl( A^{u_1}\cdots A^{u_L} A^{w_1}\cdots A^{w_{N-L}} \bigr) \notag \end{align}

factors through the two bond pairs cut by the block boundary. Writing the trace as a sum over the bond index pair \((a,b)\in \{ 1,\ldots ,D\} ^2\) exhibits \(W=L'R'\) with \(L'\) having \(D^2\) columns, so \(\operatorname{rank}\rho _L\leq \operatorname{rank}W\leq D^2\).

Lemma 26.6.70 The reduced pure block state is a density matrix

For an MPS tensor \(A\) with \(V^{(N)}(A)\neq 0\), the reduced state \(\rho _L^{(N)}(A)\) of the first \(L\) spins is a density matrix: it is positive semidefinite and has unit trace.

Proof

Positive semidefiniteness is preserved by the partial trace of the positive semidefinite normalized pure state, and the partial trace preserves the trace, which the normalization fixes to one.

Proposition 26.6.71 Pure-state area-law upper bound

Let \(A\) be an MPS tensor of bond dimension \(D\geq 1\) with \(V^{(N)}(A)\neq 0\). For every block length \(L\le N\), \(S_L^{(N)}(A)\leq 2\log D\), uniformly in \(L\) and \(N\). This is the area law of [ CPGSV16 , Section 3, line 599 ] : the block entropy is bounded by a constant independent of the block size.

Proof

The reduced state \(\rho _L^{(N)}(A)\) is a density matrix (Lemma 26.6.70), so its rank is positive by Lemma 26.6.29. Its rank is at most \(D^2\) by Lemma 26.6.69. The rank bound on the entropy gives \(S_L^{(N)}(A)\leq \log (D^2)=2\log D\).

Lemma 26.6.72 Nonnegativity of the pure-state block entropy

For an MPS tensor \(A\) with \(V^{(N)}(A)\neq 0\) and every block length \(L\le N\), the pure-state block entropy is non-negative: \(0\le S_L^{(N)}(A)\).

Proof

The reduced state \(\rho _L^{(N)}(A)\) is a density matrix (Lemma 26.6.70), and the von Neumann entropy of a density matrix is non-negative.

Lemma 26.6.73 Full-block pure-state entropy vanishes
#

For an MPS tensor \(A\) with \(V^{(N)}(A)\neq 0\), the entropy of the whole chain vanishes: \(S_N^{(N)}(A)=0\).

Proof

After reindexing the full block, the normalized operator is the rank-one pure state

\begin{align} \frac{|V^{(N)}(A)\rangle \! \langle V^{(N)}(A)|}{\langle V^{(N)}(A) | V^{(N)}(A) \rangle }. \notag \end{align}

A pure state has von Neumann entropy zero.

Lemma 26.6.74 Empty-block pure-state entropy vanishes

For an MPS tensor \(A\) with \(V^{(N)}(A)\neq 0\), the pure-state block entropy of the empty block vanishes: \(S_0^{(N)}(A)=0\).

Proof

By the Schmidt symmetry \(S_0^{(N)}(A)=S_N^{(N)}(A)\), and the entropy of the full system vanishes for a pure state (Lemma 26.6.73).

Lemma 26.6.75 Saturation telescopes to a constant block entropy

If an MPS tensor \(A\) saturates the area law, then the block entropies coincide for all \(1\le L,L'\le \lfloor N/2\rfloor \): \(S_L^{(N)}(A)=S_{L'}^{(N)}(A)\).

Proof

The defining condition supplies \(S_m^{(N)}(A)=S_{m+1}^{(N)}(A)\) throughout the interval \(1\le m{\lt}\lfloor N/2\rfloor \). Apply Lemma 26.6.4.

Lemma 26.6.76 Pure-state mutual information is twice the block entropy

For an MPS tensor \(A\) with \(V^{(N)}(A)\neq 0\), the mutual information of the purification MPDO equals twice the pure-state block entropy: \(I_L=2S_L^{(N)}(A)\).

Proof

By definition, \(I_L=S_L+S_{N-L}-S_N\) for the generated state. The global entropy of the pure state vanishes (Lemma 26.6.73), and the Schmidt symmetry (Lemma 26.6.62) gives \(S_{N-L}=S_L\), so \(I_L=2S_L\).

Proposition 26.6.77 Pure-state mutual-information bound

Let \(A\) be an MPS tensor of bond dimension \(D\geq 1\) with \(V^{(N)}(A)\neq 0\). For the purification MPDO of \(A\), whose generated operator is the pure state \(|V^{(N)}(A)\rangle \! \langle V^{(N)}(A)|\), the mutual information between a block of \(L\) spins and the rest satisfies \(I_L\leq 4\log D\), uniformly in \(L\) and \(N\).

Proof

For a pure state, \(I_L=2S_L^{(N)}(A)\), since the global entropy \(S_N\) vanishes and a block and its complement share the same Schmidt spectrum. The block-entropy bound \(S_L^{(N)}(A)\leq 2\log D\) (Proposition 26.6.71) then gives \(I_L\leq 4\log D\).

26.7 Simple tensors

Definition 26.7.1 Physical-trace transfer of a doubled-index tensor
#

For a doubled-index tensor \(B\) with physical dimension \(d^{2}\), the physical-trace transfer is the bond matrix obtained by closing the ket leg against the bra leg of one tensor:

\begin{align} \mathcal T_{B} & =\sum _{i} B^{\, ii}. \label{eq:rfp_phys_trace} \end{align}

This is the transfer object of the zero-correlation-length condition of [ CPGSV16 , Definition 4.2, lines 735–739 ] , applied to one element of a basis of normal tensors.

Lemma 26.7.2 Identification with the tensor-level transfer

The physical-trace transfer of the doubled-index view of an MPO tensor is the physical-trace transfer of the tensor itself.

Proof

If \(M^{\mathrm{dbl}}\) is the doubled-index view of \(M\), then \((M^{\mathrm{dbl}})^{(i,j)}=M^{ij}\), and hence \(\mathcal T_{M^{\mathrm{dbl}}} =\sum _i(M^{\mathrm{dbl}})^{ii} =\sum _i M^{ii} =\mathcal T_M\).

Lemma 26.7.3 Blockwise form of the physical-trace transfer

For a sector decomposition with basis elements \(A_{j}\) and weights \(\mu _{j,q}\), the physical-trace transfer of the assembled tensor is the block direct sum of the weighted transfers of the copies:

\begin{align} \mathcal T & =\bigoplus _{j}\bigoplus _{q}\mu _{j,q} \mathcal T_{A_{j}}. \label{eq:rfp_blockwise_transfer} \end{align}
Proof

The diagonal physical sum distributes over the block direct sum:

\begin{align} \mathcal T & =\sum _i S^{ii} =\sum _i\bigoplus _{j,q}\mu _{j,q}A_j^{ii} \notag \\ & =\bigoplus _{j,q}\mu _{j,q}\sum _i A_j^{ii} =\bigoplus _{j,q}\mu _{j,q}\mathcal T_{A_j}. \notag \end{align}
Definition 26.7.4 Simple tensor

First block a positive number of physical sites and write the blocked doubled-index tensor in canonical form over a basis of normal tensors, as prescribed at line 815 of [ CPGSV16 ] . A tensor generating MPDOs is simple if one such canonical form has no nilpotent basis element [ CPGSV16 , line 822 ] . A basis element is nilpotent when tracing \(R\le D\) sites annihilates its density operators for all large chain lengths [ CPGSV16 , line 819 ] ; this is nilpotency of its physical-trace transfer matrix.

Definition 26.7.5 Simple tensor in blocked canonical form

A tensor generating MPDOs is in simple canonical form if it has a basis-of-normal-tensors decomposition whose basis elements all have non-nilpotent physical-trace transfer. This records the simple horizontal-canonical-form data of the already-blocked tensor \(K\) fixed in [ CPGSV16 , Appendix C.2, line 1628 ] .

Lemma 26.7.6 Simple canonical-form tensors are horizontal canonical

A simple tensor already in the chosen blocked canonical-form setting is in horizontal canonical form.

Proof

The canonical-form data in the simplicity hypothesis—the sector decomposition, its basis-of-normal-tensors property, and the block-diagonal gauge—give a horizontal canonical form. Positivity and non-nilpotency are not needed for this conclusion.

26.8 Gibbs states of nearest-neighbor commuting Hamiltonians

A density operator on a periodic chain is a Gibbs state of a nearest-neighbor commuting Hamiltonian if

\begin{align} \rho ^{(N)} & \propto \bigoplus _x n_x \exp \! \left(-\sum _{j=1}^N\tau _j(h^{(x)})\right), \notag \\ n_x& \in \mathbb {N}, \notag \end{align}

where the one-site spaces belonging to distinct labels \(x\) are orthogonal and \([h^{(x)},\tau _1(h^{(x)})]=0\). With the projector-limit convention of [ CPGSV16 , Definition 4.8, lines 829–850 ] , this is equivalently

\begin{align} \rho ^{(N)} & \propto \bigoplus _x n_x \prod _{j=1}^N\tau _j(B^{(x)}), \notag \\ B^{(x)}& \geq 0, \notag \end{align}

with commuting neighboring translates. The orthogonal sum and the multiplicities are part of the definition. Definition 4.8 decomposes the global Hilbert space into the uniform product sectors and requires the associated one-site spaces to be mutually orthogonal; it does not impose a resolution of a larger one-site identity by the sector projections.

The following auxiliary single-bond presentation does not make the sector labels or multiplicities explicit. Its bond acts on the full two-site space. It gives the one-sector case of Definition 26.8.1; the converse comparison is not used.

Definition 26.8.2 Single-bond commuting-form data for an MPDO
#

For a fixed chain length \(N \ge 2\), this consists of one positive semidefinite two-site operator \(B\ge 0\) whose translated copies commute pairwise on the periodic \(N\)-site chain: \([B_{i,i+1},B_{j,j+1}]=0\).

Definition 26.8.3 Single-bond commuting form

An MPO tensor \(M\) has the single-bond commuting-form property if for every \(N \ge 2\) there is a two-site operator \(B\) as in Definition 26.8.2 and a constant \(c{\gt}0\) such that

\begin{align} \rho ^{(N)}(M) & =c\prod _{i=0}^{N-1}B_{i,i+1}. \notag \end{align}

The bond in this chainwise condition may depend on \(N\). It is therefore weaker than the single translation-invariant bond family used in the proposition at [ CPGSV16 , Appendix C.2, lines 1597–1619 ] .

Definition 26.8.4 Single-bond product predicate

This condition asks, for every chain length \(N\geq 2\), for one positive bond on the full two-site space and one positive normalization such that

\begin{align} \rho ^{(N)}(M) & =c\prod _{i=0}^{N-1}B_{i,i+1}, \notag \\ c& {\gt}0, \notag \\ B& \ge 0, \notag \\[B_{i,i+1},B_{j,j+1}]& =0. \notag \end{align}

This auxiliary condition contains no explicit sector labels or multiplicities.

Theorem 26.8.5 Single-bond predicate iff single-bond commuting form

The single-bond product predicate is equivalent to the existence of single-bond commuting-form data on every finite chain. This is an equivalence between two presentations of the same condition.

Proof

Expanding the two definitions gives the same identity \(\rho ^{(N)}(M)=c\prod _{i=0}^{N-1}B_{i,i+1}\) with \(c{\gt}0\).

Definition 26.8.6 Single-bond predicate with doubled-index idempotence

This is the conjunction of the single-bond condition with the doubled-index transfer identity \(\mathcal{E}_M\circ \mathcal{E}_M=\mathcal{E}_M\). The source physical-trace condition is Definition 26.4.2.

Theorem 26.8.7 Single-bond predicate with idempotence iff single-bond form with it

The single-bond condition with doubled-index transfer idempotence is equivalent to the conjunction of the single-bond commuting-form property with that same idempotence condition.

Proof

Expand the single-bond conjunction and apply Theorem 26.8.5.

A single positive commuting bond is the one-sector instance of the explicit GSNNCH decomposition, with sector projection equal to the identity and multiplicity one.

Proof

Take one sector, its one-site projection to be the identity, its multiplicity to be one, and its bond to be the given bond.

Definition 26.8.9 Restriction to an orthogonal physical sector

Let \(P\) be an orthogonal one-site projection and let \(K\) be an MPO tensor fixed by compression with \(P\) on its two physical indices. A physical support restriction consists of a dimension \(e\) and an isometry \(V:\mathbb {C}^e\longrightarrow \mathbb {C}^d\) such that

\begin{align} V^*V& =\mathbb {1}, \notag \\ VV^*& =P, \notag \end{align}

for which the restricted tensor \(K_P=V^*KV\) is injective and its inclusion into the ambient physical space recovers \(K\) exactly.

Suppose that the source BNT projectors have been constructed after the common physical blocking, and let \(\mathcal K_s\) be the normal representative with its common copy weight absorbed. Then \(\mathcal K_s\) admits a physical support restriction to the range of \(P_s\). In particular, for some isometry \(V_s\),

\begin{align} V_sV_s^*& =P_s, \notag \\ \mathcal K_s & =V_s(V_s^*\mathcal K_sV_s)V_s^*, \notag \end{align}

and the restricted tensor \(V_s^*\mathcal K_sV_s\) is injective.

Proof

The projector identity \(P_s\mathcal K_sP_s=\mathcal K_s\) gives an isometric inclusion of its range. The simultaneous one-site spanning condition makes each normal representative injective, and multiplication by its nonzero common weight preserves injectivity. Write \(K_{P_s}=V_s^*\mathcal K_sV_s\). Each ambient matrix slice satisfies

\begin{align} (\mathcal K_s)_{ij} & =\sum _{p,q}(V_s)_{ip} \overline{(V_s)_{jq}}\, (K_{P_s})_{pq}. \notag \end{align}

Hence

\begin{align} \operatorname{span}_{\mathbb {C}}\{ (\mathcal K_s)_{ij}\} _{i,j} & \subseteq \operatorname{span}_{\mathbb {C}}\{ (K_{P_s})_{pq}\} _{p,q}. \notag \end{align}

The left-hand side is the full virtual matrix algebra, so \(K_{P_s}\) is injective. The two isometry identities give the exact reconstruction.

Theorem 26.8.11 SAL passes to the physical support restriction

If \(K\) satisfies saturation of the area law and \(K=V K_P V^*\) is a physical support restriction, then the injective restricted tensor \(K_P\) also satisfies saturation of the area law.

Proof

On a chain of every positive length, the sitewise inclusion \(V^{\otimes N}\) is an isometry and

\begin{align} \rho ^{(N)}(K) & =V^{\otimes N}\rho ^{(N)}(K_P)(V^{\otimes N})^*. \notag \end{align}

The trace is therefore unchanged. After a contiguous marginal is taken, the isometry on the traced-out sites disappears, while the isometry on the retained sites remains. Thus every block marginal of \(K\) is an isometric conjugate of the corresponding marginal of \(K_P\). Their nonzero spectra, and hence their entropies and mutual informations, coincide. The consecutive equalities defining SAL for \(K\) consequently give those for \(K_P\).

Theorem 26.8.12 The restricted commuting product has a supported ambient realization

Let \(K=V K_P V^*\) be a physical support restriction of an MPO tensor satisfying SAL. Proposition C.8 applied to the injective tensor \(K_P\) gives a positive two-site bond \(B_P\) whose cyclic translates commute pairwise on every periodic chain of length \(N\geq 2\). Its lift \(B=V^{\otimes 2}B_P(V^{\otimes 2})^*\) is positive, its cyclic translates commute pairwise on every such ambient chain, and \((P\otimes P)B(P\otimes P)=B\). Moreover, for every \(N\geq 2\) one has the exact identity

\begin{align} \rho ^{(N)}(K) & =\prod _{i=0}^{N-1}B_{i,i+1}. \notag \end{align}
Proof

The preceding theorem gives SAL for the injective restricted tensor, so Proposition C.8 supplies its positive bond. Since \(V^*V=\mathbb {1}\), positivity is preserved under conjugation by \(V^{\otimes 2}\). Also, \(V^{\otimes 2}(V^{\otimes 2})^*=P\otimes P\); multiplying the lifted bond by this projection on either side therefore leaves it unchanged.

It remains to prove commutativity after the lift. On a three-site chain, isometric conjugation carries the product of two adjacent restricted bonds to the product of their lifted bonds. The restricted product is Hermitian because its positive factors commute. Its conjugate is therefore Hermitian; since the lifted factors are Hermitian, their product equals the product in the reverse order. The two-site periodic chain is handled by the same argument with the two oppositely oriented bonds. Locality and cyclic translation then give pairwise commutativity for every \(N\geq 2\).

Finally, isometric conjugation preserves every nonempty product of restricted bonds. The image of each restricted bond is the corresponding lifted bond multiplied by the projection onto the range of \(V^{\otimes N}\). The support projections contributed by the first \(N-1\) bonds cover all sites and leave the full commuting product fixed. Hence the range projection disappears, and the restricted finite-chain product identity becomes the asserted ambient identity, still with normalization scalar one.

Definition 26.8.13 Orthogonally supported commuting sector products

Let \(\{ K_x\} _{x=0}^{g-1}\) be MPO tensors on a common one-site space. An orthogonally supported family of commuting sector products consists of pairwise orthogonal one-site projections \(P_x\) and positive two-site operators \(B^{(x)}\) such that

\begin{align} (P_x\otimes P_x)B^{(x)}(P_x\otimes P_x) & =B^{(x)}, \notag \\[\tau _i(B^{(x)}),\tau _j(B^{(x)})]& =0, \notag \end{align}

and, for every \(N\geq 2\),

\begin{align} \rho ^{(N)}(K_x) & =\prod _{i=0}^{N-1}\tau _i(B^{(x)}). \notag \end{align}

Together with natural multiplicities \(n_x\), these objects determine the corresponding finite-chain sector decomposition in Definition 26.8.1.

Theorem 26.8.14 SAL supplies orthogonally supported BNT sector products

Suppose that the BNT physical projectors \(P_x\) have been selected and that every common-weight-absorbed representative \(\mathcal K_x\) satisfies SAL. Then there are positive two-site bonds \(B^{(x)}\) such that the projections \(P_x\) are pairwise orthogonal,

\begin{align} (P_x\otimes P_x)B^{(x)}(P_x\otimes P_x) & =B^{(x)}, \notag \end{align}

all cyclic translates of each \(B^{(x)}\) commute pairwise, and, for every \(N\geq 2\),

\begin{align} \rho ^{(N)}(\mathcal K_x) & =\prod _{i=0}^{N-1}\tau _i(B^{(x)}). \notag \end{align}

Thus the absorbed BNT representatives have an orthogonally supported family of commuting sector products with normalization scalar one.

Proof

Restrict \(\mathcal K_x\) isometrically to the range of \(P_x\). The restricted tensor is injective and satisfies SAL, so Proposition C.8 gives its positive commuting bond product. Apply Theorem 26.8.12 in every sector. The lifted bond is supported on \(P_x\otimes P_x\) and realizes \(\mathcal K_x\) exactly. The BNT projector construction gives \(P_xP_y=0\) for \(x\ne y\), which completes the sector family.

Suppose that \(\{ K_x\} _{x=0}^{g-1}\) has an orthogonally supported family of commuting sector products and that, for every \(N\geq 2\),

\begin{align} \rho ^{(N)}(M) & =\sum _{x=0}^{g-1}n_x\rho ^{(N)}(K_x), \notag \\ n_x& \in \mathbb {N}. \notag \end{align}

Then \(M\) has the explicit GSNNCH sector form with outer sectors \(x\) and natural multiplicities \(n_x\).

Proof

For each \(N\geq 2\), the represented unnormalized sector sum is

\begin{align} \sum _{x=0}^{g-1}n_x \prod _{i=0}^{N-1}\tau _i(B^{(x)}) & =\sum _{x=0}^{g-1}n_x\rho ^{(N)}(K_x) =\rho ^{(N)}(M). \notag \end{align}

Thus the positive proportionality constant in Definition 26.8.1 is one.

Theorem 26.8.16 Local orthogonal sums preserve SAL

Let \(\{ K_x\} _{x=0}^{g-1}\) be a nonempty finite family of MPO tensors, let \(n_x\) be positive natural numbers, and let \(P_x\) be pairwise orthogonal one-site projections. Suppose that, for every \(N{\gt}0\),

\begin{align} \rho ^{(N)}(M) & =\sum _{x=0}^{g-1}n_x\rho ^{(N)}(K_x). \notag \end{align}

For \(N\geq 2\) and \(1\leq L\leq N\), write \(\widehat\rho _{x,N,L}\) for the normalized marginal of \(\rho ^{(N)}(K_x)\) on the first \(L\) sites. Assume that the sector label is visible on the first retained site:

\begin{align} (P_x\otimes \mathbb {1}^{\otimes (L-1)}) \widehat\rho _{x,N,L} & =\widehat\rho _{x,N,L}. \notag \end{align}

If every \(K_x\) satisfies SAL, then \(M\) satisfies SAL.

This is the conditional last inference in the proposition at [ CPGSV16 , Appendix C.2, lines 1801–1808 ] . It assumes sectorwise SAL. The printed proposition states the conclusion from the GSNNCH form alone, but its proof invokes the single-sector proposition at lines 1597–1619, whose hypotheses include ZCL. The theorem here does not supply that omitted sectorwise implication.

Proof

For fixed \(N\), put

\begin{align} p_x & =\frac{n_x\operatorname{tr}(\rho ^{(N)}(K_x))}{\operatorname{tr}(\rho ^{(N)}(M))}. \notag \end{align}

Positivity of the chain operators, positivity of \(n_x\), and nonemptiness of the family give \(p_x{\gt}0\) and a nonzero normalization for \(M\). Every nonempty normalized marginal decomposes as

\begin{align} \widehat\rho _{N,L}(M) & =\sum _x p_x\widehat\rho _{x,N,L}. \notag \end{align}

Put \(Q_x=P_x\otimes \mathbb {1}^{\otimes (L-1)}\). The support identity gives \(Q_x\widehat\rho _{x,N,L}=\widehat\rho _{x,N,L}\), while \(P_xP_y=0\) for \(x\ne y\) gives \(Q_xQ_y=0\). Thus the summands have pairwise annihilating supports. Hence

\begin{align} S_L(M) & =\sum _x(-p_x\log p_x+p_xS_L(K_x)). \notag \end{align}

Substitution in \(I_L=S_L+S_{N-L}-S_N\) gives

\begin{align} I_L(M) & =-\sum _xp_x\log p_x+\sum _xp_xI_L(K_x). \notag \end{align}

The first sum is independent of \(L\), while sectorwise SAL gives \(I_L(K_x)=I_{L+1}(K_x)\) for every \(x\). Therefore \(I_L(M)=I_{L+1}(M)\) throughout the SAL range.

Lemma 26.8.17 Commuting sector products have local marginal support

Suppose that \(K_x\) is the periodic product of translates of a positive two-site operator \(B_x\), and that \(B_x\) is supported on \(P_x\otimes P_x\). If \(N\geq 2\) and \(1\leq L\leq N\), then the normalized marginal of \(K_x\) on the first \(L\) sites satisfies

\begin{align} (P_x\otimes \mathbb {1}^{\otimes (L-1)}) \widehat\rho _{x,N,L} & =\widehat\rho _{x,N,L}. \notag \end{align}
Proof

The first translated bond is fixed by multiplication by \(P_x\) on its first tensor factor. Hence the full periodic product is fixed by the corresponding one-site action. Taking the partial trace over the final \(N-L\) sites preserves this identity.

Corollary 26.8.18 Orthogonal commuting sector sums preserve SAL

Let \(K_x\) be a nonempty finite family, let an orthogonally supported commuting sector family realize the tensors \(K_x\), and let \(n_x\) be positive natural numbers. Suppose that, for every \(N{\gt}0\),

\begin{align} \rho ^{(N)}(M) & =\sum _x n_x\rho ^{(N)}(K_x). \notag \end{align}

If every \(K_x\) satisfies SAL, then \(M\) satisfies SAL.

Proof

The preceding lemma supplies the marginal-support hypothesis of Theorem 26.8.16; the remaining hypotheses are precisely the assumed outer-sector equality, positivity of the multiplicities, and sectorwise SAL.

Corollary 26.8.19 Orthogonal BNT sector sums preserve SAL

Let \(M\) have a nonempty basis-of-normal-tensors decomposition with positive copy numbers \(n_x\) and copy-independent weights \(\mu _x\). Put \(K_x=\mu _xA_x\), and suppose that the decomposition generates the same positive-length matrix product vectors as \(M\). If an independently supplied orthogonally supported commuting sector family realizes the tensors \(K_x\), and every \(K_x\) satisfies SAL, then \(M\) satisfies SAL.

Proof

The positive-length canonical-form identity gives \(\rho ^{(N)}(M)=\sum _x n_x\rho ^{(N)}(K_x)\). Apply Corollary 26.8.18.

Corollary 26.8.20 Orthogonal BNT sector products give the GSNNCH form

Let \(M\) be an MPO tensor and let its BNT canonical form have normal representatives \(A_x\), copy numbers \(n_x\), and copy-independent weights \(\mu _x\). Put \(\mathcal K_x=\mu _xA_x\), and assume that this canonical form generates the same matrix product vectors as \(M\) at every positive length. If the representatives \(\mathcal K_x\) have orthogonally supported commuting sector products, then

\begin{align} \rho ^{(N)}(M) & =\sum _x n_x\rho ^{(N)}(\mathcal K_x). \notag \end{align}

This gives the explicit GSNNCH form with the BNT copy numbers \(n_x\) as its natural multiplicities.

Proof

Apply Theorem 26.8.15 to the positive-length BNT decomposition. Its coefficients are exactly the copy numbers \(n_x\) after the common weights have been absorbed.

Corollary 26.8.21 Sectorwise SAL gives the BNT GSNNCH form

Let \(M\) be an MPO tensor and let its BNT canonical form have normal representatives \(A_x\), copy numbers \(n_x\), and copy-independent weights \(\mu _x\). Put \(\mathcal K_x=\mu _xA_x\), and assume that this canonical form generates the same matrix product vectors as \(M\) at every positive length. Equivalently, for every \(N{\gt}0\),

\begin{align} \rho ^{(N)}(M) & =\sum _x n_x\rho ^{(N)}(\mathcal K_x). \notag \end{align}

Under the BNT projector-selection hypotheses, if every \(\mathcal K_x\) satisfies SAL, then \(M\) has the source GSNNCH form. Its outer sectors are the BNT sectors and its natural multiplicities are the copy numbers \(n_x\).

Proof

Theorem 26.8.14 supplies the orthogonally supported commuting sector products. Apply Corollary 26.8.20.

Lemma 26.8.22 Cyclic-shift transport of an embedded local operator

Let \(B\) act on \(L\) consecutive spins of the periodic \(N\)-site chain, embedded at base site \(i\), and let \(r\) denote the cyclic shift of sites. Reindexing both chain configurations by \(r\) carries the embedded operator to its translate at the shifted base site:

\begin{align} \tau _i(B)[\sigma \circ r, \eta \circ r] & =\tau _{r(i)}(B)[\sigma ,\eta ]. \notag \end{align}
Proof

Entrywise from the definitions: the shift carries the window at \(i\) to the window at \(r(i)\), preserves agreement of two configurations outside the window, and preserves the extracted window values.

Lemma 26.8.23 Translates of a sector bond commute pairwise

For every sector \(x\) of an explicit GSNNCH decomposition and every finite chain length \(N\geq 2\), all cyclic translates of the sector bond commute: \([\tau _i(B^{(x)}),\tau _j(B^{(x)})]=0\).

Proof

Translates with disjoint windows commute because they act on disjoint sites, and two length-two windows overlap only when their starting sites coincide or are cyclic neighbors. For the neighboring pairs, applying the transport identity of Lemma 26.8.22 \(p\) times to the neighboring commutation \([\tau _0(B^{(x)}),\tau _1(B^{(x)})]=0\) of Definition 26.8.1 gives \([\tau _p(B^{(x)}),\tau _{p+1}(B^{(x)})]=0\) for every \(p\), which covers all overlapping pairs.

Lemma 26.8.24 Positivity of the sector-bond translates

An operator embedded into the periodic chain from a positive semidefinite local factor is positive semidefinite; in particular every translate \(\tau _i(B^{(x)})\) of a sector bond is positive semidefinite.

Proof

In the coordinates given by the window-plus-complement splitting of the chain, the embedded operator decomposes as

\begin{align} \tau _i(B) & \cong B\otimes \mathbb {1}_{\mathrm{comp}}, \notag \end{align}

where the identity acts on the cyclic complement of the window. A tensor product of positive semidefinite operators is positive semidefinite, and \(B^{(x)}\geq 0\) by Definition 26.8.1.

Each sector product \(\prod _{j=1}^N\tau _j(B^{(x)})\) of an explicit GSNNCH decomposition is positive semidefinite; hence so are the represented operator

\begin{align} \bigoplus _x n_x \prod _{j=1}^N\tau _j(B^{(x)}) \notag \end{align}

and every chain operator equal to a positive multiple of it.

Proof

A product of pairwise commuting positive semidefinite matrices is positive semidefinite: for two commuting factors \(A\) and \(B\), the square root of \(A\) commutes with \(B\), so \(AB=\sqrt A\, B\, \sqrt A\geq 0\), as congruence by \(\sqrt A\) preserves positive semidefiniteness; iterate along the product. Each sector product is such a product by Lemmas 26.8.24 and 26.8.23, and the sum with natural coefficients preserves positivity.

Each sector product of an explicit GSNNCH decomposition is invariant under the cyclic shift of the periodic chain, where spin \(N+1\) is identified with the first; hence so are the represented operator and every chain operator equal to a positive multiple of it [ CPGSV16 , lines 838–842 ] .

Proof

By the transport identity of Lemma 26.8.22, the cyclic shift carries each translate \(\tau _j(B^{(x)})\) to \(\tau _{j+1}(B^{(x)})\), so it permutes the factors of each sector product cyclically. All factors commute by Lemma 26.8.23, so the product is unchanged, and so is the sum over sectors.

Lemma 26.8.27 The sector form passes to the trace normalization

If a finite-chain operator of an MPO tensor has the explicit sector form of Definition 26.8.1 and nonzero trace, then its trace normalization has the sector form as well.

Proof

By Lemma 26.8.25 the operator is positive semidefinite, so its nonzero trace is positive and the normalization multiplies the sector sum by a positive constant.

Theorem 26.8.28 Sector form with nonvanishing traces gives GSNNCH

If every finite-chain operator of an MPO tensor has the explicit sector form of Definition 26.8.1 and a nonzero trace, then the normalized finite-chain states are density operators with that sector form, so the tensor generates Gibbs states of a nearest-neighbor commuting Hamiltonian.

Proof

Positivity of each chain operator follows from Lemma 26.8.25, and the normalized state has unit trace and keeps the sector form by Lemma 26.8.27.

26.9 Two-site and positive-length physical blocking

The two-site block is the virtual contraction of two copies of \(K\):

\tnpic[physical=updown, tensor style=box]{%
        \tn[mpo, up={$(i_1,i_2)$}, down={$(j_1,j_2)$}]{M}}   \(=\)  \tnpic[physical=updown, tensor style=box]{%
        \tn[mpo, up=$i_1$, down=$j_1$]{K} &
        \tn[mpo, up=$i_2$, down=$j_2$]{K}}

The two ket indices and the two bra indices are grouped into the blocked physical indices, as in [ CPGSV16 , Theorem 4.9, lines 851–856 ] .

Definition 26.9.1 Positive-length physical blocking of an MPO tensor

For a positive integer \(L\), group \(L\) adjacent physical sites and denote the resulting local tensor by \(M^{[L]}\). It has a length-\(L\) ket word \(I=(i_1,\ldots ,i_L)\) and a length-\(L\) bra word \(J=(j_1,\ldots ,j_L)\) as its physical indices, and

\begin{align} (M^{[L]})^{I,J} & =M^{i_1j_1}\cdots M^{i_Lj_L}. \notag \end{align}

Thus the ket and bra words are grouped separately. This is the MPO version of the physical blocking used for the basis of normal tensors in [ CPGSV16 , lines 317–345 ] . It is a local tensor, not the closed-chain operator \(O_L(M)\) of [ CPGSV16 , lines 962–967 ] .

Let \(L{\gt}0\). Pairing the ket and bra letters site by site gives the canonical identification \(\{ 0,\ldots ,d^L-1\} ^2\simeq \{ 0,\ldots ,d^2-1\} ^L\). Under this identification, the doubled-index MPS tensor of \(M^{[L]}\) is the physical reindexing of the \(L\)-blocked doubled-index MPS tensor of \(M\). In particular, one is injective if and only if the other is.

Proof

Decode the blocked ket and bra words, pair their letters at each site, and compare the two ordered matrix products. Physical reindexing by a bijection preserves the span of the tensor matrices.

Theorem 26.9.3 Positive blocking commutes with the MPO product

For \(L{\gt}0\) and two MPO tensors \(M,N\) with the same physical dimension, let juxtaposition denote the MPO tensor product obtained by contracting the intermediate physical index. Then \((MN)^{[L]}=M^{[L]}N^{[L]}\).

Proof

Expand the product tensor and sum over its length-\(L\) intermediate physical word. Reindexing this word by one blocked physical index gives the product of the two blocked tensors.

Theorem 26.9.4 Closed MPO chains under physical blocking

Let \(L\in \mathbb {N}\), and let

\begin{align} \Phi _{N,L}\colon \{ 0,\ldots ,d^L-1\} ^N & \longrightarrow \{ 0,\ldots ,d-1\} ^{NL} \notag \end{align}

concatenate the \(N\) blocked words. For blocked configurations \(\sigma \) and \(\tau \),

\begin{align} \rho ^{(N)}(M^{[L]})_{\sigma ,\tau } & =\rho ^{(NL)}(M)_{\Phi _{N,L}(\sigma ),\Phi _{N,L}(\tau )}. \notag \end{align}

The algebraic identity holds for every \(L\in \mathbb {N}\). For \(L\geq 1\), positivity of the original nonempty chain of length \(NL\) shows that blocking \(L\) adjacent physical sites of an MPDO again gives an MPDO. This is the closed-chain identification implicit when the one-site tensor and its two-site blocking are placed in vertical canonical form in [ CPGSV16 , Appendix C.4, lines 1952–2017 ] .

Proof

Write \(\sigma _k=(\sigma _{k,0},\ldots ,\sigma _{k,L-1})\) and \(\tau _k=(\tau _{k,0},\ldots ,\tau _{k,L-1})\). For each \(k\), \((M^{[L]})^{\sigma _k,\tau _k} =\prod _{j=0}^{L-1}M^{\sigma _{k,j},\tau _{k,j}}\). Taking both products in increasing index order gives

\begin{align} \prod _{k=0}^{N-1}(M^{[L]})^{\sigma _k,\tau _k} & =\prod _{k=0}^{N-1}\prod _{j=0}^{L-1} M^{\sigma _{k,j},\tau _{k,j}} =\prod _{r=0}^{NL-1} M^{(\Phi _{N,L}(\sigma ))_r,(\Phi _{N,L}(\tau ))_r}. \notag \end{align}

Taking the virtual trace gives the equality in the theorem. The map \(\Phi _{N,L}\) is a bijection, and simultaneous reindexing of the rows and columns preserves positive semidefiniteness.

Definition 26.9.5 Two-site blocking of an MPO tensor
#

For an MPO tensor \(K\), its two-site blocking \(K^{[2]}\) has physical indices \((i_0,i_1)\) and \((j_0,j_1)\) and matrices

\begin{align} (K^{[2]})^{(i_0,i_1),(j_0,j_1)} & =K^{i_0j_0}K^{i_1j_1}. \notag \end{align}

This is the blocking used in [ CPGSV16 , Theorem 4.9, lines 851–856 ] .

Let \(\varphi :\{ 0,\ldots ,d^2-1\} \to \{ 0,\ldots ,d-1\} ^2\) be the canonical bijection. Then \((K^{[2]})^{i,j} =(K^{[L]})^{\varphi (i),\varphi (j)}\bigm |_{L=2}\). Consequently, for every nonempty chain length \(N\), the closed MPO of \(K^{[2]}\) is obtained from the closed MPO of the general length-two block by applying \(\varphi \) independently at every ket and bra site. In particular, if \(K\) generates matrix product density operators, then so does \(K^{[2]}\).

Proof

Decode a blocked index as an ordered pair. The two local tensors are then the same product \(K^{i_0j_0}K^{i_1j_1}\). Applying this equality at every site gives the closed-chain reindexing, and simultaneous row and column reindexing preserves positive semidefiniteness.

Lemma 26.9.7 Two-site blocking preserves normalized BNT-refined horizontal form

If an MPO tensor \(K\) is in normalized BNT-refined horizontal form, then its two-site blocking \(K^{[2]}\) is again in that form.

Proof

Block every normal representative in the horizontal sector decomposition by two sites and square each copy weight. Positive blocking preserves irreducibility, left-canonical normalization, eventual linear independence of the representative states, and inequivalence of distinct representatives. Normalized self-overlap is preserved by \(O_{A_j^{[2]}A_j^{[2]}}(N)=O_{A_jA_j}(2N)\longrightarrow 1\). Hence the blocked sector decomposition is again a BNT canonical form. If \(\varphi \) is the canonical bijection between a pair of ket–bra indices and a length-two word in the doubled alphabet, then \((K^{[2]})^{\mathrm{MPS}}=\varphi ^*\! \left(\operatorname {block}_2(K^{\mathrm{MPS}})\right)\). Thus \(\varphi \) only relabels the physical basis. Finally, if \(X\) is the original block-diagonal virtual gauge and \(S\) its sector tensor, word evaluation gives \(((K^{[2]})^{\mathrm{MPS}})_i=X(\varphi ^*(S^{[2]}))_iX^{-1}\). Therefore this blocked decomposition and the same copy gauges witness normalized BNT-refined horizontal form for \(K^{[2]}\).

Theorem 26.9.8 One-site and two-site vertical canonical forms

Let \(K\) be an MPO tensor in normalized BNT-refined horizontal form that generates matrix product density operators. Then both \(K\) and \(K^{[2]}\) satisfy the vertical canonical-form conditions of Definition 23.4.6. This is the initial canonical-form step in [ CPGSV16 , Appendix C.4, lines 1951–1956 ] .

Proof

The preceding blocking results show that \(K^{[2]}\) is in normalized BNT-refined horizontal form and generates matrix product density operators. Apply Theorem 23.4.100 first to \(K\) and then to \(K^{[2]}\).

Let the vertical sectors be labelled by \(\alpha \), with simple matrix algebra \(M_{d_\alpha }\) and positive diagonal multiplicity matrix

\begin{align} \mu _\alpha & =\operatorname{diag}(\mu _{\alpha ,0},\ldots ,\mu _{\alpha ,r_\alpha -1}). \notag \end{align}

Write \(m_\alpha =\operatorname{tr}(\mu _\alpha )\). The normalized embedding and the left partial trace are

\begin{align} R_\mu \! \left(\bigoplus _\alpha X_\alpha \right) & =\bigoplus _\alpha \frac{\mu _\alpha }{m_\alpha }\otimes X_\alpha , \notag \\ \widetilde R_\mu \! \left(\bigoplus _\alpha Y_\alpha \right) & =\bigoplus _\alpha \operatorname{tr}_{\mathrm{mult}}(Y_\alpha ). \notag \end{align}

On a weighted sector, \(\widetilde R_\mu (\lambda _\alpha \mu _\alpha \otimes X_\alpha ) =\lambda _\alpha m_\alpha X_\alpha \). Thus the partial trace is the canonical extension to the full block matrix space of the inverse map displayed in [ CPGSV16 , Appendix C.4, lines 1957–1971 ] .

Let \((d_\alpha )_\alpha \) and \((r_\alpha )_\alpha \) be finite families of dimensions with \(r_\alpha {\gt}0\), and suppose that every diagonal entry of \(\mu _\alpha \) is positive. Then the normalized embedding

\begin{align} R_\mu \colon \bigoplus _\alpha M_{d_\alpha }(\mathbb {C}) & \longrightarrow \bigoplus _\alpha M_{r_\alpha d_\alpha }(\mathbb {C}), \notag \\ R_\mu ((X_\alpha )_\alpha ) & =\left(\frac{\mu _\alpha }{m_\alpha }\otimes X_\alpha \right)_\alpha \notag \end{align}

is a direct-sum Kraus map. Without any condition on the multiplicities, the map

\begin{align} \widetilde R\colon \bigoplus _\alpha M_{r_\alpha d_\alpha }(\mathbb {C}) & \longrightarrow \bigoplus _\alpha M_{d_\alpha }(\mathbb {C}), \notag \\ \widetilde R((Y_\alpha )_\alpha ) & =(\operatorname{tr}_{\mathrm{mult}}(Y_\alpha ))_\alpha \notag \end{align}

is a direct-sum Kraus map. Its restriction to the weighted sectors is the retraction in [ CPGSV16 , Appendix C.4, lines 1961–1970 ] .

Proof

Exchange the two coordinates within each sector by \(w(\alpha ,q,i)=(\alpha ,i,q)\). Let \(R_w\) be the corresponding matrix reindexing. For the normalized embedding, set \(\rho _\alpha =m_\alpha ^{-1}\mu _\alpha \). The hypotheses give \(\rho _\alpha \succeq 0\) and \(\operatorname{tr}(\rho _\alpha )=1\). Let \(\mathcal P\) be the orthogonally controlled preparation of these density matrices. Thus

\begin{align} [\mathcal P(Z)]_{\langle \alpha ,(i,q)\rangle , \langle \beta ,(j,s)\rangle } & = \begin{cases} Z_{\langle \alpha ,i\rangle ,\langle \alpha ,j\rangle } \rho _\alpha (q,s), & \alpha =\beta ,\\ 0, & \alpha \ne \beta . \end{cases} \notag \end{align}

The preparation Kraus operators resolve the identity in each sector, so \(\mathcal P\) is trace-preserving and completely positive. Reindexing by \(w^{-1}\) changes \(X_\alpha \otimes \rho _\alpha \) into \(\rho _\alpha \otimes X_\alpha \). Consequently, the full-matrix extension satisfies

\begin{align} [\widehat R_\mu (Z)]_{\langle \alpha ,(q,i)\rangle , \langle \beta ,(s,j)\rangle } & = \begin{cases} \rho _\alpha (q,s) Z_{\langle \alpha ,i\rangle ,\langle \alpha ,j\rangle }, & \alpha =\beta ,\\ 0, & \alpha \ne \beta , \end{cases} \notag \\ \widehat R_\mu & =R_{w^{-1}}\circ \mathcal P. \notag \end{align}

This proves complete positivity of the normalized embedding.

Now let \(\mathcal C_{\operatorname{tr}}\) be the controlled partial trace over the \(\mathbb {C}^{r_\alpha }\) factors. For a matrix \(Y\) on \(\bigoplus _\alpha (\mathbb {C}^{r_\alpha }\otimes \mathbb {C}^{d_\alpha })\), the full-matrix extension satisfies

\begin{align} [\widehat{\widetilde R}(Y)]_{\langle \alpha ,i\rangle , \langle \beta ,j\rangle } & = \begin{cases} \sum _{q=0}^{r_\alpha -1} Y_{\langle \alpha ,(q,i)\rangle ,\langle \alpha ,(q,j)\rangle }, & \alpha =\beta ,\\ 0, & \alpha \ne \beta . \end{cases} \notag \end{align}

The diagonal case is the ordinary right partial trace after applying \(R_w\), and the off-diagonal case vanishes under the orthogonal sector control. Hence \(\widehat{\widetilde R}=\mathcal C_{\operatorname{tr}}\circ R_w\). Equivalence reindexing and the controlled dependent partial trace are trace-preserving completely positive maps, so their composition has a Kraus representation.

Lemma 26.9.11 Retraction of the normalized vertical-sector embedding

Suppose that every multiplicity space is nonzero and every diagonal entry of \(\mu _\alpha \) is positive. Then \(m_\alpha \ne 0\) for every \(\alpha \), and \(\widetilde R_\mu \circ R_\mu =\operatorname{id}\).

Proof

Positivity of the diagonal entries and nonemptiness of the multiplicity space give \(m_\alpha =\sum _q\mu _{\alpha ,q}{\gt}0\). The Kronecker-product identity for the left partial trace then gives

\begin{align} \operatorname{tr}_{\mathrm{mult}} \left(m_\alpha ^{-1}\mu _\alpha \otimes X_\alpha \right) & =m_\alpha ^{-1}\operatorname{tr}(\mu _\alpha )X_\alpha =X_\alpha . \notag \end{align}

For vertical BNT tensors \(M_\alpha \) with simple matrix algebras \(M_{d_\alpha }\) and a family of complex scalars \((c_\alpha )_\alpha \), define

\begin{align} V_c(X) & =\bigoplus _\alpha c_\alpha M_\alpha (X), \notag \\ M_\alpha (X) & =\sum _{a,b}X_{ba}M_{\alpha ,ab}. \notag \end{align}

For each \(L\geq 0\), let

\begin{align} C_L(V_c) & =\operatorname{span}_{\mathbb {C}}\left\{ V_c(X_1)\cdots V_c(X_L): X_1,\ldots ,X_L\in M_D\right\} \subseteq \prod _\alpha M_{d_\alpha }. \notag \end{align}

Write \(V_m\) for the specialization obtained by taking \(c_\alpha =m_\alpha =\operatorname{tr}(\mu _\alpha )\).

Lemma 26.9.13 Contraction against a matrix unit

Let \(M=(M_{ab})_{a,b=0}^{D-1}\) be a matrix-product tensor whose physical index is identified with the ordered pair \((a,b)\). Then \(M(E_{ba})=M_{ab}\).

Lemma 26.9.14 Contraction in the encoded product coordinate

If \(r\in \{ 0,\ldots ,D^2-1\} \) encodes the ordered pair \((\lfloor r/D\rfloor ,r\bmod D)\), then \(M\! \left(E_{(r\bmod D),\lfloor r/D\rfloor }\right)=M_r\).

Definition 26.9.15 Sectorwise scaling equivalence
#

For scalars \(c_\alpha \ne 0\), the map

\begin{align} \varphi _c\colon \prod _\alpha M_{d_\alpha } & \longrightarrow \prod _\alpha M_{d_\alpha }, \notag \\ (X_\alpha )_\alpha & \longmapsto (c_\alpha X_\alpha )_\alpha \notag \end{align}

is a linear equivalence.

Lemma 26.9.16 Weighted contraction of matrix-unit words

For a word \(w=((a_1,b_1),\ldots ,(a_L,b_L))\),

\begin{align} V_c(E_{b_1a_1})\cdots V_c(E_{b_La_L}) & =\bigoplus _\alpha c_\alpha ^L M_\alpha ^w. \notag \end{align}
Lemma 26.9.17 Transfer of simultaneous word spanning

Fix \(L\geq 0\) and suppose that every \(c_\alpha \) is nonzero. If the simultaneous word tuples \((M_\alpha ^w)_\alpha \) of length \(L\) span \(\prod _\alpha M_{d_\alpha }\), then \(C_L(V_c)=\prod _\alpha M_{d_\alpha }\).

Theorem 26.9.18 Nonzero-weight vertical bond contractions generate the sector algebra

Suppose that \((M_\alpha )_\alpha \) is a basis of normal tensors and that \((c_\alpha )_\alpha \) is any family of nonzero complex scalars. Then there is a positive integer \(L\) such that \(C_L(V_c)=\prod _\alpha M_{d_\alpha }\).

Proof

Choose \(L{\gt}0\) for which the simultaneous word tuples \((M_\alpha ^w)_\alpha \) span \(\prod _\alpha M_{d_\alpha }\). Since every \(c_\alpha \) is nonzero, so is \(c_\alpha ^L\). Apply Lemma 26.9.17.

Theorem 26.9.19 Vertical bond contractions generate the sector algebra

Suppose that \((M_\alpha )_\alpha \) is a basis of normal tensors, every multiplicity space is nonzero, and every diagonal entry of \(\mu _\alpha \) is positive. Then there is a positive integer \(L\) such that \(C_L(V_m)=\prod _\alpha M_{d_\alpha }=:\mathcal A_1\). This is the spanning assertion used in [ CPGSV16 , Appendix C.4, lines 1980–1990 ] .

Proof

Since every multiplicity space is nonzero and every diagonal entry is positive, \(m_\alpha =\sum _{q=0}^{\operatorname{mult}(\alpha )-1}\mu _{\alpha ,q}{\gt}0\). Apply the preceding theorem to the nonzero family \(c_\alpha =m_\alpha =\operatorname{tr}(\mu _\alpha )\).

Theorem 26.9.20 Fixed spanning contraction products determine an endomorphism

Let \(F\) be a linear endomorphism of \(\prod _\alpha M_{d_\alpha }\). Suppose that \(C_L(V_c)\) is the whole sector algebra and, for every choice of bond matrices \(X_1,\ldots ,X_L\),

\begin{align} F(V_c(X_1)\cdots V_c(X_L)) & =V_c(X_1)\cdots V_c(X_L). \notag \end{align}

Then \(F\) is the identity.

Proof

Since the displayed products span the domain, every \(Y\in \prod _\alpha M_{d_\alpha }\) has the form \(Y=\sum _i\lambda _iV_c(X_1^{(i)})\cdots V_c(X_L^{(i)})\). Hence

\begin{align} F(Y) & =\sum _i\lambda _i F\! \left(V_c(X_1^{(i)})\cdots V_c(X_L^{(i)})\right) =\sum _i\lambda _i V_c(X_1^{(i)})\cdots V_c(X_L^{(i)}) =Y. \notag \end{align}

Thus \(F\) is the identity.

Definition 26.9.21 Products of fixed points
#

Let \(F\) be a linear endomorphism of \(\mathcal A=\prod _\alpha M_{d_\alpha }\), and write \(\mathcal F=\{ X\in \mathcal A:F(X)=X\} \). For \(L\geq 0\), define

\begin{align} C_L(\mathcal F) & =\operatorname{span}_{\mathbb {C}}\{ X_1\cdots X_L:X_1,\ldots ,X_L\in \mathcal F\} . \notag \end{align}

This is the product space used in the dimension argument of [ CPGSV16 , Appendix C.4, lines 1980–1993 ] .

Theorem 26.9.22 Density blocks of a faithful fixed family bound products

Let \(\mathcal A=\prod _\alpha M_{d_\alpha }\), and let \(F:\mathcal A\to \mathcal A\) be positive and trace preserving. Suppose that the trace adjoint \(F^*\) satisfies the Schwarz inequality and that \(F\) fixes a family \(\rho =(\rho _\alpha )_\alpha \) for which every \(\rho _\alpha \) is positive definite. If \(\mathcal F=\operatorname{Fix}(F)\), then, for every \(L{\gt}0\), \(\dim C_L(\mathcal F)\leq \dim \mathcal F\).

Proof

Extend \(F\) to the full matrix algebra by diagonal compression followed by block-diagonal embedding, and choose a numbered basis of the ambient space. The extension is positive and trace preserving, its trace adjoint satisfies the Schwarz inequality, and the embedded family \(\rho \) is a positive definite fixed point. The fixed points therefore have the form

\begin{align} U\left(\bigoplus _k\sigma _k\otimes X_k\right)U^*, \qquad X_k& \in M_{h_k}(\mathbb {C}), \notag \end{align}

where \(\operatorname{tr}(\sigma _k)=1\). The parametrization \((X_k)_k\mapsto \bigoplus _k\sigma _k\otimes X_k\) is injective, since its left partial trace is \((X_k)_k\). Every product of \(L\) fixed points lies in the range of

\begin{align} (Y_k)_k & \longmapsto U\left(\bigoplus _k\sigma _k^L\otimes Y_k\right)U^*. \notag \end{align}

Thus the span of these products has dimension at most \(\sum _k h_k^2\), which is the dimension of the fixed-point space of the extension. Writing \(\mathcal E\) for the fixed-point space of the full-matrix extension, the injective block-diagonal embedding and diagonal compression give the dimension chain

\begin{align} \dim C_L(\mathcal F) & \leq \dim C_L(\mathcal E) \leq \dim \mathcal E \leq \dim \mathcal F. \notag \end{align}
Theorem 26.9.23 Fixed contractions and the dimension of their fixed-point space

Let \(F\) be a linear endomorphism of \(\mathcal A=\prod _\alpha M_{d_\alpha }\). Suppose that the following three conditions hold, with the second required for every bond matrix \(X\):

\begin{align} C_L(V_c)& =\mathcal A, \notag \\ F(V_c(X))& =V_c(X), \notag \\ \dim C_L(\mathcal F)& \leq \dim \mathcal F, \qquad \mathcal F=\{ Y\in \mathcal A:F(Y)=Y\} . \notag \end{align}

Then \(F=\operatorname{id}_{\mathcal A}\).

This is the finite-dimensional conclusion in [ CPGSV16 , Appendix C.4, lines 1980–1993 ] . It does not assume that the products \(V_c(X_1)\cdots V_c(X_L)\) are fixed.

Proof

Since every \(V_c(X)\) belongs to \(\mathcal F\), every product occurring in \(C_L(V_c)\) belongs to \(C_L(\mathcal F)\). Hence

\begin{align} \mathcal A=C_L(V_c) & \subseteq C_L(\mathcal F)\subseteq \mathcal A, \notag \end{align}

so \(C_L(\mathcal F)=\mathcal A\). Therefore

\begin{align} \dim \mathcal A=\dim C_L(\mathcal F) & \leq \dim \mathcal F\leq \dim \mathcal A. \notag \end{align}

Thus \(\mathcal F=\mathcal A\), and \(F\) is the identity.

Theorem 26.9.24 Faithful fixed family in a finite product

Let \(F\) be a positive trace-preserving endomorphism of \(\mathcal A=\prod _\alpha M_{d_\alpha }\). Suppose that each \(V_j\) is fixed by \(F\) and, for some \(L{\gt}0\), the identity belongs to

\begin{align} \operatorname{span}_{\mathbb {C}} \{ V_{j_1}\cdots V_{j_L}:j_1,\ldots ,j_L\in J\} . \notag \end{align}

Then there is a fixed family \(\rho =(\rho _\alpha )_\alpha \) such that every \(\rho _\alpha \) is positive definite.

This is a local finite-product consequence used to formalize the fixed-point argument in [ CPGSV16 , Appendix C.4, lines 1980–1993 ] ; CPSV16 applies Wolf’s density-block description directly rather than stating this intermediate result.

Proof

Extend \(F\) to the full matrix algebra by diagonal compression followed by block-diagonal embedding. This extension is positive and trace preserving. Block-diagonal embedding preserves the identity and every product \(V_{j_1}\cdots V_{j_L}\), so Theorem 26.9.62 gives a positive-definite fixed point \(\widehat\rho \) of the extension. Fixed points of the extension are block diagonal. Thus

\begin{align} \widehat\rho & =\bigoplus _\alpha \rho _\alpha , \notag \\ F(\rho ) & =\rho . \notag \end{align}

Every diagonal block \(\rho _\alpha \) of the positive-definite matrix \(\widehat\rho \) is positive definite.

Theorem 26.9.25 Identity criterion from fixed contractions

Let \(F\) be a positive trace-preserving endomorphism of \(\mathcal A=\prod _\alpha M_{d_\alpha }\) whose trace adjoint satisfies the Schwarz inequality. Suppose that, for some \(L{\gt}0\), \(C_L(V_c)=\mathcal A\) and \(F(V_c(X))=V_c(X)\) for every bond matrix \(X\). Then \(F=\operatorname{id}_{\mathcal A}\). No product \(V_c(X_1)\cdots V_c(X_L)\) is assumed to be fixed.

This is the implication used for each transported square composite in [ CPGSV16 , Appendix C.4, lines 1980–1995 ] .

Proof

The fixed contractions and their positive-length product span give a positive-definite fixed family \(\rho =(\rho _\alpha )_\alpha \). Hence Theorem 26.9.22 gives \(\dim C_L(\mathcal F)\leq \dim \mathcal F\), where \(\mathcal F=\operatorname{Fix}(F)\). Since \(C_L(V_c)=\mathcal A\) and \(V_c(X)\in \mathcal F\), the preceding theorem gives \(F=\operatorname{id}_{\mathcal A}\).

Retain the coordinates \((\alpha ,a,i)\), where \(\alpha \) labels a simple sector, \(a\) labels a diagonal entry of \(\mu _\alpha \), and \(0\leq i{\lt}d_\alpha \). The family \((Y_\alpha )_\alpha \) is represented on this space by \(\bigoplus _\alpha Y_\alpha \). Write \(\iota \) for this inclusion, \(\pi \) for extraction of the diagonal summands, and \(P=\iota \pi \). Composing \(\iota \) and \(\pi \) with \(R_\mu \) and \(\widetilde R_\mu \) defines their retained-coordinate forms.

Lemma 26.9.27 Extraction after vertical-sector inclusion

The diagonal-summand extraction is a left inverse of the inclusion: \(\pi \iota =\operatorname{id}\).

Proof

Restricting \(\bigoplus _\beta Y_\beta \) to the rows and columns with sector label \(\alpha \) gives \(Y_\alpha \).

Lemma 26.9.28 Entries retained by the vertical-sector projection

For every retained-coordinate matrix \(Z\), \(P(Z)_{(\alpha ,a,i),(\alpha ,b,j)} =Z_{(\alpha ,a,i),(\alpha ,b,j)}\).

Proof

Both indices lie in the same extracted diagonal summand.

Lemma 26.9.29 Entries removed by the vertical-sector projection

If \(\alpha \neq \beta \), then \(P(Z)_{(\alpha ,a,i),(\beta ,b,j)}=0\).

Proof

The two indices belong to distinct diagonal summands.

Lemma 26.9.30 Idempotence of the vertical-sector projection

The projection onto the vertical-sector diagonal summands is idempotent: \(P^2=P\).

Proof

The identity \(\pi \iota =\operatorname{id}\) gives \(P^2=\iota \pi \iota \pi =\iota \pi \).

Lemma 26.9.31 Retraction in retained vertical-sector coordinates

Suppose that every multiplicity space is nonzero and every diagonal entry of \(\mu _\alpha \) is positive. Then the retained-coordinate partial trace is a left inverse of the normalized retained-coordinate embedding.

Proof

First extract the diagonal summands, then apply \(\widetilde R_\mu R_\mu =\operatorname{id}\).

Lemma 26.9.32 Weighted vertical contraction in retained coordinates

For every horizontal bond matrix \(X\), contraction of \(\bigoplus _\alpha \mu _\alpha \otimes M_\alpha \) gives \(\bigoplus _\alpha \mu _\alpha \otimes M_\alpha (X)\).

Proof

Flattening the index triple \((\alpha ,a,i)\) gives the entry formula

\begin{align} B(X)_{(\alpha ,a,i),(\beta ,b,j)} & =\delta _{\alpha \beta }\delta _{ab} \mu _{\alpha ,a}M_\alpha (X)_{ij}. \notag \end{align}
Definition 26.9.33 Bond-matrix contraction of a vertical tensor
#

Let \(A\) be a tensor whose physical label is a pair \((a,b)\) of horizontal bond indices. For a bond matrix \(X\), define

\begin{align} A(X)& =\sum _{a,b}X_{ba}A_{ab}. \notag \end{align}

The order of the entries of \(X\) is chosen so that \(A(X)_{ij}=\operatorname{tr}(M^{ij}X)\) when \(A_{ab,ij}=M^{ij}_{ab}\).

Lemma 26.9.34 Contraction under fixed left and right multiplication

Let \(L\) and \(K\) be fixed matrices of compatible sizes. Then \(\left((a,b)\mapsto L A_{ab}K\right)(X)=L A(X)K\).

Proof

Distributivity of matrix multiplication over finite sums gives

\begin{align} \sum _{a,b}X_{ba}\left(LA_{ab}K\right) & =L\left(\sum _{a,b}X_{ba}A_{ab}\right)K. \notag \end{align}
Lemma 26.9.35 Contraction of a weighted block sum

For a weighted block-diagonal tensor \(A=\bigoplus _\alpha \mu _\alpha A_\alpha \), one has \(A(X)=\bigoplus _\alpha \mu _\alpha A_\alpha (X)\).

Proof

Since each tensor letter is block diagonal,

\begin{align} \sum _{a,b}X_{ba} \left(\bigoplus _\alpha \mu _\alpha A_\alpha \right)_{ab} & =\bigoplus _\alpha \mu _\alpha \sum _{a,b}X_{ba}(A_\alpha )_{ab} =\bigoplus _\alpha \mu _\alpha A_\alpha (X). \notag \end{align}
Lemma 26.9.36 Vertical contraction and physical closure

For the vertically viewed tensor \(\widetilde M_{ab,ij}=M^{ij}_{ab}\), bond-matrix contraction is the one-site physical closure: \(\widetilde M(X)=M(X)\).

Proof

For every pair of physical indices,

\begin{align} \widetilde M(X)_{ij} & =\sum _{a,b}X_{ba}M^{ij}_{ab} =\operatorname{tr}(M^{ij}X) =M(X)_{ij}. \notag \end{align}
Lemma 26.9.37 Contraction of the assembled vertical tensor

The contraction of the assembled vertical tensor is the weighted block diagonal of the sector contractions:

\begin{align} \left(\bigoplus _\alpha \mu _\alpha \otimes M_\alpha \right)(X) & =\bigoplus _\alpha \mu _\alpha \otimes M_\alpha (X). \notag \end{align}
Proof

Applying the preceding lemma to the block form \(\bigoplus _\alpha \mu _\alpha \otimes M_\alpha \) of the assembled tensor gives

\begin{align} \left(\bigoplus _\alpha \mu _\alpha \otimes M_\alpha \right)(X) & =\bigoplus _\alpha \mu _\alpha \otimes M_\alpha (X). \notag \end{align}
Lemma 26.9.38 Contraction of a letterwise forward identity

Let \(B_{ab}\) be an arbitrary vertical tensor. If \(U\widetilde M_{ab}U^\dagger =B_{ab}\) for every pair \((a,b)\), then, for every bond matrix \(X\), \(U M(X)U^\dagger =B(X)\).

Proof

By the definition of bond-matrix contraction,

\begin{align} U M(X)U^\dagger & =U\left(\sum _{a,b}X_{ba}\widetilde M_{ab}\right)U^\dagger =\sum _{a,b}X_{ba} \left(U\widetilde M_{ab}U^\dagger \right) =\sum _{a,b}X_{ba}B_{ab} =B(X). \notag \end{align}
Lemma 26.9.39 Contraction of a letterwise reconstruction identity

Let \(B_{ab}\) be an arbitrary vertical tensor. If \(\widetilde M_{ab}=U^\dagger B_{ab}U\) for every pair \((a,b)\), then, for every bond matrix \(X\), \(M(X)=U^\dagger B(X)U\).

Proof

Contracting the letterwise identity gives

\begin{align} M(X) & =\sum _{a,b}X_{ba}\widetilde M_{ab} =\sum _{a,b}X_{ba}\left(U^\dagger B_{ab}U\right) =U^\dagger \left(\sum _{a,b}X_{ba}B_{ab}\right)U =U^\dagger B(X)U. \notag \end{align}

Suppose that

\begin{align} U\widetilde M_{ab}U^\dagger & =\left(\bigoplus _\alpha \mu _\alpha \otimes M_\alpha \right)_{ab} \notag \end{align}

is a one-site vertical canonical-form identity. Contracting against an arbitrary bond matrix \(X\) gives

\begin{align} U M(X)U^\dagger & =\bigoplus _\alpha \mu _\alpha \otimes M_\alpha (X). \notag \end{align}

If the reverse letterwise identity is also given, then

\begin{align} M(X) & =U^\dagger \left(\bigoplus _\alpha \mu _\alpha \otimes M_\alpha (X)\right)U. \notag \end{align}

These are the contracted canonical-form identities used in [ CPGSV16 , Appendix C.4, lines 1955–1979 ] .

Proof

Since \(A(X)_{ij}=\sum _{a,b}X_{ba}A_{ab,ij}\) and \(\widetilde M_{ab,ij}=M^{ij}_{ab}\), one has \(M(X)=\sum _{a,b}X_{ba}\widetilde M_{ab}\). Distributivity of fixed left and right multiplication over finite sums gives

\begin{align} U\left(\sum _{a,b}X_{ba}\widetilde M_{ab}\right)U^\dagger & =\sum _{a,b}X_{ba} \left(U\widetilde M_{ab}U^\dagger \right). \notag \end{align}

Substituting the forward hypothesis into this equality gives

\begin{align} U M(X)U^\dagger & =\sum _{a,b}X_{ba} \left(\bigoplus _\alpha \mu _\alpha \otimes M_\alpha \right)_{ab} =\left(\bigoplus _\alpha \mu _\alpha \otimes M_\alpha \right)(X). \notag \end{align}

Applied blockwise, the same calculation gives

\begin{align} \left(\bigoplus _\alpha \mu _\alpha \otimes M_\alpha \right)(X) & =\bigoplus _\alpha \mu _\alpha \otimes M_\alpha (X). \notag \end{align}

If the reverse letterwise identity is given, the same calculation yields

\begin{align} M(X) & =\sum _{a,b}X_{ba}\widetilde M_{ab} \notag \\ & =U^\dagger \left(\sum _{a,b}X_{ba} \left(\bigoplus _\alpha \mu _\alpha \otimes M_\alpha \right)_{ab}\right)U \notag \\ & =U^\dagger \left(\bigoplus _\alpha \mu _\alpha \otimes M_\alpha (X)\right)U. \notag \end{align}
Definition 26.9.41 Four-site physical closure
#

For a virtual matrix \(X\), the four-site physical closure of \(K\) is the operator \(K_4(X)\) whose matrix coefficients are

\begin{align} K_4(X)_{(i_0,(i_1,(i_2,i_3))),(j_0,(j_1,(j_2,j_3)))} & =\operatorname{tr}\! \left(K^{i_0j_0}K^{i_1j_1}K^{i_2j_2}K^{i_3j_3}X\right). \notag \end{align}
Lemma 26.9.42 Coordinates of the four-site regrouping

The canonical four-coordinate regrouping and its inverse satisfy

\begin{align} R_4(\sigma ) & =(\sigma _0,(\sigma _1,(\sigma _2,\sigma _3))), \notag \\ R_4^{-1}(i_0,(i_1,(i_2,i_3))) & =(i_0,i_1,i_2,i_3). \notag \end{align}
Proof

Both identities follow from the definition of the canonical right-associated regrouping.

Theorem 26.9.43 General and right-associated four-site closures

Under the canonical right-associated identification of four-site configurations with quadruples of physical indices,

\begin{align} K_4(X)_{(i_0,(i_1,(i_2,i_3))),(j_0,(j_1,(j_2,j_3)))} & =\operatorname{tr}\! \left(K^{i_0j_0}K^{i_1j_1}K^{i_2j_2}K^{i_3j_3}X\right). \notag \end{align}
Proof

Expand the general four-site closure in the right-associated coordinates.

After identifying one blocked physical index with two original indices, \((K^{[2]})_1(X)=K_2(X)\).

Proof

Expand one blocked tensor matrix and decode its two physical indices.

Definition 26.9.45 Physical maps in vertical canonical coordinates

Let \(U_1\) and \(U_2\) be the physical coordinate changes in vertical canonical forms of \(M\) and its two-site blocking, respectively. Let \(J\) be the canonical relabelling from matrices indexed by pairs of one-site physical indices to matrices indexed by one blocked physical index. For the refinement and coarse-graining maps \(T\) and \(S\), define

\begin{align} T_{\mathrm v}(Z) & =U_2 J\! \left(T(U_1^\dagger ZU_1)\right)U_2^\dagger , \notag \\ S_{\mathrm v}(W) & =U_1 S\! \left(J^{-1}(U_2^\dagger WU_2)\right)U_1^\dagger . \notag \end{align}

These are the physical maps after absorbing the two vertical coordinate changes, as in [ CPGSV16 , Appendix C.4, lines 1955–1979 ] . They are intermediate maps on the retained physical coordinate spaces; the normalized sector maps \(R_1,R_2,\widetilde R_1,\widetilde R_2\) have not yet been composed with them.

For a bond matrix \(X\), write \(\mathcal M^{(1)}(X)\) and \(\mathcal M^{(2)}(X)\) for the one-site and two-site physical closures, respectively, and write

\begin{align} B_1(X) & =\bigoplus _\alpha \mu _\alpha \otimes M_\alpha (X), \notag \\ B_2(X) & =\bigoplus _\beta \nu _\beta \otimes A_\beta (X) \notag \end{align}

for the contracted one-site and two-site vertical canonical forms. If

\begin{align} T(\mathcal M^{(1)}(X)) & =\mathcal M^{(2)}(X), \notag \\ S(\mathcal M^{(2)}(X)) & =\mathcal M^{(1)}(X), \notag \end{align}

then

\begin{align} T_{\mathrm v}(B_1(X)) & =B_2(X), \notag \\ S_{\mathrm v}(B_2(X)) & =B_1(X). \notag \end{align}

These are the physical-coordinate identities which, after composition with \(R_1,R_2,\widetilde R_1,\widetilde R_2\), give the two displayed identities for \(\widetilde T\) and \(\widetilde S\) in [ CPGSV16 , Appendix C.4, lines 1955–1979 ] .

Proof

The reverse one-site canonical-form identity gives \(U_1^\dagger B_1(X)U_1=\mathcal M^{(1)}(X)\). Applying \(T\), relabelling its two-site output by \(J\), and using the forward blocked canonical-form identity gives

\begin{align} T_{\mathrm v}(B_1(X)) & =U_2J(T(\mathcal M^{(1)}(X)))U_2^\dagger =U_2J(\mathcal M^{(2)}(X))U_2^\dagger =B_2(X). \notag \end{align}

The reverse blocked canonical-form identity and the equation for \(S\) give, in the other direction,

\begin{align} S_{\mathrm v}(B_2(X)) & =U_1S(\mathcal M^{(2)}(X))U_1^\dagger =U_1\mathcal M^{(1)}(X)U_1^\dagger =B_1(X). \notag \end{align}
Definition 26.9.47 Refinement and coarse-graining on vertical sectors

Define maps between the one-site and two-site simple-sector algebras by

\begin{align} \widetilde T & =\widetilde R_2T_{\mathrm v}R_1, \notag \\ \widetilde S & =\widetilde R_1S_{\mathrm v}R_2. \notag \end{align}

The partial trace and diagonal-summand extraction define these maps on the full matrix algebras. Their agreement with the normalized maps in [ CPGSV16 , Appendix C.4, lines 1972–1979 ] is asserted on the weighted block-diagonal image. At this stage there is no assertion that the image is preserved, that the two maps are inverse, completely positive, or trace preserving, or that the sector labels have been matched. The final renormalization fixed-point conclusion is separate.

Definition 26.9.48 Positive vertical-sector families and total trace

A vertical-sector family \(X=(X_\alpha )_\alpha \) is positive when every \(X_\alpha \) is positive semidefinite. Its total sector trace is

\begin{align} \operatorname {Tr}_{\mathrm{sec}}(X) & =\sum _\alpha \operatorname{tr}(X_\alpha ). \notag \end{align}

Suppose that every multiplicity space is nonzero and every diagonal entry of \(\mu _\alpha \) is positive. The normalized embedding \(R_\mu \) sends a positive sector family to a positive retained matrix and satisfies \(\operatorname{tr}(R_\mu (X))=\operatorname {Tr}_{\mathrm{sec}}(X)\). Conversely, the sectorwise partial trace sends a positive retained matrix to a positive sector family and satisfies \(\operatorname {Tr}_{\mathrm{sec}}(\widetilde R_\mu (Z))=\operatorname{tr}(Z)\). These trace identities follow by summing the traces of the diagonal sectors; deleting the off-diagonal sector entries does not change the trace.

Proof

A positive diagonal weight matrix has positive trace, and its Kronecker product with each positive \(X_\alpha \) is positive. Partial trace preserves positivity. The two trace formulas follow from \(\operatorname{tr}(A\otimes B)=\operatorname{tr}(A)\operatorname{tr}(B)\) and the normalization by \(\operatorname{tr}(\mu _\alpha )\).

Lemma 26.9.50 Normalized embedding of multiplicity-trace-scaled sectors

Suppose that every multiplicity space is nonzero and every diagonal entry of \(\mu _\alpha \) is positive. For \(m_\alpha =\operatorname{tr}(\mu _\alpha )\),

\begin{align} R_\mu \! \left(\bigoplus _\alpha m_\alpha X_\alpha \right) & =\bigoplus _\alpha \mu _\alpha \otimes X_\alpha . \notag \end{align}
Proof

In each sector,

\begin{align} R_\mu (m_\alpha X_\alpha ) & =m_\alpha ^{-1}m_\alpha (\mu _\alpha \otimes X_\alpha ) =\mu _\alpha \otimes X_\alpha . \notag \end{align}
Lemma 26.9.51 Partial trace of weighted vertical sectors

For \(m_\alpha =\operatorname{tr}(\mu _\alpha )\),

\begin{align} \widetilde R_\mu \! \left(\bigoplus _\alpha \mu _\alpha \otimes X_\alpha \right) & =\bigoplus _\alpha m_\alpha X_\alpha . \notag \end{align}
Proof

Taking the partial trace over the multiplicity factor gives

\begin{align} \widetilde R_\mu (\mu _\alpha \otimes X_\alpha ) & =\operatorname{tr}(\mu _\alpha )X_\alpha =m_\alpha X_\alpha . \notag \end{align}

Let \(U:\mathbb {C}^n\to \mathbb {C}^r\) satisfy \(UU^\dagger =1\). If \(Z\geq 0\), then

\begin{align} \operatorname{tr}(UZU^\dagger ) & \leq \operatorname{tr}(Z), \notag \\ \operatorname{tr}(UZU^\dagger )=\operatorname{tr}(Z) & \Longleftrightarrow U^\dagger UZ=Z. \notag \end{align}

For every \(W\in \mathbb {C}^{r\times r}\), one also has \(\operatorname{tr}(U^\dagger WU)=\operatorname{tr}(W)\).

Proof

Put \(P=U^\dagger U\). The matrices \(P\) and \(1-P\) are orthogonal projections, and

\begin{align} \operatorname{tr}(UZU^\dagger ) & =\operatorname{tr}(PZ), \notag \\ \operatorname{tr}(Z)-\operatorname{tr}(PZ) & =\operatorname{tr}((1-P)Z)\geq 0. \notag \end{align}

The last trace vanishes precisely when \((1-P)Z=0\). The formula for \(W\) follows by cyclicity of trace and \(UU^\dagger =1\).

Definition 26.9.53 Matrices before active-sector compression

Let \(Z_T(X)\) be the matrix obtained by applying the normalized one-site embedding, expanding by \(U_1^\dagger \), applying \(T\), and relabelling the two-site indices, before compression by \(U_2\). Define \(Z_S(Y)\) in the reverse direction, before compression by \(U_1\).

Suppose that the physical maps are completely positive and trace preserving and \(U_iU_i^\dagger =1\). For positive sector families \(X\in \mathcal A_1\) and \(Y\in \mathcal A_2\), the matrices \(Z_T(X)\) and \(Z_S(Y)\) are positive and

\begin{align} \operatorname{tr}(Z_T(X)) & =\operatorname {Tr}_{\mathrm{sec}}(X), \notag \\ \operatorname{tr}(Z_S(Y)) & =\operatorname {Tr}_{\mathrm{sec}}(Y). \notag \end{align}

After the final compression and sectorwise partial trace,

\begin{align} \operatorname {Tr}_{\mathrm{sec}}(\widetilde T(X)) & =\operatorname{tr}(U_2Z_T(X)U_2^\dagger ), \notag \\ \operatorname {Tr}_{\mathrm{sec}}(\widetilde S(Y)) & =\operatorname{tr}(U_1Z_S(Y)U_1^\dagger ). \notag \end{align}
Proof

Positivity follows successively from the normalized embedding, expansion by an adjoint, the physical map, relabelling, and partial trace. The trace identities follow from the preceding two lemmas and trace preservation of the physical maps.

Suppose that the multiplicity spaces are nonzero, their diagonal weights are positive, the physical maps \(T\) and \(S\) are completely positive and trace preserving, and the vertical coordinate maps satisfy \(U_iU_i^\dagger =1\). Then \(\widetilde T\) and \(\widetilde S\) preserve pointwise positive semidefiniteness. For pointwise positive families \(X\in \mathcal A_1\) and \(Y\in \mathcal A_2\), their total sector traces obey

\begin{align} \operatorname {Tr}_{\mathrm{sec}}(\widetilde T(X)) & \leq \operatorname {Tr}_{\mathrm{sec}}(X), \notag \\ \operatorname {Tr}_{\mathrm{sec}}(\widetilde S(Y)) & \leq \operatorname {Tr}_{\mathrm{sec}}(Y). \notag \end{align}

The trace loss vanishes precisely when

\begin{align} U_2^\dagger U_2 Z_T(X) & =Z_T(X), \notag \\ U_1^\dagger U_1 Z_S(Y) & =Z_S(Y), \notag \end{align}

respectively.

This result concerns positivity and trace on positive elements. It does not assert a complete-positivity structure for the finite products, a trace-preserving extension to their full ambient matrix spaces, or an inverse relation between the two transported maps.

Proof

The normalized diagonal embedding and the sectorwise partial trace preserve positivity. Before the final compression, trace preservation of the physical map and \(U_iU_i^\dagger =1\) give the original sector trace. For a positive matrix \(Z\) and a coisometry \(U\), put \(P=U^\dagger U\). Then

\begin{align} \operatorname{tr}(UZU^\dagger ) & =\operatorname{tr}(PZ) \leq \operatorname{tr}(Z). \notag \end{align}

Since \(1-P\) is an orthogonal projection, equality is equivalent to \(\operatorname{tr}((1-P)Z)=0\), hence to \((1-P)Z=0\).

Lemma 26.9.56 Two-site support after refinement

For a bond matrix \(X\), set \(V_1(X)=\bigoplus _\alpha m_\alpha M_\alpha (X)\). Suppose that both vertical canonical forms satisfy their exact reconstruction identities, the one-site multiplicity spaces are nonzero, their diagonal weights are positive, \(T(\mathcal M^{(1)}(X))=\mathcal M^{(2)}(X)\), and \(U_2U_2^\dagger =1\). Then \(U_2^\dagger U_2 Z_T(V_1(X))=Z_T(V_1(X))\). This is the refinement support identity used in [ CPGSV16 , Appendix C.4, lines 1955–1980 ] .

Proof

Let \(\mathcal R^{-1}\) relabel a matrix indexed by two one-site indices as a matrix indexed by the blocked two-site index. Then

\begin{align} Z_T(V_1(X)) & =\mathcal R^{-1}\! \left[T\! \left(U_1^\dagger B_1(X)U_1\right)\right] =\mathcal R^{-1}\! \left[T\! \left(\mathcal M^{(1)}(X)\right)\right] =\mathcal R^{-1}\! \left[\mathcal M^{(2)}(X)\right] =U_2^\dagger B_2(X)U_2. \notag \end{align}

Here the first equality is the normalized embedding, the second and last are the two reconstruction identities, and the middle equality is the refinement identity. The equality before the last is precisely the blocked-index relabelling theorem. Therefore

\begin{align} U_2^\dagger U_2Z_T(V_1(X)) & =U_2^\dagger (U_2U_2^\dagger )B_2(X)U_2 =Z_T(V_1(X)). \notag \end{align}
Lemma 26.9.57 One-site support after coarse-graining

For a bond matrix \(X\), set \(V_2(X)=\bigoplus _\beta n_\beta A_\beta (X)\). Suppose that both vertical canonical forms satisfy their exact reconstruction identities, the two-site multiplicity spaces are nonzero, their diagonal weights are positive, \(S(\mathcal M^{(2)}(X))=\mathcal M^{(1)}(X)\), and \(U_1U_1^\dagger =1\). Then \(U_1^\dagger U_1 Z_S(V_2(X))=Z_S(V_2(X))\). This is the coarse-graining support identity used in [ CPGSV16 , Appendix C.4, lines 1955–1980 ] .

Proof

Let \(\mathcal R\) decode a matrix indexed by the blocked two-site index as a matrix indexed by two one-site indices. Then

\begin{align} Z_S(V_2(X)) & =S\! \left(\mathcal R\! \left[U_2^\dagger B_2(X)U_2\right]\right) =S\! \left(\mathcal M^{(2)}(X)\right) =\mathcal M^{(1)}(X) =U_1^\dagger B_1(X)U_1. \notag \end{align}

Here the first equality is the normalized embedding, the next equality is the blocked-index relabelling theorem, the middle equality is the coarse-graining identity, and the last is the one-site reconstruction. Therefore

\begin{align} U_1^\dagger U_1Z_S(V_2(X)) & =U_1^\dagger (U_1U_1^\dagger )B_1(X)U_1 =Z_S(V_2(X)). \notag \end{align}
Lemma 26.9.58 Trace preservation on one-site canonical-form contractions

Under the hypotheses of Lemma 26.9.56, suppose in addition that \(U_1U_1^\dagger =1\) and that \(T\) is completely positive and trace preserving. Then \(\operatorname {Tr}_{\mathrm{sec}}(\widetilde T(V_1(X)))=\operatorname {Tr}_{\mathrm{sec}}(V_1(X))\).

Proof

Cyclicity of trace and the preceding support identity give

\begin{align} \operatorname {Tr}_{\mathrm{sec}}(\widetilde T(V_1(X))) & =\operatorname{tr}(U_2^\dagger U_2Z_T(V_1(X))) =\operatorname{tr}(Z_T(V_1(X))) =\operatorname {Tr}_{\mathrm{sec}}(V_1(X)). \notag \end{align}
Lemma 26.9.59 Trace preservation on two-site canonical-form contractions

Under the hypotheses of Lemma 26.9.57, suppose in addition that \(U_2U_2^\dagger =1\) and that \(S\) is completely positive and trace preserving. Then \(\operatorname {Tr}_{\mathrm{sec}}(\widetilde S(V_2(X)))=\operatorname {Tr}_{\mathrm{sec}}(V_2(X))\).

Proof

Cyclicity of trace and the preceding support identity give

\begin{align} \operatorname {Tr}_{\mathrm{sec}}(\widetilde S(V_2(X))) & =\operatorname{tr}(U_1^\dagger U_1Z_S(V_2(X))) =\operatorname{tr}(Z_S(V_2(X))) =\operatorname {Tr}_{\mathrm{sec}}(V_2(X)). \notag \end{align}

Suppose that every multiplicity space for \(\mu _\alpha \) and \(\nu _\beta \) is nonzero, every diagonal entry of these two matrices is positive, and

\begin{align} T_{\mathrm v}\! \left(\bigoplus _\alpha \mu _\alpha \otimes X_\alpha \right) & =\bigoplus _\beta \nu _\beta \otimes Y_\beta , \notag \\ S_{\mathrm v}\! \left(\bigoplus _\beta \nu _\beta \otimes Y_\beta \right) & =\bigoplus _\alpha \mu _\alpha \otimes X_\alpha . \notag \end{align}

Writing \(m_\alpha =\operatorname{tr}(\mu _\alpha )\) and \(n_\beta =\operatorname{tr}(\nu _\beta )\), one has

\begin{align} \widetilde T\! \left(\bigoplus _\alpha m_\alpha X_\alpha \right) & =\bigoplus _\beta n_\beta Y_\beta , \notag \\ \widetilde S\! \left(\bigoplus _\beta n_\beta Y_\beta \right) & =\bigoplus _\alpha m_\alpha X_\alpha . \notag \end{align}

In particular, take \(X_\alpha =M_\alpha (X)\) and \(Y_\beta =A_\beta (X)\) from the contractions of the one-site and two-site vertical canonical forms. The physical closure identities for \(T\) and \(S\) then imply the two hypotheses above, so the same conclusions hold for these source-generated sector operators.

Proof

Since \(\widetilde T=\widetilde R_2T_{\mathrm v}R_1\), one has

\begin{align} \widetilde T\! \left(\bigoplus _\alpha m_\alpha X_\alpha \right) & =\widetilde R_2\! \left(T_{\mathrm v}\! \left(\bigoplus _\alpha \mu _\alpha \otimes X_\alpha \right)\right) =\widetilde R_2\! \left(\bigoplus _\beta \nu _\beta \otimes Y_\beta \right) =\bigoplus _\beta n_\beta Y_\beta . \notag \end{align}

Likewise, \(\widetilde S=\widetilde R_1S_{\mathrm v}R_2\) gives

\begin{align} \widetilde S\! \left(\bigoplus _\beta n_\beta Y_\beta \right) & =\widetilde R_1\! \left(S_{\mathrm v}\! \left(\bigoplus _\beta \nu _\beta \otimes Y_\beta \right)\right) =\widetilde R_1\! \left(\bigoplus _\alpha \mu _\alpha \otimes X_\alpha \right) =\bigoplus _\alpha m_\alpha X_\alpha . \notag \end{align}

For every bond matrix \(X\), set

\begin{align} V_1(X)& =\bigoplus _\alpha m_\alpha M_\alpha (X), \notag \\ V_2(X)& =\bigoplus _\beta n_\beta A_\beta (X). \notag \end{align}

Under the hypotheses of the preceding theorem, the transported composites satisfy

\begin{align} (\widetilde S\circ \widetilde T)(V_1(X)) & =V_1(X), \notag \\ (\widetilde T\circ \widetilde S)(V_2(X)) & =V_2(X). \notag \end{align}

Thus the one-site and two-site contraction families lie in the respective fixed-point spaces, as in Appendix C.4, lines 1974–1980. These equations do not assert that either composite is the identity on the whole sector algebra; that conclusion requires the fixed-point structure argument of Appendix C.4, lines 1980–1993.

Proof

The preceding theorem gives \(\widetilde T(V_1(X))=V_2(X)\) and \(\widetilde S(V_2(X))=V_1(X)\). Hence

\begin{align} (\widetilde S\circ \widetilde T)(V_1(X)) & =\widetilde S(V_2(X))=V_1(X), \notag \\ (\widetilde T\circ \widetilde S)(V_2(X)) & =\widetilde T(V_1(X))=V_2(X). \notag \end{align}
Theorem 26.9.62 Faithful fixed point from fixed product generators

Let \(\mathcal M\) be a finite full matrix algebra over \(\mathbb C\), and let \(F:\mathcal M\to \mathcal M\) be positive and trace nonincreasing. Suppose that a family \((V_j)_{j\in J}\) consists of fixed points of \(F\) and that, for some \(L{\gt}0\), the identity belongs to the linear span of the products \(V_{j_1}\cdots V_{j_L}\) in \(\mathcal M\). Then \(F\) has a positive-definite fixed point. This is the local full-matrix intermediate implication used in [ CPGSV16 , Appendix C.4, lines 1980–1995 ] ; it is not stated there as a separate theorem.

Proof

Boundedness of the forward orbits gives the mean-ergodic projection \(P\). Set \(\rho =P(\mathbf1)\) and let \(Q\) be the support projection of \(\rho \). For every \(j\), the maximal-support property of \(\rho \) gives \(QV_jQ=V_j\). Since \(Q\) is a projection, this implies \(QV_j=V_j=V_jQ\). By induction, for every \(k\geq 1\),

\begin{align} Q\cdot V_{j_1}\cdots V_{j_k}\cdot Q & =V_{j_1}\cdots V_{j_k}. \notag \end{align}

The product-span hypothesis and linearity then give \(Q\mathbf1Q=\mathbf1\). Since \(Q^2=Q\), one has \(Q=Q^2=Q\mathbf1Q=\mathbf1\). Thus \(\rho \) is positive definite, and the construction of \(P\) gives \(F(\rho )=\rho \).

Theorem 26.9.63 Trace preservation from fixed product generators

Let \(\mathcal M\) be a finite full matrix algebra over \(\mathbb C\), and let \(F:\mathcal M\to \mathcal M\) be positive and trace nonincreasing. Suppose that \(F(V_j)=V_j\) for every \(j\in J\). Put \(\mathcal V=\operatorname{span}_{\mathbb {C}}\{ V_j:j\in J\} \) and, in the notation of [ CPGSV16 , Appendix C.4 ] , define

\begin{align} C_L(\mathcal V) & =\operatorname{span}_{\mathbb {C}}\{ v_1\cdots v_L:v_1,\ldots ,v_L\in \mathcal V\} . \notag \end{align}

If \(\mathbf1\in C_L(\mathcal V)\) for some \(L{\gt}0\), then \(F\) is trace preserving.

Proof

Multilinearity gives

\begin{align} C_L(\mathcal V) & =\operatorname{span}_{\mathbb {C}}\{ V_{j_1}\cdots V_{j_L}:j_1,\ldots ,j_L\in J\} . \notag \end{align}

By Theorem 26.9.62, there is a positive-definite matrix \(\rho \) such that \(F(\rho )=\rho \). Let \(F^*\) be the trace-pairing adjoint and set \(\Delta =\mathbf1-F^*(\mathbf1)\). For every positive semidefinite \(X\), trace nonincrease gives \(\operatorname{tr}(\Delta X)=\operatorname{tr}(X)-\operatorname{tr}(F(X))\geq 0\). Positivity of \(F^*\) and self-duality of the positive semidefinite cone therefore give \(\Delta \geq 0\). The fixed-point equation gives \(\operatorname{tr}(\rho \Delta )=0\), so positive definiteness of \(\rho \) forces \(\Delta =0\). Thus \(F^*(\mathbf1)=\mathbf1\), which is equivalent to trace preservation.

Theorem 26.9.64 Trace transfer through the canonical full-matrix extension

Let \(\mathcal A=\bigoplus _{\alpha \in I}\mathcal M_{d_\alpha \times d_\alpha }\), let \(\iota :\mathcal A\to \operatorname{End}(\bigoplus _\alpha \mathbb C^{d_\alpha })\) be the block-diagonal embedding, and let \(\pi \) be diagonal compression. For a linear map \(F:\mathcal A\to \mathcal A\), set \(\widehat F=\iota \circ F\circ \pi \). Then:

  1. if \(F\) is trace nonincreasing on positive elements of \(\mathcal A\), then \(\widehat F\) is trace nonincreasing;

  2. if \(\widehat F\) is trace preserving, then \(F\) preserves the total trace on \(\mathcal A\).

Proof

If \(Y\geq 0\), then \(\pi (Y)\geq 0\), and the trace identities for diagonal compression and block-diagonal embedding give

\begin{align} \operatorname{tr}(\widehat F(Y)) & =\operatorname{tr}_{\mathcal A}(F(\pi (Y))) \leq \operatorname{tr}_{\mathcal A}(\pi (Y)) =\operatorname{tr}(Y). \notag \end{align}

This proves the first assertion. For \(X\in \mathcal A\), the identity \(\pi \circ \iota =\operatorname{id}_{\mathcal A}\) gives, whenever \(\widehat F\) is trace preserving,

\begin{align} \operatorname{tr}_{\mathcal A}(F(X)) & =\operatorname{tr}(\widehat F(\iota (X))) =\operatorname{tr}(\iota (X)) =\operatorname{tr}_{\mathcal A}(X). \notag \end{align}
Theorem 26.9.65 Trace preservation on a finite sum from fixed products

Let \(\mathcal A=\bigoplus _{\alpha \in I}\mathcal M_{d_\alpha \times d_\alpha }\) be a finite sum of full matrix algebras, with total trace \(\operatorname{tr}_{\mathcal A}(X)=\sum _{\alpha \in I}\operatorname{tr}(X_\alpha )\). Let \(F:\mathcal A\to \mathcal A\) be positive and trace nonincreasing. Suppose that \(F(V_j)=V_j\) for every \(j\in J\). With \(\mathcal V=\operatorname{span}_{\mathbb {C}}\{ V_j:j\in J\} \), put

\begin{align} C_L(\mathcal V) & =\operatorname{span}_{\mathbb {C}}\{ v_1\cdots v_L:v_1,\ldots ,v_L\in \mathcal V\} . \notag \end{align}

If \(\mathbf1_{\mathcal A}\in C_L(\mathcal V)\) for some \(L{\gt}0\), then \(F\) preserves the total trace on \(\mathcal A\).

Proof

Multilinearity first gives

\begin{align} C_L(\mathcal V) & =\operatorname{span}_{\mathbb {C}}\{ V_{j_1}\cdots V_{j_L}:j_1,\ldots ,j_L\in J\} . \notag \end{align}

Let \(\iota :\mathcal A\to \operatorname{End}(\bigoplus _\alpha \mathbb C^{d_\alpha })\) be the block-diagonal embedding and let \(\widehat F\) be the canonical full-matrix extension. These maps satisfy

\begin{align} \iota (XY)& =\iota (X)\iota (Y), \notag \\ \iota (\mathbf1_{\mathcal A})& =\mathbf1, \notag \\ \widehat F(\iota (X))& =\iota (F(X)). \notag \end{align}

The extension is positive and trace nonincreasing. The matrices \(\iota (V_j)\) are fixed by \(\widehat F\), and the displayed identities carry the product-span hypothesis to the full matrix algebra. Theorem 26.9.63 makes \(\widehat F\) trace preserving. Restricting to block-diagonal matrices proves preservation of \(\operatorname{tr}_{\mathcal A}\) by \(F\).

Theorem 26.9.66 Trace sandwich on finite sums of matrix algebras

Let \(\mathcal A\) and \(\mathcal B\) be finite sums of full matrix algebras, and let \(T:\mathcal A\to \mathcal B\) and \(S:\mathcal B\to \mathcal A\) be linear maps. Suppose that \(T\) is positive, both maps are trace nonincreasing, and \(S\circ T\) is trace preserving. Then \(T\) is trace preserving.

Proof

For every positive \(X\in \mathcal A\), positivity of \(T\) and the two trace-nonincreasing inequalities give

\begin{align} \operatorname{tr}_{\mathcal A}(X) & =\operatorname{tr}_{\mathcal A}(S(T(X))) \leq \operatorname{tr}_{\mathcal B}(T(X)) \leq \operatorname{tr}_{\mathcal A}(X). \notag \end{align}

Hence the middle term equals the endpoints. Equality extends from the positive cone to Hermitian matrices by positive and negative parts. For arbitrary \(X\), put

\begin{align} H_1& =X+X^\dagger , \notag \\ H_2& =\mathrm{i}(X-X^\dagger ), \notag \\ X& =\frac12(H_1-\mathrm{i}H_2). \notag \end{align}

Both \(H_1\) and \(H_2\) are Hermitian, so linearity proves trace preservation for every \(X\).

Theorem 26.9.67 Trace preservation of the transported vertical-sector maps

Suppose that every one-site and two-site multiplicity space is nonzero and every corresponding diagonal weight is positive. Let \(\widetilde M^{(1)}\) and \(\widetilde M^{(2)}\) be the vertical tensors of \(M\) and its two-site blocking, and let \(B_1\) and \(B_2\) be their assembled one-site and two-site canonical forms. Assume that both canonical forms are bases of normal tensors and that, for every vertical letter \(\ell \),

\begin{align} U_i\widetilde M^{(i)}_\ell U_i^\dagger & =(B_i)_\ell , \notag \\ \widetilde M^{(i)}_\ell & =U_i^\dagger (B_i)_\ell U_i, \notag \\ U_iU_i^\dagger & =\mathbf1 \qquad (i=1,2). \notag \end{align}

Assume in addition that the physical maps \(T\) and \(S\) are completely positive and trace preserving and that, for every horizontal bond matrix \(Z\), the two physical-coordinate identities hold:

\begin{align} T(\mathcal M^{(1)}(Z))& =\mathcal M^{(2)}(Z), \notag \\ S(\mathcal M^{(2)}(Z))& =\mathcal M^{(1)}(Z). \notag \end{align}

Then each transported map and both square composites preserve the appropriate total sector trace. For the individual maps,

\begin{align} \sum _\beta \operatorname{tr}(\widetilde T(X)_\beta ) & =\sum _\alpha \operatorname{tr}(X_\alpha ), \notag \\ \sum _\alpha \operatorname{tr}(\widetilde S(Y)_\alpha ) & =\sum _\beta \operatorname{tr}(Y_\beta ). \notag \end{align}

For the square composites,

\begin{align} \sum _\alpha \operatorname{tr}((\widetilde S\widetilde T)(X)_\alpha ) & =\sum _\alpha \operatorname{tr}(X_\alpha ), \notag \\ \sum _\beta \operatorname{tr}((\widetilde T\widetilde S)(Y)_\beta ) & =\sum _\beta \operatorname{tr}(Y_\beta ). \notag \end{align}

Neither of the stronger range inclusions is assumed:

\begin{align} T(R_1(\mathcal A_1))& \subseteq R_2(\mathcal A_2), \notag \\ S(R_2(\mathcal A_2))& \subseteq R_1(\mathcal A_1). \notag \end{align}
Proof

Each transported map is positive and trace nonincreasing, and hence so are the square composites \(\widetilde S\widetilde T\) and \(\widetilde T\widetilde S\). The fixed-generator lemma and the product-spanning theorem give the hypotheses of Theorem 26.9.65 for both composites. Thus both preserve the corresponding total trace.

For positive \(X\in \mathcal A_1\), one has

\begin{align} \operatorname{tr}_{\mathcal A_1}(X) & =\operatorname{tr}_{\mathcal A_1} ((\widetilde S\widetilde T)(X)) \leq \operatorname{tr}_{\mathcal A_2}(\widetilde T(X)) \leq \operatorname{tr}_{\mathcal A_1}(X). \notag \end{align}

Theorem 26.9.66 therefore makes \(\widetilde T\) trace preserving. Applying the same theorem to \(\widetilde S\) and \(\widetilde T\widetilde S\) proves the assertion for \(\widetilde S\).

Lemma 26.9.68 Complete positivity of refinement in vertical coordinates

If the physical refinement map \(T\) is completely positive, then the transported map \(T_{\mathrm v}\) in vertical canonical coordinates is completely positive.

Proof

By Definition 26.9.45,

\begin{align} T_{\mathrm v}(Z) & =U_2J\! \left(T(U_1^\dagger ZU_1)\right)U_2^\dagger . \notag \end{align}

The two single-operator conjugations and the reindexing \(J\) are completely positive, so the assertion follows by composition.

Lemma 26.9.69 Complete positivity of coarse-graining in vertical coordinates

If the physical coarse-graining map \(S\) is completely positive, then the transported map \(S_{\mathrm v}\) in vertical canonical coordinates is completely positive.

Proof

By Definition 26.9.45,

\begin{align} S_{\mathrm v}(W) & =U_1S\! \left(J^{-1}(U_2^\dagger WU_2)\right)U_1^\dagger . \notag \end{align}

Again, single-operator conjugation, reindexing, and composition preserve complete positivity.

Lemma 26.9.70 Retained-coordinate block-diagonal inclusion

Let \(\iota \) be block-diagonal inclusion of the weighted vertical-sector block family into its full matrix algebra, and let \(W\) be the canonical reindexing to retained physical coordinates. Then the retained-coordinate inclusion is \(\iota _{\mathrm v}=W\circ \iota \).

Proof

This is the defining relation between the direct-sum and retained coordinates.

Lemma 26.9.71 Retained-coordinate diagonal-block extraction

Let \(\pi \) be diagonal-block extraction to the weighted vertical-sector block family, and let \(W\) be the canonical reindexing to retained physical coordinates. Then the retained-coordinate extraction is \(\pi _{\mathrm v}=\pi \circ W^{-1}\).

Proof

This is the inverse defining relation between the retained and direct-sum coordinates.

Lemma 26.9.72 Full-matrix factorization of transported refinement

Write \(\widehat R_1\) for normalized state preparation, \(\widehat{\widetilde R}_2\) for controlled partial trace, and \(W_i\) for retained-coordinate reindexing. The full-matrix extension of the transported refinement map is

\begin{align} \widehat{\widetilde T} & =\widehat{\widetilde R}_2\circ W_2^{-1}\circ T_{\mathrm v}\circ W_1\circ \widehat R_1. \label{eq:rfp_refinement_extension} \end{align}
Proof

Substitute the preceding inclusion and extraction identities into \(\widetilde T=\widetilde R_2T_{\mathrm v}R_1\).

Lemma 26.9.73 Full-matrix factorization of transported coarse-graining

Write \(\widehat R_2\) for normalized state preparation, \(\widehat{\widetilde R}_1\) for controlled partial trace, and \(W_i\) for retained-coordinate reindexing. The full-matrix extension of the transported coarse-graining map is

\begin{align} \widehat{\widetilde S} & =\widehat{\widetilde R}_1\circ W_1^{-1}\circ S_{\mathrm v}\circ W_2\circ \widehat R_2. \label{eq:rfp_coarse_extension} \end{align}
Proof

Substitute the preceding inclusion and extraction identities into \(\widetilde S=\widetilde R_1S_{\mathrm v}R_2\).

Under the hypotheses of Theorem 26.9.67, the maps

\begin{align} \widetilde T& :\mathcal A_1\longrightarrow \mathcal A_2, \notag \\ \widetilde S& :\mathcal A_2\longrightarrow \mathcal A_1 \notag \end{align}

are completely positive. The trace adjoints of the two square composites satisfy the Schwarz inequality in every simple summand.

Proof

Let \(\iota _i\) and \(\pi _i\) be block-diagonal inclusion and diagonal-block extraction, respectively, and let \(W_i\) denote the canonical reindexing from the weighted vertical-sector coordinates to the retained physical coordinates. The full-matrix extension of the transported refinement map has the factorization (??). Here \(\widehat R_1\) is normalized state preparation, \(\widehat{\widetilde R}_2\) is controlled partial trace, and

\begin{align} T_{\mathrm v}(Z) & =U_2J\! \left(T(U_1^\dagger ZU_1)\right)U_2^\dagger . \notag \end{align}

Every factor is completely positive. The analogous identities

\begin{align} S_{\mathrm v}(W) & =U_1S\! \left(J^{-1}(U_2^\dagger WU_2)\right)U_1^\dagger \notag \end{align}

and (??) prove complete positivity of \(\widetilde S\). These factorizations are exact on the full matrix algebras: \(\pi _iW_i^{-1}\) is precisely extraction of the retained diagonal sector blocks. Thus no range inclusion is used.

Composition gives complete positivity of \(\widetilde S\widetilde T\) and \(\widetilde T\widetilde S\). The preceding theorem gives trace preservation of these two composites. Their trace adjoints are therefore unital completely positive maps, and the Kadison–Schwarz inequality applies in each simple summand.

Theorem 26.9.75 Transported vertical-sector composites are identities

Under precisely the hypotheses of Theorem 26.9.67, the transported maps satisfy

\begin{align} \widetilde S\circ \widetilde T & =\operatorname{id}_{\mathcal A_1}, \label{eq:mpdo_vsector_ST_id}\\ \widetilde T\circ \widetilde S & =\operatorname{id}_{\mathcal A_2}. \label{eq:mpdo_vsector_TS_id} \end{align}

Thus \(\widetilde T\) and \(\widetilde S\) are mutually inverse. This is the identity-composition conclusion of [ CPGSV16 , Appendix C.4, lines 1974–1995 ] .

Proof

For each square composite \(F\), positivity follows from positivity of the two transported maps. Theorem 26.9.67 and Theorem 26.9.74 give trace preservation and the Schwarz inequality for \(F^*\), respectively. Lemma 26.9.61 gives \(F(V_i(X))=V_i(X)\) for every bond matrix \(X\). Theorem 26.9.19 gives a positive integer \(L_i\) such that \(C_{L_i}(V_i)=\mathcal A_i\). Applying Theorem 26.9.25 first to \(F=\widetilde S\circ \widetilde T\) and then to \(F=\widetilde T\circ \widetilde S\) proves (??) and (??).

Theorem 26.9.76 Unitary relabelling of transported vertical sectors

Under the hypotheses of Theorem  26.9.75, write

\begin{align} \mathcal A_1& =\prod _{\alpha }M_{D^{(1)}_\alpha }(\mathbb {C}), & \mathcal A_2& =\prod _{\beta }M_{D^{(2)}_\beta }(\mathbb {C}). \notag \end{align}

There are an equivalence \(\sigma \) of the two sector index sets, equalities \(D^{(1)}_\alpha =D^{(2)}_{\sigma (\alpha )}\), and unitaries \(V_\alpha \in M_{D^{(2)}_{\sigma (\alpha )}}(\mathbb {C})\) such that

\begin{align} \widetilde T(0,\ldots ,0,X,0,\ldots ,0) & =(0,\ldots ,0,V_\alpha \, \iota _\alpha (X)\, V_\alpha ^*,0,\ldots ,0), \notag \end{align}

where the nonzero entry on the right is in position \(\sigma (\alpha )\), and

\begin{align} \widetilde S(0,\ldots ,0,Y,0,\ldots ,0) & =(0,\ldots ,0,\iota _\alpha ^{-1} (V_\alpha ^*YV_\alpha ),0,\ldots ,0), \notag \end{align}

where the entries on the left and right are in positions \(\sigma (\alpha )\) and \(\alpha \), respectively. These identities hold for every \(X\in M_{D^{(1)}_\alpha }(\mathbb {C})\) and \(Y\in M_{D^{(2)}_{\sigma (\alpha )}}(\mathbb {C})\). Here \(\iota _\alpha \) is the reindexing induced by the displayed dimension equality. These are the mutually inverse unitary formulas of [ CPGSV16 , Appendix C.4, line 1997 ] . They make no assertion about the multiplicities, weights, or coefficient identity at lines 2001–2008.

Proof

The two basis-of-normal-tensors decompositions have positive matrix dimensions. The transported maps are completely positive and preserve the total block trace, and the preceding theorem gives both inverse laws. Apply Theorem 25.7.9 to this pair. Its equivalence of summands, dimension equalities, and unitary matrices give the two displayed formulas without changing the chosen relabelling.

Theorem 26.9.77 Coefficient comparison for transported vertical sectors

Under the hypotheses and with the notation of Theorem  26.9.76, let \(\mu _\alpha \) and \(\nu _\beta \) be the positive diagonal multiplicity matrices in the one-site and two-site vertical canonical forms, and set \(m_\alpha =\operatorname{tr}(\mu _\alpha )\) and \(n_\beta =\operatorname{tr}(\nu _\beta )\). For every horizontal bond matrix \(X\) and every sector \(\alpha \),

\begin{align} A^{(2)}_{\sigma (\alpha )}(X) & =\frac{m_\alpha }{n_{\sigma (\alpha )}} V_\alpha \iota _\alpha (A^{(1)}_\alpha (X))V_\alpha ^*. \notag \end{align}

Consequently, for every tensor letter \(a\),

\begin{align} A^{(2)}_{\sigma (\alpha ),a} & =\frac{m_\alpha }{n_{\sigma (\alpha )}} V_\alpha \, \iota _\alpha (A^{(1)}_{\alpha ,a})V_\alpha ^*. \notag \end{align}

This is the coefficient identity in [ CPGSV16 , Appendix C.4, lines 2001–2008 ] . It compares the traces of the multiplicity matrices; it does not assert equality of their dimensions or of their individual diagonal entries.

Proof

Decompose the weighted contraction family into its individual matrix summands. At the summand paired with \(\alpha \), the unitary formula gives

\begin{align} m_\alpha V_\alpha \iota _\alpha (A^{(1)}_\alpha (X))V_\alpha ^* & =n_{\sigma (\alpha )}A^{(2)}_{\sigma (\alpha )}(X). \notag \end{align}

Positivity of \(\nu _{\sigma (\alpha )}\) makes \(n_{\sigma (\alpha )}\) nonzero, so division gives the first identity. Taking \(X\) to be a matrix unit gives the tensor-letter identity.

Under the hypotheses and with the sector correspondence of Theorem  26.9.77, let \(B\) be the vertical reading of the two-site blocking, and write \(O_L(A)=\operatorname{Tr}_{\mathrm{bond}}(A_{i_1}\cdots A_{i_L})\) for the length-\(L\) closed-chain operator. If \(L{\gt}0\), then the same equivalence \(\sigma \), dimension identifications, and unitaries appearing in the tensor-letter identity satisfy

\begin{align} O_L(B) & =\sum _\alpha \left(\frac{m_\alpha }{n_{\sigma (\alpha )}}\right)^L \operatorname{tr}\! \left(\nu _{\sigma (\alpha )}^L\right) O_L\! \left(A^{(1)}_\alpha \right), \notag \\ O_L(B) & =\sum _{\alpha ,\beta } \operatorname{tr}(\mu _\alpha ^L) \operatorname{tr}(\mu _\beta ^L) O_L\! \left(A^{(1)}_\alpha \right) O_L\! \left(A^{(1)}_\beta \right). \notag \end{align}

These are the two representations in [ CPGSV16 , Appendix C.4, lines 2011–2018 ] .

Local fix (blocked coefficient exponent): CPSV16 Appendix C.4, line 2013 prints \(m_\gamma ^L/n_\gamma \). The line-2008 tensor scaling and line 2040 give \((m_\gamma /n_\gamma )^L\). This is documented in docs/paper-gaps/cpsv16_blocked_operator_trace_ratio_exponent.tex.

Proof

The two-site vertical canonical form first gives \(O_L(B)=\sum _\delta \operatorname{tr}(\nu _\delta ^L) O_L(A^{(2)}_\delta )\). Reindex this sum by \(\delta =\sigma (\alpha )\). The tensor-letter identity from the preceding theorem multiplies every letter of \(A^{(1)}_\alpha \) by \(m_\alpha /n_{\sigma (\alpha )}\). Along a chain of length \(L\) this scalar therefore occurs to the power \(L\); unitary conjugation and the bond-index identification leave the closing trace unchanged. This proves the first formula.

For the second formula, the vertical reading of a two-site block is the product tensor of two copies of the one-site vertical reading. Closed chains turn this tensor product into multiplication of operators. Expand each copy by the one-site vertical canonical form, \(O_L(\widetilde M)=\sum _\alpha \operatorname{tr}(\mu _\alpha ^L)O_L(A^{(1)}_\alpha )\), and distribute the product of the two finite sums.

Suppose that the vertical reading of \(M\) is reconstructed from a retained tensor \(A\) by a coisometry \(U\). The two-site blocking is then reconstructed from the product of two copies of \(A\) by the Kronecker square of \(U\). Moreover, if \(M\) is in normalized BNT-refined horizontal form and generates positive operators, this retained product tensor has invariant-projector closure and has no nontrivial periodic vectors. No full-support assumption is imposed on the retained bond space.

Proof

The Kronecker square of a coisometry is again a coisometry. Expanding a blocked vertical letter gives the product of the two one-site reconstructions and hence the asserted exact compression formula. Normalized BNT-refined horizontal form and positivity are preserved by two-site blocking. Invariant-projector closure descends to an exact reducing compression, while a periodic vector in the compression would embed isometrically as a periodic vector of the blocked vertical tensor.

In the retained coordinates, the product tensor is the orthogonal direct sum over ordered pairs of BNT copies. Its summand indexed by \(((\alpha ,q),(\beta ,r))\) is \(\mu _{\alpha ,q}\mu _{\beta ,r}(M_\alpha M_\beta )\). Every such summand has invariant-projector closure and has no nontrivial periodic vectors. This includes zero-dimensional summands and requires no nonvanishing assumption on the displayed scalar.

Proof

The canonical inclusion of a dependent direct-sum block is an isometry. After transporting this inclusion through the retained-coordinate equivalence, it intertwines the chosen summand with the full retained product tensor on both sides. Its range projection therefore commutes with every tensor letter. Invariant-projector closure descends by exact compression, and any periodic vector of the summand would embed as a periodic vector of the full retained product.

Theorem 26.9.81 Normal-corner decomposition of a retained copy pair

For every ordered pair of retained BNT copies, the weighted product tensor has an exact orthogonal decomposition into positive multiples of normal tensors. The corresponding corner isometries are retained, intertwine in both directions, and reconstruct every tensor letter. The active family is allowed to be empty; in particular, no normal block is introduced for a zero-dimensional or identically zero copy-pair tensor.

Proof

Apply the canonical-form sufficient condition to the invariant-projector closure and periodic-exclusion properties of the preceding theorem. Its spectral construction discards precisely the corners on which every letter vanishes and retains the isometry of every nonzero corner.

A retained-product spectral family records, simultaneously for every ordered pair of retained BNT copies, all nonzero normal corners, their positive spectral coefficients, and their local isometries. Its active labels form the dependent union of the local corner families; this union is enumerated by a single finite type. The local isometries and their inclusions remain part of the data, and their range projections can be formed when needed.

Suppose that the one-site vertical tensor has the stated exact coisometric reconstruction, that \(M\) is in normalized BNT-refined horizontal form, and that \(M\) generates positive operators. Then simultaneous retained-product spectral data exist. In copy coordinates, the assembled vertical tensor is the direct sum of the weighted simple blocks. The canonical inclusion of each copy is an isometry, intertwines in both directions, and its compression selects exactly that weighted block. Likewise, the canonical inclusion of a copy pair, followed by its local corner isometry, is an isometry into the retained product bond space and intertwines in both directions. Composing once more with the adjoint of the squared vertical coisometry gives an isometry into the bond space of the blocked vertical tensor. Under the exact coisometric reconstruction, these ambient inclusions intertwine each active weighted corner with the blocked vertical tensor in both directions. In particular, if \(J_j\) is the ambient inclusion of an active corner, then \(J_j^\dagger \mathcal V(M^{(2)})^iJ_j=\lambda _jA_j^i\). These explicit composite inclusions retain the range projections required for the sector-weight comparison.

Proof

In copy coordinates the assembled tensor is block diagonal. The canonical dependent-sum inclusion is an isometry, and the two block-diagonal intertwining identities give its forward, adjoint, and compression formulas. Choose the exact normal-corner decomposition of every copy-pair tensor. The canonical copy-pair inclusions are isometries and select the weighted diagonal blocks of the retained product tensor. Composition with each local isometry gives the retained inclusion and both intertwining identities. Finally, write the blocked vertical tensor as \(T=W^\dagger CW\) and the ambient inclusion as \(J=W^\dagger R\). The coisometry identity \(WW^\dagger =1\) transports both retained intertwining identities from \(C\) to \(T\); the compression identity then follows from \(J^\dagger J=1\). For any blocked BNT label, choose its first multiplicity copy. Composing its canonical inclusion with the adjoint reconstruction coisometry gives an isometric reference corner of the blocked vertical tensor. Transport along an equality of bond dimensions preserves its isometry and exact compression formula.

Enumerate the dependent family of active corners by a single finite label set. The resulting coefficients are positive, the blocks are normal, and the inclusion ranges are pairwise orthogonal. For every tensor letter,

\begin{align} C^i & =\sum _j W_j(\lambda _j A_j^i)W_j^\dagger , \notag \\ W_j^\dagger W_l & =\delta _{jl}, \notag \\ C^iW_j & =W_j(\lambda _jA_j^i), \notag \\ W_j^\dagger C^i & =(\lambda _jA_j^i)W_j^\dagger . \notag \end{align}

Each compression \(W_j^\dagger C^iW_j\) is \(\lambda _jA_j^i\), and \(C\) has the same positive-length closed chains as the finite direct sum \(\bigoplus _j\lambda _jA_j\).

Proof

First reconstruct the retained product as the sum of its canonical copy-pair blocks. Substitute the exact local spectral reconstruction in every pair, distribute the two inclusion maps across the finite sums, and identify the iterated sum with the dependent active-label sum. Finally transport this sum through the active-label enumeration. Isometry, orthogonality, intertwining, and compression are inherited by composition; the closed-chain equality follows from the exact isometric reconstruction. This is the active-corner decomposition in [ CPGSV16 , Appendix C.4, lines 2020–2029 ] .

Suppose that the one-site vertical tensor has the stated exact coisometric reconstruction, and let \((A^{(2)}_\gamma )_\gamma \) be a basis of normal tensors for the blocked vertical tensor. For every active product corner \(A_j\) there are a label \(\gamma (j)\), an equality of bond dimensions, an invertible matrix \(X_j\), and a scalar \(\zeta _j\) of modulus one such that, after transporting the blocked tensor along the dimension equality,

\begin{align} A_j^i & =\zeta _jX_jA^{(2),i}_{\gamma (j)}X_j^{-1}. \notag \end{align}

The choices may be made simultaneously. No converse coverage or surjectivity of \(j\mapsto \gamma (j)\) is asserted.

Scope restriction (active product BNT): The conclusion gives only one-way coverage of active product corners. It does not assert that every blocked BNT label occurs. This is documented in docs/paper-gaps/cpsv16_bnt_uniqueness_zero_coefficient.tex.

Local fix (per-pair support): Appendix C.4, lines 2011–2029 of [ CPGSV16 ] compares a sum over all retained copy pairs and does not isolate a fixed pair. Here fixed-pair support follows from the exact squared reconstruction and the canonical direct-sum corner; a zero pair contributes an empty active family. See docs/paper-gaps/cpsv16_figure11_per_pair_support.tex.

Proof

The squared coisometric reconstruction gives equality of all positive-length closed chains between the blocked vertical tensor and the retained product. Transport the blocked basis of normal tensors along this equality. Proposition 2.7, applied to the flattened positive normal decomposition, then covers each active corner by a blocked BNT tensor up to an invertible gauge and a unit-modulus phase. Classical choice makes these comparisons simultaneous.

Assume that every blocked BNT label has positive multiplicity and that the blocked vertical tensor has the exact coisometric reconstruction \(T=U_2^\dagger C_2U_2\). Let \(E_{\gamma ,0}\) be the canonical inclusion of the first copy of label \(\gamma \), and put \(F_\gamma =U_2^\dagger E_{\gamma ,0}\). Then \(F_\gamma \) is an isometry, intertwines \(T\) with the distinguished weighted BNT copy in both directions, and compresses \(T\) to that copy exactly. For an active product corner covered by \(\gamma \), transport \(F_\gamma \) along the stated equality of bond dimensions. The transported map remains an isometry and obeys the corresponding transported compression identity.

Proof

The copy inclusion is isometric and selects one diagonal block of the assembled tensor. Inserting \(T=U_2^\dagger C_2U_2\) and \(U_2U_2^\dagger =1\) gives both intertwining identities and compression. Transport along equality of bond dimensions preserves these equations.

Suppose that \(M\) is in normalized BNT-refined horizontal form and generates positive operators. Assume exact coisometric reconstructions of its one-site and blocked vertical tensors, positive multiplicities and weights for the blocked BNT, and normality of its BNT representatives. For every active product corner \(j\), one has \(0{\lt}\lambda _j\zeta _j\).

Proof

Compare two isometric corners of the blocked vertical tensor carrying the same normal representative. The distinguished blocked copy has positive weight by hypothesis. The active corner has weight \(\lambda _j\zeta _j\) by its exact compression and gauge–phase identity. This scalar is nonzero because \(\lambda _j{\gt}0\) and \(|\zeta _j|=1\). Normality gives a nonzero range-projection corner; the BNT-refined horizontal hypothesis separates it at some finite chain length. The sector-weight comparison with the distinguished reference corner then yields \(\lambda _j\zeta _j{\gt}0\).

Under the hypotheses of the preceding positivity theorem, for every active product corner \(j\) there is a real number \(\omega _j{\gt}0\) such that

\begin{align} X_j^\dagger X_j & =\omega _j\mathbb {1}, \notag \\ \omega _j^{-1/2}X_j & \in \mathrm{U}(D_j). \notag \end{align}
Proof

Apply the Figure 8 comparison to the active corner and the distinguished blocked reference corner. Both coefficients are positive, so horizontal canonicality and positivity identify their Gram-dressed normal tensors. Normal-tensor rigidity then makes \(X_j^\dagger X_j\) a positive real multiple of the identity. Division by the positive square root gives a unitary matrix.

Definition 26.9.89 Original-label corner family

An original-label corner family for the retained product records, for every active corner of each copy pair, an original one-site BNT label, a positive coefficient, and an isometric inclusion into the raw product bond space. Distinct corners belonging to one copy pair have orthogonal ranges. Each inclusion intertwines the raw product tensor with the stated positive multiple of its original BNT representative, and the resulting corners reconstruct every tensor letter exactly.

Local fix (Figure-11 fixed-pair support): A copy pair with no active corner is represented by an empty family; no unsupported corner is inserted. See docs/paper-gaps/cpsv16_figure11_per_pair_support.tex.

Let the active product corners be covered by blocked BNT representatives, let the blocked representatives be identified with the original BNT by the trace-ratio unitary conjugacies, and suppose that the active gauge–phase coefficients are positive. If \(X_j^\dagger X_j=\omega _j\mathbb {1}\) with \(\omega _j{\gt}0\), then every retained copy pair has an original-label corner family. Its coefficient at an active corner is

\begin{align} \frac{\lambda _j\zeta _j}{w_{\alpha ,q}w_{\beta ,r}} \frac{\operatorname{tr}D_{\gamma (j)}}{\operatorname{tr}D^{(2)}_{\sigma (\gamma (j))}}, \notag \end{align}

which is positive. The normalized inclusions are isometries with pairwise orthogonal ranges, intertwine the raw product tensor with these positive multiples of the original BNT representatives, and reconstruct every raw product letter exactly.

Local fix (Figure-11 fixed-pair support): Empty active families remain empty. Exact weighted reconstruction and positivity of the outer copy weight imply that the corresponding raw product vanishes. See docs/paper-gaps/cpsv16_figure11_per_pair_support.tex.

Proof

Transport each local inclusion first by the normalized active comparison gauge and then by the unitary identifying the blocked representative with its original one-site label. The first normalization preserves isometry and orthogonality; the second unitary transport does likewise. The two conjugacy equations give the stated coefficient and intertwining identity. Positivity follows from the active gauge–phase coefficient, the two positive multiplicity traces, and the positive outer copy weight. Conjugating each corner term through the two transports recovers its local spectral term. Summing these identities gives the weighted reconstruction, and cancellation of the nonzero outer weight gives the raw reconstruction.

Theorem 26.9.91 Fusion coisometries from original-label corners

Given an original-label corner family, choose the distinguished retained copy of every BNT label. For fixed labels \(\alpha ,\beta \), let the multiplicity of \(\gamma \) be the number of active corners of the distinguished copy pair whose original label is \(\gamma \), and put the corresponding positive corner coefficients on the diagonal of \(\chi _{\alpha ,\beta ,\gamma }\). The block row of the adjoints of the corner inclusions, regrouped by these label fibers, defines a fusion coisometry. It satisfies

\begin{align} \chi _{\alpha ,\beta ,\gamma ;r} & {\gt}0, \notag \\ U_{\alpha ,\beta }U_{\alpha ,\beta }^\dagger & =1, \notag \\ U_{\alpha ,\beta }(M_\alpha M_\beta )^{ij} U_{\alpha ,\beta }^\dagger & =\bigoplus _\gamma \chi _{\alpha ,\beta ,\gamma }\otimes M_\gamma ^{ij}, \notag \end{align}

together with the exact reconstruction

\begin{align} (M_\alpha M_\beta )^{ij} & =U_{\alpha ,\beta }^\dagger \left(\bigoplus _\gamma \chi _{\alpha ,\beta ,\gamma }\otimes M_\gamma ^{ij}\right) U_{\alpha ,\beta }. \notag \end{align}

Empty label fibers contribute zero-dimensional diagonal blocks. This is the decomposition of CPSV16, Appendix C.4, lines 2020–2029.

Scope restriction (active product BNT): Only active product corners are retained. A label absent from the distinguished copy pair has zero fusion multiplicity. See docs/paper-gaps/cpsv16_bnt_uniqueness_zero_coefficient.tex.

Local fix (Figure-11 fixed-pair support): The distinguished copy pair may have an empty active family; no unsupported corner is inserted. See docs/paper-gaps/cpsv16_figure11_per_pair_support.tex.

Local fix (Figure-11 fusion coisometry): The retained-row map is a coisometry onto the active direct sum. Exact reconstruction includes any common zero corner discarded by the forward map. See docs/paper-gaps/cpsv16_figure11_fusion_coisometry.tex.

Proof

For each distinguished copy pair, form the block row from the adjoints of its pairwise orthogonal isometric corner inclusions. The block-row identity makes this map a coisometry. Its forward conjugation is block diagonal over the active corners, while the corner reconstruction gives the reverse identity. Regrouping the active-corner sum by the original label turns each label fiber into the diagonal matrix whose entries are precisely the positive corner coefficients. These identities are valid without separate cases when a fiber or the whole active family is empty.

Under the one-site and two-site vertical basis-of-normal-tensors decompositions and the two completely positive, trace-preserving physical-closure transport identities, assume that the one-site tensor is in normalized BNT-refined horizontal form and defines a matrix product density operator. Then there are positive diagonal multiplicity matrices \(\chi _{\alpha ,\beta ,\gamma }\) and matrices \(U_{\alpha ,\beta }\) such that every diagonal entry is positive and

\begin{align} U_{\alpha ,\beta }U_{\alpha ,\beta }^{\dagger } & =1, \notag \\ U_{\alpha ,\beta }(M_\alpha M_\beta )^{ij} U_{\alpha ,\beta }^{\dagger } & =\bigoplus _\gamma \chi _{\alpha ,\beta ,\gamma }\otimes M_\gamma ^{ij}, \notag \end{align}

while the exact reconstruction is

\begin{align} (M_\alpha M_\beta )^{ij} & =U_{\alpha ,\beta }^{\dagger } \left(\bigoplus _\gamma \chi _{\alpha ,\beta ,\gamma }\otimes M_\gamma ^{ij}\right) U_{\alpha ,\beta }. \notag \end{align}

This is the positive fusion decomposition of CPSV16, Appendix C.4, lines 2020–2029.

Scope restriction (active product BNT): Only active product corners occur. A label absent from a fixed product pair has zero fusion multiplicity. See docs/paper-gaps/cpsv16_bnt_uniqueness_zero_coefficient.tex.

Local fix (Figure-11 fixed-pair support): A fixed product pair may have no active corner, and no unsupported sector is inserted. See docs/paper-gaps/cpsv16_figure11_per_pair_support.tex.

Local fix (Figure-11 fusion coisometry): The retained-row map is a coisometry onto the active direct sum, and its adjoint gives the exact reconstruction. See docs/paper-gaps/cpsv16_figure11_fusion_coisometry.tex.

Proof

First decompose every retained copy-pair tensor into its active normal corners and compare these corners with the two-site vertical basis. Positivity of matrix product density operators makes every resulting scalar positive, while the Gram comparison normalizes each gauge to a unitary. The inverse vertical-sector transport then returns the corners to the original one-site labels. Their orthogonal isometric inclusions form the rows of \(U_{\alpha ,\beta }\). Grouping these rows by the original label gives the positive diagonal matrices \(\chi _{\alpha ,\beta ,\gamma }\); corner intertwining and corner reconstruction give the two displayed identities.

Theorem 26.9.93 Positive fusion decomposition of vertical products

Let \(M\) be in normalized BNT-refined horizontal form, generate matrix product density operators, and satisfy the renormalization fixed-point condition of Definition 26.2.1. Then one may choose a vertical basis of normal tensors \(\{ M_\alpha \} _\alpha \) for which there are positive diagonal matrices \(\chi _{\alpha ,\beta ,\gamma }\) and matrices \(U_{\alpha ,\beta }\). Every diagonal entry of \(\chi _{\alpha ,\beta ,\gamma }\) is positive, and

\begin{align} U_{\alpha ,\beta }U_{\alpha ,\beta }^{\dagger } & =1, \notag \\ U_{\alpha ,\beta }(M_\alpha M_\beta )^{ij} U_{\alpha ,\beta }^{\dagger } & =\bigoplus _\gamma \chi _{\alpha ,\beta ,\gamma }\otimes M_\gamma ^{ij}, \notag \\ (M_\alpha M_\beta )^{ij} & =U_{\alpha ,\beta }^{\dagger } \left(\bigoplus _\gamma \chi _{\alpha ,\beta ,\gamma }\otimes M_\gamma ^{ij}\right) U_{\alpha ,\beta }. \notag \end{align}

Thus the renormalization fixed-point and matrix-product-density-operator assumptions, together with normalized BNT-refined horizontal form, imply the positive fusion decomposition of CPSV16, Appendix C.4, lines 2020–2029.

Scope restriction (active product BNT): Only active product corners occur. A label absent from a fixed product pair has zero fusion multiplicity. See docs/paper-gaps/cpsv16_bnt_uniqueness_zero_coefficient.tex.

Local fix (Figure-11 fixed-pair support): A fixed product pair may have no active corner, and no unsupported sector is inserted. See docs/paper-gaps/cpsv16_figure11_per_pair_support.tex.

Local fix (Figure-11 fusion coisometry): The retained-row map is a coisometry onto the active direct sum, and its adjoint gives the exact reconstruction. See docs/paper-gaps/cpsv16_figure11_fusion_coisometry.tex.

Proof

Apply the proved normalized BNT-refined specialization of Proposition 4.13 to \(M\) and to its two-site blocking. In each case, retain the CPSV basis-of-normal-tensors assertion, the positive multiplicity matrices, and both coisometric decomposition identities. Unpack the two completely positive, trace-preserving maps in the renormalization fixed-point condition. The preceding transported-sector theorem then supplies the positive diagonal family, the row coisometries, the forward fusion identity, and exact reconstruction for the chosen one-site vertical basis.

Theorem 26.9.94 Two-site closure of the two-site blocking

After identifying two blocked physical indices with four original indices, one has \((K^{[2]})_2(X)=K_4(X)\).

Proof

Expand the two blocked tensor matrices and reassociate their product.

26.10 Simple local structure from SAL and ZCL

26.10.1 Simple canonical-form weights

Lemma 26.10.1.1 Blockwise zero-correlation-length equation

Suppose a tensor with zero correlation length is gauge-equivalent, through block-diagonal copy gauges, to an assembled sector decomposition. There is a scalar \(\lambda {\gt}0\) such that every copy satisfies

\begin{align} (\mu _{j,q}\mathcal T_{A_j})^2 & =\lambda \mu _{j,q}\mathcal T_{A_j}. \label{eq:rfp_block_zcl} \end{align}

This is the block equation in [ CPGSV16 , Appendix C.2, lines 1652–1657 ] .

Proof

Write \(\mathcal T_M=G\mathcal T_SG^{-1}\), where \(G\) is the induced block-diagonal gauge. The equation \(\mathcal T_M^2=\lambda \mathcal T_M\) therefore becomes \(\mathcal T_S^2=\lambda \mathcal T_S\) after conjugation by \(G^{-1}\). Restriction to the \((j,q)\)-th diagonal block gives (??).

Theorem 26.10.1.2 Copy independence for a non-nilpotent sector decomposition

Let a tensor with zero correlation length be gauge-equivalent, through block-diagonal copy gauges, to an assembled sector decomposition whose basis elements all have non-nilpotent physical-trace transfer. Then the weights do not depend on the copy index: \(\mu _{j,q}=\mu _{j}\) [ CPGSV16 , Appendix C.2, lines 1646–1661 ] .

Proof

Zero correlation length states \(\mathcal T_M^{2}=\lambda \mathcal T_M\) with \(\lambda {\gt}0\). If \(\mathcal T_M=X\mathcal T_SX^{-1}\) is the block-diagonal gauge to the transfer of the assembled sector decomposition, then cancellation of \(X\) and \(X^{-1}\) gives \(\mathcal T_S^{2}=\lambda \mathcal T_S\). By Lemmas 26.7.2 and 26.7.3, the identity descends to every copy:

\begin{align} \mu _{j,q}^{2}\mathcal T_{A_j}^{2} & =\lambda \mu _{j,q}\mathcal T_{A_j}, \notag \\ \mathcal T_{A_j}^{2} & =\frac{\lambda }{\mu _{j,q}}\mathcal T_{A_j}. \notag \end{align}

The left side does not depend on \(q\), and \(\mathcal T_{A_j}\ne 0\) because it is not nilpotent, so \(\lambda /\mu _{j,q}\) is independent of \(q\), which gives \(\mu _{j,q}=\mu _{j,q'}\).

Corollary 26.10.1.3 Simple canonical-form tensors with zero correlation length

A simple canonical-form tensor (Definition 26.7.5) with zero correlation length has non-nilpotent basis transfers and weights independent of the copy index.

Proof

Apply Theorem 26.10.1.2 to the witness supplied by the simple canonical-form predicate.

Definition 26.10.1.4 Common sector weight and absorbed representative

Suppose the weights over each representative do not depend on the copy index. Choose the common weight \(\mu _j\) from any copy over \(j\) and absorb it into the representative:

\begin{align} \mathcal K_j& =\mu _j A_j. \notag \end{align}

This is the convention of [ CPGSV16 , Appendix C.2, equation CFK, lines 1660–1665 ] .

Lemma 26.10.1.5 Every copy has the common weight

For every copy \(q\) over \(j\), one has \(\mu _{j,q}=\mu _j\).

Proof

Compare the \(q\)-th copy with the distinguished copy used to define \(\mu _j\).

Theorem 26.10.1.6 Coefficient after common-weight absorption

Let \(r_j\) be the number of horizontal copies of representative \(j\). Then its coefficient on a chain of length \(N\) is

\begin{align} \sum _q\mu _{j,q}^{N}& =r_j\mu _j^{N}. \notag \end{align}

Thus the natural multiplicity is the horizontal copy count \(r_j\).

Proof

Every term in the copy sum equals \(\mu _j^N\), and there are \(r_j\) terms.

The common weight is nonzero, and hence for every chain length \(N\),

\begin{align} q_j=\sum _q\mu _{j,q}^{N}& =r_j\mu _j^{N}\ne 0. \notag \end{align}

This is the coefficient nonvanishing used in the choice \(m_j=q_j\widetilde m_j\) in [ CPGSV16 , Appendix C.2, lines 1714–1718 ] . It does not assert nonvanishing of the independent virtual tail contraction \(\widetilde m_j\).

Proof

The distinguished copy weight is nonzero by the sector data. Since \(r_j{\gt}0\), both factors in \(r_j\mu _j^N\) are nonzero.

Suppose the weights over each representative are independent of the copy index, and none of the physical-trace transfers \(\mathcal B_j=\sum _i A_j^{ii}\) is nilpotent. There is one positive tail length \(L\) such that, for every representative \(A_j\), some virtual indices \(\alpha ,\beta \) satisfy \(\widetilde m_j=[\mathcal B_j^L]_{\alpha ,\beta }\ne 0\). At total chain length \(L+3\), the corresponding copy coefficient is \(q_j=\sum _q\mu _{j,q}^{L+3}\ne 0\). Thus the three-site closing matrix satisfies

\begin{align} R_j& =q_j\mathcal B_j^L, \notag \\ (R_j)_{\alpha ,\beta } & =q_j\widetilde m_j\ne 0. \notag \end{align}

This is the traced-tail selection made in [ CPGSV16 , Appendix C.2, lines 1714–1718 ] .

Proof

Since \(\mathcal B_j\) is not nilpotent, every positive power of \(\mathcal B_j\) is nonzero; in particular, one common positive power has a nonzero entry for every \(j\). The preceding theorem supplies the nonzero coefficient at length \(L+3\). Therefore its product with the selected entry of \(\mathcal B_j^L\) is nonzero.

Theorem 26.10.1.9 Canonical form with natural multiplicities

After absorbing the common weight, the matrix product vector of the assembled tensor is

\begin{align} \mathcal V_N(S)& =\sum _j r_j\mathcal V_N(\mathcal K_j). \notag \end{align}

This is equation CFK of [ CPGSV16 , Appendix C.2, lines 1660–1665 ] ; the same multiplicities occur in equation sigmaNKj of [ CPGSV16 , Appendix C.2, lines 1756–1759 ] .

Proof

Expand the assembled tensor by representatives, use Theorem 26.10.1.6, and absorb \(\mu _j^N\) into the length-\(N\) matrix product vector of \(A_j\).

Definition 26.10.1.10 Three-site family closure and outer inverse contraction

Let \((\mathcal K_s)_s\) be a finite family of MPO tensors, with \(\mathcal K_s^{ij}\in M_{D_s}(\mathbb {C})\), and let \(R_s\in M_{D_s}(\mathbb {C})\). A three-site operator is a family closure when

\begin{align} \rho _{i_1i_2i_3,j_1j_2j_3} & =\sum _s\operatorname{tr}\! \left(\mathcal K_s^{i_1j_1}\mathcal K_s^{i_2j_2} \mathcal K_s^{i_3j_3}R_s\right). \notag \end{align}

Given a simultaneous left inverse \(C\) as in Theorem 27.3.74, contracting \(C\) against the first and third physical sites of \(\rho \) defines the outer inverse contraction

\begin{align} (\Gamma _{x,y})_{i_2j_2} & =\sum _{i_1,j_1,i_3,j_3} C_{x,(i_1,j_1)}C_{y,(i_3,j_3)} \rho _{(i_1,i_2,i_3),(j_1,j_2,j_3)}. \notag \end{align}

The closure is the sector-sum form of the displayed equation for \(\sigma _3^{(N)}\) in [ CPGSV16 , Appendix C.2, lines 1343–1348 ] , used with the block-canonical tensor in the Case II calculation at [ CPGSV16 , Appendix C.2, lines 1726–1732 ] . The outer contraction is the sector-family form of the Case I contraction in [ CPGSV16 , Appendix C.2, lines 1415–1438 ] ; the same construction is used with sector projectors at lines 1719–1725.

Suppose that the doubled-index tensor has the horizontal BNT representation \(S\), the copy weights over each representative agree, the physical-trace transfers \(\mathcal B_j=\sum _iA_j^{ii}\) are not nilpotent, and the original tensor satisfies SAL. After identifying length-three configurations with ordered triples, the normalized three-site marginal of the four-site state is the family closure

\begin{align} (\sigma ^{(4)}_3)_{i_1i_2i_3,j_1j_2j_3} & =\sum _j\operatorname{tr}\! \left(A_j^{i_1j_1}A_j^{i_2j_2}A_j^{i_3j_3}\widehat R_j\right), \notag \end{align}

where

\begin{align} \widehat R_j & =\operatorname{tr}(\rho ^{(4)})^{-1}q_j\mathcal B_j, \notag \\ q_j& =\sum _q\mu _{j,q}^{4}. \notag \end{align}

Every \(\widehat R_j\) is nonzero. More generally, a tail of length \(L\) gives \(\widehat R_j=\operatorname{tr}(\rho ^{(L+3)})^{-1}q_j\mathcal B_j^L\). This is the normalized traced-tail expansion used in [ CPGSV16 , Appendix C.2, lines 1714–1732 ] .

Proof

Equality of the positive-length matrix-product-vector families expands every matrix entry of the original operator as the sum of the BNT entries with coefficients \(q_j\). Summing the diagonal physical configurations of the tail gives \(\mathcal B_j^L\). The global normalization multiplies every closing matrix by \(\operatorname{tr}(\rho ^{(L+3)})^{-1}\). At \(L=1\), SAL makes this scalar nonzero, copy independence makes \(q_j\) nonzero, and nonnilpotence makes \(\mathcal B_j\) nonzero.

Theorem 26.10.1.12 Collapse of the outer inverse contraction

Let \(x=(s,\alpha _1,\beta _1)\) and \(y=(t,\alpha _3,\beta _3)\). For a three-site family closure and a simultaneous left inverse, the outer inverse contraction vanishes when \(s\ne t\). When \(s=t\), it is \((\mathcal K_s^{i_2j_2})_{\beta _1,\alpha _3} (R_s)_{\beta _3,\alpha _1}\). In particular, the contraction retains precisely one entry of the middle physical slice and one entry of the closing matrix, with the orientation shown above. This is the sector-family form of the Case I contraction in [ CPGSV16 , Appendix C.2, lines 1415–1438 ] . The basis-of-normal-tensors inverse is constructed at lines 1666–1676 and the resulting contraction is used in the Case II calculation at lines 1719–1732 of the same appendix. The closing entry \(R_s(\beta _3,\alpha _1)\) is the corrected tail-index orientation of the display at lines 1422–1438, recorded in docs/paper-gaps/cpgsv17_mpdo_sal_zcl_eta_local_structure.tex.

Proof

Expand the family closure and interchange the finite sector and physical sums. For \(x=(x_s,x_\alpha ,x_\beta )\), the inverse identity is

\begin{align} \sum _{i,j} C_{x,(i,j)}\mathcal K_s^{ij} & = \begin{cases} E_{x_\alpha ,x_\beta },& x_s=s,\\ 0,& x_s\ne s. \end{cases} \notag \end{align}

Hence distinct labels give zero. For equal labels, the remaining trace is

\begin{align} \operatorname{tr}\! \left(E_{\alpha _1,\beta _1}\mathcal K_s^{i_2j_2} E_{\alpha _3,\beta _3}R_s\right) & =(\mathcal K_s^{i_2j_2})_{\beta _1,\alpha _3} (R_s)_{\beta _3,\alpha _1}. \notag \end{align}
Corollary 26.10.1.13 Three-site collapse from the one-letter span

Under the one-letter product-algebra spanning hypothesis, there is a simultaneous left inverse for which every three-site family closure has the preceding diagonal-sector contraction and vanishing off-diagonal contractions.

Proof

Choose the simultaneous left inverse from Theorem 27.3.74 and apply Theorem 26.10.1.12.

26.10.2 Markov decomposition and inverse-map sector factorization

For the simple MPDO case in Appendix C.2 of [ CPGSV16 ] , the strong-area-law hypothesis is used locally through the equality case of strong subadditivity for a normalized three-site reduced state.

Definition 26.10.2.1 Local \(\eta \)-structure for a three-site reduced state
#

For a three-site density operator \(\rho _{ABC}\), the local \(\eta \)-structure is the quantum Markov decomposition on the middle subsystem \(B\) produced by equality in strong subadditivity. Concretely, after a unitary change of basis on \(B\), one has a finite direct-sum decomposition

\begin{align} B & =\bigoplus _k(b_1^{(k)}\otimes b_2^{(k)}), \notag \\ \rho _{ABC} & =\bigoplus _k \rho _{A b_1}^{(k)}\otimes \rho _{b_2 C}^{(k)}. \notag \end{align}
Definition 26.10.2.2 Canonical projections of a Hayashi decomposition

Let \(B=\bigoplus _k(b_1^{(k)}\otimes b_2^{(k)})\) be the middle-site decomposition, and let \(E_k\) be the coordinate projection onto its \(k\)-th summand. In the original physical basis, define \(Q_k=U_B^*E_kU_B\). These are the projectors introduced in [ CPGSV16 , Appendix C.2, lines 1364–1368 ] ; the unitary implements the basis change described in [ CPGSV16 , Appendix C.2, lines 1437–1440 ] .

Each \(Q_k\) is an orthogonal projection, distinct summands are mutually orthogonal, and the family resolves the identity:

\begin{align} Q_kQ_\ell & =0 \quad \text{if } k\ne \ell , \notag \\ \sum _k Q_k& =\mathbb {1}. \notag \end{align}

The first two assertions follow from the orthogonal direct-sum decomposition in [ CPGSV16 , Appendix C.2, lines 1364–1368 ] ; the resolution of the identity is stated in [ CPGSV16 , Appendix C.2, lines 1693–1697 ] .

Proof

The coordinate projections satisfy

\begin{align} E_k^*& =E_k, \notag \\ E_k^2& =E_k, \notag \\ \sum _k E_k& =\mathbb {1}. \notag \end{align}

Reindexing the direct sum and conjugating by \(U_B\) preserve these identities. Hence each \(Q_k=U_B^*E_kU_B\) is a star projection and therefore an orthogonal projection, while \(\sum _k Q_k=U_B^*(\sum _kE_k)U_B=\mathbb {1}\). Finally, multiplying the resolution on both sides by \(Q_k\) gives

\begin{align} \sum _\ell Q_kQ_\ell Q_k& =Q_k, \notag \\ Q_kQ_\ell Q_k& =(Q_\ell Q_k)^*(Q_\ell Q_k)\geq 0. \notag \end{align}

The \(\ell =k\) term already equals \(Q_k\), so every term with \(\ell \ne k\) vanishes. Thus \((Q_\ell Q_k)^*(Q_\ell Q_k)=0\), hence \(Q_\ell Q_k=0\). Taking adjoints gives \(Q_kQ_\ell =0\) for \(\ell \ne k\).

Definition 26.10.2.4 Markov factors of a simultaneous inverse

Let \(C_x\) and \(C_y\) be two rows of a simultaneous left inverse, and choose a Hayashi decomposition of the three-site operator. In its \(k\)-th Markov sector, set

\begin{align} A_x^{(k)}(l,l’) & =\sum _{i_1,j_1} C_{x,(i_1,j_1)} \rho _{A b_1;(i_1,l),(j_1,l')}^{(k)}, \notag \\ B_y^{(k)}(r,r’) & =\sum _{i_3,j_3} C_{y,(i_3,j_3)} \rho _{b_2 C;(r,i_3),(r',j_3)}^{(k)}. \notag \end{align}

These are the two factors obtained in the projected contraction of  [ CPGSV16 , Appendix C.2, lines 1719–1725 ] .

Theorem 26.10.2.5 Outer inverse contraction in Markov coordinates

Let \(\Gamma _{x,y}\) denote the outer inverse contraction. In the basis of the chosen Hayashi decomposition,

\begin{align} {[U_B\Gamma _{x,y}U_B^\dagger ]}_{(k,l,r),(k',l',r')} & = \begin{cases} p_k A_x^{(k)}(l,l’)B_y^{(k)}(r,r’), & k=k’,\\ 0, & k\ne k’. \end{cases} \notag \end{align}

In particular, the probability \(p_k\) remains explicit. This identity requires neither a nonvanishing condition on \(p_k\) nor assumptions of saturated area law or zero correlation length.

Proof

Expand the two matrix products and the outer inverse contraction. The Hayashi block decomposition makes the middle-site contraction zero for \(k\ne k'\). For \(k=k'\), the remaining four outer sums separate into the product defining \(A_x^{(k)}\) and \(B_y^{(k)}\), with the common factor \(p_k\).

Theorem 26.10.2.6 Entrywise BNT–Markov identity

Let \(x=(s,\alpha _1,\beta _1)\) and \(y=(t,\alpha _3,\beta _3)\). Comparing the two expressions for the same outer inverse contraction gives

\begin{align} & \begin{cases} p_k A_x^{(k)}(l,l’)B_y^{(k)}(r,r’), & k=k’,\\ 0, & k\ne k’ \end{cases} \notag \\ & \quad = \begin{cases} {(R_s)}_{\beta _3,\alpha _1} [U_B\kappa ^{(s)}_{\beta _1,\alpha _3}U_B^\dagger ]_{(k,l,r),(k',l',r')}, & s=t,\\ 0, & s\ne t. \end{cases} \notag \end{align}

Here \(\kappa ^{(s)}_{\beta _1,\alpha _3}(i,j) ={(\mathcal K_s^{ij})}_{\beta _1,\alpha _3}\). Thus both the normal-sector and Markov-sector off-diagonal entries are retained in the statement, rather than being suppressed by a prior choice of equal labels. This is the full entrywise identity used in  [ CPGSV16 , Appendix C.2, lines 1719–1732 ] .

The closing entry \({(R_s)}_{\beta _3,\alpha _1}\) is the corrected tail-index orientation of the display at lines 1422–1438, recorded in docs/paper-gaps/cpgsv17_mpdo_sal_zcl_eta_local_structure.tex.

Proof

The preceding theorem identifies the left side with the transformed outer inverse contraction. The collapse theorem identifies the contraction with zero when \(s\ne t\) and with \({(R_s)}_{\beta _3,\alpha _1} \kappa ^{(s)}_{\beta _1,\alpha _3}\) when \(s=t\). Conjugating this matrix by \(U_B\) gives the right side.

Theorem 26.10.2.7 Off-diagonal Markov blocks of a BNT sector

Fix a normal sector \(s\) and virtual indices \(\alpha _1,\beta _3\) for which \({(R_s)}_{\beta _3,\alpha _1}\ne 0\). Then, for every \(\beta _1,\alpha _3\) and every pair of distinct Markov sectors \(k\ne k'\), one has

\begin{align} [U_B\kappa ^{(s)}_{\beta _1,\alpha _3}U_B^\dagger ]_{(k,l,r),(k',l',r')} & =0. \notag \end{align}

Thus each physical slice of the \(s\)-th normal tensor is block diagonal in the Markov decomposition. This is equation Qks in  [ CPGSV16 , Appendix C.2, lines 1682–1688 and 1730–1735 ] .

The nonzero closing entry uses the corrected orientation \({(R_s)}_{\beta _3,\alpha _1}\) recorded in docs/paper-gaps/cpgsv17_mpdo_sal_zcl_eta_local_structure.tex.

Proof

In the entrywise BNT–Markov identity, take equal normal-sector labels and distinct Markov-sector labels. The left side vanishes, while the right side is the selected closing entry times the displayed block. Cancel the nonzero closing entry.

Definition 26.10.2.8 Diagonal BNT block in a Markov sector

For a normal sector \(s\) and a Markov sector \(k\), let

\begin{align} O_s^{(k)}(\beta ,\alpha ) & = [U_B\kappa ^{(s)}_{\beta ,\alpha }U_B^\dagger ]_{k,k}. \notag \end{align}

The assertion \(O_s^{(k)}\ne 0\) means that this block is nonzero for at least one pair of virtual indices \(\beta ,\alpha \).

Theorem 26.10.2.9 Existence of a normal-sector label

If \(p_k\ne 0\), then there is a normal sector \(s\) for which \(O_s^{(k)}\ne 0\).

This is the existence part of equation QkKjs in [ CPGSV16 , Appendix C.2, lines 1733–1737 ] . Restricting to \(p_k\ne 0\) is the literal version of the source’s preceding removal of summands for which \(Q_k\sigma _3^{(N)}Q_k=0\).

Proof

Choose nonzero diagonal entries of the trace-one left and right states in sector \(k\). The corresponding diagonal entry of the Hayashi decomposition is nonzero because \(p_k\ne 0\). Expanding the same entry by the three-site normal-sector family therefore leaves at least one nonzero summand, whose middle tensor has \(O_s^{(k)}\ne 0\).

Suppose, in addition, that every closing matrix \(R_s\) is nonzero. If \(p_k\ne 0\), there is a unique normal sector \(j_k\) for which \(O_{j_k}^{(k)}\ne 0\).

This is the cancellation argument in equation QkKjs. The stated nonzero-closing-matrix condition isolates the step obtained in the source from simplicity and the common-weight choice at [ CPGSV16 , Appendix C.2, lines 1714–1718 ] . Its derivation from those preceding hypotheses is Theorem 26.10.1.11.

Proof

Assume that sectors \(s\ne t\) both have nonzero \(k\)-blocks. A diagonal instance of the BNT–Markov identity for \(s\) gives a nonzero left factor. A mixed instance with normal-sector labels \(s,t\) forces the right factor selected from \(t\) to vanish. A diagonal instance for \(t\) then has zero left-hand side and a nonzero right-hand side, a contradiction.

Definition 26.10.2.11 Normal-sector projections on the active support

Under the hypotheses of Theorem 26.10.2.10, define

\begin{align} P_s & =\sum _{\substack {k:p_k\ne 0\\ \begin{bgroup} j_k=s \end{bgroup}}}Q_k, \notag \\ P_{\mathrm{act}} & =\sum _{k:p_k\ne 0}Q_k. \notag \end{align}

This is equation Pis, restricted to the positive-weight Markov support retained here.

Theorem 26.10.2.12 Orthogonality and resolution on the active support

Every \(P_s\) is an orthogonal projection, distinct \(P_s\) are mutually orthogonal, and \(\sum _s P_s=P_{\mathrm{act}}\).

Proof

Each \(P_s\) is a sum of mutually orthogonal Markov-sector projections. Distinct labels have disjoint sums. Finally, summing over \(s\) counts each positive-weight Markov sector exactly once.

Let \(1\leq m\leq \lfloor N/2\rfloor \), and divide the chain into four consecutive regions \(A,B,C,D\) of lengths \(m-1,1,N-m-1,1\). If the tensor saturates the area law, then its marginal on \(ABC\) satisfies \(S(ABC)+S(B)=S(AB)+S(BC)\). Indeed, this is the entropy form of \(I_1=I_m\). Taking \(m=2\) gives the regions of lengths \(1,1,N-3\), and then taking \(N=4\) shows that the three-site reduced state of the four-site chain satisfies equality in strong subadditivity.

Conversely, suppose the tensor generates positive semidefinite periodic operators and their traces are nonzero at every positive chain length. If the displayed equality holds for every \(N\) and every \(1\leq m\leq \lfloor N/2\rfloor \), then the tensor saturates the area law. This is the choice of regions used in [ CPGSV16 , Appendix C.2, lines 1760–1780 ] . The endpoint corrects the strict inequality printed at source line 1771: Definition 4.6 and the concluding comparison both require \(m=\lfloor N/2\rfloor \). This local correction is recorded in docs/paper-gaps/cpgsv17_mpdo_sal_zcl_eta_local_structure.tex.

Proof

By saturation, \(I_1=I_m\). Expanding the two mutual informations and cancelling the entropy of the full chain gives \(S_{N-1}+S_1=S_m+S_{N-m}\), which is the stated equality for the regions \(A,B,C\). Conversely, this equality gives \(I_1=I_m\). If it holds for every admissible \(m\), comparing the cases \(m=L\) and \(m=L+1\) gives \(I_L=I_{L+1}\) and hence saturation of the area law.

Theorem 26.10.2.14 All-cut quantum Markov structure implies SAL

Suppose that the periodic operators are positive semidefinite and have nonzero trace at every positive chain length. For every \(N\) and every \(1\leq m\leq \lfloor N/2\rfloor \), divide the chain into four consecutive regions of lengths \(m-1,1,N-m-1,1\). If the marginal on the first three regions admits a quantum Markov decomposition on its one-site middle system, then the tensor saturates the area law.

Proof

The quantum Markov decomposition gives equality in strong subadditivity at every admissible cut: \(S(\rho _{ABC})+S(\rho _B)=S(\rho _{AB})+S(\rho _{BC})\). These equalities at every admissible cut imply saturation of the area law by Theorem 26.10.2.13.

Theorem 26.10.2.15 SAL implies local \(\eta \)-structure

If a normalized three-site reduced state satisfies the equality case of strong subadditivity — the local entropy form of the simple-MPDO strong area law — then it admits the local \(\eta \)-structure of Definition 26.10.2.1.

Proof

This is the forward implication of the Hayashi equality characterization. The product-reference raw Petz formula, including its singular-support compression, is given by Theorem 21.2.49. The singular-support equality-to-recovery theorem is still separate. Beyond it, the remaining structural ingredient is the family-level Koashi–Imoto decomposition and the induced action of the middle-system channel on its common direct-sum factors.

Lemma 26.10.2.16 Partial trace along a right tensor factor

Suppose that \(C\simeq C'\otimes E\). The partial trace over \(E\) is given entrywise by

\begin{align} (\operatorname{tr}_E X)_{(a,c'),(a',d')} & =\sum _e X_{(a,c',e),(a',d',e)}. \notag \end{align}

It preserves positivity and trace.

Proof

Reindex \(C\) as \(C'\otimes E\) and apply the ordinary right partial trace. Its entry formula gives the displayed sum. Positivity follows by tracing a positive matrix, and invariance of the full trace under reindexing gives trace preservation.

Theorem 26.10.2.17 Right marginals preserve a quantum Markov decomposition

Suppose that \(C\simeq C'\otimes E\) and

\begin{align} \rho _{ABC} & =\bigoplus _k p_k\rho _{A b_1}^{(k)} \otimes \rho _{b_2 C}^{(k)} \notag \end{align}

is a quantum Markov decomposition on \(B\). Then the marginal \(\rho _{ABC'}=\operatorname{tr}_E(\rho _{ABC})\) has the decomposition

\begin{align} \rho _{ABC'} & =\bigoplus _k p_k\rho _{A b_1}^{(k)} \otimes \operatorname{tr}_E\! \left(\rho _{b_2 C}^{(k)}\right). \notag \end{align}
Proof

The middle-system decomposition, its unitary change of basis, and the probabilities \(p_k\) are unchanged. Partial trace preserves positivity and trace, so each \(\operatorname{tr}_E(\rho _{b_2 C}^{(k)})\) is a density operator. Applying \(\operatorname{tr}_E\) to the block-diagonal identity gives the displayed formula.

Lemma 26.10.2.18 Tracing a terminal block

Let \(a,b,c,N\in \mathbb N\) satisfy \(a+b+c\leq N\). For configurations \(u,v\) on the first \(a+b\) sites,

\begin{align} \sum _y \sigma _{a+b+c}^{(N)}(K)_{u\mathbin \Vert y,\, v\mathbin \Vert y} & =\sigma _{a+b}^{(N)}(K)_{u,v}, \notag \end{align}

where the sum ranges over configurations on the last \(c\) sites. The same identity holds after replacing an arithmetically equal block length by its canonical identification.

Proof

Expand both reduced states as partial traces of the normalized periodic state. The left-hand side first traces the complement of the \((a+b+c)\)-site block and then its last \(c\) sites; combining the two sums gives the partial trace onto the first \(a+b\) sites.

Let \(K\) satisfy the strong area law and let \(N\geq 4\). If \(\sigma _3^{(N)}(K)\) is obtained from the normalized \(N\)-site periodic state by tracing out all but its first three sites, then \(\sigma _3^{(N)}(K)\) admits a quantum Markov decomposition on its middle site. This is the three-site marginal result proved in [ CPGSV16 , Appendix C.2, lines 1351–1371 ] . The decomposition may depend on \(N\).

Proof

Divide the first \(N-1\) sites into consecutive regions of lengths \(1\), \(1\), and \(N-3\). Let \(\rho ^{\mathrm{flat}}_{ABC}\) denote this marginal in the corresponding index set \(\{ 0,\ldots ,d^1{-}1\} \times \{ 0,\ldots ,d^1{-}1\} \times \{ 0,\ldots ,d^{N-3}{-}1\} \). By Theorem 26.10.2.13,

\begin{align} S(\rho ^{\mathrm{flat}}_{ABC})+S(\rho ^{\mathrm{flat}}_B) & =S(\rho ^{\mathrm{flat}}_{AB})+S(\rho ^{\mathrm{flat}}_{BC}). \notag \end{align}

The first two singleton blocks have the canonical identification \(e_{\mathrm{site}}:\{ 0,\ldots ,d{-}1\} \simeq \{ 0,\ldots ,d^1{-}1\} \), and reindexing these factors preserves the displayed equality. Positivity and unit trace follow from the normalized reduced state, so the Hayashi characterization gives a quantum Markov decomposition of the \((N-1)\)-site marginal. Finally split the third region as \(C\simeq c\otimes E\), where \(c\) is its first site and \(E\) contains the remaining \(N-4\) sites. Theorem 26.10.2.17 gives the same middle-site direct sum after tracing out \(E\). The contiguous-block reduction gives

\begin{align} \sigma _3^{(N)}(K) & =\operatorname{tr}_{4,\ldots ,N-1} \left[\sigma _{N-1}^{(N)}(K)\right], \notag \end{align}

which identifies the resulting operator with \(\sigma _3^{(N)}(K)\).

Theorem 26.10.2.20 Four-site SAL marginals have Hayashi decompositions

Let \(K\) satisfy the strong area law. If \(\sigma _3^{(4)}(K)\) is obtained from its normalized four-site periodic state by tracing out the fourth site, then \(\sigma _3^{(4)}(K)\) admits a quantum Markov decomposition on its middle site.

Proof

This is the case \(N=4\) of Theorem 26.10.2.19.

Suppose that the common blocking has been performed, so that the BNT representatives have a simultaneous one-letter span. For the normalized three-site marginal \(\sigma _3^{(4)}\), there are a simultaneous inverse \(C\) and a Hayashi decomposition such that every Markov sector \(k\) with \(p_k\ne 0\) has a unique BNT label \(j_k\). Consequently,

\begin{align} P_s & =\sum _{\substack {k:p_k\ne 0\\ \begin{bgroup} j_k=s \end{bgroup}}}Q_k. \notag \end{align}

Each \(P_s\) is an orthogonal projection, \(P_sP_t=0\) for \(s\ne t\), and \(\sum _sP_s=P_{\mathrm{act}}\). No independent nonzero-closing-matrix hypothesis is required. This is the four-site specialization of equations QkKjs and Pis in [ CPGSV16 , Appendix C.2, lines 1714–1737 ] . The Hayashi decomposition uses the forward equality characterization of strong subadditivity recorded in Theorem 21.4.40; no additional analytic assumption is introduced here.

Proof

The canonical ordered-triple reindexing is the submatrix convention of the SAL-to-Hayashi theorem. Choose the simultaneous inverse from the one-letter span and the Hayashi decomposition from SAL. By Theorem 26.10.1.11, the same marginal is a BNT family closure whose closing matrices are all nonzero. The generic uniqueness and projector theorems now give the unique labels, orthogonality, mutual disjointness, and resolution of the active support.

Definition 26.10.2.22 Sitewise physical action and absorbed BNT representatives

For a one-site matrix \(V\), write \(V^{\otimes N}\) in the configuration basis as

\begin{align} (V^{\otimes N})_{s,t} & =\prod _{n=1}^{N}V_{s_n,t_n}. \notag \end{align}

If the copies of the \(j\)-th normal tensor have common coefficient \(\mu _j\), let \(\mathcal K_j=\mu _j A_j\) denote the representative with this coefficient absorbed into its local tensor.

Under the hypotheses of Theorem 26.10.2.21, the resulting projectors satisfy \(P_sA_iP_t=0\) whenever \(s\ne t\) or \(i\ne s\). For the matching label, they satisfy \(P_iA_iP_i=A_i\). Consequently, \(\sum _sP_sA_iP_s=A_i\), which is the local diagonal decomposition required for the sector entropy argument. Equivalently, compressing the physical legs of \(A_i\) by \(P_s\) retains \(A_i\) for \(s=i\) and gives the zero local tensor otherwise. This is the local projection relation in [ CPGSV16 , Appendix C.2, lines 1680–1755 ] .

The Markov summands of zero Hayashi weight are retained in the ambient decomposition. They annihilate every normal-sector physical slice, so the displayed local identities do not require the stronger assertion \(\sum _sP_s=\mathbb {1}\) outside the active support.

Proof

Distinct Hayashi sectors give zero off-diagonal corners. On an active diagonal sector, uniqueness of the BNT label kills every normal tensor except the matching one. A zero-weight diagonal sector also kills every physical slice: otherwise the nonzero closing matrix would make the corresponding three-site Markov block nonzero. Summing these statements over the Hayashi sectors gives the asserted \(P_sA_iP_t\) identities.

Definition 26.10.2.24 Completion on the zero-weight Markov sectors

Fix a BNT label \(s_0\). Each positive-weight Markov sector retains its unique BNT label, while every zero-weight Markov sector is assigned the label \(s_0\). If \(\widehat S_s\) is the set of Markov sectors with completed label \(s\), define

\begin{align} \widehat P_s & =\sum _{k\in \widehat S_s}Q_k. \notag \end{align}

Let \(K\) be simple, in biCF, and satisfy SAL. Assume in addition that the common blocking has been performed, the copy weights over each BNT representative agree, and the representatives have a simultaneous one-site span. There is a distinguished BNT label \(s_0\) such that the completed projectors are orthogonal and, for distinct labels \(s\) and \(t\),

\begin{align} \widehat P_s\widehat P_t& =0, \notag \\ \sum _s\widehat P_s& =\mathbb {1}. \notag \end{align}

For every physical slice of the \(i\)-th BNT representative, whenever \(s\ne t\) or \(i\ne s\),

\begin{align} \widehat P_sK_i^{\beta \alpha }\widehat P_t& =0. \notag \end{align}

This is the copy-independent-weight specialization of the separating-projector lemma in [ CPGSV16 , Appendix C.2, lines 1680–1737 ] .

Proof

A unit-modulus BNT weight supplies the label \(s_0\). The Markov-sector projections \(Q_k\) are mutually orthogonal and sum to the identity, so partitioning all labels by \(\widehat S_s\) proves orthogonality and the identity resolution. If \(p_k=0\), then \(Q_kK_i^{\beta \alpha }Q_k=0\) for every \(i,\beta ,\alpha \). If \(p_k\ne 0\), then \(Q_kK_i^{\beta \alpha }Q_k=0\) whenever the BNT label of sector \(k\) is not \(i\). For distinct Markov sectors, \(Q_kK_i^{\beta \alpha }Q_l=0\) whenever \(k\ne l\). Hence, whenever \(s\ne t\) or \(i\ne s\),

\begin{align} \widehat P_sK_i^{\beta \alpha }\widehat P_t & =\sum _{k\in \widehat S_s}\sum _{l\in \widehat S_t} Q_kK_i^{\beta \alpha }Q_l =0, \notag \end{align}

since every summand vanishes by one of the three preceding cases.

Theorem 26.10.2.26 Separating projectors for a simple tensor satisfying ZCL and SAL

Let \(K\) be a simple tensor in block-injective canonical form which satisfies ZCL and SAL. For the representatives \(\mathcal K_i\) of its BNT, there are orthogonal projectors \(P_s\) such that

\begin{align} \sum _sP_s& =\mathbb {1}, \notag \\ P_sK_i^{\beta \alpha }P_t& =0 \quad \text{whenever }s\ne t\text{ or }i\ne s. \notag \end{align}

This is the separating-projector lemma in [ CPGSV16 , Appendix C.2, lines 1626–1691 ] .

Proof

Write the horizontal canonical form as \(K=G(\bigoplus _{j,q}\mu _{j,q}\mathcal K_j)G^{-1}\). Restricting the ZCL equation to the \((j,q)\)-th block and using the non-nilpotence supplied by simplicity gives \(\mu _{j,q}=\mu _{j,q'}\) for all \(j,q,q'\). The block-diagonal gauge preserves every positive-length periodic state, so the canonical-form tensor and \(K\) generate the same such states. The preceding copy-independent-weight theorem now supplies the projectors.

For every nonempty periodic chain and every normal-sector label \(s\),

\begin{align} P_s^{\otimes N} \sigma ^{(N)}(K)\, P_s^{\otimes N} & =n_s\, \sigma ^{(N)}(\mathcal K_s), \qquad N\geq 1. \label{eq:rfp_positive_compression} \end{align}

This is equation sigmaNKj in [ CPGSV16 , Appendix C.2, lines 1756–1759 ] .

Here and throughout the MPDO discussion, a periodic chain has positive length.

Proof

Sitewise multiplication by \(P_s\) is the periodic MPO obtained by changing every local physical matrix by \(P_s\). The preceding theorem replaces each normal representative by itself when its label is \(s\) and by the zero tensor otherwise. For \(N\geq 1\), the latter has zero periodic MPO. The surviving coefficient is \(n_s\mu _s^N\), which is precisely \(n_s\) times the MPO of the representative with \(\mu _s\) absorbed locally.

Under the hypotheses of Theorem 26.10.2.27, every absorbed BNT element \(\mathcal K_s\) generates positive semidefinite operators on all nonempty periodic chains. Indeed, \(P_s^{\otimes N}\sigma ^{(N)}(K)P_s^{\otimes N}\geq 0\) and \(n_s{\gt}0\), so (??) gives \(\sigma ^{(N)}(\mathcal K_s)\geq 0\). This is the first positivity conclusion in  [ CPGSV16 , Appendix C.2, lines 1753–1759 ] .

Proof

Congruence by the Hermitian projection \(P_s^{\otimes N}\) preserves positive semidefiniteness. Multiplication by the inverse of the positive integer \(n_s\) then gives positivity of the sector operator.

Theorem 26.10.2.29 Zero correlation length of the absorbed BNT elements

Let \(K\) have zero correlation length and let \(\mathcal K_s=\mu _sA_s\) be an absorbed BNT element of its horizontal canonical form. If the physical-trace transfer \(\mathcal B_s\) is not nilpotent, then \(\mathcal K_s\) has zero correlation length. More precisely,

\begin{align} \mathcal T_{\mathcal K_s} & =\mu _s\mathcal B_s\ne 0, \notag \\ \mathcal T_{\mathcal K_s}^{2} & =\lambda \mathcal T_{\mathcal K_s}, \qquad \lambda {\gt}0. \notag \end{align}

This is the final zero-correlation-length conclusion in [ CPGSV16 , Appendix C.2, line 1781 ] .

Proof

Lemma 26.10.1.1 gives the displayed quadratic identity. The common weight is nonzero, and nonnilpotence of \(\mathcal B_s\) implies \(\mathcal B_s\ne 0\), so the absorbed transfer is nonzero.

Let \(M\) generate matrix product density operators and have source zero correlation length. Then, for every \(N\geq 1\), \(\operatorname{tr}(\sigma ^{(N)}(M)){\gt}0\). In particular, after a common blocking has made the simultaneous BNT word span full at one letter, the absorbed BNT elements selected in Theorem 26.10.2.29 have a well-defined normalized state at every physical chain length. This is the biCF hypothesis imposed at the start of Case II in the source; its relation with finite physical blocking is recorded in docs/paper-gaps/cpgsv17_bicf_block_separation.tex. This supplies the strict form of the sector normalization used in [ CPGSV16 , Appendix C.2, lines 1760–1780 ] .

Proof

Write the physical-trace transfer as \(\mathcal T_M=\lambda E\), where \(\lambda {\gt}0\) and \(E\) is a nonzero idempotent. A nonzero idempotent on a finite-dimensional complex vector space has nonzero trace, while \(E^N=E\) for \(N\geq 1\). Hence

\begin{align} \operatorname{tr}(\sigma ^{(N)}(M)) & =\operatorname{tr}(\mathcal T_M^N) =\lambda ^N\operatorname{tr}(E) \ne 0. \notag \end{align}

Positivity of the density operator then makes this trace strictly positive.

Let \(K\) saturate the area law and have zero correlation length, and let its horizontal BNT canonical form, up to block-diagonal gauge, have normal representatives \(A_s\), common copy weights \(\mu _s\), and copy numbers \(n_s\). Assume that the physical-trace transfer of every \(A_s\) is nonnilpotent. After a common blocking, assume explicitly that the simultaneous one-letter word tuples of the \(A_s\) span the direct sum of their full matrix algebras. Put \(\mathcal K_s=\mu _sA_s\).

For every nonempty chain, define

\begin{align} p_s^{(N)} & = \frac{n_s\, \operatorname{tr}\! \left(\sigma ^{(N)}(\mathcal K_s)\right)}{\operatorname{tr}\! \left(\sigma ^{(N)}(K)\right)}. \notag \end{align}

Then \(p_s^{(N)}{\gt}0\), and every nonempty prefix marginal has the same sector decomposition with these probabilities. Translation invariance identifies the other contiguous blocks of the same length. Consequently, every absorbed representative \(\mathcal K_s\) saturates the area law.

The one-letter simultaneous span is the block-injective canonical-form hypothesis imposed at the start of Case II in [ CPGSV16 , line 1628 ] . Its relation with finite physical blocking is recorded in docs/paper-gaps/cpgsv17_bicf_block_separation.tex. The entropy conclusion is the argument of [ CPGSV16 , Appendix C.2, lines 1748–1781 ] .

Proof

The BNT projections carry every normalized marginal on mutually annihilating supports, so the preceding support form of entropy additivity gives

\begin{align} S_L(K) & =H\! \left(p^{(N)}\right) +\sum _s p_s^{(N)}S_L(\mathcal K_s), \qquad 1\leq L\leq N. \notag \end{align}

The four marginals entering strong subadditivity have the same probabilities. Substitution in the equality for \(K\) cancels all four Shannon terms. Strong subadditivity gives the corresponding inequality in each sector, and strict positivity of every \(p_s^{(N)}\) forces every such inequality to be an equality. Comparing the equalities for block lengths \(L\) and \(L+1\) proves saturation for \(\mathcal K_s\).

Definition 26.10.2.32 Injective inverse map for a simple MPO tensor

A simple MPO tensor \(K\) is called injective if its doubled-index MPS tensor is injective. For such a tensor, the chosen decomposition map of the doubled-index MPS furnishes a concrete inverse tensor \(K^{-1}\) together with right- and left-physical realization maps that turn virtual bond insertions back into local physical operators.

Theorem 26.10.2.33 Inverse-map identities for an injective simple MPO tensor

For an injective simple MPO tensor, contracting \(K^{-1}\) with \(K\) recovers the matrix units on the virtual bond space. Likewise, every right virtual insertion admits a physical realization, this realization is multiplicative, and the analogous left-insertion statement also holds.

For an injective simple tensor, contracting \(K^{-1}\) with \(K\) through the physical index identifies the corresponding virtual legs. In components, this is the matrix-unit identity

\begin{align} \sum _p(K^{-1})^{\alpha ,\beta }_p(K^p)_{\alpha ',\beta '} & =\delta _{\alpha ,\alpha '}\delta _{\beta ,\beta '}. \label{eq:rfp_inverse_matrix_units} \end{align}

Its two Kronecker factors are the two bare cups:

\begin{tenkz}[rows={ket, bra}, tensor style=box]
        \tn{K^{-1}} \\
        \tn{K}
    \end{tenkz} \( = \) \begin{tenkz}[rows={wire, wire}, east=cup]
        \tnghost{} \\
        \tnghost{}
    \end{tenkz} \( \otimes \) \begin{tenkz}[rows={wire, wire}, west=cup]
        \tnghost{} \\
        \tnghost{}
    \end{tenkz}

This is the identity in [ CPGSV16 , Appendix C.2, lines 1376–1380 ] .

Applying this inverse map to the doubled physical index and closing its virtual legs against a further copy of \(K\) recovers \(K\):

\begin{tenkz}[
            rows={ket:nopair, ket, bra},
            west=cup,
            east=cup,
            tensor style=box]
        \tn[up=p]{K} \\
        \tn{K^{-1}} \\
        \tn{K}
    \end{tenkz} \( = \) \begin{tenkz}[physical=up, tensor style=box]
        \tn[up=p]{K}
    \end{tenkz}

This is the single-block identity in [ CPGSV16 , Appendix C.2, lines 1671–1676 ] .

Definition 26.10.2.34 Normalized fourth-site virtual tail

Let \(\mathcal K\) be an MPO tensor and set \(Z_4=\operatorname{tr}[\rho ^{(4)}(\mathcal K)]\). Its normalized fourth-site virtual tail is

\begin{align} R_4 & :=Z_4^{-1}\mathcal T_{\mathcal K} =\operatorname{tr}[\rho ^{(4)}(\mathcal K)]^{-1} \sum _{i_4=0}^{d-1}\mathcal K^{i_4i_4}. \label{eq:rfp_normalized_tail} \end{align}

Thus the contraction of the fourth ket and bra indices is incorporated into the virtual closing matrix. This is the \(N=4\) specialization of the normalization convention and three-site marginal in [ CPGSV16 , lines 792–793 and 1343–1348 ] .

Theorem 26.10.2.35 Three-site marginal closed by the normalized fourth-site tail

Let \(u=(i_1,i_2,i_3)\) and \(v=(j_1,j_2,j_3)\) be physical words of length three. The corresponding entry of the first-three-site marginal of the normalized four-site periodic operator is

\begin{align} \sigma _3^{(4)}(\mathcal K)_{u,v} & =\operatorname{tr}\! \left(\mathcal K^{u,v}R_4\right) =\operatorname{tr}\! \left(\mathcal K^{i_1j_1}\mathcal K^{i_2j_2} \mathcal K^{i_3j_3}R_4\right). \label{eq:rfp_three_site_marginal} \end{align}
\begin{tenkz}[physical=updown, periodic]
        \tn[up=$i_1$, down=$j_1$]{\mathcal K} &
        \tn[up=$i_2$, down=$j_2$]{\mathcal K} &
        \tn[up=$i_3$, down=$j_3$]{\mathcal K} &
        \tnX{R_4}
    \end{tenkz}
Figure 26.1 Tracing the fourth site of the normalized four-site periodic MPO leaves the physical legs of sites \(1,2,3\) open and replaces the fourth site by the virtual closing operator \(R_4=\operatorname{tr}[\rho ^{(4)}(\mathcal K)]^{-1} \sum _{i_4}\mathcal K^{i_4 i_4}\); compare the normalization convention and three-site marginal in [ CPGSV16 , lines 792–793 and 1343–1348 ] .
Proof

Expanding the partial trace over the fourth site and factoring each length-four word at its last letter gives

\begin{align} \sigma _3^{(4)}(\mathcal K)_{u,v} & =Z_4^{-1}\sum _{i_4=0}^{d-1} \operatorname{tr}\! \left(\mathcal K^{u,v}\mathcal K^{i_4i_4}\right). \notag \end{align}

Linearity of the trace and (??) now yield

\begin{align} Z_4^{-1}\sum _{i_4=0}^{d-1} \operatorname{tr}\! \left(\mathcal K^{u,v}\mathcal K^{i_4i_4}\right) & =\operatorname{tr}\! \left(\mathcal K^{u,v} \left(Z_4^{-1}\sum _{i_4=0}^{d-1}\mathcal K^{i_4i_4}\right)\right) =\operatorname{tr}\! \left(\mathcal K^{u,v}R_4\right). \notag \end{align}
Theorem 26.10.2.36 Non-vanishing of the normalized fourth-site tail

If \(Z_4=\operatorname{tr}[\rho ^{(4)}(\mathcal K)]\ne 0\), then \(R_4\ne 0\).

Proof

If \(R_4=0\), then the tail formula makes every entry of \(\sigma _3^{(4)}(\mathcal K)\) vanish, so \(\operatorname{tr}[\sigma _3^{(4)}(\mathcal K)]=0\). On the other hand, \(Z_4\ne 0\) implies \(\operatorname{tr}[\sigma _3^{(4)}(\mathcal K)]=1\), a contradiction.

Theorem 26.10.2.37 A nonzero entry of the normalized fourth-site tail

If \(Z_4\ne 0\), there exist virtual indices \(\beta \) and \(\alpha \) such that \((R_4)_{\beta ,\alpha }\ne 0\). These are the indices selected before the sector factorization in [ CPGSV16 , Appendix C.2, lines 1431–1437 ] .

Proof

If every matrix entry of \(R_4\) vanished, then \(R_4\) would be the zero matrix, contrary to the preceding theorem.

Definition 26.10.2.38 Three-site inverse-map contraction

Let \(\mathcal K\) be an injective simple MPO tensor, and let \(R\in M_{D}(\mathbb {C})\) be the virtual contraction of the sites following a three-site word. For virtual indices \(\alpha _1,\beta _1,\alpha _3,\beta _3\), define

\begin{align} C_{\alpha _1,\beta _1,\alpha _3,\beta _3}(p_2;R) & := \sum _{p_1,p_3} (\mathcal K^{-1})^{\alpha _1,\beta _1}_{p_1} (\mathcal K^{-1})^{\alpha _3,\beta _3}_{p_3} \operatorname{tr}\! \left(\mathcal K^{p_1}\mathcal K^{p_2}\mathcal K^{p_3}R\right). \label{eq:rfp_inverse_contraction} \end{align}

This is the contraction used in the proof of [ CPGSV16 , Appendix C.2, lines 1415–1438 ] .

Theorem 26.10.2.39 Evaluation of the three-site inverse-map contraction

For every middle physical index \(p_2\),

\begin{align} C_{\alpha _1,\beta _1,\alpha _3,\beta _3}(p_2;R) & =\mathcal K^{p_2}_{\beta _1,\alpha _3} R_{\beta _3,\alpha _1}. \label{eq:rfp_inverse_contraction_eval} \end{align}
\(\Bigl(\) \begin{tenkz}[compact, physical=down,
                          west label=$\alpha_1$, east label=$\beta_1$]
                \tn[down=$p_1$]{\mathcal K^{-1}}
            \end{tenkz}\(\; \otimes \; \mathbb {1}\; \otimes \; \)\begin{tenkz}[compact, physical=down,
                          west label=$\alpha_3$, east label=$\beta_3$]
                \tn[down=$p_3$]{\mathcal K^{-1}}
            \end{tenkz} \(\Bigr)\) \begin{tenkz}[compact, physical=up, periodic]
                \tn[up=$p_1$]{\mathcal K} &
                \tn[up=$p_2$]{\mathcal K} &
                \tn[up=$p_3$]{\mathcal K} &
                \tnX{R}
            \end{tenkz} \( = \) \begin{tenkz}[compact, physical=up,
                          west label=$\beta_1$, east label=$\alpha_3$]
                \tn[up=$p_2$]{\mathcal K}
            \end{tenkz} \( \otimes \) \begin{tenkz}[compact,
                          west label=$\beta_3$, east label=$\alpha_1$]
                \tnX{R}
            \end{tenkz}
Figure 26.2 Applying \(\mathcal K^{-1}\) at the first and third sites collapses the three-site contraction to \(\mathcal K^{p_2}_{\beta _1,\alpha _3}R_{\beta _3,\alpha _1}\), where \(p_2=(i_2,j_2)\) is the doubled physical index; compare [ CPGSV16 , Appendix C.2, lines 1415–1438 ] .
Proof

Move the two finite sums through the trace. By the inverse-map identity

\begin{align} \sum _p(\mathcal K^{-1})^{\alpha ,\beta }_p\, \mathcal K^p & =E_{\alpha ,\beta }, \notag \end{align}

which is the matrix form of (??), the double sum collapses to

\begin{align} \operatorname{tr}\! \left(E_{\alpha _1,\beta _1}\mathcal K^{p_2} E_{\alpha _3,\beta _3}R\right) & =\mathcal K^{p_2}_{\beta _1,\alpha _3} R_{\beta _3,\alpha _1}. \notag \end{align}
Definition 26.10.2.40 Three-site closure against a virtual tail
#

Let \(\mathcal K\) be an MPO tensor and let \(R\in M_{D}(\mathbb {C})\). A tripartite operator \(\rho \) is the three-site closure of \(\mathcal K\) against \(R\) if

\begin{align} \rho _{i_1i_2i_3,j_1j_2j_3} & =\operatorname{tr}\! \left(\mathcal K^{i_1j_1}\mathcal K^{i_2j_2} \mathcal K^{i_3j_3}R\right). \label{eq:rfp_three_site_closure} \end{align}

This is the algebraic form of the three-site reduced operator in [ CPGSV16 , Appendix C.2, lines 1422–1433 ] .

Definition 26.10.2.41 Physical slice and Hayashi inverse factors

Fix virtual indices \(\beta ,\alpha \) and set \(\kappa _{\beta ,\alpha }(i,j)=\mathcal K^{ij}_{\beta ,\alpha }\). For a Hayashi sector \(k\), define the two inverse factors

\begin{align} A^{(k)}_{\alpha _1,\beta _1}(l,l’) & := \sum _{i_1,j_1} (\mathcal K^{-1})^{\alpha _1,\beta _1}_{(i_1,j_1)} (\rho _{A b_1}^{(k)})_{(i_1,l),(j_1,l')}, \notag \\ B^{(k)}_{\alpha _3,\beta _3}(r,r’) & := \sum _{i_3,j_3} (\mathcal K^{-1})^{\alpha _3,\beta _3}_{(i_3,j_3)} (\rho _{b_2 C}^{(k)})_{(r,i_3),(r',j_3)}. \notag \end{align}

These are the two factors in the sectorwise inverse-map calculation of [ CPGSV16 , Appendix C.2, lines 1407–1428 ] .

Let \(\mathcal K\) be injective and let \(\rho \) be its three-site closure against \(R\). Applying the inverse tensor at the two outer sites collapses the closure to one entry of the middle physical slice and one entry of the tail:

\begin{align} & \sum _{i_1,j_1,i_3,j_3} (\mathcal K^{-1})^{\alpha _1,\beta _1}_{(i_1,j_1)} (\mathcal K^{-1})^{\alpha _3,\beta _3}_{(i_3,j_3)} \rho _{i_1i_2i_3,j_1j_2j_3} \notag \\ & \qquad =\mathcal K^{i_2j_2}_{\beta _1,\alpha _3} R_{\beta _3,\alpha _1}. \label{eq:rfp_outer_collapse} \end{align}

Consequently, for any matrix \(U\) on the middle site,

\begin{align} & R_{\beta _3,\alpha _1} (U\kappa _{\beta _1,\alpha _3}U^\dagger )_{b,b'} \notag \\ & \qquad =\sum _{i_1,j_1,i_3,j_3} (\mathcal K^{-1})^{\alpha _1,\beta _1}_{(i_1,j_1)} (\mathcal K^{-1})^{\alpha _3,\beta _3}_{(i_3,j_3)} \sum _{i_2,j_2} U_{b,i_2} \rho _{i_1i_2i_3,j_1j_2j_3} \overline{U_{b',j_2}}. \label{eq:rfp_conjugated_slice} \end{align}
Proof

Substituting the three-site closure relation  (??) converts the left-hand side of (??) to \(C_{\alpha _1,\beta _1,\alpha _3,\beta _3}((i_2,j_2);R)\). Theorem 26.10.2.39 then gives

\begin{align} C_{\alpha _1,\beta _1,\alpha _3,\beta _3}((i_2,j_2);R) & =\mathcal K^{i_2j_2}_{\beta _1,\alpha _3} R_{\beta _3,\alpha _1}, \notag \end{align}

which is (??). The second identity follows by expanding the matrix product entrywise,

\begin{align} (U\kappa _{\beta _1,\alpha _3}U^\dagger )_{b,b'} & =\sum _{i_2,j_2} U_{b,i_2} \kappa _{\beta _1,\alpha _3}(i_2,j_2) \overline{U_{b',j_2}}, \notag \end{align}

multiplying by \(R_{\beta _3,\alpha _1}\), substituting

\begin{align} R_{\beta _3,\alpha _1} \kappa _{\beta _1,\alpha _3}(i_2,j_2) & =\sum _{i_1,j_1,i_3,j_3} (\mathcal K^{-1})^{\alpha _1,\beta _1}_{(i_1,j_1)} (\mathcal K^{-1})^{\alpha _3,\beta _3}_{(i_3,j_3)} \rho _{i_1i_2i_3,j_1j_2j_3}, \notag \end{align}

and reordering the finite sums.

Theorem 26.10.2.43 Sectorwise inverse-map comparison

Suppose that \(\mathcal K\) is injective, \(\rho \) is its three-site closure against \(R\), and a Hayashi decomposition of \(\rho \) has been chosen. Write

\begin{align} \widetilde\kappa ^{(k)}_{\beta _1,\alpha _3} ((l,r),(l’,r’)) & := \left[U_B\kappa _{\beta _1,\alpha _3}U_B^\dagger \right]_{(k,l,r),(k,l',r')}. \notag \end{align}

Then every diagonal sector satisfies

\begin{align} R_{\beta _3,\alpha _1} \widetilde\kappa ^{(k)}_{\beta _1,\alpha _3} ((l,r),(l’,r’)) & =p_k A^{(k)}_{\alpha _1,\beta _1}(l,l’) B^{(k)}_{\alpha _3,\beta _3}(r,r’). \label{eq:rfp_sector_comparison} \end{align}

The probability \(p_k\) remains explicit because both sector density operators are normalized. No zero-correlation-length or non-vanishing hypothesis is used in this comparison.

For fixed \(k,\alpha _1,\beta _3\), the identity (??) reads coefficientwise as follows.

\(R_{\beta _3,\alpha _1}\, \) \tnpic[
    physical=updown,
    west label=$\beta_1$,
    east label=$\alpha_3$
]{
    \tn[
        mpo,
        up={$(l,r)$},
        down={$(l',r')$}
    ]{\widetilde\kappa^{(k)}}
} \( = \) \(p_k\, A^{(k)}_{\alpha _1,\beta _1}(l,l') B^{(k)}_{\alpha _3,\beta _3}(r,r')\).
Proof

At fixed indices \((k,l,r)\) and \((k,l',r')\), the Hayashi block equality is

\begin{align} & \sum _{i_2,j_2} [U_B]_{(k,l,r),i_2} \rho _{i_1i_2i_3,j_1j_2j_3} \overline{[U_B]_{(k,l',r'),j_2}} \notag \\ & \qquad =p_k(\rho _{A b_1}^{(k)})_{(i_1,l),(j_1,l')} (\rho _{b_2 C}^{(k)})_{(r,i_3),(r',j_3)}. \notag \end{align}

For each \(i_2,j_2\), the preceding theorem gives

\begin{align} & \sum _{i_1,j_1,i_3,j_3} (\mathcal K^{-1})^{\alpha _1,\beta _1}_{(i_1,j_1)} (\mathcal K^{-1})^{\alpha _3,\beta _3}_{(i_3,j_3)} \rho _{i_1i_2i_3,j_1j_2j_3} \notag \\ & \qquad =\mathcal K^{i_2j_2}_{\beta _1,\alpha _3} R_{\beta _3,\alpha _1}. \notag \end{align}

Apply

\begin{align} \sum _{i_1,j_1,i_3,j_3} & (\mathcal K^{-1})^{\alpha _1,\beta _1}_{(i_1,j_1)} (\mathcal K^{-1})^{\alpha _3,\beta _3}_{(i_3,j_3)}\, (-) \notag \end{align}

to the Hayashi block equality. Substituting the preceding display and interchanging the finite sums gives

\begin{align} & \sum _{i_1,j_1,i_3,j_3} (\mathcal K^{-1})^{\alpha _1,\beta _1}_{(i_1,j_1)} (\mathcal K^{-1})^{\alpha _3,\beta _3}_{(i_3,j_3)} \notag \\ & \qquad {}\times \left(\sum _{i_2,j_2} [U_B]_{(k,l,r),i_2} \rho _{i_1i_2i_3,j_1j_2j_3} \overline{[U_B]_{(k,l',r'),j_2}}\right) \notag \\ & \qquad =\sum _{i_2,j_2} [U_B]_{(k,l,r),i_2} \mathcal K^{i_2j_2}_{\beta _1,\alpha _3} R_{\beta _3,\alpha _1} \overline{[U_B]_{(k,l',r'),j_2}}. \notag \end{align}

The right-hand side is

\begin{align} & R_{\beta _3,\alpha _1} \sum _{i_2,j_2} [U_B]_{(k,l,r),i_2} \kappa _{\beta _1,\alpha _3}(i_2,j_2) \overline{[U_B]_{(k,l',r'),j_2}} \notag \\ & \qquad =R_{\beta _3,\alpha _1} \widetilde\kappa ^{(k)}_{\beta _1,\alpha _3} ((l,r),(l’,r’)). \notag \end{align}

The contraction of the right-hand side of the Hayashi block equality is \(p_k A^{(k)}_{\alpha _1,\beta _1}(l,l') B^{(k)}_{\alpha _3,\beta _3}(r,r')\). Since the Hayashi block equality holds, equating the two contractions gives (??).

Theorem 26.10.2.44 The four-site marginal is a three-site closure

Carried onto the tripartite site index, the three-site marginal of the normalized four-site chain is the three-site closure of \(\mathcal K\) against the normalized fourth-site tail \(R_4\).

Proof

The entry formula (??) for \(\sigma _3^{(4)}(\mathcal K)\), carried onto the tripartite site index \((i_1,i_2,i_3)\), gives

\begin{align} \rho _{i_1i_2i_3,j_1j_2j_3} & =\operatorname{tr}\! \left(\mathcal K^{i_1j_1}\mathcal K^{i_2j_2} \mathcal K^{i_3j_3}R_4\right), \notag \end{align}

which is the three-site closure condition (??) against \(R_4\).

Theorem 26.10.2.45 Vanishing of the off-diagonal Hayashi sectors

In the setting of Theorem 26.10.2.43, for all \(k\ne k'\), every off-diagonal sector satisfies

\begin{align} R_{\beta _3,\alpha _1} \left[U_B\kappa _{\beta _1,\alpha _3}U_B^\dagger \right]_{(k,l,r),(k',l',r')} & =0. \label{eq:rfp_offdiagonal_vanishing} \end{align}

Together with the diagonal comparison this gives the direct-sum structure of the factorized tensor: the direct sum over sectors is inherited from the splitting of the middle site.

Proof

For \(b\) in sector \(k\) and \(b'\) in sector \(k'\) with \(k\ne k'\), the Hayashi block equality at off-diagonal indices gives

\begin{align} \sum _{i_2,j_2}(U_B)_{b,i_2} \rho _{i_1i_2i_3,j_1j_2j_3} \overline{(U_B)_{b',j_2}} & =0. \notag \end{align}

Substituting this vanishing into the expansion of Theorem 26.10.2.42 gives (??).

Definition 26.10.2.46 Sector tensors

Fix outer virtual indices \(\alpha _1,\beta _3\) and a Hayashi sector \(k\). The sector tensors are

\begin{align} (l_k)_{\beta _1} & :=R_{\beta _3,\alpha _1}^{-1}\, p_k A^{(k)}_{\alpha _1,\beta _1}, \notag \\ (r_k)_{\alpha _3} & :=B^{(k)}_{\alpha _3,\beta _3}. \notag \end{align}

These are the tensors of the factorization displayed in [ CPGSV16 , Appendix C.2, lines 1435–1448 ] .

Lemma 26.10.2.47 Zero-weight left sector tensor

If \(p_k=0\), then \((l_k)_\beta =0\) for every virtual index \(\beta \). Consequently, \(\eta _{h,k}=0\) for every sector \(h\).

Proof

The scalar weight \(p_k\) is a factor of every matrix entry of \((l_k)_\beta \). Each neighboring operator entering sector \(k\) contains \((l_k)_\beta \) as its target factor.

Theorem 26.10.2.48 Sector factorization of an injective simple tensor

Suppose that \(\mathcal K\) is injective, \(\rho \) is its three-site closure against \(R\), a Hayashi decomposition of \(\rho \) has been chosen, and the outer indices satisfy \(R_{\beta _3,\alpha _1}\ne 0\). Then for all virtual indices \(\beta _1,\alpha _3\),

\begin{align} U_B\, \kappa _{\beta _1,\alpha _3}\, U_B^\dagger & =\bigoplus _k (l_k)_{\beta _1}\otimes (r_k)_{\alpha _3}. \label{eq:rfp_sector_factorization} \end{align}

The direct sum refers to the physical indices and is inherited from the splitting of the middle site. This is the factorization displayed at [ CPGSV16 , Appendix C.2, lines 1435–1448 ] .

In the middle-site basis selected by \(U_B\), the same factorization (??) is displayed as

\begin{tenkz}[rows={op:none, op, op:none}, tensor style=box]
        \tn[pill, wide=2, legs at={1,2}]{U_B} & \\
        \tn[wide=2]{\kappa_{\beta_1,\alpha_3}} & \\
        \tn[pill, wide=2, legs at={1,2}]{U_B^\dagger} &
    \end{tenkz} \( = \bigoplus _k\) \begin{tenkz}[physical=updown, east=none, tensor style=box]
        \tn{l_k}
    \end{tenkz} \( \otimes \) \begin{tenkz}[physical=updown, west=none, tensor style=box]
        \tn{r_k}
    \end{tenkz}
Proof

On a diagonal sector, the sectorwise comparison gives \(R_{\beta _3,\alpha _1}\widetilde\kappa ^{(k)} =p_kA^{(k)}B^{(k)}\), and dividing by the nonzero entry \(R_{\beta _3,\alpha _1}\) produces \((l_k)_{\beta _1}\otimes (r_k)_{\alpha _3}\). On an off-diagonal sector, the product with \(R_{\beta _3,\alpha _1}\) vanishes, and since \(R_{\beta _3,\alpha _1}\ne 0\) the sector itself vanishes.

Theorem 26.10.2.49 Existence of the sector tensors

Let \(\mathcal K\) be injective with nonzero four-site trace, let \(\rho \) be a three-site closure of \(\mathcal K\) against the normalized fourth-site tail \(R_4\), and choose a Hayashi decomposition of \(\rho \). Then there exist sector tensors \(l_k\) and \(r_k\) such that, for all virtual indices \(\beta _1,\alpha _3\),

\begin{align} U_B\, \kappa _{\beta _1,\alpha _3}\, U_B^\dagger & =\bigoplus _k (l_k)_{\beta _1}\otimes (r_k)_{\alpha _3}. \notag \end{align}

The neighboring operators \(\eta _{k,h}\) are assembled from these tensors in Definition 26.10.3.1; the remaining steps of [ CPGSV16 , Appendix C.2, Lemma C.4 ] prove the all-length identity and primitivity.

Proof

A nonzero four-site trace supplies outer indices with \((R_4)_{\beta _3,\alpha _1}\ne 0\), and the sector factorization applies.

26.10.3 Neighboring operators and commuting bond products

Definition 26.10.3.1 Neighboring operators
#

Fix outer virtual indices \(\alpha _1,\beta _3\) with the chosen Hayashi decomposition, and let \(l_k,r_k\) be the sector tensors of Definition 26.10.2.46. For each pair of sectors \((k,h)\), the neighboring operator contracts the right sector tensor of one site with the left sector tensor of the following site over the virtual bond they share:

\begin{align} \eta _{k,h} & =\sum _{\gamma }(r_k)_{\gamma }\otimes (l_h)_{\gamma }. \notag \end{align}

It acts on the neighboring bond space \(B_k^{R}\otimes B_h^{L}\). This is the operator displayed in [ CPGSV16 , Appendix C.2, lines 1441–1445 ] .

Theorem 26.10.3.2 Neighboring bond contraction

In the setting of Theorem 26.10.2.48, for all sectors \(k,h\) and virtual indices \(\beta _1,\alpha _3\), contracting the shared virtual bond of two neighboring factorized slices leaves the neighboring operator between the outer sector tensors:

\begin{align} & \sum _{\gamma } \left[U_B\kappa _{\beta _1,\gamma }U_B^\dagger \right]_{(k,l_1,r_1),(k,l_1',r_1')} \left[U_B\kappa _{\gamma ,\alpha _3}U_B^\dagger \right]_{(h,l_2,r_2),(h,l_2',r_2')} \notag \\ & \quad = \left[(l_k)_{\beta _1}\right]_{l_1,l_1'} \left[\eta _{k,h}\right]_{(r_1,l_2),(r_1',l_2')} \left[(r_h)_{\alpha _3}\right]_{r_2,r_2'}. \notag \end{align}

This is the single-bond step of the identity assembling \(\bigotimes _{n}\eta _{k_n,k_{n+1}}\) from the factorized chain in [ CPGSV16 , Appendix C.2, lines 1446–1449 ] .

Proof

Substituting the sector factorization (Theorem 26.10.2.48) into each slice, the outer sector tensors decouple from the bond sum, and the inner sum over the shared bond \(\gamma \) reads

\begin{align} \sum _{\gamma } [(r_k)_{\gamma }]_{r_1,r_1'} [(l_h)_{\gamma }]_{l_2,l_2'} & = [\eta _{k,h}]_{(r_1,l_2),(r_1',l_2')}, \notag \end{align}

by definition of the neighboring operator.

A physical-sector factorization of an MPO tensor \(\mathcal{K}\) consists of a finite decomposition

\begin{align} \mathbb {C}^d & \simeq \bigoplus _k(B_k^L\otimes B_k^R), \notag \end{align}

whose left and right factors are nonzero, an isometry \(U\) on the physical space, and matrix families \((l_k)_\beta \) and \((r_k)_\alpha \) such that every physical slice satisfies

\begin{align} U\kappa _{\beta ,\alpha }U^\dagger & =\bigoplus _k(l_k)_\beta \otimes (r_k)_\alpha . \notag \end{align}

No positivity, trace factorization, or quantum-Markov decomposition is included in this datum. This is the factorization displayed in [ CPGSV16 , Appendix C.2, lines 1381–1388 ] .

Definition 26.10.3.4 Algebraic neighboring contraction

For sectors \(k,h\), contract the common virtual index of the right and left sector tensors:

\begin{align} \eta _{k,h} & =\sum _a(r_k)_a\otimes (l_h)_a. \notag \end{align}

This is an operator on \(B_k^R\otimes B_h^L\). Positivity is not part of this definition; it is a separate hypothesis in Proposition C.7.

Definition 26.10.3.5 One-site matrix spaces of sector sets

For a sector \(k\) and physical matrix indices \(x,y\) in its summand, let \(A_{k;x,y}\in M_{D}(\mathbb {C})\) be the corresponding entry of the sector-coordinate tensor. For a set \(S\) of sectors, define

\begin{align} \mathcal{A}_S & =\operatorname{span}\{ A_{k;x,y}:k\in S\} . \notag \end{align}

These are the matrix spaces associated with the physical projections in [ CPGSV16 , Appendix C.2, lines 1463–1467 ] .

Let \(S\) and \(C\) be sets of sectors. If \(\eta _{k,h}=0\) for every \(k\in S\) and \(h\in C\), then \(XY=0\) for every \(X\in \mathcal{A}_S\) and \(Y\in \mathcal{A}_C\). No conclusion in the reverse product order is asserted. This is the directed local-orthogonality implication used in [ CPGSV16 , Appendix C.2, lines 1463–1470 ] .

Proof

Expand two generating matrices in sector coordinates. Their product has entries

\begin{align} \sum _{\gamma } (l_k)_\beta (r_k)_\gamma (l_h)_\gamma (r_h)_\alpha . \notag \end{align}

The middle contraction is a matrix entry of \(\eta _{k,h}\) and therefore vanishes. Bilinearity extends the conclusion from the generators to the two linear spans.

Definition 26.10.3.7 Vertex rephasing of the sector tensors

Let \(z_k\in \mathbb {C}\) satisfy \(|z_k|=1\) for every sector. Replacing

\begin{align} (l_k)_a& \longmapsto z_k(l_k)_a, \notag \\ (r_k)_a& \longmapsto z_k^{-1}(r_k)_a \notag \end{align}

leaves every physical-slice factorization unchanged.

Vertex rephasing transforms the neighboring operators by \(\eta _{k,h}\longmapsto z_k^{-1}z_h\, \eta _{k,h}\). It leaves every sector virtual matrix unchanged, preserves the nonzero neighboring support, and leaves every complete cyclic product of neighboring operators unchanged. These are the rephasing identities used in [ CPGSV16 , Appendix C.2, lines 1434–1450 ] .

Let \(S\) be a set of active sectors in a physical-sector factorization, and suppose that \((l_k)_\beta =0\) for every \(k\notin S\) and every \(\beta \). Retain every physical summand and define

\begin{align} \widehat l_k& =l_k, \notag \\ \widehat r_k& = \begin{cases} r_k,& k\in S,\\ 0,& k\notin S. \end{cases} \notag \end{align}

Then \(\widehat l_k\otimes \widehat r_k=l_k\otimes r_k\) for every \(k\), so the physical-slice factorization is unchanged. The neighboring operators become

\begin{align} \widehat\eta _{k,h} & = \begin{cases} \eta _{k,h},& k\in S,\\ 0,& k\notin S. \end{cases} \notag \end{align}

This is the reparameterization freedom in the factorization and neighboring contraction of [ CPGSV16 , Appendix C.2, lines 1434–1445 ] .

Definition 26.10.3.10 Inverse-map physical-sector factorization

Let \(\mathcal{K}\) be injective, let \(\rho \) be its three-site closure against a virtual tail \(R\), and choose a Hayashi decomposition of \(\rho \). Fix outer indices such that \(R_{\beta _3,\alpha _1}\ne 0\). The inverse-map tensors \(l_k,r_k\), together with the Hayashi physical decomposition and unitary, determine a physical-sector factorization of \(\mathcal{K}\).

The left and right factor spaces are nonzero because the corresponding Hayashi density matrices have trace one; their nonzero dimensions are conclusions rather than hypotheses. No positivity of the neighboring operators is asserted. This gives the factorization in [ CPGSV16 , Appendix C.2, equations AppUkU=rl and formK, lines 1383–1387 and 1434–1439 ] .

Theorem 26.10.3.11 Identification of the neighboring operators

For all sectors \(k,h\), the neighboring contraction of the resulting physical-sector factorization is the inverse-map operator

\begin{align} \eta _{k,h} & =\sum _\gamma (r_k)_\gamma \otimes (l_h)_\gamma . \notag \end{align}

This is equation etarl in [ CPGSV16 , Appendix C.2, lines 1441–1445 ] .

Definition 26.10.3.12 Zero-weight inverse-map reparameterization

In the inverse-map factorization, retain every physical sector and its factor spaces, and set

\begin{align} \widehat l_k& =l_k, \notag \\ \widehat r_k& = \begin{cases} r_k,& p_k\ne 0,\\ 0,& p_k=0. \end{cases} \notag \end{align}

The physical-slice factorization is unchanged. This treats the zero-weight freedom left by the Hayashi decomposition used in [ CPGSV16 , Appendix C.2, lines 1415–1445 ] .

The neighboring operators of the reparameterized factorization are

\begin{align} \widehat\eta _{k,h} & = \begin{cases} \eta _{k,h},& p_k\ne 0,\\ 0,& p_k=0. \end{cases} \notag \end{align}

Thus a zero-weight sector has no outgoing support edge. Since \(p_h=0\) also gives \(l_h=0\), it has no incoming support edge either.

Proof

The neighboring contraction uses \(r_k\) at its source and \(l_h\) at its target. The first assertion follows from the definition of \(\widehat r_k\), and the last assertion follows from Lemma 26.10.2.47.

Corollary 26.10.3.14 SAL gives a raw physical-sector factorization

Every injective MPO tensor satisfying SAL admits a physical-sector factorization. This is only the raw algebraic factorization from Lemma C.4 and equations formK and etarl; coherent positivity of the neighboring operators, recurrence, and primitivity are not part of this conclusion.

Let \(N\geq 1\). For a cyclic sector configuration \(k=(k_0,\ldots ,k_{N-1})\), write

\begin{align} I_k & =\prod _{n=0}^{N-1}(B_{k_n}^L\times B_{k_n}^R). \notag \end{align}

Applying the one-site sector decomposition at every site gives a bijection

\begin{align} \Phi _N:\{ 0,\ldots ,d{-}1\} ^{\, N} & \longrightarrow \coprod _{k_0,\ldots ,k_{N-1}}I_k. \notag \end{align}

On \(I_k\), define the cyclic neighboring product by

\begin{align} \Omega _k(x,y) & =\prod _{n=0}^{N-1} \eta _{k_n,k_{n+1}} ((x_n^R,x_{n+1}^L),(y_n^R,y_{n+1}^L)), \notag \end{align}

where site labels are read modulo \(N\).

Suppose that the physical-sector factorization is given. For every \(N\geq 1\), the physically transformed MPO is block diagonal in the cyclic sector configurations, and

\begin{align} \operatorname{reindex}_{\Phi _N}(M_N(\widetilde{\mathcal{K}})) & =\bigoplus _{k_0,\ldots ,k_{N-1}}\Omega _k. \notag \end{align}

This is the all-length algebraic decomposition in [ CPGSV16 , Appendix C.2, lines 1435–1450 ] , conditional here on the displayed physical-sector factorization. It does not assert positivity of the individual neighboring operators.

Proof

Fix a sector configuration \(k\) and entries \(x,y\in I_k\). Expanding the closed horizontal contraction gives

\begin{align} \sum _g\prod _n (l_{k_n})_{g_n}(x_n^L,y_n^L) (r_{k_n})_{g_{n+1}}(x_n^R,y_n^R). \notag \end{align}

Cyclically shifting the summation variables and collecting the factors with the same horizontal index turns this expression into \(\Omega _k(x,y)\). If the row and column sector configurations differ, one transformed physical slice lies between distinct direct summands and vanishes. Thus all off-diagonal sector blocks vanish.

Every injective MPO tensor satisfying SAL admits a physical-sector factorization such that, for every \(N\geq 1\) and every cyclic sector configuration \(k=(k_0,\ldots ,k_{N-1})\) with \(k_N=k_0\),

\begin{align} \bigotimes _{n=0}^{N-1}\eta _{k_n,k_{n+1}} & \geq 0. \notag \end{align}

This is the projected-chain inequality in [ CPGSV16 , Appendix C.2, Lemma C.4, lines 1446–1450 ] . It does not assert positivity of the individual neighboring operators.

Proof

Choose the raw physical-sector factorization supplied by SAL. The physical basis change sends the positive \(N\)-site MPO to a positive congruence. Each cyclic neighboring product is a diagonal sector compression of this congruence and is therefore positive semidefinite.

For an arbitrary virtual matrix \(X\), define the outer boundary operator on \(B_k^L\otimes B_h^R\) by

\begin{align} B_{k,h}(X) & =\sum _{a,b}X_{b,a}\, (l_k)_a\otimes (r_h)_b. \notag \end{align}

The map \(X\mapsto B_{k,h}(X)\) is complex-linear. No positivity of \(X\) or \(B_{k,h}(X)\) is assumed.

First pass to the physical basis selected by \(U\), so that each slice is written in the sector coordinates of Definition 26.10.3.3. Form the two-site closure of this sector-coordinate tensor, restrict it to the physical sectors \((k,h)\), and reindex its physical factors by

\begin{align} ((L_k,R_k),(L_h,R_h)) & \longmapsto ((L_k,R_h),(R_k,L_h)). \notag \end{align}

Denote the resulting matrix by \(\mathcal{K}_{2;k,h}(X)\).

For every virtual matrix \(X\) and every sector pair \((k,h)\),

\begin{align} \mathcal{K}_{2;k,h}(X) & =B_{k,h}(X)\otimes \eta _{k,h}. \notag \end{align}
Proof

At the regrouped matrix entry indexed by \(((\lambda _k,\rho _h),(\rho _k,\lambda _h))\) and \(((\lambda '_k,\rho '_h),(\rho '_k,\lambda '_h))\), the virtual trace expands as the scalar

\begin{align} \sum _{a,b,c}X_{b,a} [(l_k)_a]_{\lambda _k,\lambda '_k} [(r_k)_c]_{\rho _k,\rho '_k} [(l_h)_c]_{\lambda _h,\lambda '_h} [(r_h)_b]_{\rho _h,\rho '_h}. \notag \end{align}

Commuting scalar factors and collecting the sums over \((a,b)\) and \(c\) gives respectively \(B_{k,h}(X)\) and \(\eta _{k,h}\).

First pass to the physical basis selected by \(U\) and form the three-site closure of the resulting sector-coordinate tensor. Restrict this closure to the sectors \((k,l,h)\) and reindex its physical factors by

\begin{align} ((L_k,R_k),((L_l,R_l),(L_h,R_h))) & \longmapsto ((L_k,R_h),((R_k,L_l),(R_l,L_h))). \notag \end{align}

Denote the resulting matrix by \(\mathcal{K}_{3;k,l,h}(X)\).

For every virtual matrix \(X\) and fixed sectors \((k,l,h)\),

\begin{align} \mathcal{K}_{3;k,l,h}(X) & =B_{k,h}(X)\otimes (\eta _{k,l}\otimes \eta _{l,h}). \notag \end{align}
\begin{tenkz}[physical=updown, boundary=none, compact]
            \tn[pill, wide=6, legs at={1,2,3,4,5,6},
                up={$L_k$,$R_h$,$R_k$,$L_l$,$R_l$,$L_h$},
                down={$L_k$,$R_h$,$R_k$,$L_l$,$R_l$,$L_h$}]
              {{\cal K}_{3;k,l,h}(X)}
        \end{tenkz} \(\; =\; \) \begin{tenkz}[physical=updown, boundary=none, compact]
            \tn[up=$L_k$, down=$L_k$]{l_k} & \tnX{X} &
            \tn[up=$R_h$, down=$R_h$]{r_h}
        \end{tenkz} \(\; \otimes \; \) \begin{tenkz}[physical=updown, boundary=none, compact]
            \tn[up=$R_k$, down=$R_k$]{r_k} &
            \tn[up=$L_l$, down=$L_l$]{l_l}
        \end{tenkz} \(\; \otimes \; \) \begin{tenkz}[physical=updown, boundary=none, compact]
            \tn[up=$R_l$, down=$R_l$]{r_l} &
            \tn[up=$L_h$, down=$L_h$]{l_h}
        \end{tenkz}
Proof

At the regrouped matrix entry indexed by \(((\lambda _k,\rho _h),((\rho _k,\lambda _l),(\rho _l,\lambda _h)))\) and its primed counterpart, the left-hand side is the scalar

\begin{align} \sum _{a,b,c,e}X_{b,a} [(l_k)_a]_{\lambda _k,\lambda '_k} [(r_k)_c]_{\rho _k,\rho '_k} [(l_l)_c]_{\lambda _l,\lambda '_l} [(r_l)_e]_{\rho _l,\rho '_l} [(l_h)_e]_{\lambda _h,\lambda '_h} [(r_h)_b]_{\rho _h,\rho '_h}. \notag \end{align}

Reordering the four finite sums separates the \((a,b)\) boundary contraction from the neighboring contractions indexed by \(c\) and \(e\), which gives the three factors on the right-hand side.

Definition 26.10.3.23 Three-site neighboring operator

For every outer-sector pair \((k,h)\), define

\begin{align} \Omega _{k,h} & =\bigoplus _l (\eta _{k,l}\otimes \eta _{l,h}). \notag \end{align}

This is the direct sum of the two neighboring contractions appearing in the three-site closure factorization [ CPGSV16 , Appendix C.2, lines 1510–1516 ] .

\begin{align} \mathfrak R_2(\mathcal{K}_2(X))_{k,h} & =a_kb_hB_{k,h}(X). \notag \end{align}
\begin{tenkz}[physical=updown, boundary=none, compact]
              \tn[pill, wide=2, legs at={1,2},
                  up={{$L_k$},{$R_h$}}, down={{$L_k$},{$R_h$}}]
                {\mathfrak R_2({\cal K}_2(X))_{k,h}}
          \end{tenkz} \(\; =\; a_kb_h\; \) \begin{tenkz}[physical=updown, boundary=none, compact]
              \tn[up=$L_k$, down=$L_k$]{l_k} & \tnX{X} &
              \tn[up=$R_h$, down=$R_h$]{r_h}
          \end{tenkz}
\begin{align} \mathfrak R_3(\mathcal{K}_3(X))_{k,l,h} & =B_{k,h}(X)\otimes \eta _{k,l}\otimes \eta _{l,h}. \notag \end{align}
Figure 26.3 First each slice is conjugated by \(U\) and expressed in the corresponding sector coordinates. After restriction to fixed sectors and the displayed regroupings, the arbitrary-\(X\) two- and three-site closures separate into the boundary factor and respectively one or two neighboring contractions. The displayed identities do not assert positivity, preparation, recovery, or the full conclusion of Proposition C.7. They follow the contractions in [ CPGSV16 , lines 638–655 and Appendix C.2, lines 1435–1448 ] .

Suppose that every neighboring operator is positive semidefinite and that there are real numbers \(a_k,b_h\) such that

\begin{align} \operatorname{tr}(\eta _{k,h})& =a_kb_h, \notag \\ \sum _k a_kb_k& =1. \notag \end{align}

These are precisely the remaining hypotheses used in the construction of Proposition C.7 after the physical-sector factorization has been fixed [ CPGSV16 , Appendix C.2, lines 1389–1403 ] .

Assume the neighboring-operator trace factorization of Definition 26.10.3.24. Then, for every outer-sector pair \((k,h)\),

\begin{align} \operatorname{tr}(\Omega _{k,h}) & =\sum _l\operatorname{tr}(\eta _{k,l})\operatorname{tr}(\eta _{l,h}) =a_kb_h. \notag \end{align}

This is the normalization used in the coarse-graining channel of [ CPGSV16 , Appendix C.2 ] , lines 1547–1555.

Proof

The trace of a direct sum is the sum of the traces of its blocks, and the trace of a tensor product is the product of the traces. Hence

\begin{align} \operatorname{tr}(\Omega _{k,h}) & =\sum _l(a_kb_l)(a_lb_h) =a_kb_h\sum _l a_lb_l =a_kb_h. \notag \end{align}

For every virtual matrix \(X\),

\begin{align} \operatorname{tr}_{R_k\otimes L_h}\! \left(\mathcal{K}_{2;k,h}(X)\right) & =\operatorname{tr}(\eta _{k,h})B_{k,h}(X) =a_kb_h B_{k,h}(X). \notag \end{align}

Similarly,

\begin{align} \operatorname{tr}_{(R_k\otimes L_l)\otimes (R_l\otimes L_h)} \! \left(\mathcal{K}_{3;k,l,h}(X)\right) & =\operatorname{tr}(\eta _{k,l})\operatorname{tr}(\eta _{l,h})B_{k,h}(X), \notag \end{align}

and summing the scalar coefficient over \(l\) gives \(a_kb_h\).

Proof

The partial trace of \(A\otimes B\) is \(\operatorname{tr}(B)A\). The two-site identity follows immediately. For three sites, the coefficient is

\begin{align} \sum _l (a_kb_l)(a_lb_h) & =a_k\left(\sum _l a_lb_l\right)b_h =a_kb_h. \notag \end{align}

The two- and three-site physical spaces are reindexed by their canonical direct sums over sector pairs and triples, with each summand further regrouped into its boundary and neighboring factors. Write \(\mathfrak G_2\) and \(\mathfrak G_3\) for these reindexings of matrices.

After the canonical regrouping of all physical-sector indices, the full closures are

\begin{align} \mathfrak G_2(\mathcal{K}_2(X)) & =\bigoplus _{k,h}B_{k,h}(X)\otimes \eta _{k,h}, \notag \\ \mathfrak G_3(\mathcal{K}_3(X)) & =\bigoplus _{k,l,h}B_{k,h}(X)\otimes (\eta _{k,l}\otimes \eta _{l,h}). \notag \end{align}

Every matrix entry between distinct sector tuples vanishes.

Proof

On a diagonal sector tuple these are the fixed-sector factorizations. For distinct sector labels \(k\ne p\), the block structure of the sector-coordinate tensor gives \([U\kappa _{\beta ,\alpha }U^\dagger ]_{k,p}=0\). Consequently, if \((k,h)\ne (p,q)\) or \((k,l,h)\ne (p,m,q)\), respectively, then

\begin{align} [\mathfrak G_2(\mathcal{K}_2(X))]_{(k,h),(p,q)} & =0, \notag \\[\mathfrak G_3(\mathcal{K}_3(X))]_{(k,l,h),(p,m,q)} & =0. \notag \end{align}
Definition 26.10.3.29 Two-site sector bond

In the two-site sector coordinates, define

\begin{align} B_{\mathrm{sector}} & =\bigoplus _{k,h} \left(\mathbb {1}_{B_k^L\otimes B_h^R}\otimes \eta _{k,h}\right). \notag \end{align}

Thus the outer factors carry the identity, while the neighboring factors carry the operator \(\eta _{k,h}\). This is the local bond in [ CPGSV16 , Appendix C.2, Proposition C.8, lines 1581–1593 ] .

Theorem 26.10.3.30 Positivity of the two-site sector bond

Suppose that \(\eta _{k,h}\) is positive semidefinite for every pair of sectors. Then \(B_{\mathrm{sector}}\) is positive semidefinite. The positivity premise is the conclusion at [ CPGSV16 , Appendix C.2, lines 1446–1450 ] .

Proof

Each summand \(\mathbb {1}_{B_k^L\otimes B_h^R}\otimes \eta _{k,h}\) is positive semidefinite. Positivity is preserved by finite block diagonals and by the reindexing from the regrouped direct sum to the two-site sector coordinates.

Definition 26.10.3.31 Two-site bond in physical coordinates

Let \(V_2\) be the two-site tensor product of the project’s coordinate map, so that \(V_2XV_2^\dagger \) expresses a physical operator \(X\) in sector coordinates. Thus \(V_2=U_{\mathrm{paper}}^\dagger \) in the convention of [ CPGSV16 , Appendix C.2, lines 1581–1583 ] . Define

\begin{align} B_{\mathrm{physical}} & =V_2^\dagger B_{\mathrm{sector}}V_2, \notag \end{align}

and identify pairs of physical indices with functions \(\{ 0,1\} \to \{ 0,\ldots ,d-1\} \). This is the physical two-site bond in [ CPGSV16 , Appendix C.2, Proposition C.8, lines 1581–1593 ] .

Suppose that \(\eta _{k,h}\) is positive semidefinite for every pair of sectors. Then \(B_{\mathrm{physical}}\) is positive semidefinite, both with pair indices and with two-site configuration indices.

Proof

Apply positivity of \(B_{\mathrm{sector}}\) to the congruence \(V_2^\dagger B_{\mathrm{sector}}V_2\). Reindexing the resulting matrix by two-site configurations preserves positivity.

Definition 26.10.3.33 Three-site lifts of a two-site operator

Let \(B\) be an operator on two copies of a finite-dimensional space \(H\). On the right-associated space \(H\otimes (H\otimes H)\), define

\begin{align} B_{01} & =\alpha (B\otimes \mathbb {1}_H)\alpha ^{-1}, & B_{12} & =\mathbb {1}_H\otimes B, \notag \end{align}

where \(\alpha :(H\otimes H)\otimes H\to H\otimes (H\otimes H)\) is the canonical associator.

Under the canonical identification of three-site configurations with \(H\otimes (H\otimes H)\), the translates of the physical bond beginning at sites \(0\) and \(1\) are respectively \((B_{\mathrm{physical}})_{01}=B_{01}\) and \((B_{\mathrm{physical}})_{12}=B_{12}\).

Proof

An entry of the first translate vanishes unless the third indices agree; its remaining entry is that of \(B_{\mathrm{physical}}\). Similarly, an entry of the second translate vanishes unless the first indices agree. These are precisely the matrix entries of \(B_{01}\) and \(B_{12}\).

Theorem 26.10.3.35 Commutativity on a fixed sector triple

Fix sectors \((k,l,h)\). On the regrouped sector space, set

\begin{align} C_{01}^{k,l,h} & =\mathbb {1}_{B_k^L\otimes B_h^R}\otimes \left(\eta _{k,l}\otimes \mathbb {1}_{B_l^R\otimes B_h^L}\right), \notag \\ C_{12}^{k,l,h} & =\mathbb {1}_{B_k^L\otimes B_h^R}\otimes \left(\mathbb {1}_{B_k^R\otimes B_l^L}\otimes \eta _{l,h}\right). \notag \end{align}

Then \(C_{01}^{k,l,h}C_{12}^{k,l,h} =C_{12}^{k,l,h}C_{01}^{k,l,h}\). This is the fixed-sector calculation in [ CPGSV16 , Appendix C.2, Proposition C.8, lines 1589–1593 ] .

On the sector triple \((k,l,h)\), the two operators act on distinct neighboring factors, while the outer factors \(B_k^L\) and \(B_h^R\) remain unchanged. Their commutativity is therefore the local identity \(\eta _{k,l}^{(12)}\eta _{l,h}^{(23)} =\eta _{l,h}^{(23)}\eta _{k,l}^{(12)}\).

Proof

The operators \(\eta _{k,l}\) and \(\eta _{l,h}\) act on the distinct factors \(B_k^R\otimes B_l^L\) and \(B_l^R\otimes B_h^L\), respectively. The claim follows from the mixed-product identity for tensor products.

Theorem 26.10.3.36 Commutativity of adjacent physical bonds

The two translates of the physical bond on three sites commute:

\begin{align} (B_{\mathrm{physical}})_{01}(B_{\mathrm{physical}})_{12} & =(B_{\mathrm{physical}})_{12}(B_{\mathrm{physical}})_{01}. \notag \end{align}

This is the adjacent-bond calculation in [ CPGSV16 , Appendix C.2, Proposition C.8, lines 1589–1593 ] .

Proof

Regroup the three-site sector coordinates into the direct sum over triples \((k,l,h)\). The two bonds become block diagonal, with blocks \(C_{01}^{k,l,h}\) and \(C_{12}^{k,l,h}\), which commute by Theorem 26.10.3.35. Conjugating by the three-fold physical coordinate unitary preserves the equality. The three-site translation identities then give the displayed physical commutator.

Theorem 26.10.3.37 Agreement outside a cyclic window
#

Let \(W_i^L=\{ i,i+1,\ldots ,i+L-1\} \) be a cyclic window of length \(L\leq N\). Two configurations agree outside \(W_i^L\) precisely when their values agree at every site not contained in \(W_i^L\).

Proof

Replacing the entries in \(W_i^L\) does not affect any complementary site. Conversely, if the two configurations agree on the complement, replacing the window of the first by the window of the second reconstructs the second configuration.

Theorem 26.10.3.38 Multiplicativity of cyclic local embeddings
#

Let \(E_i^L\) embed an operator on \(L\) consecutive sites into an \(N\)-site periodic chain at the cyclic window beginning at \(i\). Then \(E_i^L(BC)=E_i^L(B)E_i^L(C)\).

Proof

Identify a periodic configuration with its restriction to \(W_i^L\) and its restriction to the cyclic complement. In these coordinates, \(E_i^L(B)=B\otimes \mathbb {1}\), so the assertion is the mixed-product identity.

Theorem 26.10.3.39 Commutativity on disjoint cyclic windows

Let \(L\leq N\), and let \(W_i^L\) and \(W_j^L\) be disjoint cyclic windows in an \(N\)-site periodic chain. For arbitrary operators \(B\) and \(C\) on \(L\) sites, \(E_i^L(B)E_j^L(C)=E_j^L(C)E_i^L(B)\).

Proof

Apply both sides to a chain amplitude. The first order of application is a double sum over replacements on \(W_i^L\) and \(W_j^L\). Since the windows are disjoint, each replacement leaves the other restricted configuration unchanged, and the two replacements commute. Interchanging the two finite sums gives the reverse order.

Theorem 26.10.3.40 Adjacent physical bonds on periodic chains

Let \(N\geq 3\). For every site \(i\in \mathbb {Z}/N\mathbb {Z}\), including \(i=N-1\), the adjacent translates of the physical bond commute:

\begin{align} (B_{\mathrm{physical}})_{i,i+1} (B_{\mathrm{physical}})_{i+1,i+2} & = (B_{\mathrm{physical}})_{i+1,i+2} (B_{\mathrm{physical}})_{i,i+1}. \notag \end{align}

This is the periodic-chain form of the adjacent-bond calculation in [ CPGSV16 , Appendix C.2, Proposition C.8, lines 1571–1593 ] . The case \(N=2\) is treated separately below, because its two translated bonds have the same support with opposite cyclic order.

Proof

Enclose the two bonds in the cyclic three-site window beginning at \(i\). In these coordinates they are the bonds beginning at sites \(0\) and \(1\), respectively. Embedding an operator into a fixed cyclic window preserves products, so the assertion follows from Theorem 26.10.3.36.

Theorem 26.10.3.41 Commutativity of the crossed two-site translates

On the periodic chain of length two, the translates beginning at sites zero and one read the physical sites in the opposite cyclic orders \((0,1)\) and \((1,0)\). Nevertheless they commute: \(B_{01}B_{10}=B_{10}B_{01}\). This is the length-two instance of the translated-bond commutativity in [ CPGSV16 , Appendix C.2, Proposition C.8 ] . The source does not discuss the crossed finite-size ordering separately.

Proof

Fix sectors \((k,h)\) and regroup the two physical sites as \((L_k\otimes R_h)\otimes (R_k\otimes L_h)\). The translate in the order \((0,1)\) is \(\mathbb {1}_{L_k\otimes R_h}\otimes \eta _{k,h}\), while the translate in the order \((1,0)\) is \(\eta _{h,k}^{\mathrm{op}}\otimes \mathbb {1}_{R_k\otimes L_h}\), where \(\eta _{h,k}^{\mathrm{op}}\) denotes the same matrix after exchanging the factors \(R_h\) and \(L_k\). These operators act on complementary factors and commute. Taking the direct sum over \((k,h)\) and conjugating by the two-fold physical coordinate unitary proves the claim.

Theorem 26.10.3.42 Disjoint physical bonds on periodic chains

Let \(N\geq 2\), and suppose that the cyclic bonds beginning at \(i\) and \(j\) have disjoint two-site supports. Then their physical bond operators commute: \((B_{\mathrm{physical}})_{i,i+1} (B_{\mathrm{physical}})_{j,j+1} =(B_{\mathrm{physical}})_{j,j+1} (B_{\mathrm{physical}})_{i,i+1}\). This is the locality part of the pairwise commutation assertion in [ CPGSV16 , Appendix C.2, Proposition C.8, lines 1571–1593 ] .

Proof

This is Theorem 26.10.3.39 applied to the same physical bond operator in both windows. No positivity or additional property of the sector factorization is needed for this locality step.

Theorem 26.10.3.43 Pairwise commutativity of the physical bonds

Suppose that the physical-sector factorization is given. For every periodic chain of length \(N\geq 2\) and every pair of sites \(i,j\in \mathbb {Z}/N\mathbb {Z}\), the corresponding translates of the physical bond commute:

\begin{align} (B_{\mathrm{physical}})_{i,i+1} (B_{\mathrm{physical}})_{j,j+1} & = (B_{\mathrm{physical}})_{j,j+1} (B_{\mathrm{physical}})_{i,i+1}. \notag \end{align}

This is the pairwise commutation assertion in [ CPGSV16 , Appendix C.2, Proposition C.8, lines 1571–1593 ] , conditional here on the physical-sector factorization constructed in the preceding results.

Proof

For \(N=2\), equal translates commute trivially, while the two distinct translates commute by Theorem 26.10.3.41. Let \(N\geq 3\). If the two cyclic supports are disjoint, apply Theorem 26.10.3.42. Otherwise, Lemma 14.1.11 shows that the two starting sites either coincide or are cyclic neighbors. The coincident case is immediate, and the two neighboring orientations follow from Theorem 26.10.3.40 and its symmetric equality.

Theorem 26.10.3.44 Exact product of physical-sector bonds

Suppose that \(K\) is equipped with a physical-sector factorization \(F\). Let \(B_i\) denote the cyclic translate beginning at site \(i\) of the physical two-site bond determined by \(F\). For every \(N\geq 2\), the \(N\)-site periodic operator is

\begin{align} \rho _N & =B_0B_1\cdots B_{N-1}. \notag \end{align}

No positivity, zero-correlation-length, injectivity, or normalization hypothesis is required. This is the product identity in [ CPGSV16 , Appendix C.2, Proposition C.8, lines 1581–1593 ] , conditional here on the given physical-sector factorization.

Proof

For a fixed cyclic sector sequence, contraction of the virtual index between the right tensor at site \(i\) and the left tensor at site \(i+1\) produces \(\eta _{k_i,k_{i+1}}\). Taking the virtual trace therefore gives the cyclic product of these neighboring operators. The translated sector bonds give the same ordered product. Conjugating by the tensor power of the one-site coordinate unitary gives the stated physical identity. For \(N=2\), the second translate has the opposite cyclic order; the two factors are the ordinary and crossed bonds.

Theorem 26.10.3.45 Unit scalar in the physical-sector product

Under the physical-sector factorization \(F\) of the preceding theorem, for every \(N\geq 2\) there is a real number \(c{\gt}0\) such that \(\rho _N=c\, B_0B_1\cdots B_{N-1}\). Here the bonds are the canonical bonds determined by \(F\), and one may take \(c=1\). No positivity hypothesis on the neighboring operators \(\eta _{k,h}\) is required.

Proof

Take \(c=1\) in Theorem 26.10.3.44.

Theorem 26.10.3.46 Positive translation-invariant bond datum

Suppose that every neighboring operator \(\eta _{k,h}\) is positive semidefinite. Then the physical bond is positive semidefinite and all of its cyclic translates commute on every periodic chain of length at least two. Thus it determines a single translation-invariant positive bond datum. This assertion does not include the product formula for the finite-chain density operator.

Proof

Positivity is Theorem 26.10.3.32; pairwise commutativity is Theorem 26.10.3.43.

Theorem 26.10.3.47 \(\eta \)-local structure from a positive physical-sector factorization

Suppose that a physical-sector factorization of \(K\) is given and that every neighboring operator \(\eta _{k,h}\) is positive semidefinite. Then the physical two-site bond determines an \(\eta \)-local structure for \(K\). Its translated copies commute pairwise, and for every \(N\geq 2\), \(\rho _N=B_0B_1\cdots B_{N-1}\). If the virtual dimension of \(K\) is positive, then \(K\) itself is a fixed tensor representation of this product family, with the same virtual dimension. Thus the positive normalization scalar may be chosen to be \(1\). This is Proposition C.8 conditional on the coherently positive physical-sector factorization that the source derives from SAL.

Proof

Theorem 26.10.3.46 gives the positive translation-invariant bond and its pairwise commuting translates. Theorem 26.10.3.44 realizes every finite-chain operator with normalization scalar \(1\).

Corollary 26.10.3.48 \(\eta \)-local structure from SAL

Every injective MPO tensor satisfying SAL admits an \(\eta \)-local structure. Thus there is a single positive two-site bond whose cyclic translates commute pairwise and whose ordered product is the finite-chain density operator at every length \(N\geq 2\), with normalization scalar one. This is the conclusion of Proposition C.8.

Proof

Theorem 26.10.4.41 supplies the positive physical-sector factorization. Apply Theorem 26.10.3.47.

Corollary 26.10.3.49 Normal representative for the SAL-selected bond

Let \(K\) be injective and satisfy SAL, and suppose that its doubled-index matrix-product tensor is normal. There is a positive physical-sector factorization whose selected two-site bond \(B\) has \(K\) itself as a normal fixed tensor representation. Its virtual dimension is the virtual dimension of \(K\), and for every \(N\geq 2\), \(\rho _N(K)=B_0B_1\cdots B_{N-1}\). In particular, the scalar is one. This is an existential statement about the bond selected in the proof of Proposition C.8; it does not assert uniqueness or normal rescalability for an arbitrary proportional commuting-bond presentation.

Proof

SAL implies that the virtual dimension is positive. The positive physical-sector factorization is supplied by Theorem 26.10.4.41. For its selected bond, use \(K\) as the fixed tensor. The exact product identity is Theorem 26.10.3.44, and normality is the given hypothesis on the doubled-index tensor.

26.10.4 Closed-sector contractions and coherent rephasing

Definition 26.10.4.1 Closed sector tensors

Tracing the two physical legs of a sector tensor leaves a vector over the virtual bond:

\begin{align} |l_k)_{\gamma }& :=\operatorname{tr}\left[(l_k)_{\gamma }\right], \notag \\ (r_k|_{\gamma }& :=\operatorname{tr}\left[(r_k)_{\gamma }\right]. \notag \end{align}

These are the closed tensors of [ CPGSV16 , Appendix C.2, lines 1473–1477 ] .

Definition 26.10.4.2 Closed-sector pairing operator

For sector tensors \((l_k)_\beta \) and \((r_k)_\alpha \), close their physical legs and set

\begin{align} S& :=\sum _k |l_k)(r_k|. \label{eq:rfp_pairing_operator} \end{align}

This is the pairing operator displayed in [ CPGSV16 , Appendix C.2, lines 1473–1493 ] .

Theorem 26.10.4.3 Sector trace pairing

For all sectors \(k,h\), the trace of the neighboring operator is the pairing of the closed sector tensors: \(T_{k,h}=\operatorname{tr}(\eta _{k,h})=(r_k|l_h)\). This is [ CPGSV16 , Appendix C.2, lines 1452–1455 and 1478–1481 ] .

Proof

Expanding the definition of the neighboring operator and applying \(\operatorname{tr}(A\otimes B)=\operatorname{tr}(A) \operatorname{tr}(B)\) gives

\begin{align} \operatorname{tr}(\eta _{k,h}) & =\sum _{\gamma }\operatorname{tr}((r_k)_{\gamma }\otimes (l_h)_{\gamma }) =\sum _{\gamma }\operatorname{tr}[(r_k)_{\gamma }]\, \operatorname{tr}[(l_h)_{\gamma }] =(r_k|l_h). \notag \end{align}
Definition 26.10.4.4 Concrete closed-sector trace matrix

For the inverse-map sector tensors, define the complex matrix \(T_{k,h}:=(r_k|l_h)\). Equivalently, \(T_{k,h}=\operatorname{tr}(\eta _{k,h})\). This is the trace matrix in [ CPGSV16 , Appendix C.2, lines 1478–1481 ] .

Theorem 26.10.4.5 Closed-sector form of the physical-trace transfer

More generally, any sector factorization \(U_B\kappa _{\beta ,\alpha }U_B^\dagger =\bigoplus _k(l_k)_\beta \otimes (r_k)_\alpha \) gives the closed-sector pairing operator

\begin{align} \mathcal T_{\cal K}& =\sum _k |l_k)(r_k|. \label{eq:rfp_trace_transfer} \end{align}

This identifies the transfer matrix of Definition 26.4.1 with the operator on the left-hand side of the zero-correlation-length identity in [ CPGSV16 , Appendix C.2, lines 1489–1493 ] .

Proof

Trace the sector factorization over the physical index. Unitary invariance gives \(\operatorname{tr}(U_B\kappa _{\beta ,\alpha }U_B^\dagger ) =\operatorname{tr}(\kappa _{\beta ,\alpha })\). The trace of the block diagonal is the sum of the block traces. In each sector,

\begin{align} \operatorname{tr}((l_k)_\beta \otimes (r_k)_\alpha ) & =\operatorname{tr}[(l_k)_\beta ]\, \operatorname{tr}[(r_k)_\alpha ] =[|l_k)(r_k|]_{\beta ,\alpha }. \notag \end{align}

Summing over \(k\) gives (??).

Corollary 26.10.4.6 Physical-trace transfer from the inverse-map sectors

Let \({\cal K}\) be injective. Let \(R\) and \(\rho \) give a three-site closure of \({\cal K}\), choose a Hayashi decomposition of \(\rho \), and fix virtual indices \(\alpha _1,\beta _3\) such that \(R_{\beta _3,\alpha _1}\ne 0\). For the corresponding closed sector tensors, \(\mathcal T_{\cal K}=\sum _k |l_k)(r_k|\).

Proof

The inverse-map sector tensors satisfy the sector factorization of Theorem 26.10.2.48. Apply Theorem 26.10.4.5.

Let \({\cal K}\) be injective. Let \(R\) and \(\rho \) give a three-site closure of \({\cal K}\), choose a Hayashi decomposition of \(\rho \), and fix virtual indices \(\alpha _1,\beta _3\) such that \(R_{\beta _3,\alpha _1}\ne 0\). Form the corresponding closed sector tensors \(|l_k)\) and \((r_k|\). If \({\cal K}\) has source zero correlation length, set \(S:=\sum _k |l_k)(r_k|\). Then there is a real number \(\lambda {\gt}0\) such that

\begin{align} S^2& =\lambda S, \label{eq:rfp_pairing_quasi_idempotent}\\ (\lambda ^{-1}S)^2& =\lambda ^{-1}S. \notag \end{align}

If \({\cal K}\) is the canonically normalized representative satisfying \(\mathcal T_{\cal K}^2=\mathcal T_{\cal K}\), then the raw pairing operator itself satisfies \(S^2=S\). This is the display preceding [ CPGSV16 , Appendix C.2, Lemma C.5 ] ; the first identity records the rescaling-invariant form of the same zero-correlation-length condition.

Proof

Substitute \(S=\mathcal T_{\cal K}\) from Corollary 26.10.4.6 into the defining relation \(\mathcal T_{\cal K}^2=\lambda \mathcal T_{\cal K}\), and then apply Lemma 26.4.4 to obtain (??) and its normalized form. Under literal idempotence, the same substitution gives \(S^2=S\) directly.

Theorem 26.10.4.8 Normalized closed-sector trace relations

Under the hypotheses of Theorem 26.10.4.7, suppose that \({\cal K}\) has source zero correlation length. There is a real number \(\lambda {\gt}0\) such that, for \(\widehat T:=\lambda ^{-1}T\), one has

\begin{align} \widehat T^2& =\widehat T^3. \label{eq:rfp_trace_square_cube} \end{align}

For every positive integer \(N\), one also has

\begin{align} \operatorname{tr}(\widehat T^N)& =\operatorname{tr}(\widehat T). \label{eq:rfp_trace_powers} \end{align}

This is the valid trace-power display in [ CPGSV16 , Appendix C.2, lines 1490–1497 ] . No idempotence or rank-one conclusion for \(\widehat T\) is asserted.

Proof

Let \(L\) be the matrix whose \(h\)th column is \(|l_h)\), and let \(Q\) be the matrix whose \(k\)th row is \((r_k|\). Then \(S=LQ\) and \(T=QL\). Place the normalization scalar on \(L\). Since \(\lambda ^{-1}LQ\) is idempotent, associativity gives

\begin{align} (Q\lambda ^{-1}L)^2 & =Q(\lambda ^{-1}LQ)\lambda ^{-1}L =Q(\lambda ^{-1}LQ)^2\lambda ^{-1}L =(Q\lambda ^{-1}L)^3. \notag \end{align}

Cyclicity of trace and the idempotence of \(\lambda ^{-1}LQ\) give

\begin{align} \operatorname{tr}(Q\lambda ^{-1}L) & =\operatorname{tr}(\lambda ^{-1}LQ) =\operatorname{tr}((\lambda ^{-1}LQ)^2) =\operatorname{tr}((Q\lambda ^{-1}L)^2). \notag \end{align}

By (??), \(\widehat T^N=\widehat T^2\) for every \(N\geq 2\), which proves (??).

Definition 26.10.4.9 Explicit neighboring \(\eta \)-operator data

Fix a Hayashi decomposition witness \(h_\eta \). An explicit neighboring \(\eta \)-family is a dependent family \((\eta _{k,h})\) indexed by sector pairs, where \(\eta _{k,h}\) acts on the neighboring bond space \(B_k^{R} \otimes B_h^{L}\). Requiring positivity for each pair gives the corresponding positive \(\eta \)-data.

Definition 26.10.4.10 Neighboring operators from sector tensors

Let \((l_k)_a\) and \((r_k)_a\) be sector tensors indexed by the horizontal virtual index \(a\). For neighboring sectors \(k,h\), define an operator on \(B_k^R\otimes B_h^L\) by

\begin{align} \eta _{k,h}((x_R,x_L),(y_R,y_L)) & =\sum _a (r_k)_a(x_R,y_R)(l_h)_a(x_L,y_L). \label{eq:rfp_eta_entries} \end{align}

Thus \(\eta _{k,h}=r_k l_h\) is the contraction over the shared horizontal index in [ CPGSV16 , Appendix C.2, equation (etarl) ] . Positivity is not part of this definition.

Lemma 26.10.4.11 Entries of the neighboring operators

For every pair of sectors and every pair of matrix indices, the entry of \(\eta _{k,h}\) is the contraction displayed in (??).

Proof

This is immediate from the definition of \(\eta _{k,h}\).

Neighboring right and left sector tensors meet in the bond operator \(\eta _{k,h}=r_k l_h\):

\begin{tenkz}[physical=updown, boundary=none]
        \tn[pill, wide=2, legs at={1,2},
            up={{$x_R$},{$x_L$}}, down={{$y_R$},{$y_L$}}]{\eta_{k,h}}
    \end{tenkz} \( = \) \begin{tenkz}[physical=updown, boundary=none,
                  bond label={$a$ at 1-2}]
        \tn[up=$x_R$, down=$y_R$]{r_k} & \tn[up=$x_L$, down=$y_L$]{l_h}
    \end{tenkz}

This is the contraction in [ CPGSV16 , Appendix C.2, lines 1441–1445 ] .

Theorem 26.10.4.12 Cyclic contraction of the sector tensors

Let \(N\geq 1\) and let \(k_0,\ldots ,k_{N-1}\) be a cyclic sequence of sectors. Fix matrix indices in the left and right factor of every sector, and abbreviate

\begin{align} L_n(a)& =(l_{k_n})_a(x_n^L,y_n^L), \notag \\ R_n(a)& =(r_{k_n})_a(x_n^R,y_n^R). \notag \end{align}

With all site labels read modulo \(N\),

\begin{align} \sum _{g_0,\ldots ,g_{N-1}} \prod _{n=0}^{N-1}L_n(g_n)R_n(g_{n+1}) & =\prod _{n=0}^{N-1} \eta _{k_n,k_{n+1}} ((x_n^R,x_{n+1}^L),(y_n^R,y_{n+1}^L)). \label{eq:rfp_cyclic_contraction} \end{align}

This is the entrywise cyclic contraction at [ CPGSV16 , Appendix C.2, lines 1446–1450 ] .

Proof

Expand the product of the sums defining the neighboring operators and set \(g'_n=g_{n+1}\). Cyclic invariance of the finite product and commutativity of scalar multiplication give

\begin{align} \sum _{g_0,\ldots ,g_{N-1}} \prod _{n=0}^{N-1}L_n(g_n)R_n(g_{n+1}) & =\sum _{g'_0,\ldots ,g'_{N-1}} \prod _{n=0}^{N-1}R_n(g’_n)L_{n+1}(g’_n) \notag \\ & =\prod _{n=0}^{N-1}\sum _a R_n(a)L_{n+1}(a). \notag \end{align}

The last expression is the product of the corresponding entries of \(\eta _{k_n,k_{n+1}}\), as in (??).

Theorem 26.10.4.13 Closed sector word as neighboring contractions

Under the hypotheses of the preceding theorem, define \(M_n(a,b)=L_n(a)R_n(b)\). Then

\begin{align} \operatorname{tr}(M_0M_1\cdots M_{N-1}) & =\prod _{n=0}^{N-1} \eta _{k_n,k_{n+1}} ((x_n^R,x_{n+1}^L),(y_n^R,y_{n+1}^L)). \label{eq:rfp_sector_word} \end{align}
\begin{align} \operatorname{tr}(M_{k_0}\cdots M_{k_{N-1}}) & =\operatorname{tr}(\eta _{k_0,k_1}\otimes \cdots \otimes \eta _{k_{N-1},k_0}). \notag \end{align}
Figure 26.4 Closing the horizontal indices of the factorized sector tensors pairs each right factor with the left factor at the next site. The cycle therefore becomes the product of the neighboring operators \(\eta _{k_n,k_{n+1}}\); compare [ CPGSV16 , Appendix C.2, lines 1446–1450 ] .
Proof

Expanding the trace of the matrix word gives

\begin{align} \operatorname{tr}(M_0M_1\cdots M_{N-1}) & =\sum _{g_0,\ldots ,g_{N-1}} \prod _{n=0}^{N-1}M_n(g_n,g_{n+1}). \notag \end{align}

Substituting \(M_n(a,b)=L_n(a)R_n(b)\) gives the cyclic sum in (??); applying that identity yields (??).

Definition 26.10.4.14 Sector-adapted chain coordinates

For a sector configuration \(k=(k_0,\ldots ,k_{N-1})\), let

\begin{align} I_k& =\prod _{n=0}^{N-1} \bigl(\{ 0,\ldots ,d_L(k_n)-1\} \times \{ 0,\ldots ,d_R(k_n)-1\} \bigr). \notag \end{align}

Applying the one-site Hayashi decomposition at every site gives a bijection

\begin{align} \Phi _N:\{ 0,\ldots ,d-1\} ^N & \longrightarrow \coprod _{k_0,\ldots ,k_{N-1}} I_k. \notag \end{align}

We write \(\operatorname{reindex}_{\Phi _N}(M)\) for the matrix obtained by transporting both indices of \(M\) along this bijection.

Definition 26.10.4.15 Physical conjugation of an MPO tensor
#

Let \(U\) be a matrix on the physical space. The physical conjugation of \({\cal K}\) by \(U\) is the tensor \(\widetilde{\cal K}\) defined by

\begin{align} \widetilde\kappa _{\beta ,\alpha }^{\, ij} & =(U\kappa _{\beta ,\alpha }U^\dagger )_{ij}. \notag \end{align}

Its horizontal bond indices are unchanged. When \(U\) is unitary, this is the corresponding physical basis change.

Definition 26.10.4.16 Cyclic tensor product of neighboring operators

Let \(N\geq 1\) and let \(k\) be a sector configuration. Define the matrix \(\Omega _k\) on \(I_k\) by

\begin{align} \Omega _k(x,y) & =\prod _{n=0}^{N-1} \eta _{k_n,k_{n+1}} ((x_n^R,x_{n+1}^L),(y_n^R,y_{n+1}^L)). \label{eq:rfp_cyclic_eta_product} \end{align}

Thus \(\Omega _k=\eta _{k_0,k_1}\otimes \cdots \otimes \eta _{k_{N-1},k_0}\) after the neighboring tensor factors are ordered cyclically.

Theorem 26.10.4.17 A fixed sector block is the cyclic neighboring product

Suppose that the physical slices in the Hayashi basis satisfy

\begin{align} U_B\kappa _{\beta ,\alpha }U_B^\dagger & =\bigoplus _q(l_q)_\beta \otimes (r_q)_\alpha . \notag \end{align}

Let \(\eta _{q,h}=r_q l_h\). For every \(N\geq 1\) and every sector configuration \(k\), the corresponding diagonal block of \(\operatorname{reindex}_{\Phi _N}(M_N(\widetilde{\cal K}))\) is \(\Omega _k\).

Proof

Fix \(x,y\in I_k\) and expand the closed horizontal trace of the MPO word. The sector factorization writes each local entry as a product of entries of \(l_{k_n}\) and \(r_{k_n}\). Set

\begin{align} M_n(\beta ,\alpha ) & =(l_{k_n})_\beta (x_n^L,y_n^L) (r_{k_n})_\alpha (x_n^R,y_n^R). \notag \end{align}

Then

\begin{align} \bigl[\operatorname{reindex}_{\Phi _N} (M_N(\widetilde{\cal K}))\bigr]_{(k,x),(k,y)} & =\operatorname{tr}(M_0M_1\cdots M_{N-1}) \notag \\ & =\prod _{n=0}^{N-1}\eta _{k_n,k_{n+1}} ((x_n^R,x_{n+1}^L),(y_n^R,y_{n+1}^L)) =\Omega _k(x,y). \notag \end{align}

The second equality is Theorem 26.10.4.13, and the last is (??).

Under the same sector factorization hypothesis, for every \(N\geq 1\),

\begin{align} \operatorname{reindex}_{\Phi _N} (M_N(\widetilde{\cal K})) & =\bigoplus _{k_0,\ldots ,k_{N-1}} \eta _{k_0,k_1}\otimes \eta _{k_1,k_2}\otimes \cdots \otimes \eta _{k_{N-1},k_0}. \label{eq:rfp_sector_decomposition} \end{align}

This is the algebraic sector decomposition in [ CPGSV16 , Appendix C.2, lines 1446–1450 ] . It does not assert that the individual neighboring operators are positive.

Proof

If the row and column sector configurations coincide, the corresponding block is Theorem 26.10.4.17. If they differ, choose a site \(n\) at which their labels \(k_n\) and \(h_n\) are unequal. Block diagonality gives \([U_B\kappa _{\beta ,\alpha }U_B^\dagger ] _{(k_n, \cdot ),(h_n, \cdot )}=0\) for every pair of horizontal indices. This local factor occurs in every cyclic horizontal-index product, so every summand in the closed trace is zero, proving (??).

Let \(A\) and \(B\) be nonzero complex square matrices whose Kronecker product \(A\otimes B\) is positive semidefinite. Then there is a scalar \(c\ne 0\) with \(cA\ge 0\) and \(c^{-1}B\ge 0\). Since \((cA)\otimes (c^{-1}B)=A\otimes B\), the rescaled factors represent the same product.

Proof

On a product vector \(x\otimes y\) the quadratic form of \(A\otimes B\) factors, so \((x^\dagger A\, x)(y^\dagger B\, y)\ge 0\) for all vectors \(x\) and \(y\). By polarization a complex matrix is determined by its quadratic form; since \(A\) and \(B\) are nonzero there are vectors with \(a=v_0^\dagger A\, v_0\ne 0\) and \(c=w_0^\dagger B\, w_0\ne 0\). Every value \(x^\dagger (cA)\, x=(x^\dagger A\, x)\, c\) is non-negative, and over the complex numbers a non-negative quadratic form already forces the matrix to be Hermitian, hence positive semidefinite. For the second factor, \(ac{\gt}0\) and \(a\, (y^\dagger B\, y)\ge 0\) give \(c^{-1}(y^\dagger B\, y)=(a\, (y^\dagger B\, y))(ac)^{-1}\ge 0\).

Lemma 26.10.4.20 A matrix and its negative cannot both be positive

If \(X\) and \(-X\) are positive semidefinite complex matrices, then \(X=0\).

Proof

The quadratic form of \(X\) is both non-negative and nonpositive, hence vanishes identically. Polarization gives \(X=0\).

Definition 26.10.4.21 Finite Kronecker product
#

For square matrices \(A_n\) indexed by \(n=0,\ldots ,N-1\), possibly with different index types, their finite Kronecker product is the matrix with entries

\begin{align} \left(\bigotimes _{n=0}^{N-1}A_n\right)_{x,y} & =\prod _{n=0}^{N-1}(A_n)_{x_n,y_n}. \notag \end{align}
Lemma 26.10.4.22 Elementary finite Kronecker identities

A finite Kronecker product of nonzero matrices is nonzero. Replacing one factor \(A_i\) by \(cA_i\) multiplies the whole finite product by \(c\).

Proof

Choose a nonzero entry in each factor and evaluate the product at the resulting row and column. The rescaling identity follows immediately from the entry formula in Definition 26.10.4.21.

Let \(M\ne 0\). If \(c_1,c_2\ne 0\) and both \(c_1M\) and \(c_2M\) are positive semidefinite, then \(c_1=t c_2\) for some positive real number \(t\). Every complex scalar of unit modulus is nonzero. In particular, every nonzero scalar \(c\) has a unit-modulus part \(u=c/|c|\), positivity of \(cM\) implies positivity of \(uM\), and there is at most one such unit scalar when \(M\ne 0\).

Proof

Hermiticity of \(c_1M\) and \(c_2M\) gives \(c_2\overline{c_1}=c_1\overline{c_2}\), so \(c_1/c_2\) is real. It cannot be negative: otherwise \(c_1M\) and its negative would both be positive semidefinite, forcing \(c_1M=0\). Thus the quotient is positive. Multiplication by \(|c|^{-1}{\gt}0\) replaces \(c\) by its unit-modulus part without changing positivity. Two admissible unit scalars differ by a positive real number of modulus one, and are therefore equal.

Theorem 26.10.4.24 Positive rescaling of a finite Kronecker product

Let \(N\geq 1\), and let \(A_0,\ldots ,A_{N-1}\) be nonzero complex square matrices, with possibly different dimensions. If their finite Kronecker product is positive semidefinite, then there are nonzero scalars \(c_0,\ldots ,c_{N-1}\) such that

\begin{align} \prod _{n=0}^{N-1}c_n& =1, \notag \\ c_nA_n& \geq 0 \quad (0\leq n{\lt}N). \notag \end{align}
Proof

The assertion is proved by induction on \(N\). Separate the first factor from the remaining Kronecker product and apply Theorem 26.10.4.19. Absorb the inverse of the first rescaling coefficient into one factor of the tail, then apply the induction hypothesis. The resulting coefficients are nonzero, their product is one, and every rescaled factor is positive semidefinite.

Lemma 26.10.4.25 One-sided product obstruction in a full matrix algebra

Let \(\mathcal A_1,\mathcal A_2\subseteq M_{D}(\mathbb {C})\) be nonzero linear subspaces. If \(XY=0\) for every \(X\in \mathcal A_1\) and \(Y\in \mathcal A_2\), then \(\mathcal A_1+\mathcal A_2\ne M_{D}(\mathbb {C})\). No vanishing condition on products in the reverse order is required. This is the matrix-algebra obstruction used in [ CPGSV16 , Appendix C.2, lines 1465–1470 ] .

Proof

Choose nonzero matrices \(X\in \mathcal A_1\) and \(Y\in \mathcal A_2\), together with nonzero entries \(X_{ip}\) and \(Y_{qj}\). If the two subspaces spanned the full matrix algebra, write the matrix unit \(E_{pq}=E_1+E_2\) with \(E_1\in \mathcal A_1\) and \(E_2\in \mathcal A_2\). The one-sided product hypothesis gives

\begin{align} XE_{pq}Y& =X(E_1Y)+(XE_2)Y=0. \notag \end{align}

Its \((i,j)\) entry is \(X_{ip}Y_{qj}\ne 0\), a contradiction.

Definition 26.10.4.26 Nonzero sector support and recurrence

The nonzero support graph of a neighboring-operator family has a directed edge \(k\to h\) precisely when \(\eta _{k,h}\ne 0\). Its support is recurrent when every such edge belongs to a directed cycle, equivalently when \(h\) can reach \(k\) whenever \(k\to h\) is an edge.

In sector coordinates, let \(A_{k;x,y}\) be the virtual matrix obtained from the \((x,y)\) entry within sector \(k\). The sector-coordinate family contains all transformed physical matrices, while the virtual-matrix family consists of all matrices \(A_{k;x,y}\).

Let \({\cal K}\) be injective and let

\begin{align} U\kappa _{\beta ,\alpha }U^\dagger & =\bigoplus _k(l_k)_\beta \otimes (r_k)_\alpha \notag \end{align}

be a physical-sector factorization. Then the virtual matrices \(A_{k;x,y}\) obtained from all within-sector physical entries span the full virtual matrix algebra \(M_{D}(\mathbb {C})\).

Proof

Since \(U\) is unitary, every original physical matrix of \({\cal K}\) is a linear combination of the matrices in the transformed physical coordinates. The off-diagonal sector entries in those coordinates vanish, while each diagonal sector entry is one of the matrices \(A_{k;x,y}\). Injectivity says that the original physical matrices span \(M_{D}(\mathbb {C})\), and the conclusion follows.

For a physical-sector factorization, let \(A_{k;x,y}\in M_{D}(\mathbb {C})\) be the virtual matrix obtained from the physical matrix entry \((x,y)\) within sector \(k\). Suppose that all such matrices span \(M_{D}(\mathbb {C})\) and that both endpoint sectors of every nonzero neighboring operator contain a nonzero matrix of this form. Then every nonzero \(\eta _{k,h}\) admits a two-edge return: there is a sector \(j\) for which

\begin{align} \eta _{h,j}& \ne 0, \notag \\ \eta _{j,k}& \ne 0. \notag \end{align}

In particular, the nonzero neighboring support is recurrent.

Proof

A nonzero entry of \(\eta _{k,h}\), together with nonzero sector matrices at \(k\) and \(h\), gives matrices \(A\) from sector \(k\) and \(B\) from sector \(h\) with \(AB\ne 0\). By nondegeneracy of the trace pairing, choose \(Y\) with \(\operatorname{tr}(ABY)\ne 0\). Expanding \(Y\) in the spanning family, some sector matrix \(C\) from a sector \(j\) satisfies \(\operatorname{tr}(ABC)\ne 0\). Cyclicity of the trace gives \(BC\ne 0\) and \(CA\ne 0\). The sector multiplication identity then forces \(\eta _{h,j}\ne 0\) and \(\eta _{j,k}\ne 0\).

A vertex \(h\) is reachable from \(k\) in the nonzero sector support if and only if there is a finite directed walk from \(k\) to \(h\). Consequently, the support is recurrent if and only if every directed edge admits a directed return walk.

Proof

A walk gives an element of the reflexive transitive closure by induction on its edges. Conversely, append the final edge at each induction step in the reflexive transitive closure.

Every nonempty closed directed walk of length \(N\) determines a cyclic family of vertices \(v_0,\ldots ,v_{N-1}\). Each \(v_n\to v_{n+1}\) is an edge, where \(v_N=v_0\), and for any edge weights in a commutative monoid, \(\operatorname {wt}(w)=\prod _{n=0}^{N-1}\kappa _{v_n,v_{n+1}}\).

Proof

Enumerate the sources of the successive edges. The last edge ends at the initial vertex because the walk is closed. The product identity follows by induction on the number of edges.

Theorem 26.10.4.32 Closed-walk criterion for vertex phases

Let \(E\) be a directed relation on a set \(V\), and suppose that every edge \(a\to b\) admits a directed return walk from \(b\) to \(a\). Let \(G\) be a group and assign a weight \(\kappa _{a,b}\in G\) to each ordered pair of vertices. If the product of the edge weights along every closed directed walk is one, then there are vertex weights \(z_a\in G\) such that \(\kappa _{a,b}=z_a^{-1}z_b\) whenever \(a\to b\) is an edge. This is the graph-theoretic coboundary step needed to make the phase choices in [ CPGSV16 , Appendix C.2, lines 1446–1450 ] coherent across a recurrent support component.

Proof

Reachability is an equivalence relation because every edge has a return walk. Choose one vertex in each reachability class and, for every vertex \(a\), choose a walk from the class representative to \(a\). Define \(z_a\) as the product of the edge weights along this walk. If two such walks have the same endpoints, append a common return walk; the two resulting closed walks have weight one, so the original walk weights agree. Comparing the chosen walk to \(b\) with the chosen walk to \(a\) followed by the edge \(a\to b\) gives \(z_b=z_a\kappa _{a,b}\).

Definition 26.10.4.33 Horizontal bond fiber of a sector cycle

For a cyclic sector assignment \((k_n)_{n\in \mathbb Z/N\mathbb Z}\), the horizontal bond fiber at \(n\) is

\begin{align} H_n& =B^R_{k_n}\times B^L_{k_{n+1}}. \notag \end{align}

Shifting the left component by one site identifies \(\prod _n H_n\) with the vertex-indexed sector fiber used in the cyclic neighboring-operator product.

Lemma 26.10.4.34 A cyclic block is a finite Kronecker product

Reindexing a cyclic neighboring-operator block along its horizontal bond fiber gives the finite Kronecker product \(\bigotimes _{n=0}^{N-1}\eta _{k_n,k_{n+1}}\).

Proof

Expand both sides entrywise. The shifted left component of the bond fiber at site \(n+1\) is precisely the left index paired with the right component at site \(n\).

Let \(N\geq 1\), and fix a cyclic sector assignment \(k_0,\ldots ,k_{N-1}\) such that every operator \(\eta _{k_n,k_{n+1}}\) is nonzero. If the corresponding cyclic tensor product is positive semidefinite, then there are nonzero scalars \(c_n\) satisfying

\begin{align} \prod _{n=0}^{N-1}c_n& =1, \notag \\ c_n\eta _{k_n,k_{n+1}}& \geq 0 \quad (0\leq n{\lt}N). \notag \end{align}

This is a choice on one fixed cycle. It does not assert that choices made on two different cycles agree on a common edge.

Proof

Reindex the cyclic sector block by the shared horizontal-bond indices. Its matrix entries then become the finite Kronecker product of the consecutive neighboring operators. Apply Theorem 26.10.4.24.

Let \({\cal K}\) be an injective MPDO, let \(R\) give a three-site closure, and fix an \(\eta \)-structure and a nonzero tail entry. Let \(N\geq 1\). For a cyclic sector assignment \(k_0,\ldots ,k_{N-1}\), suppose that every concrete operator \(\eta _{k_n,k_{n+1}}\) obtained from these data is nonzero. Then there are nonzero scalars \(c_n\) such that

\begin{align} \prod _{n=0}^{N-1}c_n& =1, \notag \\ c_n\eta _{k_n,k_{n+1}}& \geq 0 \quad (0\leq n{\lt}N). \notag \end{align}

This is the specialization of Theorem 26.10.4.35 to the inverse-map sector operators; positivity of the cyclic product follows from the MPDO property.

Proof

The fixed-sector cyclic product is positive semidefinite by Theorem 26.10.4.38. Apply Theorem 26.10.4.35.

Theorem 26.10.4.37 The conjugated chain is a congruence

For every matrix \(U\) on the physical space and every \(N\ge 1\),

\begin{align} \rho ^{(N)}(\widetilde{\cal K}) & =U^{\otimes N} \rho ^{(N)}({\cal K}) (U^{\otimes N})^\dagger . \notag \end{align}

In particular \(\rho ^{(N)}(\widetilde{\cal K})\ge 0\) whenever \(\rho ^{(N)}({\cal K})\ge 0\).

Proof

Expand the closed trace over bond configurations \(g\) (with \(g_{N+1}=g_1\)), and each conjugated local entry over its two physical indices:

\begin{align} [\rho ^{(N)}(\widetilde{\cal K})]_{\sigma ,\tau } & =\sum _{g}\prod _{n=1}^{N} \widetilde\kappa _{g_n,g_{n+1}}^{\, \sigma _n\tau _n} \notag \\ & =\sum _{g}\prod _{n=1}^{N}\sum _{p_n,q_n} U_{\sigma _n p_n} \kappa _{g_n,g_{n+1}}^{\, p_n q_n} \overline{U_{\tau _n q_n}}. \notag \end{align}

Distributing the site product over the physical sums factors the two \(U\)-products out of the bond sum, which leaves the matrix entry of \(U^{\otimes N}\rho ^{(N)}({\cal K})(U^{\otimes N})^\dagger \). Positivity is preserved by any congruence.

Theorem 26.10.4.38 Positivity of the projected chain blocks

Let \({\cal K}\) be an MPDO whose transformed physical slices satisfy the sector factorization hypothesis. Then for every \(N\ge 1\) and every cyclic sector assignment \(k_1,\ldots ,k_N\) with \(k_{N+1}=k_1\),

\begin{align} 0 & \leq [Q_{k_1}\otimes \cdots \otimes Q_{k_N}]\, \tilde\sigma [Q_{k_1}\otimes \cdots \otimes Q_{k_N}] \notag \\ & =\bigotimes _{n=1}^{N}\eta _{k_n,k_{n+1}}. \notag \end{align}

This is the positivity half of the display at [ CPGSV16 , Appendix C.2, lines 1446–1450 ] .

Proof

The cyclic tensor product \(\Omega _k\) of Definition 26.10.4.16 is a diagonal sector block of the basis-conjugated chain by Theorem 26.10.4.17. The conjugated chain is positive semidefinite by Theorem 26.10.4.37 and the MPDO property, and a principal submatrix of a positive semidefinite matrix is positive semidefinite.

Let \({\cal K}\) be an injective MPDO with the chosen Hayashi decomposition and a nonzero tail entry. Then for all sectors \(k,h\):

  1. \(\eta _{k,k}\ge 0\);

  2. \(\eta _{k,h}\otimes \eta _{h,k}\ge 0\);

  3. if \(\eta _{k,h}\ne 0\) and \(\eta _{h,k}\ne 0\), there is a scalar \(c\ne 0\) with \(c\, \eta _{k,h}\ge 0\), \(c^{-1}\eta _{h,k}\ge 0\), and \((c\, \eta _{k,h})\otimes (c^{-1}\eta _{h,k})=\eta _{k,h}\otimes \eta _{h,k}\).

Proof

The chain of length one projected to the sector \(k\) is \(\eta _{k,k}\) up to the exchange of its two tensor factors, and the chain of length two projected to \((k,h)\) is \(\eta _{k,h}\otimes \eta _{h,k}\), both positive by Theorem 26.10.4.38. The third item, including the Kronecker-product-preserving equality, is Theorem 26.10.4.19.

Let \((\eta _{k,h})\) be a neighboring-operator family for which every nonempty cyclic tensor product is positive semidefinite. Suppose, in addition, that every nonzero edge \(k\to h\) admits a directed return path from \(h\) to \(k\). Then there are unit complex numbers \(z_k\) such that \(z_k^{-1}z_h\, \eta _{k,h}\geq 0\) for all \(k\) and \(h\). Consequently, if the neighboring operators arise from the inverse-map physical-sector factorization of an injective MPDO and its nonzero support is recurrent, the sector tensors admit a reciprocal rephasing for which all neighboring operators are positive semidefinite. This factorization determines the positive commuting nearest-neighbor product structure of Proposition C.8.

This is a scope-restricted result. Recurrence is not a hypothesis of Lemma C.4 in [ CPGSV16 , Appendix C.2, lines 1406–1450 ] . Its derivation for the zero-weight reparameterized inverse-map factorization is treated in Theorem 26.10.4.41 and recorded in docs/paper-gaps/cpgsv17_mpdo_sal_zcl_eta_local_structure.tex.

Proof

For a nonzero edge, choose a directed return path and close it with the edge. Positive rescaling of the corresponding cyclic tensor product supplies a scalar that makes the edge operator positive; retain only its unit-modulus part. On any closed directed walk, positive rescaling of the associated cyclic tensor product gives phases whose product is one. Uniqueness of the unit phase identifies them edge by edge with the chosen phases. Hence the chosen edge phases have product one around every closed walk. The closed-walk criterion gives \(\kappa _{k,h}=z_k^{-1}z_h\) on every nonzero edge. Zero edge operators are already positive semidefinite. Finally, reciprocal rephasing of the left and right sector tensors multiplies each neighboring operator by this phase and preserves the physical-slice factorization. The conditional eta-local construction then gives the positive commuting product data.

Let \({\cal K}\) be an injective MPO tensor satisfying SAL. Then it admits a physical-sector factorization for which every neighboring operator \(\eta _{k,h}=\sum _a (r_k)_a\otimes (l_h)_a\) is positive semidefinite. Zero-weight Hayashi sectors remain in the physical direct sum, but their right tensors may be set to zero without changing the physical slices.

Proof

First set the right tensor to zero in every zero-weight sector. The left tensor already vanishes there, so this does not alter the factorization and removes every support edge incident to such a sector. Every remaining endpoint has positive weight. If all virtual matrices in a positive-weight sector vanished, then the corresponding middle-site block of the three-site closure would vanish; this contradicts its Hayashi expression as a nonzero weight times two trace-one sector states. Thus every endpoint of a nonzero edge contains a nonzero virtual matrix. Injectivity supplies spanning by all sector virtual matrices, and triangle closure gives recurrence. The projected chain identity makes every cyclic Kronecker product positive semidefinite. Apply Theorem 26.10.4.40 to obtain the coherent vertex rephasing.

Theorem 26.10.4.42 Positivity choice with symmetric support

In the setting of Theorem 26.10.4.39, assume in addition that the nonzero neighboring operators occur in symmetric pairs: \(\eta _{k,h}=0\) forces \(\eta _{h,k}=0\). Then there is a positive semidefinite family \(\eta '_{k,h}\) with \(\eta '_{k,k}=\eta _{k,k}\) and, for every pair of sectors, scalars \(c_{k,h}\ne 0\) with \(\eta '_{k,h}=c_{k,h} \eta _{k,h}\) and \(\eta '_{h,k}=c_{k,h}^{-1} \eta _{h,k}\). In particular every two-site block \(\eta '_{k,h}\otimes \eta '_{h,k}=\eta _{k,h}\otimes \eta _{h,k}\) of the sector-adapted decomposition is unchanged.

The source asserts at [ CPGSV16 , Appendix C.2, lines 1446–1450 ] that the \(\eta \)’s can be chosen positive semidefinite, without the symmetric-support hypothesis. That hypothesis excludes a scalar obstruction: a nonzero neighboring operator whose reverse pair vanishes is constrained only by cycles through at least three sectors, and a coherent choice for the whole family can then fail.

Proof

The diagonal operators are positive by Theorem 26.10.4.39, and their scalar is taken to be one. For a pair of distinct sectors, either both neighboring operators vanish and any nonzero scalar works, or both are nonzero by symmetric support and Theorem 26.10.4.39 supplies the reciprocal pair of scalars. Choosing the scalar once per unordered pair makes the two assignments reciprocal, and the block-preserving equality of Theorem 26.10.4.19 applied to that scalar gives \(\eta '_{k,h}\otimes \eta '_{h,k}=\eta _{k,h}\otimes \eta _{h,k}\).

26.10.5 Normalized preparations and controlled partial traces

Every explicit neighboring \(\eta \)-family determines a sector-by-sector trace matrix. We give both its complex-valued form and the real-part version, which is the direct data for the real Perron–Frobenius matrix \(T\) used in the rank-one step.

Definition 26.10.5.2 Rank-one factorization of neighboring-operator traces

Let \((\eta _{k,h})\) be a positive neighboring-operator family. A rank-one trace factorization consists of real families \((a_k)\) and \((b_h)\) such that

\begin{align} \operatorname{tr}(\eta _{k,h}) & = a_kb_h, \notag \\ \sum _l a_lb_l & = 1. \notag \end{align}

These identities occur in [ CPGSV16 , Appendix C.2, lines 1395–1402 ] .

Definition 26.10.5.3 Direct-sum neighboring operator

For sectors \(k,h\), define the positive-operator candidate

\begin{align} \Omega _{k,h} & =\bigoplus _l(\eta _{k,l}\otimes \eta _{l,h}). \notag \end{align}

The summand indexed by \(l\) acts on \((B_k^R\otimes B_l^L)\otimes (B_l^R\otimes B_h^L)\). This is the operator adjoined by \(\mathcal T_{k,h}\) in [ CPGSV16 , Appendix C.2, lines 1527–1535 ] .

Theorem 26.10.5.4 Positivity of finite dependent block diagonals
#

Let \((A_i)_{i\in I}\) be a finite family of positive semidefinite matrices, where the size of \(A_i\) may depend on \(i\). Then the block-diagonal matrix \(\bigoplus _{i\in I}A_i\) is positive semidefinite.

Proof

Write each \(A_i=B_i^*B_i\) using its positive square root. The dependent block diagonal then satisfies \(\bigoplus _i A_i=(\bigoplus _i B_i)^*(\bigoplus _i B_i)\).

Theorem 26.10.5.5 Positivity of the direct-sum neighboring operator

Every operator \(\Omega _{k,h}\) is positive semidefinite.

Proof

For every \(l\), positivity is preserved by the Kronecker product: \(\eta _{k,l}\succeq 0\) and \(\eta _{l,h}\succeq 0\) imply \(\eta _{k,l}\otimes \eta _{l,h}\succeq 0\). Apply Theorem 26.10.5.4 to the family \((\eta _{k,l}\otimes \eta _{l,h})_l\).

Theorem 26.10.5.6 Trace of the direct-sum neighboring operator

The trace is

\begin{align} \operatorname{tr}(\Omega _{k,h}) & =\sum _l\operatorname{tr}(\eta _{k,l})\operatorname{tr}(\eta _{l,h}). \notag \end{align}

Under the rank-one trace factorization, this becomes

\begin{align} \operatorname{tr}(\Omega _{k,h}) & =a_kb_h\sum _l a_lb_l=a_kb_h. \notag \end{align}

This is the trace calculation in [ CPGSV16 , Appendix C.2, lines 1531–1535 ] .

Proof

The direct-sum and Kronecker trace identities give

\begin{align} \operatorname{tr}(\Omega _{k,h}) & =\sum _l\operatorname{tr}(\eta _{k,l}\otimes \eta _{l,h}) =\sum _l\operatorname{tr}(\eta _{k,l})\operatorname{tr}(\eta _{l,h}). \notag \end{align}

Substitute \(\operatorname{tr}(\eta _{k,h})=a_kb_h\) and \(\sum _l a_lb_l=1\).

Every product \(a_kb_h\) is non-negative. If \(a_kb_h=0\), then \(\eta _{k,h}=0\) and \(\Omega _{k,h}=0\).

Proof

Since \(\eta _{k,h}\succeq 0\), its trace is non-negative, and hence \(a_kb_h=\operatorname{tr}(\eta _{k,h})\geq 0\). If \(a_kb_h=0\), then \(\eta _{k,h}\succeq 0\) and \(\operatorname{tr}(\eta _{k,h})=a_kb_h=0\), which imply \(\eta _{k,h}=0\). The same implication gives \(\Omega _{k,h}=0\) because \(\Omega _{k,h}\succeq 0\) and \(\operatorname{tr}(\Omega _{k,h})=a_kb_h=0\).

Definition 26.10.5.8 Normalized active neighboring operators

With the convention \(0^{-1}=0\), define for every pair \((k,h)\)

\begin{align} \widehat\eta _{k,h} & =(a_kb_h)^{-1}\eta _{k,h}, \notag \\ \widehat\Omega _{k,h} & =(a_kb_h)^{-1}\Omega _{k,h}. \notag \end{align}

These operators are normalized when the pair is active, namely when \(a_kb_h\ne 0\).

Theorem 26.10.5.9 Positivity of normalized neighboring operators

For every pair \((k,h)\), the operators \(\widehat\eta _{k,h}\) and \(\widehat\Omega _{k,h}\) are positive semidefinite.

Proof

By Theorem 26.10.5.7, \(a_kb_h\geq 0\), and hence \((a_kb_h)^{-1}\geq 0\). Since \(\eta _{k,h}\succeq 0\) and \(\Omega _{k,h}\succeq 0\), multiplication by \((a_kb_h)^{-1}\) gives \(\widehat\eta _{k,h}\succeq 0\) and \(\widehat\Omega _{k,h}\succeq 0\).

If \(a_kb_h\ne 0\), then \(\widehat\eta _{k,h}\) and \(\widehat\Omega _{k,h}\) have trace one. Consequently the maps

\begin{align} X& \longmapsto X\otimes \widehat\eta _{k,h}, \notag \\ X& \longmapsto X\otimes \widehat\Omega _{k,h} \notag \end{align}

are trace-preserving and completely positive. These are the individual preparations \(\mathcal S_{k,h}\) and \(\mathcal T_{k,h}\) in [ CPGSV16 , Appendix C.2, lines 1527–1535 and 1551–1555 ] .

Proof

On an active pair, \(\operatorname{tr}(\widehat\eta _{k,h}) =(a_kb_h)^{-1}\operatorname{tr}(\eta _{k,h}) =(a_kb_h)^{-1}a_kb_h=1\). Likewise, \(\operatorname{tr}(\widehat\Omega _{k,h})=1\) follows from \(\operatorname{tr}(\Omega _{k,h})=a_kb_h\). Apply Lemma 26.1.37 to each operator.

Lemma 26.10.5.11 Trace-one matrices have nonempty index spaces
#

If a matrix indexed by a finite type has trace one, then its index type is nonempty.

Proof

A matrix on an empty index space has trace zero, contrary to the hypothesis.

Lemma 26.10.5.12 Nonemptiness of the Hayashi sector factors

Every left and right factor in a Hayashi sector is nonzero-dimensional.

Proof

A matrix on an empty index space has trace zero. Hence \(\operatorname{tr}(\rho _k^R)=1\) implies \(\dim (B_k^R\otimes C){\gt}0\), which implies \(\dim B_k^R{\gt}0\), and the same argument applied to \(\rho _k^L\) gives \(d_k^L{\gt}0\).

Lemma 26.10.5.13 Existence of a Hayashi sector

The set of Hayashi sectors is nonempty.

Proof

The sector-weight identity \(\sum _k p_k=1\) implies \(m{\gt}0\).

Lemma 26.10.5.14 Nonemptiness of the neighboring auxiliary spaces

For every pair of sectors \((k,h)\), the spaces carrying \(\eta _{k,h}\) and \(\Omega _{k,h}\) are nonzero-dimensional.

Proof

The tensor product carrying \(\eta _{k,h}\) is nonzero-dimensional by Lemma 26.10.5.12. Choosing an intermediate sector \(l\) by Lemma 26.10.5.13 then supplies an element of the direct-sum space carrying \(\Omega _{k,h}\).

Definition 26.10.5.15 Faithful uniform density matrix
#

On a nonzero finite-dimensional space \(H\), define

\begin{align} \tau _H& =\frac{1}{\dim H}I_H. \notag \end{align}
Theorem 26.10.5.16 The uniform density matrix is faithful and normalized

The matrix \(\tau _H\) is positive definite and has trace one.

Proof

Since \(\dim H{\gt}0\), the scalar \((\dim H)^{-1}\) is positive. Thus \(\tau _H\) is positive definite, and \(\operatorname{tr}(\tau _H)=(\dim H)^{-1}\dim H=1\).

For every sector pair define

\begin{align} \overline\eta _{k,h} & = \begin{cases} \widehat\eta _{k,h},& a_kb_h\ne 0,\\ \tau _{B_k^R\otimes B_h^L},& a_kb_h=0, \end{cases} \notag \\ \overline{\mathcal S}_{k,h}(X) & =X\otimes \overline\eta _{k,h}. \notag \end{align}

On an active pair this is precisely the preparation \(\mathcal S_{k,h}\) of [ CPGSV16 , Appendix C.2, lines 1551–1555 ] ; the second branch gives a normalized extension on a pair where the displayed source quotient is undefined.

For every pair \((k,h)\), the operator \(\overline\eta _{k,h}\) is positive semidefinite with trace one. Hence \(\overline{\mathcal S}_{k,h}\) is trace-preserving and completely positive. If \(a_kb_h\ne 0\), then both the density matrix and the preparation equal their normalized active forms.

Proof

The two branches give

\begin{align} a_kb_h\ne 0 & \Longrightarrow \overline\eta _{k,h}=\widehat\eta _{k,h}\succeq 0, \quad \operatorname{tr}(\overline\eta _{k,h})=1, \notag \\ a_kb_h=0 & \Longrightarrow \overline\eta _{k,h}=\tau _{B_k^R\otimes B_h^L}\succ 0, \quad \operatorname{tr}(\overline\eta _{k,h})=1. \notag \end{align}

The state-preparation result applies in either case.

For every sector pair define

\begin{align} \mathcal H^{\Omega }_{k,h} & = \bigoplus _l (B_k^R\otimes B_l^L)\otimes (B_l^R\otimes B_h^L), \notag \\ \overline\Omega _{k,h} & = \begin{cases} \widehat\Omega _{k,h},& a_kb_h\ne 0,\\ \tau _{\mathcal H^{\Omega }_{k,h}},& a_kb_h=0, \end{cases} \notag \\ \overline{\mathcal T}_{k,h}(X) & =X\otimes \overline\Omega _{k,h}. \notag \end{align}

Thus \(\mathcal H^{\Omega }_{k,h}\) is the carrier space, whereas \(\Omega _{k,h}\), \(\widehat\Omega _{k,h}\), and \(\overline\Omega _{k,h}\) are operators on it: respectively the unnormalized neighboring operator, its normalization on an active pair, and its completed density on an arbitrary pair. On an active pair this is precisely the preparation \(\mathcal T_{k,h}\) of [ CPGSV16 , Appendix C.2, lines 1527–1535 ] ; the inactive branch is a normalized extension.

For every pair \((k,h)\), the operator \(\overline\Omega _{k,h}\) is positive semidefinite with trace one. Hence \(\overline{\mathcal T}_{k,h}\) is trace-preserving and completely positive. On every active pair it equals the normalized active preparation.

Proof

The two branches give

\begin{align} a_kb_h\ne 0 & \Longrightarrow \overline\Omega _{k,h}=\widehat\Omega _{k,h}\succeq 0, \quad \operatorname{tr}(\overline\Omega _{k,h})=1, \notag \\ a_kb_h=0 & \Longrightarrow \overline\Omega _{k,h}=\tau _{\mathcal H^{\Omega }_{k,h}}\succ 0, \quad \operatorname{tr}(\overline\Omega _{k,h})=1. \notag \end{align}

The state-preparation result therefore applies to \(\overline{\mathcal T}_{k,h}\).

Definition 26.10.5.21 Globally controlled neighboring-state preparation

Let \(H=\bigoplus _{k,h}H_{k,h}\). Orthogonally controlling the completed preparations over the sector pairs gives a map

\begin{align} \overline{\mathcal S}_1(X) & =\sum _{k,h,a}\widetilde A_{k,h,a}X \widetilde A_{k,h,a}^{\dagger }, \notag \end{align}

where \((A_{k,h,a})_a\) is a Kraus family for \(\overline{\mathcal S}_{k,h}\) and the tilde denotes its extension by zero outside \(H_{k,h}\). Thus the map discards inter-sector coherences and applies the completed preparation in each diagonal sector. On active sectors this is the sector-control formula for \(\mathcal S_1\) in [ CPGSV16 , Appendix C.2, lines 1548–1555 ] .

Theorem 26.10.5.22 Diagonal-sector action of the completed neighboring preparation

If \(X_{k,h}\) is the \((k,h)\) diagonal block of \(X\), then

\begin{align} [\overline{\mathcal S}_1(X)]_{k,h} & =\overline{\mathcal S}_{k,h}(X_{k,h}) =X_{k,h}\otimes \overline\eta _{k,h}. \notag \end{align}
Proof

The diagonal-block formula and invariance under Kraus-index relabeling give

\begin{align} [\overline{\mathcal S}_1(X)]_{k,h} & =\Phi _{\widetilde A_{k,h}}(X_{k,h}) =\Phi _{A_{k,h}}(X_{k,h}), \notag \\ \Phi _{A_{k,h}}(X_{k,h}) & =X_{k,h}\otimes \overline\eta _{k,h}. \notag \end{align}
Theorem 26.10.5.23 The globally controlled neighboring-state preparation is trace-preserving completely positive

The map \(\overline{\mathcal S}_1\) is trace-preserving and completely positive.

Proof

If \((A_{k,h,a})_a\) is the sectorwise Kraus family, then

\begin{align} \sum _{k,h,a}\widetilde A_{k,h,a}^{\dagger }\widetilde A_{k,h,a} & =\bigoplus _{k,h}\left(\sum _a A_{k,h,a}^{\dagger }A_{k,h,a}\right) =\bigoplus _{k,h}I_{H_{k,h}}=I_H. \notag \end{align}

Thus the controlled Kraus family is trace-preserving.

Definition 26.10.5.24 Globally controlled direct-sum preparation

Orthogonally controlling the completed direct-sum preparations gives

\begin{align} \overline{\mathcal T}_1(X) & =\sum _{k,h,a}\widetilde B_{k,h,a}X \widetilde B_{k,h,a}^{\dagger }, \notag \end{align}

where \((B_{k,h,a})_a\) is a Kraus family for \(\overline{\mathcal T}_{k,h}\). This map discards inter-sector coherences and, on active sectors, is the sector-control formula for \(\mathcal T_1\) in [ CPGSV16 , Appendix C.2, lines 1523–1535 ] .

Theorem 26.10.5.25 Diagonal-sector action of the completed direct-sum preparation

If \(X_{k,h}\) is the \((k,h)\) diagonal block of \(X\), then

\begin{align} [\overline{\mathcal T}_1(X)]_{k,h} & =\overline{\mathcal T}_{k,h}(X_{k,h}) =X_{k,h}\otimes \overline\Omega _{k,h}. \notag \end{align}
Proof

The diagonal-block formula and invariance under Kraus-index relabeling give

\begin{align} [\overline{\mathcal T}_1(X)]_{k,h} & =\Phi _{\widetilde B_{k,h}}(X_{k,h}) =\Phi _{B_{k,h}}(X_{k,h}), \notag \\ \Phi _{B_{k,h}}(X_{k,h}) & =X_{k,h}\otimes \overline\Omega _{k,h}. \notag \end{align}
Theorem 26.10.5.26 The globally controlled direct-sum preparation is trace-preserving completely positive

The map \(\overline{\mathcal T}_1\) is trace-preserving and completely positive.

Proof

For the sectorwise Kraus family \((B_{k,h,a})_a\),

\begin{align} \sum _{k,h,a}\widetilde B_{k,h,a}^{\dagger }\widetilde B_{k,h,a} & =\bigoplus _{k,h}\left(\sum _a B_{k,h,a}^{\dagger }B_{k,h,a}\right) =\bigoplus _{k,h}I_{H_{k,h}}=I_H. \notag \end{align}

The orthogonal-control theorem now gives the claim.

Remark 26.10.5.27 Scope of the completed preparation
#

The conclusions above begin with the rank-one trace factorization \(\operatorname{tr}(\eta _{k,h})=a_kb_h\) and \(\sum _l a_lb_l=1\). Deriving this factorization for the inverse-map neighboring operators from the strong area law and zero correlation length is the Perron–Frobenius step of [ CPGSV16 , Appendix C.2, lines 1404–1410 and 1484–1498 ] . The completed maps therefore give the global controlled preparation once that factorization is supplied; they do not by themselves prove the full two-map statement [ CPGSV16 , Appendix C.2, lines 1510–1517 ] . The regrouping maps, shift maps, and the required closure identities are separate parts of that statement.

Definition 26.10.5.28 Controlled dependent partial trace

Let

\begin{align} H& =\bigoplus _{i\in I}(A_i\otimes B_i), \notag \\ K& =\bigoplus _{i\in I}A_i. \notag \end{align}

The controlled dependent partial trace discards the off-diagonal blocks between distinct \(i\) and applies \(\operatorname{tr}_{B_i}\) to the \(i\)th diagonal block.

Theorem 26.10.5.29 Diagonal blocks of the controlled dependent partial trace

If \(X_{ii}\) denotes the \(i\)th diagonal block of \(X\), then \([\mathcal C_{\operatorname{tr}}(X)]_{ii}=\operatorname{tr}_{B_i}(X_{ii})\).

Proof

If \((K_{i,j})_j\) is the Kraus family chosen for \(\operatorname{tr}_{B_i}\), then the diagonal-block formula gives

\begin{align} [\mathcal C_{\operatorname{tr}}(X)]_{ii} & =\sum _j K_{i,j}X_{ii}K_{i,j}^\dagger =\operatorname{tr}_{B_i}(X_{ii}). \notag \end{align}
Theorem 26.10.5.30 The controlled dependent partial trace is trace-preserving completely positive

The controlled dependent partial trace is trace-preserving and completely positive.

Proof

Choose Kraus operators \((V_{i,a})_a\) for \(\operatorname{tr}_{B_i}\) and extend each \(V_{i,a}\) by zero outside the \(i\)th summand. Their controlled family satisfies

\begin{align} \sum _{i,a}\widetilde V_{i,a}^{\dagger }\widetilde V_{i,a} & =\bigoplus _i\left(\sum _aV_{i,a}^{\dagger }V_{i,a}\right) =\bigoplus _i \mathbb {1}_{A_i\otimes B_i} =\mathbb {1}_H. \notag \end{align}

Its Kraus form gives complete positivity, and the displayed resolution of the identity gives trace preservation.

In sector-adapted coordinates, regroup two sites by

\begin{align} ((l_k,r_k),(l_h,r_h)) & \longmapsto ((l_k,r_h),(r_k,l_h)). \notag \end{align}

Globally this gives the dependent-sum equivalence

\begin{align} \left(\bigoplus _k L_k\otimes R_k\right)^{\! \otimes 2} & \simeq \bigoplus _{k,h}(L_k\otimes R_h)\otimes (R_k\otimes L_h). \notag \end{align}

The forward equivalence prepares the neighboring factors \(R_k\otimes L_h\) for the partial trace in \(\mathcal T_0\); its inverse is the shift \(\mathcal S_2\). These are the reorderings in [ CPGSV16 , Appendix C.2, lines 1521–1522 and 1555–1559 ] .

Definition 26.10.5.32 The two-site partial-trace map \(\mathcal T_0\)

Define \(\mathcal T_0\) by the two-site regrouping followed, in each pair \((k,h)\), by the partial trace over \(R_k\otimes L_h\). Its output is indexed by the retained outer factors \(L_k\otimes R_h\). Thus, writing \(R_{\Phi _2}\) for the regrouping reindexing,

\begin{align} \mathcal T_0 & =\operatorname{CTr}_{(R_k\otimes L_h)_{k,h}}\circ R_{\Phi _2}. \label{eq:rfp_t0_factorization} \end{align}
Theorem 26.10.5.33 \(\mathcal T_0\) is trace-preserving completely positive

The map \(\mathcal T_0\) is trace-preserving and completely positive.

Proof

By (??), \(\mathcal T_0\) is the composition of the controlled dependent partial trace with reindexing along the two-site equivalence. The first map is trace-preserving and completely positive by Theorem 26.10.5.30, and the second by Theorem 26.1.17. Their composition is therefore trace-preserving and completely positive.

The map \(\mathcal S_2\) is matrix reindexing along the inverse two-site equivalence. Thus

\begin{align} ((l_k,r_h),(r_k,l_h)) & \longmapsto ((l_k,r_k),(l_h,r_h)). \notag \end{align}
Theorem 26.10.5.35 \(\mathcal S_2\) is trace-preserving completely positive

The shift \(\mathcal S_2\) is trace-preserving and completely positive.

Proof

If \(\Phi _2\) is the two-site regrouping, then \(\mathcal S_2=R_{\Phi _2^{-1}}\). It is therefore trace-preserving and completely positive by Theorem 26.1.17.

Regroup three sites by

\begin{align} ((l_k,r_k),((l_l,r_l),(l_h,r_h))) & \longmapsto ((l_k,r_h),((r_k,l_l),(r_l,l_h))). \notag \end{align}

Equivalently,

\begin{align} \left(\bigoplus _k L_k\otimes R_k\right)^{\! \otimes 3} & \simeq \bigoplus _{k,h}(L_k\otimes R_h)\otimes \left[\bigoplus _l (R_k\otimes L_l)\otimes (R_l\otimes L_h)\right]. \notag \end{align}

The forward equivalence prepares the four middle subspins for \(\mathcal S_0\); its inverse is the shift \(\mathcal T_2\) in [ CPGSV16 , Appendix C.2, lines 1535–1540 and 1547 ] .

Define \(\mathcal S_0\) by the three-site regrouping followed, for every outer pair \((k,h)\), by the partial trace over

\begin{align} \bigoplus _l(R_k\otimes L_l)\otimes (R_l\otimes L_h). \notag \end{align}

Thus, writing \(R_{\Phi _3}\) for the regrouping reindexing,

\begin{align} \mathcal S_0 & =\operatorname{CTr}_{\left(\bigoplus _l(R_k\otimes L_l)\otimes (R_l\otimes L_h)\right)_{k,h}}\circ R_{\Phi _3}. \label{eq:rfp_s0_factorization} \end{align}
Theorem 26.10.5.38 \(\mathcal S_0\) is trace-preserving completely positive

The map \(\mathcal S_0\) is trace-preserving and completely positive.

Proof

By (??), \(\mathcal S_0\) is the composition of the controlled dependent partial trace with reindexing along the three-site equivalence. The controlled trace and equivalence reindexing are trace-preserving and completely positive by Theorems 26.10.5.30 and 26.1.17, respectively. Their composition has the same property.

Definition 26.10.5.39 The three-site shift \(\mathcal T_2\)

The map \(\mathcal T_2\) is matrix reindexing along the inverse three-site equivalence. On each summand it sends

\begin{align} ((l_k,r_h),((r_k,l_l),(r_l,l_h))) & \longmapsto ((l_k,r_k),((l_l,r_l),(l_h,r_h))). \notag \end{align}
Theorem 26.10.5.40 \(\mathcal T_2\) is trace-preserving completely positive

The shift \(\mathcal T_2\) is trace-preserving and completely positive.

Proof

If \(\Phi _3\) is the three-site regrouping, then \(\mathcal T_2=R_{\Phi _3^{-1}}\). It is therefore trace-preserving and completely positive by Theorem 26.1.17.

For fixed sectors \((k,h)\), define the fiberwise form of \(\mathcal T_0\) by regrouping two sites and tracing \(R_k\otimes L_h\). For fixed \((k,l,h)\), define the fiberwise form of \(\mathcal S_0\) by regrouping three sites and tracing \((R_k\otimes L_l)\otimes (R_l\otimes L_h)\).

Theorem 26.10.5.42 The fiberwise partial traces are trace-preserving completely positive

Every fiberwise form of \(\mathcal T_0\) and \(\mathcal S_0\) is trace-preserving and completely positive.

Proof

The fiberwise forms factor as

\begin{align} \mathcal T_0^{(k,h)} & =\operatorname{tr}_{R_k\otimes L_h}\circ R_{\phi _{k,h}}, \notag \\ \mathcal S_0^{(k,l,h)} & =\operatorname{tr}_{(R_k\otimes L_l)\otimes (R_l\otimes L_h)} \circ R_{\phi _{k,l,h}}, \notag \end{align}

where \(\phi _{k,h}\) is the two-site equivalence of Definition 26.10.5.31 on the \((k,h)\) sector, \(\phi _{k,l,h}\) is the three-site equivalence of Definition 26.10.5.36 on the \((k,l,h)\) sector, and \(R_\phi \) denotes equivalence reindexing. Both factors in each composition are trace-preserving and completely positive, so the composition is as well.

On fixed sector pairs, define \(\mathcal S_2\) and \(\mathcal T_2\) by the same inverse regroupings as the corresponding global shifts.

Theorem 26.10.5.44 The fiberwise shifts are trace-preserving completely positive

Every fiberwise shift is trace-preserving and completely positive.

Proof

The shifts \(\mathcal S_2^{(k,h)}\) and \(\mathcal T_2^{(k,h)}\) are reindexings along the inverse two-site and three-site equivalences of Definitions 26.10.5.31 and 26.10.5.36, respectively. They are therefore trace-preserving and completely positive by Theorem 26.1.17.

To record the domains and codomains, set

\begin{align} \mathcal H^{\Omega }_{k,h} & =\bigoplus _l (B_k^R\otimes B_l^L)\otimes (B_l^R\otimes B_h^L), \notag \end{align}

and introduce the matrix algebras

\begin{align} \mathcal A_2 & =\operatorname{End}\! \left(\left[\bigoplus _j(B_j^L\otimes B_j^R)\right]^{\! \otimes 2}\right), & \mathcal A_{\partial } & =\operatorname{End}\! \left(\bigoplus _{k,h}B_k^L\otimes B_h^R\right), \notag \\ \mathcal A_{\eta } & =\operatorname{End}\! \left(\bigoplus _{k,h}\bigl[(B_k^L\otimes B_h^R)\otimes (B_k^R\otimes B_h^L)\bigr]\right), & \mathcal A_{\Omega } & =\operatorname{End}\! \left(\bigoplus _{k,h}\bigl[(B_k^L\otimes B_h^R)\otimes \mathcal H^{\Omega }_{k,h}\bigr]\right), \notag \\ \mathcal A_3 & =\operatorname{End}\! \left(\left[\bigoplus _j(B_j^L\otimes B_j^R)\right]^{\! \otimes 3}\right). \notag \end{align}

Thus the global maps have types

\begin{align} \mathcal T_0& :\mathcal A_2\to \mathcal A_{\partial }, \notag \\ \mathcal S_2& :\mathcal A_{\eta }\to \mathcal A_2, \notag \\ \mathcal S_0& :\mathcal A_3\to \mathcal A_{\partial }, \notag \\ \mathcal T_2& :\mathcal A_{\Omega }\to \mathcal A_3. \notag \end{align}

The controlled maps \(\mathcal T_0\) and \(\mathcal S_0\) discard coherences between distinct outer-sector pairs. For fixed \((k,h)\), the global map \(\mathcal S_0\) traces the entire carrier \(\mathcal H^{\Omega }_{k,h}\), including its direct sum over \(l\). The shifts \(\mathcal S_2\) and \(\mathcal T_2\) are global reindexings, with all displayed tensor factors present at their inputs [ CPGSV16 , Appendix C.2, lines 1521–1559 ] .

For the fiberwise maps, write

\begin{align} \mathcal A_2^{k,h} & =\operatorname{End}\! \left((B_k^L\otimes B_k^R)\otimes (B_h^L\otimes B_h^R)\right), & \mathcal A_{\partial }^{k,h} & =\operatorname{End}(B_k^L\otimes B_h^R), \notag \\ \mathcal A_{\eta }^{k,h} & =\operatorname{End}\! \left((B_k^L\otimes B_h^R)\otimes (B_k^R\otimes B_h^L)\right), & \mathcal A_{\Omega }^{k,h} & =\operatorname{End}\! \left((B_k^L\otimes B_h^R)\otimes \mathcal H^{\Omega }_{k,h}\right), \notag \\ \mathcal A_3^{k,l,h} & =\operatorname{End}\! \left((B_k^L\otimes B_k^R)\otimes (B_l^L\otimes B_l^R) \otimes (B_h^L\otimes B_h^R)\right), \notag \\ \mathcal A_3^{k,\bullet ,h} & =\operatorname{End}\! \left(\bigoplus _l \bigl[(B_k^L\otimes B_k^R)\otimes (B_l^L\otimes B_l^R) \otimes (B_h^L\otimes B_h^R)\bigr]\right). \notag \end{align}

The map \(\mathcal S_0^{(k,l,h)}\) fixes the middle sector \(l\) before taking the partial trace; it is therefore distinct from the fixed-\((k,h)\) restriction of the global controlled map \(\mathcal S_0\). The four fiberwise types are

\begin{tenkzcd}[maps, species={channel}, row sep=6mm]
    \mathcal A_2^{k,h} & \mathcal A_{\partial}^{k,h} \\
    \mathcal A_{\eta}^{k,h} & \mathcal A_2^{k,h} \\
    \mathcal A_3^{k,l,h} & \mathcal A_{\partial}^{k,h} \\
    \mathcal A_{\Omega}^{k,h} & \mathcal A_3^{k,\bullet,h}
    \tnarrow[from={(1,1)}, to={(1,2)}, species=channel]
      {\mathcal T_0^{(k,h)}}
    \tnarrow[from={(2,1)}, to={(2,2)}, species=channel]
      {\mathcal S_2^{(k,h)}}
    \tnarrow[from={(3,1)}, to={(3,2)}, species=channel]
      {\mathcal S_0^{(k,l,h)}}
    \tnarrow[from={(4,1)}, to={(4,2)}, species=channel]
      {\mathcal T_2^{(k,h)}}
  \end{tenkzcd}

26.10.6 Primitivity and rank-one trace matrices

Definition 26.10.6.1 Explicit \(\eta \)-data from the sector tensors

If every neighboring operator \(\eta _{k,h}\) of Definition 26.10.3.1 is positive semidefinite, the family constitutes explicit neighboring \(\eta \)-data. The source obtains the positivity from the projected chain identity: writing \(\tilde\sigma = U^{\dagger \otimes N} \sigma ^{(N)}({\cal K})\, U^{\otimes N}\) for the \(N\)-site operator in the sector basis and \(Q_k\) for the projector onto the \(k\)-th sector of the physical splitting, every cyclic sector assignment \(k_1,\ldots ,k_N\) (with \(k_{N+1}=k_1\)) satisfies

\begin{align} 0 & \leq [Q_{k_1}\otimes \cdots \otimes Q_{k_N}] \tilde\sigma [Q_{k_1}\otimes \cdots \otimes Q_{k_N}] =\bigotimes _{n=1}^{N}\eta _{k_n,k_{n+1}}, \notag \end{align}

and the sector tensors can be chosen so that each factor is positive semidefinite [ CPGSV16 , Appendix C.2, lines 1446–1450 ] . The all-length sector identity is Theorem 26.10.4.18. That algebraic identity does not by itself choose coherent positive representatives for all neighboring pairs, so positive semidefiniteness remains a hypothesis on the chosen representatives here. Theorem 26.10.4.39 provides the diagonal and paired positivity, and Theorem 26.10.4.42 a rescaled positive family under symmetric support.

Theorem 26.10.6.2 Trace matrix of the sector-tensor \(\eta \)-data

Under the hypotheses of Definition 26.10.6.1, the trace matrix of the explicit \(\eta \)-data is the pairing of the closed sector tensors:

\begin{align} T_{k,h} & =\operatorname{tr}(\eta _{k,h})=(r_k|l_h). \notag \end{align}
Proof

Immediate from Theorem 26.10.4.3 and the definition of the trace matrix.

Theorem 26.10.6.3 Primitivity from returns of lengths two and three

Let \(T\) be a non-negative irreducible matrix on a finite index set. If \((T^2)_{k,k}{\gt}0\) and \((T^3)_{k,k}{\gt}0\) for every index \(k\), then \(T\) is primitive.

Proof

Choose a positive path between every ordered pair of indices, and let \(L\) be the sum of the chosen path lengths. Every chosen length is at most \(L\). For a chosen path of length \(m\), write the difference \(2L+2-m\) as \(2a+3b\) with \(a,b\geq 0\). Appending these returns at the terminal index gives a positive path of common length \(2L+2\) between every ordered pair.

For sector weights \(p_k\), let \(I_*=\{ k:p_k\ne 0\} \). The one-site matrices and their spaces on \(I_*\) are

\begin{align} A_{k;x,y}, \notag \\ {\cal A}_S & =\operatorname{span}\{ A_{k;x,y}:k\in S\} , \qquad S\subseteq I_*. \notag \end{align}

The real trace matrix on this index set is

\begin{align} T^*_{k,h} & =\operatorname{Re}\operatorname{tr}(\eta _{k,h}), \qquad k,h\in I_*. \notag \end{align}

Only the trace matrix is restricted: the physical direct sum still contains every zero-weight summand.

For every sector entry, the one-site matrix used in the directed-cut argument equals the virtual matrix used in the spanning argument. If all sector virtual matrices span \(M_{D}(\mathbb {C})\) and the matrices in every zero-weight sector vanish, then \(\operatorname{span}\{ A_{k;x,y}:k\in I_*\} =M_{D}(\mathbb {C})\).

Suppose that the active one-site matrices span \(M_{D}(\mathbb {C})\) and each active sector contains a nonzero such matrix. For every \(S\subseteq I_*\), \({\cal A}_S+{\cal A}_{I_*\setminus S}=M_{D}(\mathbb {C})\), and both spaces are nonzero when the corresponding sector sets are nonempty. If \(\eta _{k,h}=0\) for \(k\in S\) and \(h\in C\), then \({\cal A}_S{\cal A}_C=0\).

Suppose that the active one-site matrices span \(M_{D}(\mathbb {C})\) and each active sector contains a nonzero such matrix. Then for every \(k,h\in I_*\) there is a directed walk

\begin{align} k=k_0\longrightarrow k_1\longrightarrow \cdots \longrightarrow k_m=h, \notag \end{align}

such that \(\eta _{k_j,k_{j+1}}\ne 0\). In particular, every active sector has an outgoing nonzero neighboring operator.

\begin{align} P_j\mathcal K_iP_{j^\prime } & =0\quad \text{unless }i=j=j^\prime . \notag \end{align}
\begin{tenkz}[rows={op:none, op, op:none}]
            \tn[mpo]{P_j} \\
            \tn[mpo]{\mathcal K_i} \\
            \tn[mpo]{P_{j^\prime}}
        \end{tenkz} \( = 0\quad \text{unless }i=j=j^\prime \)
Figure 26.5 The local-orthogonality contraction of [ CPGSV16 , Appendix C.2, lines 1457–1470 ] . After decomposing the sector trace matrix into primitive components, the source assumes that two components occur, obtains two locally orthogonal summands, and chooses orthogonal projectors \(P_1\) and \(P_2\). The displayed identity gives the cross contractions \(P_1{\cal K}P_2=P_2{\cal K}P_1=0\), and the corresponding two-site contraction also vanishes. For \({\cal A}_i=\operatorname{span}\{ \operatorname{tr}(XP_i{\cal K}P_i):X\} \), these vanishings and injectivity imply \({\cal A}_1+{\cal A}_2=M_{D}(\mathbb {C})\) and \({\cal A}_1{\cal A}_2=0\), a contradiction. Theorem 26.10.6.7 does not construct \(P_1\) or \(P_2\): an arbitrary reachability cut \(I_*=S\sqcup C\) supplies only \({\cal A}_S{\cal A}_C=0\). The common final step is the same one-sided obstruction: two nonzero matrix spaces cannot sum to \(M_{D}(\mathbb {C})\) while their ordered products vanish.

If every neighboring operator is positive semidefinite, then \(T^*\) is entrywise non-negative and \(T^*_{k,h}{\gt}0\Longleftrightarrow \eta _{k,h}\ne 0\).

Suppose that the active one-site matrices span \(M_{D}(\mathbb {C})\) and each active sector contains a nonzero such matrix. For every \(k\in I_*\) there is an \(h\in I_*\) such that

\begin{align} \eta _{k,h}& \ne 0, \notag \\ \eta _{h,k}& \ne 0. \notag \end{align}

If the neighboring operators are positive semidefinite, then \((T^{*2})_{k,k}{\gt}0\).

Theorem 26.10.6.10 Irreducibility of the active trace matrix

Suppose that the neighboring operators are positive semidefinite, the active one-site matrices span \(M_{D}(\mathbb {C})\), and each active sector contains a nonzero such matrix. Then the non-negative matrix \(T^*\) is irreducible.

Suppose that the neighboring operators are positive semidefinite, the active one-site matrices span \(M_{D}(\mathbb {C})\), each active sector contains a nonzero such matrix, and every nonzero edge closes through a third active sector. Then \((T^{*3})_{k,k}{\gt}0\) for every \(k\in I_*\). Together with the length-two returns and irreducibility, this implies that \(T^*\) is primitive.

Proof

Triangle closure supplies a positive closed walk of length three through each active sector. Combine these walks with the length-two returns and apply Theorem 26.10.6.3.

Let \({\cal K}\) be an injective tensor that generates MPDOs and satisfies SAL, and choose the positive semidefinite neighboring operators of Theorem 26.10.4.41. Restrict the sector index to the positive-weight summands of the Hayashi decomposition. Then positive semidefiniteness makes every neighboring trace real and non-negative, and the matrix

\begin{align} T^*_{k,h} & =\operatorname{Re}\operatorname{tr}(\eta _{k,h}) \notag \end{align}

is primitive. Zero-weight summands remain in the physical direct sum but are not indices of \(T^*\).

Proof

First use the zero-weight reparameterization to make every zero-weight sector isolated. Injectivity makes the nonzero-weight one-site matrices span \(M_{D}(\mathbb {C})\), and every such sector contains a nonzero matrix. Hence Theorem 26.10.6.7 gives strong connectivity of the active neighboring support. Its proof is the one-sided directed-cut argument at [ CPGSV16 , Appendix C.2, lines 1463–1470 ] .

Finally, nondegeneracy and cyclicity of the trace pairing give a closed support walk of length two through every active sector. Triangle closure gives one of length three. Strong connectivity together with these two coprime return lengths yields a common length at which every entry of the active trace-matrix power is positive. Thus \(T\) is primitive.

Let \({\cal K}\) be injective and suppose that it satisfies SAL and source zero correlation length. Then there are a physical-sector factorization, weights \(p_k\geq 0\) with \(\sum _k p_k=1\), and positive semidefinite neighboring operators \(\eta _{k,h}\) such that the active trace matrix

\begin{align} T^*_{k,h} & =\operatorname{Re}\operatorname{tr}(\eta _{k,h}), \qquad k,h\in I_*:=\{ j:p_j\ne 0\} , \notag \end{align}

is primitive. There is also a real number \(\lambda {\gt}0\) for which, upon setting \(\widehat T^*:=\lambda ^{-1}T^*\), one has \((\widehat T^*)^2=(\widehat T^*)^3\). For every positive integer \(N\), \(\operatorname{tr}((\widehat T^*)^N)=\operatorname{tr}(\widehat T^*)\). Thus the primitivity and the two normalized identities concern the same active, positively rephased trace matrix. No idempotence, rank-one, or semisimplicity conclusion is asserted.

Proof

Choose the coherent sector phases from Theorem 26.10.6.12. For the resulting factorization, let \(L\) have columns \((\operatorname{tr}((l_h)_\beta ))_\beta \) and let \(Q\) have rows \((\operatorname{tr}((r_k)_\alpha ))_\alpha \), with both indices restricted to \(I_*\). The left tensor vanishes when \(p_k=0\), so the rectangular product \(LQ\) is the full physical-trace transfer. Source zero correlation length therefore makes \(\lambda ^{-1}LQ\) idempotent for some \(\lambda {\gt}0\).

Positivity of the neighboring operators makes their traces real, and hence \(QL\) is the complexification of \(T^*\). Associativity and cyclicity of trace give, for every \(N\geq 1\),

\begin{align} (\lambda ^{-1}QL)^2 & =(\lambda ^{-1}QL)^3, \notag \\ \operatorname{tr}((\lambda ^{-1}QL)^N) & =\operatorname{tr}(\lambda ^{-1}QL). \notag \end{align}

Injectivity of the real-to-complex inclusion gives the two real matrix identities.

There is a tensor of bond dimension two with four one-dimensional physical sectors and weights \(p_k\) such that the following statements hold simultaneously: the tensor is injective and has source zero correlation length; its physical-trace transfer is idempotent; for every \(k\in \{ 0,1,2,3\} \), the weights satisfy

\begin{align} p_k& =\frac14, \notag \\ 0& \leq p_k, \notag \\ \sum _{k=0}^{3}p_k& =1; \notag \end{align}

its sector virtual matrices span \(M_{2}(\mathbb {C})\); every neighboring operator is positive semidefinite; and its active trace matrix is primitive and has trace one. Nevertheless, if \(S=LQ\) is the physical-trace transfer and \(T=QL\) is the active trace matrix, then \(Q(1-S)L=T-T^2\ne 0\). In particular, full virtual-matrix spanning does not by itself imply that the active trace matrix is idempotent.

Proof

Take

\begin{align} L& =\begin{pmatrix} \frac14 & \frac14 & \frac14 & \frac14 \\ 1 & -1 & 1 & -1 \end{pmatrix}, \notag \\ Q& =\begin{pmatrix} 1 & \frac18 \\ 1 & \frac18 \\ 1 & -\frac18 \\ 1 & -\frac18 \end{pmatrix}. \notag \end{align}

For each \(k\), the \(k\)th sector virtual matrix is the outer product of the \(k\)th column of \(L\) with the \(k\)th row of \(Q\). Their four coordinate functions are proportional to the Walsh functions \(1,x,y,xy\) on four points. More explicitly, the matrix whose columns are their coordinates in the order \((00,01,10,11)\) has determinant \(-1/64\). Hence they form a basis of \(M_{2}(\mathbb {C})\). Placing them on the diagonal physical entries gives an injective tensor and a physical-sector factorization with scalar sectors.

Direct multiplication gives

\begin{align} LQ & =\begin{pmatrix} 1 & 0 \\ 0 & 0 \end{pmatrix}, \notag \\ QL & =\begin{pmatrix} \frac38 & \frac18 & \frac38 & \frac18 \\ \frac38 & \frac18 & \frac38 & \frac18 \\ \frac18 & \frac38 & \frac18 & \frac38 \\ \frac18 & \frac38 & \frac18 & \frac38 \end{pmatrix}. \notag \end{align}

Thus \(LQ\) is idempotent, whereas every entry of \(QL\) is strictly positive, so \(QL\) is primitive. Its trace is one. Since each sector is one-dimensional, the neighboring operators are the scalar matrices \(\eta _{k,h}=\begin{pmatrix} (QL)_{k,h} \end{pmatrix}\succeq 0\).

The \((0,1)\) entry of \((QL)^2\) is \(1/4\), while the corresponding entry of \(QL\) is \(1/8\). Hence \(QL\) is not idempotent, and associativity gives \(Q(1-LQ)L=QL-(QL)^2\ne 0\).

Theorem 26.10.6.15 Positivity of bipartite partial traces

If \(\rho \) is positive semidefinite on a bipartite space \(A \otimes B\), then both reduced operators \(\operatorname{tr}_A \rho \) and \(\operatorname{tr}_B \rho \) are positive semidefinite.

Proof

Write each partial trace as the finite sum, over the traced index, of a principal submatrix of \(\rho \). Principal submatrices of a positive semidefinite matrix are positive semidefinite, and finite sums of positive semidefinite matrices remain positive semidefinite.

Definition 26.10.6.16 Hayashi–Markov extraction of explicit \(\eta \)-operators

Every Hayashi decomposition witness \(h_\eta \) canonically produces an explicit neighboring \(\eta \)-family by Kronecker-multiplying the sector-reduced states on the neighboring bond spaces:

\begin{align} \eta _{k,h} & :=\operatorname{tr}_C(\rho _{b_2 C}^{(k)}) \otimes \operatorname{tr}_A(\rho _{A b_1}^{(h)}). \notag \end{align}

Positive semidefiniteness of each \(\eta _{k,h}\) follows from the fact that partial traces preserve positivity and that positive semidefiniteness is closed under Kronecker products. This is the sector-reduced extraction; the remaining connection to [ CPGSV16 , Appendix C.2 ] is the identification of this family with the inverse-map construction in the original simple-MPDO tensor coordinates.

The trace matrix induced by the extracted family is entrywise \(T_{k,h}=1\) in both its complex-valued form and its real-valued form. If there are \(m\) sectors, then \(T=\mathbf{1}\mathbf{1}^{\mathsf T}\) and \(\operatorname{tr}(T)=m\).

Proof

Each \(\rho _{b_2 C}^{(k)}\) is a density matrix, hence has unit trace; the partial trace \(\operatorname{tr}_C\) preserves the trace. The analogous statement holds for \(\operatorname{tr}_A \rho _{A b_1}^{(h)}\). Multiplicativity of the trace under Kronecker products gives \(T_{k,h}=1\cdot 1=1\), and taking real parts gives the real-valued statement. Summing the \(m\) diagonal entries gives \(\operatorname{tr}(T)=m\).

Theorem 26.10.6.18 Positive semidefiniteness of the Hayashi–Markov trace matrix

The real trace matrix of the sector-reduced family is positive semidefinite.

Proof

This trace matrix is the all-ones matrix \(\mathbf{1}\mathbf{1}^{\mathsf T}\), hence is positive semidefinite.

Theorem 26.10.6.19 Entrywise nonnegativity of the real trace matrix

Positivity of the neighboring operators gives entrywise nonnegativity of the real trace matrix. Matrix-level positive semidefiniteness of \(T\) is a separate structural condition.

Proof

The trace of a positive semidefinite neighboring operator is non-negative in the complex order. Taking real parts gives the stated entrywise nonnegativity.

Definition 26.10.6.20 Auxiliary matrix predicates for the rank-one step

The auxiliary predicates state two matrix-theoretic ingredients used in the rank-one step of [ CPGSV16 , Appendix C.2, Lemma C.5 ] : constant traces of all positive powers and existence of a rank-one factorization \(T=ab^\top \).

The proposed implication from primitivity and constant trace powers to a rank-one factorization is not a valid general theorem. A concrete \(3\times 3\) counterexample appears in the archive. The corrected criterion proved here adds positive semidefiniteness and trace normalization, which provide the diagonalizability needed to turn the trace-power condition into a rank-one factorization.

Theorem 26.10.6.21 Trace square of a Hermitian matrix

Let \(T\) be a finite Hermitian matrix over a real or complex scalar field, with Hermitian eigenvalues \(\lambda _i\). Then \(\operatorname{tr}(T^2)=\sum _i\lambda _i^2\).

Proof

The spectral theorem writes \(T\) as a unitary conjugate of the diagonal matrix of its Hermitian eigenvalues. Squaring commutes with this conjugation, and cyclicity of trace reduces the identity to the trace of the squared diagonal matrix.

Theorem 26.10.6.22 Rank-one eigenvector resolution of a Hermitian matrix

Let \(A\) be a finite Hermitian matrix. Choose an orthonormal eigenbasis \((u_k)_k\) with eigenvalues \((\lambda _k)_k\), and let \(E_k=|u_k\rangle \! \langle u_k|\) be the rank-one projection onto \(u_k\). Then \(A=\sum _k\lambda _kE_k\).

Proof

The finite-dimensional spectral theorem gives \(A=U\operatorname{diag}(\lambda _k)U^\dagger \), where the columns of \(U\) are the vectors \(u_k\). Expanding the diagonal matrix as the sum of its rank-one coordinate projections gives the stated identity.

Theorem 26.10.6.23 PSD trace-power rank-one criterion

Let \(T\) be a finite real square matrix. If \(T\) is positive semidefinite, normalized by \(\operatorname{tr}(T)=1\), and has constant traces on all positive powers, then \(T\) has a rank-one factorization.

Proof

The spectral theorem diagonalizes the positive semidefinite matrix with non-negative real eigenvalues. The trace gives that their sum is \(1\), while the second trace moment gives that the sum of their squares is also \(1\). Hence exactly one eigenvalue is equal to \(1\) and all others vanish, so the diagonal form is rank one. Unitary conjugation preserves the existence of an outer-product factorization.

Theorem 26.10.6.24 Idempotent trace-one criterion

Let \(T\) be a finite real square matrix. If \(T^2=T\) and \(\operatorname{tr}(T)=1\), then there are real vectors \(a,b\) such that \(T=ab^\top \).

Proof

For an idempotent endomorphism \(f\), one has \(\operatorname{tr}(f)=\dim (\operatorname{range}(f))\). Hence the range of \(T\) has dimension one. Choosing a nonzero vector \(a\) spanning it expresses every column of \(T\) as \(b_j a\) for a scalar \(b_j\), and therefore \(T=ab^\top \).

Theorem 26.10.6.25 Constant trace powers of an idempotent matrix

Let \(T\) be a finite real square matrix with \(T^2=T\). Then, for every positive integer \(N\), one has \(\operatorname{tr}(T^N)=\operatorname{tr}(T)\). This recovers the trace identity displayed in the proof of [ CPGSV16 , Appendix C.2, Lemma C.5 ] from idempotence.

Proof

Induction on \(N\): for \(N\geq 1\), one has \(T^{N+1}=T^NT=TT=T\), so every positive power of \(T\) equals \(T\).

Theorem 26.10.6.26 Positive entries in every row and column of a primitive matrix

Let \(T\) be a primitive non-negative matrix. Then every row of \(T\) contains a strictly positive entry, and so does every column.

Proof

If row \(k\) of \(T\) vanishes, then, for every \(m\geq 1\),

\begin{align} (T^m)_{k,k} & =\sum _jT_{k,j}(T^{m-1})_{j,k}=0, \notag \end{align}

contradicting the strict entrywise positivity of some power of \(T\). Likewise, if column \(h\) of \(T\) vanishes, then, for every \(m\geq 1\),

\begin{align} (T^m)_{h,h} & =\sum _j(T^{m-1})_{h,j}T_{j,h}=0, \notag \end{align}

again contradicting the strict positivity of some power of \(T\).

Theorem 26.10.6.27 Rank of a strictly positive idempotent

Let \(I\) be a nonempty finite index set, and let \(P\) be a real matrix indexed by \(I\times I\). Suppose that \(P^2=P\) and \(P_{i,j}{\gt}0\) for every \(i,j\in I\). Then \(\operatorname{rank}(P)=1\).

Proof

Put \(u=P\mathbf1\), so every coordinate of \(u\) is positive and \(Pu=u\). For a fixed vector \(x\) satisfying \(Px=x\), choose an index \(k\) at which \(x_i/u_i\) is maximal and put \(c=x_k/u_k\). Then \(y=cu-x\) is non-negative, \(y_k=0\), and \(Py=y\). Hence

\begin{align} 0=y_k=(Py)_k=\sum _jP_{k,j}y_j. \notag \end{align}

Since every \(P_{k,j}\) is strictly positive, all coordinates of \(y\) vanish. Thus every fixed vector is proportional to \(u\). The range of an idempotent is its fixed space, so it is one-dimensional.

Theorem 26.10.6.28 Rank and factorization of a stationary primitive square

Let \(T\) be a primitive real \(N\times N\) matrix, where \(N\geq 1\). Multiplication by a positive scalar preserves primitivity. If \(T^2=T^3\), then \(\operatorname{rank}(T^2)=1\). There are vectors \(a,b\in \mathbb R^N\) such that

\begin{align} T^2& =ab^{\mathsf T}, \notag \\ \sum _i a_i b_i& =1. \notag \end{align}

This finite-dimensional matrix lemma supports the argument sought at [ CPGSV16 , Appendix C.2, line 1613 ] ; it is not a theorem asserted there.

Proof

Primitivity gives \(m\geq 1\) such that \((T^m)_{i,j}{\gt}0\) for every \(i,j\). Stabilization gives \(T^{2m}=T^2\). Thus, for every \(i,j\),

\begin{align} (T^2)_{i,j} & =(T^{2m})_{i,j} =\sum _k(T^m)_{i,k}(T^m)_{k,j}{\gt}0. \notag \end{align}

The same stabilization identity gives \((T^2)^2=T^2\). The preceding theorem applied to \(P=T^2\) now gives the conclusion. Since an idempotent has trace equal to its rank, \(\operatorname{tr}(T^2)=1\). Factoring its one-dimensional range gives \(T^2=ab^{\mathsf T}\), and taking the trace yields \(\sum _i a_i b_i=1\).

Theorem 26.10.6.29 Idempotence of the sector trace matrix

Let \(V\) be a module over a commutative ring, let \(l_1,\ldots ,l_n\in V\), let \(r_1,\ldots ,r_n\) be linear functionals on \(V\), and let \(T_{k,h}=(r_k|l_h)\) be the pairing matrix; for the tensors of [ CPGSV16 , Appendix C.2 ] this is the sector trace matrix. Assume the identity

\begin{align} \sum _k|l_k)(r_k| & =\sum _{k,h}T_{k,h}\, |l_k)(r_h|, \notag \end{align}

whose right-hand side is the square of its left-hand side, so that the operator \(M=\sum _k|l_k)(r_k|\) satisfies \(M^2=M\). If the vectors \(l_1,\ldots ,l_n\) are linearly independent, then \(T^2=T\). The same conclusion holds if instead the functionals \(r_1,\ldots ,r_n\) are linearly independent.

Proof

Evaluating \(M^2v=Mv\) at an arbitrary \(v\in V\) gives

\begin{align} \sum _k((r_k|Mv)-(r_k|v))\, l_k=0, \notag \end{align}

so linear independence of the \(l_k\) yields \((r_k|Mv)=(r_k|v)\) for all \(k\) and \(v\). Taking \(v=l_h\) and expanding \(Ml_h=\sum _jT_{j,h}\, l_j\) turns the left-hand side into \(\sum _jT_{k,j}T_{j,h}=(T^2)_{k,h}\) and the right-hand side into \(T_{k,h}\). For linearly independent functionals, apply the same argument in the dual space, with the \(r_k\) as vectors and evaluation at \(l_k\) as functionals. The dual pairing matrix therefore satisfies \((T^\top )^2=T^\top \). Taking transposes gives \(T^2=T\).

Equivalently, the zero-correlation-length identity is the algebraic equality

\begin{align} \sum _k|l_k)(r_k| & =\sum _{k,h}T_{k,h}\, |l_k)(r_h|, & T_{k,h}& =(r_k|l_h), \notag \end{align}

which is the displayed identity of [ CPGSV16 , Appendix C.2, lines 1490–1493 ] .

Let \(V\) be a real vector space, let \(l_1,\ldots ,l_n\in V\), let \(r_1,\ldots ,r_n\) be real linear functionals on \(V\), and let \(T_{k,h}=(r_k|l_h)\) be the pairing matrix, as in Theorem 26.10.6.29. Assuming only the identity \(M^2=M\) for the operator \(M=\sum _k|l_k)(r_k|\), without assuming linear independence of \(l_1,\ldots ,l_n\) or of \(r_1,\ldots ,r_n\), one has the following identities: the first unconditionally, the second for every \(N\geq 2\), and the third for every positive integer \(N\):

\begin{align} T^2& =T^3, \notag \\ T^N& =T^2, \notag \\ \operatorname{tr}(T^N)& =\operatorname{tr}(T). \notag \end{align}
Proof

Multiplying the identity \(M^2=M\) on the left by the functional map and on the right by the coefficient map turns the two sides directly into \(T^2\) and \(T^3\), with no independence hypothesis; induction then gives \(T^N=T^2\) for every \(N\geq 2\). For the trace identity, restrict the operator \(M\) to the finite-dimensional span of \(l_1,\ldots ,l_n\): there it is an idempotent endomorphism of a finite free module, and cyclicity of the trace of a composition between that span and the coefficient space identifies \(\operatorname{tr}(T)\) with the trace of the restriction and \(\operatorname{tr}(T^2)\) with the trace of its square, which agree since the restriction is idempotent.

Theorem 26.10.6.31 Rank-one factorization of the sector trace matrix

In the setting of Theorem 26.10.6.29 with real scalars and linearly independent vectors \(l_1,\ldots ,l_n\), if in addition \(\operatorname{tr}(T)=1\), then there are real vectors \(a,b\) such that \(T=ab^\top \). This is the factorization \(T_{k,h}=a_kb_h\) obtained in the proof of [ CPGSV16 , Appendix C.2, Lemma C.5 ] for the sector trace matrix, derived here from the displayed zero-correlation-length identity together with the linear independence of the \(l_k\), instead of the Perron–Frobenius trace-power argument of the source.

Proof

Theorem 26.10.6.29 gives \(T^2=T\), and the idempotent trace-one criterion of Theorem 26.10.6.24 gives the factorization \(T=ab^\top \).

Theorem 26.10.6.32 PSD-corrected rank-one \(T\) criterion

Let \(T\) be a finite real square matrix. Assume that \(T\) is primitive, positive semidefinite, normalized by \(\operatorname{tr}(T)=1\), and has constant traces on all positive powers. Then \(T=ab^\top \) for some vectors \(a\) and \(b\), with \(a\cdot b=1\).

Proof

The positive-semidefinite matrix criterion diagonalizes \(T\), uses the first two trace moments to show that exactly one eigenvalue is nonzero, and hence gives the factorization. Taking traces and using \(\operatorname{tr}(ab^\top )=a\cdot b\) gives the normalization \(a\cdot b=1\).

Definition 26.10.6.33 Sector tensors paired into the sector trace matrix
#

For a real \(n\times n\) matrix \(T\) and a real vector space \(V\), this structure consists of vectors \(|l_0),\ldots ,|l_{n-1})\in V\) and linear functionals \((r_0|,\ldots ,(r_{n-1}|\) on \(V\) satisfying the pairing identity \(T_{k,h}=(r_k|l_h)\) of [ CPGSV16 , Appendix C.2 ] together with the zero-correlation-length identity

\begin{align} \sum _k|l_k)(r_k| & =\sum _{k,h}T_{k,h}\, |l_k)(r_h|, \notag \end{align}

displayed in the proof of [ CPGSV16 , Lemma C.5 ] . The vectors are the closed sector tensors obtained there from the sector splitting of an injective simple tensor.

Theorem 26.10.6.34 Idempotence of the sector trace matrix from the zero-correlation-length identity

For sector tensors paired into \(T\) as in Definition 26.10.6.33, the operator \(M=\sum _k|l_k)(r_k|\) satisfies \(M^2=M\). If in addition the vectors \(|l_0),\ldots ,|l_{n-1})\) are linearly independent, then \(T^2=T\).

Proof

Substituting \(T_{k,h}=(r_k|l_h)\) into the right-hand side of the zero-correlation-length identity gives, for every \(v\in V\),

\begin{align} \sum _{k,h}T_{k,h}(r_h|v)\, |l_k) & =\sum _{k,h}(r_k|l_h)(r_h|v)\, |l_k) =\sum _k(r_k|Mv)\, |l_k) =M^2v, \notag \end{align}

so \(M^2=M\). Linear independence of the \(|l_k)\) then gives \(T^2=T\) by Theorem 26.10.6.29.

Theorem 26.10.6.35 Unconditional constant trace powers of the sector trace matrix

For sector tensors paired into \(T\) as in Definition 26.10.6.33, without any independence hypothesis on the closed sector tensors or the functionals, one has \(T^2=T^3\), and, for every positive integer \(N\), \(\operatorname{tr}(T^N)=\operatorname{tr}(T)\).

Proof

The operator identity \(M^2=M\) established in the proof of Theorem 26.10.6.34 gives \(T^2=T^3\) and the constant trace powers by Theorem 26.10.6.30, with no independence hypothesis.

Theorem 26.10.6.36 Nonvanishing and independence of the sector tensors

Suppose the sector trace matrix \(T\) of Definition 26.10.6.33 is primitive. Then every closed sector tensor satisfies \(|l_k)\neq 0\). If, in addition, each \(|l_k)\) lies in its own member of an independent family of subspaces of \(V\), then the vectors \(|l_0),\ldots ,|l_{n-1})\) are linearly independent.

Proof

By Theorem 26.10.6.26, some entry of the \(k\)-th column of \(T\) is positive, and that entry is the pairing \((r_j|l_k)\), so \(|l_k)\neq 0\). Nonzero vectors chosen from an independent family of subspaces, one from each member, are linearly independent.

Let \(T\) be a sector trace matrix with \(\operatorname{tr}(T)=1\), paired from sector tensors satisfying the zero-correlation-length identity of Definition 26.10.6.33. If the closed sector tensors \(|l_0),\ldots ,|l_{n-1})\) are linearly independent, then there are real numbers \(a_k,b_h\) such that

\begin{align} T_{k,h}& =a_kb_h, \notag \\ \sum _k a_kb_k& =1. \notag \end{align}

The same conclusion holds if, instead of the independence, \(T\) is primitive and the closed sector tensors lie in distinct members of an independent family of subspaces. In contrast with the positive-semidefinite criterion of Theorem 26.10.6.32, the constant trace powers are derived rather than assumed.

Proof

Theorem 26.10.6.34 gives \(T^2=T\), and Theorem 26.10.6.35 gives the constant trace powers unconditionally. The idempotent trace-one criterion of Theorem 26.10.6.24 yields the factorization \(T=ab^\top \), and taking traces gives \(\sum _k a_kb_k=\operatorname{tr}(T)=1\). When the independence is not assumed directly, Theorem 26.10.6.36 derives it from primitivity once each sector tensor lies in its own member of an independent family of subspaces.

26.10.7 Refinement and coarse-graining channels

On a sector pair with \(a_kb_h\ne 0\), set \(\widehat\Omega _{k,h}=(a_kb_h)^{-1}\Omega _{k,h}\). If \(a_kb_h=0\), positivity and vanishing trace imply \(\Omega _{k,h}=0\); choose any density operator on that summand and denote the resulting completed density by \(\overline\Omega _{k,h}\). The sectorwise preparation is \(X\longmapsto X\otimes \overline\Omega _{k,h}\). Taking the orthogonal direct sum over the outer sectors \((k,h)\) gives the preparation stage \(\mathcal T_1\) of [ CPGSV16 , Appendix C.2, lines 1523–1535 ] . The zero-weight choice makes the source map total without imposing a nonzero-weight hypothesis.

The normalized density is positive semidefinite and has trace one on every active pair. The density chosen on an inactive pair is positive definite and has trace one. Hence \(\overline\Omega _{k,h}\) is positive semidefinite with trace one for every pair, and agrees with \(\widehat\Omega _{k,h}\) on active pairs. The corresponding sectorwise and controlled maps prepare these densities on their diagonal summands.

Each completed preparation is trace-preserving and completely positive. The same holds for their orthogonally controlled direct sum.

Proof

On an active pair, \(\operatorname{tr}(\widehat\Omega _{k,h})=(a_kb_h)^{-1}a_kb_h=1\); the chosen density on a zero-weight pair also has trace one. Preparation by a positive operator of trace one is trace-preserving and completely positive. The orthogonal control discards coherences between distinct outer-sector pairs and applies these preparations on the diagonal summands.

Definition 26.10.7.5 The refinement channel \(\mathcal T\)

Define the channel from two physical sites to three physical sites by \(\mathcal T=\mathcal T_2\mathcal T_1\mathcal T_0\). Thus \(\mathcal T_0\) traces the neighboring subspins, \(\mathcal T_1\) adjoins the completed three-site neighboring density, and \(\mathcal T_2\) restores the three complete physical sectors. This is the refinement map in [ CPGSV16 , Appendix C.2, lines 1522–1545 ] .

Theorem 26.10.7.6 \(\mathcal T\) is trace-preserving completely positive

The refinement channel \(\mathcal T\) is trace-preserving and completely positive.

Proof

Each constituent map is trace-preserving and completely positive, and this property is preserved under composition.

Applied to the two-site closure, on the active \((k,h)\)-block, \(\mathcal T_0\) traces \(B_k^R\otimes B_h^L\) and sends \(\mathfrak R_2(\mathcal K_2(X))_{k,h}\) to \(a_kb_hB_{k,h}(X)\) on \(B_k^L\otimes B_h^R\). The preparation \(\mathcal T_1\) then adjoins

\begin{align} \widehat\Omega _{k,h} & =(a_kb_h)^{-1}\bigoplus _l (\eta _{k,l}\otimes \eta _{l,h}), \notag \end{align}

and \(\mathcal T_2\) orders the result as

\begin{align} (B_k^L\otimes B_k^R)\otimes (B_l^L\otimes B_l^R) \otimes (B_h^L\otimes B_h^R). \notag \end{align}

The refinement uses the sitewise sector coordinates \(\mathfrak R_2\) and \(\mathfrak R_3\) [ CPGSV16 , Appendix C.2, lines 1510–1516 and 1522–1545 ] . For each outer pair, write

\begin{align} \mathcal H^{\Omega }_{k,h} & =\bigoplus _l (B_k^R\otimes B_l^L)\otimes (B_l^R\otimes B_h^L) \notag \end{align}

for the carrier Hilbert space of \(\Omega _{k,h}\). The symbols \(\widehat\Omega _{k,h}\) and \(\overline\Omega _{k,h}\) denote respectively its normalized active density and its completed density on every sector pair. With the matrix algebras introduced above, the refinement stages have type

\begin{tenkzcd}[maps, species={channel}]
    \mathcal A_2 &
    \mathcal A_{\partial} &
    \mathcal A_{\Omega} &
    \mathcal A_3
    \tnarrow[from={(1,1)}, to={(1,2)}, species=channel]{\mathcal T_0}
    \tnarrow[from={(1,2)}, to={(1,3)}, species=channel]{\mathcal T_1}
    \tnarrow[from={(1,3)}, to={(1,4)}, species=channel]{\mathcal T_2}
  \end{tenkzcd}

Here \(\mathcal T_1\) adjoins \(\overline\Omega _{k,h}\) on each diagonal outer-sector summand. The composite channel has type

\begin{tenkzcd}[maps, species={channel}]
    \mathcal A_2 & \mathcal A_3
    \tnarrow[from={(1,1)}, to={(1,2)}, species=channel]{\mathcal T}
  \end{tenkzcd}
Definition 26.10.7.7 The neighboring-state preparation \(\mathcal S_1\)
#

On a sector pair with \(a_kb_h\ne 0\), let \(\mathcal S_{k,h}(X)=X\otimes \frac{\eta _{k,h}}{a_kb_h}\). If \(a_kb_h=0\), positivity and vanishing trace imply \(\eta _{k,h}=0\); choose any density operator on that unused summand. Taking the orthogonal direct sum over \((k,h)\) defines \(\mathcal S_1\).

The map \(\mathcal S_1\) is trace-preserving and completely positive.

Definition 26.10.7.9 The coarse-graining channel \(\mathcal S\)

Define the channel from three physical sites to two physical sites by \(\mathcal S=\mathcal S_2\mathcal S_1\mathcal S_0\). This is the coarse-graining map in Proposition C.7 [ CPGSV16 , Appendix C.2, lines 1547–1563 ] .

Theorem 26.10.7.10 \(\mathcal S\) is trace-preserving completely positive

The channel \(\mathcal S\) is trace-preserving and completely positive.

Proof

Each of the three factors is trace-preserving and completely positive, and this property is preserved under composition.

The coordinate equivalences used by the coarse-graining channel expose the direct sums over site-sector pairs and triples. Write \(\mathfrak R_2\) and \(\mathfrak R_3\) for the corresponding matrix reindexings. Their inverses send every sector block to the corresponding physical matrix entries. These reindexings preserve the left-right order within every physical site. They differ from the regrouped coordinates \(\mathfrak G_2\) and \(\mathfrak G_3\) of Definition 26.10.3.27, which place the two outer subspins before the neighboring subspins. If \(R_{\Phi _2}\) and \(R_{\Phi _3}\) denote the two regrouping maps, then

\begin{align} \mathfrak G_2& =R_{\Phi _2}\mathfrak R_2, \notag \\ \mathfrak G_3& =R_{\Phi _3}\mathfrak R_3. \notag \end{align}

For every virtual matrix \(X\) and outer-sector pair \((k,h)\),

\begin{align} \left[R_{\Phi _3}\mathfrak R_3(\mathcal K_3(X))\right]_{(k,h),(k,h)} & =B_{k,h}(X)\otimes \Omega _{k,h}. \notag \end{align}
Proof

On the summand labelled by the middle sector \(l\), this is the fixed-sector factorization \(B_{k,h}(X)\otimes (\eta _{k,l}\otimes \eta _{l,h})\). Taking the direct sum over \(l\) gives the stated block.

Theorem 26.10.7.13 Off-diagonal outer-sector entries of the three-site closure

Every matrix entry of \(R_{\Phi _3}\mathfrak R_3(\mathcal K_3(X))\) between distinct outer-sector pairs \((k,h)\ne (p,q)\) vanishes.

Proof

Distinct outer-sector pairs differ either in their first sector or in their third sector. In the corresponding physical slice, the sector-coordinate tensor is block diagonal, so that factor vanishes.

For every virtual matrix \(X\) and outer-sector pair \((k,h)\),

\begin{align} \left[R_{\Phi _2}\mathfrak R_2(\mathcal K_2(X))\right]_{(k,h),(k,h)} & =B_{k,h}(X)\otimes \eta _{k,h}. \notag \end{align}
Proof

This is the fixed-sector two-site factorization after identifying the sitewise sector coordinates with the regrouped boundary and neighboring coordinates.

Theorem 26.10.7.15 Diagonal-block action of \(\mathcal T_0\)

For every two-site matrix \(Y\), outer-sector pair \((k,h)\), and boundary indices \(a,b\),

\begin{align} [\mathcal T_0(Y)]_{(k,h,a),(k,h,b)} & = \left[\operatorname{tr}_{R_k\otimes L_h} \left([R_{\Phi _2}Y]_{(k,h),(k,h)}\right)\right]_{a,b}. \notag \end{align}
Proof

The controlled partial trace acts on a diagonal outer-sector block by the ordinary partial trace over its neighboring factor.

If the \((k,h)\) diagonal block of \(R_{\Phi _2}Y\) is \(B\otimes \eta _{k,h}\), then \([\mathcal T_0(Y)]_{(k,h),(k,h)}=a_kb_hB\).

Proof

The partial trace of \(B\otimes \eta _{k,h}\) is \(\operatorname{tr}(\eta _{k,h})B=a_kb_hB\).

For every outer-sector pair \((k,h)\) and boundary matrix \(B\), the completed sectorwise preparation satisfies \(\overline{\mathcal T}_{k,h}(a_kb_hB) =B\otimes \Omega _{k,h}\).

Proof

If \(a_kb_h\ne 0\), the scalar cancels the normalization in \(\widehat\Omega _{k,h}=(a_kb_h)^{-1}\Omega _{k,h}\). If \(a_kb_h=0\), both sides vanish because \(\Omega _{k,h}=0\).

Theorem 26.10.7.18 Diagonal-block action of \(\mathcal T_1\)

If the \((k,h)\) diagonal block of a boundary matrix \(Y\) is \(a_kb_hB\), then \([\mathcal T_1(Y)]_{(k,h),(k,h)} =B\otimes \Omega _{k,h}\).

Proof

On a diagonal outer-sector block, the controlled map is the completed sectorwise preparation, to which the preceding theorem applies.

Theorem 26.10.7.19 Off-diagonal action of \(\mathcal T_1\)

The map \(\mathcal T_1\) annihilates every matrix entry between distinct outer-sector pairs.

Proof

This is the orthogonal control in the definition of \(\mathcal T_1\).

Theorem 26.10.7.20 Reindexing action of \(\mathcal T_2\)

Let \(\Phi _3\) be the three-site regrouping. For every prepared matrix \(Y\) and three-site indices \(p,q\), \([\mathcal T_2(Y)]_{p,q}=Y_{\Phi _3(p),\Phi _3(q)}\).

Proof

This is matrix reindexing along the inverse regrouping \(\Phi _3^{-1}\).

Assume the neighboring-operator trace factorization of Definition 26.10.3.24. For every virtual matrix \(X\), in the canonical physical-sector coordinates selected by the isometry \(U\), the refinement channel satisfies

\begin{align} \mathcal T(\mathfrak R_2(\mathcal K_2(X))) & =\mathfrak R_3(\mathcal K_3(X)). \label{eq:rfp_t_closure} \end{align}

This is the refinement half of Proposition C.7 [ CPGSV16 , Appendix C.2, lines 1510–1516 and 1522–1545 ] .

Proof

The regrouping contained in \(\mathcal T_0\) changes \(\mathfrak R_2\) into \(\mathfrak G_2\). On the \((k,h)\) diagonal block, the partial trace then gives

\begin{align} \mathcal T_0 (\mathfrak R_2(\mathcal K_2(X)))_{k,h} & =a_kb_hB_{k,h}(X). \notag \end{align}

On an active pair, \(\mathcal T_1\) adjoins \((a_kb_h)^{-1}\Omega _{k,h}\), and hence

\begin{align} \mathcal T_1\mathcal T_0 (\mathfrak R_2(\mathcal K_2(X)))_{k,h} & =B_{k,h}(X)\otimes \Omega _{k,h}. \notag \end{align}

If \(a_kb_h=0\), both sides vanish because \(\Omega _{k,h}=0\). After the canonical reassociation of the intermediate sector sum, these are precisely the diagonal blocks of \(\mathfrak G_3(\mathcal K_3(X))\); all off-diagonal sector blocks vanish. Finally, the inverse regrouping \(\mathcal T_2\) changes \(\mathfrak G_3\) into \(\mathfrak R_3\), which gives (??).

Assume the neighboring-operator trace factorization of Definition 26.10.3.24. For every virtual matrix \(X\), in the canonical physical-sector coordinates selected by the isometry \(U\), the coarse-graining channel satisfies

\begin{align} \mathcal S(\mathfrak R_3(\mathcal K_3(X))) & =\mathfrak R_2(\mathcal K_2(X)). \label{eq:rfp_s_closure} \end{align}
Proof

On the \((k,h)\) diagonal block, \(\mathcal S_0\) traces \(\Omega _{k,h}\) and gives \(a_kb_hB_{k,h}(X)\). On an active sector pair, \(\mathcal S_1((a_kb_h)B_{k,h}(X)) =B_{k,h}(X)\otimes \eta _{k,h}\). If \(a_kb_h=0\), positivity and zero trace give \(\eta _{k,h}=0\), so both sides of this identity vanish. Finally, \(\mathcal S_2\) regroups the four factors into two physical sites. For distinct sector pairs \((k,h)\ne (p,q)\),

\begin{align} (\mathcal S_1Y)_{(k,h),(p,q)}& =0, \notag \\[\mathfrak R_2(\mathcal K_2(X))]_{(k,h),(p,q)}& =0. \notag \end{align}

These diagonal and off-diagonal identities give (??).

For the following construction, through Theorem 26.10.7.42, assume the neighboring-operator trace factorization of Definition 26.10.3.24. Write \(q=\dim \! \left(\bigoplus _k L_k\otimes R_k\right)\) for the physical dimension of the sector-coordinate tensor \(\widehat{\mathcal K}\).

Definition 26.10.7.23 Refinement in ordinary physical coordinates

Transporting \(\mathcal T\) through the canonical two-site and three-site coordinate identifications gives a channel \(\widehat{\mathcal T}:M_{q^2}(\mathbb {C})\longrightarrow M_{q^3}(\mathbb {C})\), where all multiple physical indices are associated to the right.

Theorem 26.10.7.24 The physical refinement map is a channel

The map \(\widehat{\mathcal T}\) is trace-preserving and completely positive.

Proof

The coordinate identifications are unitary permutation channels. Composing them with a trace-preserving completely positive map preserves both properties.

Theorem 26.10.7.25 Refinement identity in ordinary physical coordinates

For every virtual matrix \(X\), \(\widehat{\mathcal T}(\widehat{\mathcal K}_2(X)) =\widehat{\mathcal K}_3(X)\).

Proof

Transport the sector-coordinate identity through the inverse three-site coordinate identification.

Definition 26.10.7.26 Physical coarse-graining

Transporting \(\mathcal S\) through the canonical three-site and two-site coordinate identifications gives a channel \(\widehat{\mathcal S}:M_{q^3}(\mathbb {C})\longrightarrow M_{q^2}(\mathbb {C})\).

Theorem 26.10.7.27 The physical coarse-graining map is a channel

The map \(\widehat{\mathcal S}\) is trace-preserving and completely positive.

Proof

This follows by composition with the two coordinate-permutation channels.

Theorem 26.10.7.28 Coarse-graining identity in ordinary physical coordinates

For every virtual matrix \(X\), \(\widehat{\mathcal S}(\widehat{\mathcal K}_3(X)) =\widehat{\mathcal K}_2(X)\).

Proof

Transport the sector-coordinate identity through the inverse two-site coordinate identification.

Definition 26.10.7.29 Localized physical refinement

Reassociating three right-associated sites as \((12)3\), applying \(\widehat{\mathcal T}\otimes \operatorname{id}\) to the first two, and reassociating the result back to \(1(2(34))\) defines the localized refinement channel \(\widehat{\mathcal T}_{(12)3}:M_{q^3}(\mathbb {C})\longrightarrow M_{q^4}(\mathbb {C})\) on right-associated physical coordinates.

Theorem 26.10.7.30 The localized physical refinement is a channel

The localized refinement map is trace-preserving and completely positive.

Proof

Tensoring a channel with the identity preserves complete positivity and trace, as do the two associativity permutations.

For every virtual matrix \(X\), \((\widehat{\mathcal T}\otimes \operatorname{id}) (\widehat{\mathcal K}_3(X)) =\widehat{\mathcal K}_4(X)\), with the map understood in right-associated coordinates.

Proof

Fixing the last ket and bra indices turns the three-site closure into a two-site closure with the last tensor matrix absorbed into \(X\). Apply the two-to-three-site refinement identity to this virtual matrix.

Definition 26.10.7.32 Localized physical coarse-graining

Reassociating four right-associated sites as \((123)4\), applying \(\widehat{\mathcal S}\otimes \operatorname{id}\) to the first three, and reassociating the result back to \(1(23)\) defines the localized coarse-graining channel \(\widehat{\mathcal S}_{(123)4}:M_{q^4}(\mathbb {C})\longrightarrow M_{q^3}(\mathbb {C})\) on right-associated physical coordinates.

Theorem 26.10.7.33 The localized physical coarse-graining is a channel

The localized coarse-graining map is trace-preserving and completely positive.

Proof

Tensor the physical coarse-graining channel with the identity and compose with the two associativity permutations.

For every virtual matrix \(X\), \((\widehat{\mathcal S}\otimes \operatorname{id}) (\widehat{\mathcal K}_4(X)) =\widehat{\mathcal K}_3(X)\) in right-associated coordinates.

Proof

Fixing the last ket and bra indices identifies the four-site closure with a three-site closure having the last tensor matrix absorbed into \(X\). Apply the three-to-two-site coarse-graining identity.

Definition 26.10.7.35 Two-step physical refinement

Let \(\widehat{\mathcal K}\) be the sector-coordinate tensor selected by the physical isometry of Proposition C.7. Define

\begin{align} \widehat{\mathcal T}^2 & =\widehat{\mathcal T}_{(12)3}\circ \widehat{\mathcal T}, \notag \\ \widehat{\mathcal T}^2 & :M_{q^2}(\mathbb {C})\longrightarrow M_{q^4}(\mathbb {C}). \notag \end{align}

Here the second application acts on the first two sites and leaves the third site unchanged. Thus the superscript denotes two successive overlapping applications, as in the proof of [ CPGSV16 , Theorem 4.9, (iv)\(\Rightarrow \)(v) ] .

Theorem 26.10.7.36 The two-step physical refinement is a channel

The map \(\widehat{\mathcal T}^2\) is trace-preserving and completely positive.

Proof

It is the composition of the physical refinement channel and its localization on the first two sites.

For every virtual matrix \(X\), the sector-coordinate tensor satisfies \(\widehat{\mathcal T}^2(\widehat{\mathcal K}_2(X)) =\widehat{\mathcal K}_4(X)\).

Proof

The first refinement gives \(\widehat{\mathcal K}_3(X)\); applying the localized refinement to its first two sites gives \(\widehat{\mathcal K}_4(X)\).

Definition 26.10.7.38 Two-step physical coarse-graining

Define

\begin{align} \widehat{\mathcal S}^2 & =\widehat{\mathcal S}\circ \widehat{\mathcal S}_{(123)4}, \notag \\ \widehat{\mathcal S}^2 & :M_{q^4}(\mathbb {C})\longrightarrow M_{q^2}(\mathbb {C}). \notag \end{align}

Here the first application acts on the first three sites and leaves the fourth site unchanged. The superscript again denotes successive overlapping applications.

Theorem 26.10.7.39 The two-step physical coarse-graining is a channel

The map \(\widehat{\mathcal S}^2\) is trace-preserving and completely positive.

Proof

It is the composition of the localized coarse-graining channel and the physical coarse-graining channel.

For every virtual matrix \(X\), the sector-coordinate tensor satisfies \(\widehat{\mathcal S}^2(\widehat{\mathcal K}_4(X)) =\widehat{\mathcal K}_2(X)\).

Proof

The localized coarse-graining first gives \(\widehat{\mathcal K}_3(X)\); the second coarse-graining gives \(\widehat{\mathcal K}_2(X)\).

\(\widehat{\mathcal T}^{\, 2}:\quad \) \tnpic[compact, physical=updown, tensor style=box]{%
            \tn[mpo]{\widehat{\cal K}}
                \tnspan[box, label pos=south]{2}{\widehat{\cal K}^{[2]}} &
            \tn[mpo]{\widehat{\cal K}}} \(\quad \xrightarrow {\widehat{\mathcal T}}\quad \) \tnpic[compact, physical=updown, tensor style=box]{%
            \tn[mpo]{\widehat{\cal K}} &
            \tn[mpo]{\widehat{\cal K}} &
            \tn[mpo]{\widehat{\cal K}}} \(\quad \xrightarrow {\widehat{\mathcal T}_{(12)3}}\quad \) \tnpic[compact, physical=updown, tensor style=box]{%
            \tn[mpo]{\widehat{\cal K}}
                \tnspan[box, label pos=south]{2}{\widehat{\cal K}^{[2]}} &
            \tn[mpo]{\widehat{\cal K}} &
            \tn[mpo]{\widehat{\cal K}}
                \tnspan[box, label pos=south]{2}{\widehat{\cal K}^{[2]}} &
            \tn[mpo]{\widehat{\cal K}}}
\(\widehat{\mathcal S}^{\, 2}:\quad \) \tnpic[compact, physical=updown, tensor style=box]{%
            \tn[mpo]{\widehat{\cal K}}
                \tnspan[box, label pos=south]{2}{\widehat{\cal K}^{[2]}} &
            \tn[mpo]{\widehat{\cal K}} &
            \tn[mpo]{\widehat{\cal K}}
                \tnspan[box, label pos=south]{2}{\widehat{\cal K}^{[2]}} &
            \tn[mpo]{\widehat{\cal K}}} \(\quad \xrightarrow {\widehat{\mathcal S}_{(123)4}}\quad \) \tnpic[compact, physical=updown, tensor style=box]{%
            \tn[mpo]{\widehat{\cal K}} &
            \tn[mpo]{\widehat{\cal K}} &
            \tn[mpo]{\widehat{\cal K}}} \(\quad \xrightarrow {\widehat{\mathcal S}}\quad \) \tnpic[compact, physical=updown, tensor style=box]{%
            \tn[mpo]{\widehat{\cal K}}
                \tnspan[box, label pos=south]{2}{\widehat{\cal K}^{[2]}} &
            \tn[mpo]{\widehat{\cal K}}}
Figure 26.6 The superscripts in \(\widehat{\mathcal T}^2\) and \(\widehat{\mathcal S}^2\) denote successive overlapping applications. The dashed frames identify the two-site and four-site endpoints with one and two sites of the blocked tensor. This is the channel construction in [ CPGSV16 , Appendix C.2, lines 1821–1825 ] .

Let \(\widehat{\mathcal K}^{[2]}\) be the tensor obtained by blocking two adjacent sites of the sector-coordinate tensor \(\widehat{\mathcal K}\). Then \(\widehat{\mathcal K}^{[2]}\) is a renormalization fixed point in the sense of Definition 26.2.1. More precisely, after the canonical identifications of one blocked site with two original sites and two blocked sites with four original sites, the required channels are \(\widehat{\mathcal S}^2\) and \(\widehat{\mathcal T}^2\).

Proof

Decode one blocked index as a pair of physical indices and two blocked indices as four physical indices. The one-site and two-site closures of \(\widehat{\mathcal K}^{[2]}\) thereby become respectively \(\widehat{\mathcal K}_2(X)\) and \(\widehat{\mathcal K}_4(X)\). Transporting the two channels through these permutation identifications preserves complete positivity and trace, and the two closure identities give the required equations in Definition 26.2.1.

Theorem 26.10.7.42 Conditional two-site blocking theorem from neighboring trace factorization

Assume that the neighboring operators are positive semidefinite and that there are real families \((a_k)_k,(b_k)_k\) satisfying \(\operatorname{tr}(\eta _{k,h})=a_kb_h\) and \(\sum _k a_kb_k=1\). Let \(\mathcal K^{[2]}\) be the tensor obtained by blocking two adjacent sites of \(\mathcal K\). Then \(\mathcal K^{[2]}\) is a renormalization fixed point in the sense of Definition 26.2.1. This is [ CPGSV16 , Theorem 4.9, (iv)\(\Rightarrow \)(v) ] .

Proof

Transport the refinement and coarse-graining channels for \(\widehat{\mathcal K}^{[2]}\) through the two-site and four-site tensor powers of the physical isometry, as in (??). These unitary congruences preserve complete positivity and trace, while the corresponding closure identities carry the two fixed-point equations back to \(\mathcal K^{[2]}\).

Theorem 26.10.7.43 Blocking channels from SAL and ZCL (open)

Let \(K\) be a simple tensor in block-injective canonical form (biCF), equipped with a basis-of-normal-tensors decomposition and satisfying the strong area law and zero correlation length. Let \(M=K^{[2]}\) be its two-site blocking. Then there are trace-preserving completely positive maps in both directions between the one-site and two-site closures of \(M\). Equivalently, \(M\) is a renormalization fixed point via these two maps. This is implication (ii)\(\Rightarrow \)(v) of [ CPGSV16 , Theorem 4.9 and Appendix C.2, lines 1810–1825 ] . The separate standing biCF and BNT hypotheses are imposed at lines 849–850 and restated at line 1628 of the same source. The printed proof of implication (ii)\(\Rightarrow \)(v) refers back to the construction of Proposition C.7 after projection to each local sector. That construction requires the rank-one neighboring-trace factorization supplied in the printed argument by the refuted Lemma C.5. No proof under SAL and ZCL alone is presently known.

\begin{align} U^{\otimes 4}\widehat{\mathcal T}^{\, 2} (U^\dagger )^{\otimes 2} & =\mathcal T, \label{eq:mpdo_physical_isometry_transport}\\ U^{\otimes 2}\widehat{\mathcal S}^{\, 2} (U^\dagger )^{\otimes 4} & =\mathcal S. \notag \end{align}

Conjugation by \(U^{\otimes n}\) and \((U^\dagger )^{\otimes n}\) carries the sector-coordinate channels to the ordinary-coordinate channels. This combines Proposition C.7 with [ CPGSV16 , Appendix C.2, lines 1510–1563 and 1821–1825 ] .

Tracing the ket and bra indices of a sector tensor gives the bond vector \(|l_k)\) or the bond functional \((r_k|\). Hence a neighboring pair gives \(T_{k,h}=(r_k|l_h)=\operatorname{tr}(\eta _{k,h})\), as in [ CPGSV16 , Appendix C.2, lines 1474–1481 ] .

26.10.8 Local simple-MPDO structure

Definition 26.10.8.1 Local simple-MPDO structure

This structure records the local ingredients of [ CPGSV16 , Appendix C.2 ] : a normalized three-site reduced state with equality in strong subadditivity, the resulting Markov decomposition, and a primitive matrix \(T\) with trace one and, for every positive integer \(m\), equal positive-power traces:

\begin{align} \operatorname{tr}(T)& =1, \notag \\ \operatorname{tr}(T^m)& =\operatorname{tr}(T), \notag \end{align}

together with a rank-one factorization

\begin{align} T& =ab^\top , \notag \\ a\cdot b& =1. \notag \end{align}
Remark 26.10.8.2 Printed Lemma C.5 is refuted
#

Lemma C.5 of [ CPGSV16 , Appendix C.2, lines 1484–1499 ] claims that an injective matrix product density operator tensor satisfying the strong area law and zero correlation length has real families \((a_k)_k,(b_k)_k\) with

\begin{align} T_{k,h}=\operatorname{tr}(\eta _{k,h})& =a_kb_h, \notag \\ \sum _k a_kb_k& =1. \notag \end{align}

This claim is false under the printed hypotheses. Theorem 26.10.8.3 gives a four-sector counterexample with the source inverse-map factorization and with no such families \(a,b\).

There is an injective matrix product density operator tensor satisfying the strong area law and source zero correlation length whose source-selected inverse-map factorization has positive semidefinite neighboring operators and a primitive trace-one active trace matrix \(T\), but for which there are no families \(a,b\) satisfying \(T_{k,h}=a_kb_h\) for all \(k,h\). Equivalently, for the corresponding closed sector tensors \(L,Q\), one has \(Q(1-LQ)L=T-T^2\ne 0\). Thus the rank-one conclusion in Lemma C.5 is false under its printed hypotheses.

Proof

The four physical sectors are one-dimensional. Their cyclic transition law is doubly stochastic. After tracing one site, conditioning on the middle physical label gives, at every admissible cut,

\begin{align} \rho _{ABC} & =\bigoplus _{k=0}^{3}\frac14 \rho ^{L}_{A,k}\otimes \rho ^{R}_{k,C}. \notag \end{align}

Thus the reduced state has a four-sector quantum-Markov decomposition and the tensor satisfies the strong area law. Its physical-trace transfer is the idempotent matrix \(LQ\), so it has source zero correlation length. The explicit Hayashi decomposition and inverse map recover the displayed tensors \(L,Q\). The active trace matrix is primitive and has trace one, but direct multiplication gives \(T^2\ne T\). If \(T=ab^\top \), then

\begin{align} T^2 & =a(b^\top a)b^\top =\left(\sum _k a_kb_k\right)T =T, \notag \end{align}

where the last equality uses \(\operatorname{tr}(T)=1\). Hence \(T\) has no rank-one factorization.

There is a four-sector, bond-dimension-two tensor with a refined Hayashi decomposition whose four sectors are one-dimensional and have weight \(1/4\). Its three-site state is diagonal, with

\begin{align} \rho (i,j,k;i’,j’,k’) & =\delta _{(i,j,k),(i',j',k')} \frac14(QL)_{i,j}(QL)_{j,k}. \notag \end{align}

The normalized four-site tail is \(LQ\). For this tail, the inverse-map construction recovers the closed sector tensors \(L\) and \(Q\) exactly. Its neighboring operators therefore coincide with those obtained directly from \(L\) and \(Q\), while \(Q(1-LQ)L\ne 0\). The inverse-map construction is the one in [ CPGSV16 , Appendix C.2, lines 1413–1455 ] .

Proof

Write \(S_i=L_{\mathord \bullet i}Q_{i\mathord \bullet }\) for the four physical slices, and let \(f_i(a,b)\) be their dual coefficients, so that

\begin{align} \sum _{i=0}^{3}f_i(a,b)S_i& =E_{ab}. \notag \end{align}

With \(T=QL\), \(p_k=1/4\), and \((LQ)_{00}=1\), the two inverse-map contractions are

\begin{align} (LQ)_{00}^{-1}p_k\sum _{i=0}^{3}f_i(0,\beta )T_{ik} & =\frac14(4L_{\beta k})=L_{\beta k}, \notag \\ \sum _{i=0}^{3}f_i(\alpha ,0)T_{ki} & =Q_{k\alpha }. \notag \end{align}

Hence the neighboring operators are those obtained directly from \(L\) and \(Q\), and direct multiplication gives \(Q(1-LQ)L\ne 0\).

Corollary 26.10.8.5 Local sector structure from SAL and ZCL (open)

Let \(\mathcal K\) be an injective matrix product density operator tensor satisfying the strong area law and zero correlation length. Then there are an isometry, closed sector tensors, positive neighboring operators \(\eta _{k,h}\), and real families \((a_k)_k,(b_k)_k\) such that the inverse-map sector decomposition holds and

\begin{align} \operatorname{tr}(\eta _{k,h})& =a_kb_h, \notag \\ \sum _k a_kb_k& =1. \notag \end{align}

This is the structural corollary at [ CPGSV16 , Appendix C.2, lines 1501–1505 ] . Its printed derivation combines Lemma C.4 with the refuted Lemma C.5, so the conclusion remains open under the printed hypotheses.

Theorem 26.10.8.6 Conditional local simple-MPDO structure under stronger rank-one hypotheses

These are conditional constructions under hypotheses stronger than SAL and ZCL; neither is the printed Lemma C.5 or its corollary. In the first, \(T\) is positive semidefinite, \(\operatorname{tr}(T)=1\), and \(\operatorname{tr}(T^m)=1\) for every positive integer \(m\); the spectral theorem then gives the rank-one factorization \(T=ab^\top \) with \(a\cdot b=1\). In the second, \(T\) is the sector trace matrix of linearly independent sector tensors satisfying the zero-correlation-length pairing identity. This identity implies \(T^2=T\), so trace one gives the same rank-one factorization. In this second form the constancy of the positive-power traces is a conclusion rather than an assumption.

For \(x\ne y\), the physical supports are locally orthogonal:

\begin{tenkz}[rows={op,op}]
        \tn[mpo]{\mathcal K_y} \\
        \tn[mpo]{\mathcal K_x}
    \end{tenkz} \( = 0\)

In contraction notation, local orthogonality is \(\mathcal K_y^*\mathcal K_x=0\) whenever \(x\ne y\). This is [ CPGSV16 , Theorem 4.9(iv), lines 863–868 ] .

Expanding \(\sum _jP_j=\mathbb {1}\) on both physical indices and using the local orthogonality relations leaves only the diagonal term:

\begin{align} \mathcal K_i & =\sum _{j,j'}P_j\, \mathcal K_i\, P_{j'} =P_i\, \mathcal K_i =\mathcal K_i\, P_i. \notag \end{align}
\begin{tenkz}[physical=updown]
        \tn[mpo]{K_i}
    \end{tenkz} \( = \sum _{j,j'}\) \begin{tenkz}[rows={op:none, op, op:none}]
        \tn[mpo]{P_j} \\
        \tn[mpo]{K_i} \\
        \tn[mpo]{P_{j'}}
    \end{tenkz} \( = \) \begin{tenkz}[rows={op:none, op}]
        \tn[mpo]{P_i} \\
        \tn[mpo]{K_i}
    \end{tenkz} \( = \) \begin{tenkz}[rows={op, op:none}]
        \tn[mpo]{K_i} \\
        \tn[mpo]{P_i}
    \end{tenkz}

Equivalently, each local tensor is supported on its own sector: \(\mathcal K_i=P_i\mathcal K_i=\mathcal K_iP_i\). This is the calculation in [ CPGSV16 , Appendix C.2, lines 1745–1751 ] .

Theorem 26.10.8.7 BNT sector structure from SAL and ZCL (open)

Let \(K\) be a simple tensor in block-injective canonical form (biCF), equipped with a basis-of-normal-tensors decomposition. If \(K\) satisfies the strong area law and zero correlation length, then its basis tensors have mutually orthogonal physical supports. Moreover, each basis tensor has an inverse-map sector decomposition with positive neighboring operators \(\eta _{k,h}\) and real families \((a_k)_k,(b_k)_k\) satisfying

\begin{align} \operatorname{tr}(\eta _{k,h})& =a_kb_h, \notag \\ \sum _k a_kb_k& =1. \notag \end{align}

This is implication (ii)\(\Rightarrow \)(iv) of [ CPGSV16 , Theorem 4.9 and Appendix C.2, lines 1740–1788 ] . The separate standing biCF and BNT hypotheses are imposed at lines 849–850 and restated at line 1628 of the same source. The proof at lines 1745–1785 applies the structural corollary after establishing SAL and ZCL for each basis tensor. Since that corollary uses the refuted Lemma C.5, the printed proof does not establish this proposition.

26.11 Single-bond commuting form from the local structure

Definition 26.11.1 Translation-invariant two-site bond

This records one positive semidefinite two-site bond \(B\ge 0\) whose translated copies commute pairwise on the periodic \(N\)-site chain at every chain length \(N\ge 2\): \([B_{i,i+1},B_{j,j+1}]=0\).

Definition 26.11.2 \(\eta \)-local single-bond commuting-form data

This defines the one-bond eta-local form constructed in [ CPGSV16 , Appendix C.2 ] : a two-site bond \(B\) as in Definition 26.11.1 together with, for every chain length \(N\ge 2\), a constant \(c{\gt}0\) such that

\begin{align} \rho ^{(N)}(M) & =c\prod _{i=0}^{N-1}B_{i,i+1}. \notag \end{align}

The bond acts on the full two-site space.

A translation-invariant positive two-site bond determines finite-chain commuting-form data at every length \(N\ge 2\).

Definition 26.11.4 Common three-site coordinates for overlapping bonds

Write the two-site bond on the ordered pair of physical indices, and identify a three-site configuration \((x_0,x_1,x_2)\) with the left-associated triple \(((x_0,x_1),x_2)\). These are common coordinates for the two bonds on sites \((0,1)\) and \((1,2)\).

Let \(B\) be a translation-invariant positive two-site bond, written as an operator \(\widehat B\) on an ordered pair of physical spaces. Under the same three-site identification for both translates,

\begin{align} B_{0,1} & =\widehat B\otimes \mathbb {1}, \notag \\ B_{1,2} & =\mathbb {1}\otimes \widehat B. \notag \end{align}

Thus these two operators are respectively the left and right overlapping lifts of \(\widehat B\). Moreover, \(\widehat B\) is Hermitian and the two lifts commute. These are exactly the local hypotheses needed for the Bravyi–Vyalyi decomposition invoked at [ CPGSV16 , Appendix C.2, lines 1599–1605 ] .

Proof

Let \(\Phi \) be the matrix reindexing induced by the common three-site identification, and write \(B_{0,1}=\Phi (B_0)\) and \(B_{1,2}=\Phi (B_1)\) for the two reindexed translates. For three-site configurations \(x\) and \(y\), the two outside-window conditions are

\begin{align} (\forall r\notin \{ 0,1\} ,\ x_r=y_r) & \Longleftrightarrow x_2=y_2, \notag \\ (\forall r\notin \{ 1,2\} ,\ x_r=y_r) & \Longleftrightarrow x_0=y_0. \notag \end{align}

Hence evaluation at a pair of left-associated triples gives

\begin{align} (B_{0,1})_{(i,j,k),(i',j',k')} & =\widehat B_{(i,j),(i',j')}\delta _{k,k'} =(\widehat B\otimes \mathbb {1})_{(i,j,k),(i',j',k')}, \notag \\ (B_{1,2})_{(i,j,k),(i',j',k')} & =\delta _{i,i'}\widehat B_{(j,k),(j',k')} =(\mathbb {1}\otimes \widehat B)_{(i,j,k),(i',j',k')}. \notag \end{align}

Positivity of \(B\) gives \(\widehat B^*=\widehat B\). Finally, matrix reindexing is multiplicative, so \(\Phi (XY)=\Phi (X)\Phi (Y)\), and

\begin{align} B_0B_1=B_1B_0 & \Longrightarrow \Phi (B_0)\Phi (B_1)=\Phi (B_1)\Phi (B_0). \notag \end{align}

Substituting the two entrywise identities proves that the left and right overlapping lifts commute.

The \(\eta \)-local structure itself determines a single-bond commuting-form witness for every chain length \(N\ge 2\): writing \(B\) for its bond, the translated copies commute, \([B_{i,i+1},B_{j,j+1}]=0\), and there exists \(c{\gt}0\) with

\begin{align} \rho ^{(N)}(M) & =c\prod _{i=0}^{N-1}B_{i,i+1}. \notag \end{align}

This is the one-bond product conclusion used in [ CPGSV16 , Proposition C.8 ] .

Proof

At length \(N\), apply the commuting two-site bond and realization identity provided by the \(\eta \)-local structure.

The same \(\eta \)-local structure gives a single-bond product witness on every finite periodic chain.

Proof

Evaluate the local structure at each chain length \(N\ge 2\).

Theorem 26.11.8 Single-bond product with doubled-index idempotence

An \(\eta \)-local structure together with the doubled-index transfer condition gives the corresponding single-bond branch.

Proof

Use the commuting-form witness carried by the \(\eta \)-local structure and combine it with the doubled-index transfer hypothesis.

Let \(\widehat B\) be a pair-indexed positive two-site bond whose periodic translates commute. There are positive dimensions \(d_{l,q}=\dim H_{q,l}\) and \(d_{r,q}=\dim H_{q,r}\), a unitary decomposition \(H\cong \bigoplus _{q=0}^{K-1}H_{q,l}\otimes H_{q,r}\), and Hermitian operators \(R_q\) on \(H\otimes H_{q,l}\) and \(S_q\) on \(H_{q,r}\otimes H\) such that

\begin{align} (\mathbb {1}_H\otimes U^*)\widehat B(\mathbb {1}_H\otimes U) & =\bigoplus _{q=0}^{K-1} (R_q\otimes \mathbb {1}_{H_{q,r}}), \notag \\ (U^*\otimes \mathbb {1}_H)\widehat B(U\otimes \mathbb {1}_H) & =\bigoplus _{q=0}^{K-1} (\mathbb {1}_{H_{q,l}}\otimes S_q). \notag \end{align}

The basis bijection for each sector enumerates the numerical indices in right–left order,

\begin{align} \bigsqcup _q\bigl(\{ 0,\ldots ,d_{r,q}-1\} \times \{ 0,\ldots ,d_{l,q}-1\} \bigr) & \cong \{ 0,\ldots ,d-1\} . \notag \end{align}

Writing \(e(q,(r,s))\) for this basis bijection, the left and right spatial coordinates are respectively

\begin{align} (q,((i,s),r)) & \longmapsto (i,e(q,(r,s))), \notag \\ (q,(s,(r,k))) & \longmapsto (e(q,(r,s)),k). \notag \end{align}

Hence the tensor factors in the displayed block actions occur in left–right order.

Proof

The pair-indexed bond is Hermitian by positivity, and its two overlapping lifts commute by the common three-site identification. Apply Theorem 25.6.11.

Let \(B\) be a pair-indexed positive bond whose periodic translates commute. There are a unitary coordinate decomposition \(H\cong \bigoplus _q H_{q,r}\otimes H_{q,l}\) and positive semidefinite operators \(\eta _{q,h}\) on \(H_{q,r}\otimes H_{h,l}\). After regrouping the two-site coordinates, the \((q,h)\)-sector is \(H_{q,l}\otimes (H_{q,r}\otimes H_{h,l})\otimes H_{h,r}\), and in these regrouped coordinates

\begin{align} (U^*\otimes U^*)B(U\otimes U) & =\bigoplus _{q,h} \mathbb {1}_{H_{q,l}}\otimes \eta _{q,h}\otimes \mathbb {1}_{H_{h,r}}. \notag \end{align}

The unitary and the neighboring operators depend only on the fixed bond, and hence are independent of a chain length or bond position.

Proof

The same unitary block decomposition at both ends of \(B\) gives identity action on \(H_{q,l}\) through one block identity and on \(H_{h,r}\) through the other. For fixed basis indices \(\ell _q^0\in H_{q,l}\) and \(r_h^0\in H_{h,r}\), let \(B'=(U^*\otimes U^*)B(U\otimes U)\). The neighboring operator has entries

\begin{align} (\eta _{q,h})_{(r,\ell ),(r',\ell ')} & = B’_{(q,r,\ell _q^0;h,r_h^0,\ell ), (q,r',\ell _q^0;h,r_h^0,\ell ')}. \notag \end{align}

Thus \(\eta _{q,h}\) is a principal compression of the positive operator \(B'\), and is therefore positive semidefinite.

Theorem 26.11.11 Cyclic product of a locally decomposed bond

Suppose that, in one fixed coordinate decomposition \(H\cong \bigoplus _q H_{q,r}\otimes H_{q,l}\), after regrouping the two-site coordinates according to this decomposition, a two-site operator has the form

\begin{align} B & =\bigoplus _{q,h} \mathbb {1}_{H_{q,l}}\otimes \eta _{q,h}\otimes \mathbb {1}_{H_{h,r}}. \notag \end{align}

For every \(N\ge 2\), regroup the cyclic chain as

\begin{align} H^{\otimes N} & \cong \bigoplus _{k:\mathbb {Z}/N\mathbb {Z}\to \{ 0,\ldots ,K-1\} } \bigotimes _{n\in \mathbb {Z}/N\mathbb {Z}} \left(H_{k_n,r}\otimes H_{k_{n+1},l}\right). \notag \end{align}

Then, in these coordinates and with \(k_N=k_0\),

\begin{align} \prod _{n=0}^{N-1}B_{n,n+1} & = \bigoplus _k\bigotimes _{n=0}^{N-1}\eta _{k_n,k_{n+1}}. \notag \end{align}

At \(N=2\), the two translated windows have the opposite orders \((0,1)\) and \((1,0)\) and give the two oriented factors \(\eta _{k_0,k_1}\) and \(\eta _{k_1,k_0}\).

Proof

In a fixed sector configuration, the cyclic regrouping sends the factors \((r_n,l_n)\) to the edge factors \((r_n,l_{n+1})\). The translate beginning at \(n\) acts by \(\eta _{k_n,k_{n+1}}\) on the \(n\)th edge factor and by the identity on every other edge factor. Different sector configurations do not mix. Multiplying the translated operators therefore gives the stated direct sum of tensor products.

Let \(\sigma ^{(N)}(\mathcal K)\) be realized, for every \(N\ge 2\), by translates of one positive commuting bond. There are one unitary \(U\), positive sector dimensions, and positive semidefinite operators \(\eta _{q,h}\), all independent of \(N\), such that for every \(N\ge 2\) there is a constant \(c_N{\gt}0\) satisfying, with \(k_N=k_0\),

\begin{align} E_N^*(U^*)^{\otimes N}\sigma ^{(N)}(\mathcal K) U^{\otimes N}E_N & = c_N\bigoplus _{k_0,\ldots ,k_{N-1}} \bigotimes _{n=0}^{N-1}\eta _{k_n,k_{n+1}}. \notag \end{align}

Here \(E_N\) is the cyclic regrouping from the edge factors \(H_{k_n,r}\otimes H_{k_{n+1},l}\) to the site factors \(H_{k_n,r}\otimes H_{k_n,l}\). The factor \(c_N\) is retained from the proportionality relation in [ CPGSV16 , Appendix C.2, lines 1571–1576 ] . The passage at [ CPGSV16 , Appendix C.2, lines 1603–1605 ] suppresses this factor when invoking the coefficient-free equation sigmaNK2; the coefficient-free assertion is not part of the present theorem.

Proof

Choose the unitary and the neighboring operators from the decomposition of the fixed bond. Conjugation by \((U^*)^{\otimes N}\) carries the product of its translates to the product of the conjugated two-site bonds. The cyclic regrouping theorem changes this product into the displayed direct sum. Applying both transformations to \(\sigma ^{(N)}(\mathcal K)=c_N\prod _n B_{n,n+1}\) preserves the same positive scalar \(c_N\).

Remark 26.11.13 An arbitrary proportional presentation need not have unit scalar
#

The proportional commuting-bond form alone does not permit one common local normalization. Indeed, take physical dimension \(d=1\) and bond dimension \(D=2\), with sole matrix-product letter \(M^{00}=I_2\), and take the two-site bond to be the scalar \(B=1\). Then

\begin{align} \sigma ^{(N)} & =\operatorname{tr}(I_2^N)=2 =c_N\prod _{n=0}^{N-1}B_{n,n+1}, & c_N& =2. \notag \end{align}

Any positive neighboring decomposition of the one-dimensional physical space has one sector and one scalar \(a\ge 0\). A coefficient-free identity at lengths two and four would give \(a^2=2\) and \(a^4=2\), a contradiction. This example is not a normal injective block. More generally, the source does not claim that every proportional commuting-bond presentation can be made coefficient-free by one local rescaling. In the SAL-to-commuting-form direction, the proof chooses the neighboring operators from the source tensor and obtains scalar one directly. This distinguishes the proportionality at [ CPGSV16 , Appendix C.2, lines 1571–1576 ] from the coefficient-free invocation at [ CPGSV16 , Appendix C.2, lines 1603–1605 ] . The source-selected normal representative is Corollary 26.10.3.49.

Definition 26.11.14 Cyclic edge-weight tensor

A scalar weight \(w(i,j;i',j')\) on two consecutive ket–bra pairs determines a translation-invariant matrix-product tensor with virtual dimension \(d^2\). Its incoming virtual pair is constrained to equal the current physical ket–bra pair, while its outgoing pair records the following physical pair.

Theorem 26.11.15 Closed cyclic edge-weight identity

For every positive length \(N\), and with \(\sigma _N=\sigma _0\) and \(\tau _N=\tau _0\), the closed matrix-product operator of the cyclic edge-weight tensor is

\begin{align} \rho ^{(N)}_{\sigma ,\tau } & = \prod _{n=0}^{N-1} w(\sigma _n,\tau _n;\sigma _{n+1},\tau _{n+1}). \notag \end{align}

In the virtual trace there is precisely one potentially nonzero cyclic virtual configuration.

A fixed tensor for a bond-product family consists of a positive virtual dimension and one matrix-product tensor \(C\), independent of \(N\), such that, for every \(N\ge 2\),

\begin{align} \rho ^{(N)}(C) & =\prod _{n=0}^{N-1}B_{n,n+1}. \notag \end{align}

If \(d{\gt}0\), a cyclic scalar edge-weight expression for the entries of the product gives such a tensor with positive virtual dimension \(d^2\).

Let \(B\ge 0\) be a two-site bond whose periodic translates commute. There is a positive integer \(R\) and a matrix-product tensor \(C\) of virtual dimension \(R\), both independent of the chain length, such that for every \(N\ge 2\),

\begin{align} \rho ^{(N)}(C) & =\prod _{n=0}^{N-1}B_{n,n+1}. \notag \end{align}

The construction gives a positive \(R\) independent of \(N\). No normality, zero-correlation-length, or scalar normalization hypothesis is required.

Proof

Choose Beigi’s chain-independent one-site unitary and the positive neighboring operators \(\eta _{q,h}\). For a common matrix-unit index set \(\mathcal A\), write

\begin{align} \eta _{q,h}((r,l),(r’,l’)) & = \sum _{a\in \mathcal A} R_a(q)_{r,r'}L_a(h)_{l,l'}. \notag \end{align}

Thus the contraction of the right factor at one site with the left factor at the next satisfies \(\sum _{a\in \mathcal A}R_a(q)\otimes L_a(h)=\eta _{q,h}\). If \(V\) is the resulting unitary change to the two-site sector coordinates, this contraction gives \(\widetilde B=VBV^\dagger \) and \(B_{\mathrm{phys}}=V^\dagger \widetilde B V=B\). For a nonzero physical space, \(\mathcal A\) is nonempty and gives a positive virtual dimension. For the zero-dimensional physical space, take one virtual state and no physical sectors. The cyclic contraction formula then gives the product of the translates of \(B\) at every length \(N\ge 2\).

Let \(C\) be the selected fixed tensor of the preceding theorem. There are physical sectors \(\mathbb {C}^d\cong \bigoplus _{q=0}^{K-1}H_q^L\otimes H_q^R\), a unitary \(U\), and matrices \(L_\beta (q)\) and \(R_\alpha (q)\) such that, writing \(C_{\beta ,\alpha }\) for the physical matrix at fixed virtual indices,

\begin{align} U C_{\beta ,\alpha }U^\dagger & = \bigoplus _{q=0}^{K-1} L_\beta (q)\otimes R_\alpha (q). \notag \end{align}

The neighboring operators \(\eta _{q,h}=\sum _a R_a(q)\otimes L_a(h)\) are positive semidefinite. If \(U_2\) denotes the induced two-site change of coordinates, then

\begin{align} B & = U_2^\dagger \left[\bigoplus _{q,h} \mathbb {1}_{H_q^L\otimes H_h^R}\otimes \eta _{q,h}\right] U_2. \notag \end{align}

Thus the physical-sector factorization belongs to the same tensor \(C\) whose closed operators are the fixed products of \(B\).

Proof

Take the physical-sector factorization retained with \(C\). Its defining one-site identity is

\begin{align} U C_{\beta ,\alpha }U^\dagger & = \bigoplus _q L_\beta (q)\otimes R_\alpha (q). \notag \end{align}

Contracting the adjacent right and left factors gives \(\eta _{q,h}=\sum _a R_a(q)\otimes L_a(h)\succeq 0\), where positivity is the retained neighboring-operator property. Finally, the retained bond identity is

\begin{align} B & = U_2^\dagger \left[\bigoplus _{q,h} \mathbb {1}_{H_q^L\otimes H_h^R}\otimes \eta _{q,h}\right] U_2. \notag \end{align}
Remark 26.11.19 The scalar edge formula depends on the one-site coordinates
#

A cyclic scalar edge formula need not hold in the original physical basis. For \(d=2\), let \(X\) be the Pauli flip and set \(B=\mathbb {1}+X\otimes X\). This bond is positive semidefinite and its periodic translates commute. For every \(N\ge 2\),

\begin{align} \langle 0^N| \left(\prod _n B_{n,n+1}\right) |0^N\rangle & =2. \notag \end{align}

At \(N=2\) the periodic product is \(B^2=2B\); for \(N\ge 3\), the empty edge set and the full cycle are the two terms with zero boundary. An original-coordinate scalar edge weight would make this entry equal to \(a^N\). The cases \(N=2\) and \(N=3\) would give \(a^2=2\) and \(a^3=2\), a contradiction. Equation sigmaNK2 in [ CPGSV16 , Appendix C.2, lines 1581–1589 ] is stated only after the one-site unitary coordinate change, as used in the theorem.

Theorem 26.11.20 Eventual proportionality from a fixed product tensor

Suppose one fixed tensor \(C\) generates the products of the bond carried by an eta-local structure. Then the doubled-index tensors of \(M\) and \(C\) are eventually nonzero proportional. The proof uses only lengths \(N\ge 2\) and therefore assumes no relation at length one.

Proof

At every \(N\ge 2\), substitute the exact tensor representation into the positive realization \(\rho ^{(N)}(M)=c_N\prod _n B_{n,n+1}\), where \(c_N{\gt}0\), and read ket–bra pairs as doubled physical indices.

Let \(A\) be the normal doubled-index source tensor of positive bond dimension \(D\), and let \(C\) be a fixed tensor for its commuting-bond product. Suppose that \(sC\) is normal for some \(s{\gt}0\). Then there is a complex number \(\zeta \), with \(|\zeta |=1\), such that, for every \(N\ge 2\),

\begin{align} \rho ^{(N)}(A) & = (\zeta s)^N\prod _{n=0}^{N-1}B_{n,n+1}. \notag \end{align}

This is a conditional reduction: it does not assert that \(C\), or any rescaling of \(C\), is normal.

Proof

Scaling \(C\) by \(s\) gives \(V^{(N)}(sC)_\sigma =s^N V^{(N)}(C)_\sigma \). Thus, for all sufficiently large \(N\), the proportionality \(V^{(N)}(A)_\sigma =c_NV^{(N)}(C)_\sigma \) becomes

\begin{align} V^{(N)}(A)_\sigma & = \frac{c_N}{s^N}V^{(N)}(sC)_\sigma , & \frac{c_N}{s^N}& \ne 0. \notag \end{align}

The normal-tensor overlap dichotomy gives one \(\zeta \in \mathbb {C}\), with \(|\zeta |=1\), such that, at every positive length,

\begin{align} V^{(N)}(A)_\sigma & = \zeta ^N V^{(N)}(sC)_\sigma =(\zeta s)^N V^{(N)}(C)_\sigma . \notag \end{align}
Theorem 26.11.22 A normal rescaling forces the positive geometric law

Let \(A\) be the normal doubled-index source tensor of positive bond dimension \(D\), let \(C\) be a fixed tensor for its commuting-bond product, and suppose that \(sC\) is normal for some \(s{\gt}0\). Then the unit phase is trivial. For every \(N\ge 2\),

\begin{align} \rho ^{(N)}(A) & = s^N\prod _{n=0}^{N-1}B_{n,n+1}. \notag \end{align}

Thus a positive normal rescaling of the fixed product tensor already supplies the positive geometric realization law.

Proof

Normality gives \(\lim _{N\to \infty }\langle V^{(N)}(A) | V^{(N)}(A) \rangle =1\). Hence at two sufficiently large consecutive lengths, say \(N\) and \(N+1\), both the source vector and the fixed bond product are nonzero. Positivity of the realization gives positive numbers \(c_N,c_{N+1}\) satisfying \((\zeta s)^N=c_N\) and \((\zeta s)^{N+1}=c_{N+1}\). Consequently \(\zeta s=c_{N+1}/c_N{\gt}0\). Since \(|\zeta |=1\) and \(s{\gt}0\), one has \(\zeta =1\).

Lemma 26.11.23 Marginal stability under source zero correlation length

Let \(M\) have source zero correlation length. For every \(N\geq 0\), the normalized \(N\)-site marginal obtained by tracing two sites from \(\sigma ^{(N+2)}(M)\) equals the normalized \(N\)-site marginal obtained by tracing one site from \(\sigma ^{(N+1)}(M)\).

This is the first replacement at [ CPGSV16 , Appendix C.2, line 1613 ] . It does not imply the rank-one trace factorization asserted later on that line.

Proof

Write \(E=\mathcal T_M\) and choose \(\lambda {\gt}0\) such that \(E^2=\lambda E\). For physical configurations \(u,v\) of length \(N\), the two marginal matrix elements are \(\operatorname{tr}(M^{u,v}E^2)/\operatorname{tr}(E^{N+2})\) and \(\operatorname{tr}(M^{u,v}E)/\operatorname{tr}(E^{N+1})\). The numerator and denominator on the left are respectively \(\lambda \) times those on the right, and source zero correlation length makes the denominator on the right nonzero.

Theorem 26.11.24 Iterated marginal stability under zero correlation length

Let \(M\) have source zero correlation length. For every \(L\geq 0\), the normalized \(L\)-site marginal obtained by tracing three sites from \(\sigma ^{(L+3)}(M)\) equals the normalized \(L\)-site marginal obtained by tracing one site from \(\sigma ^{(L+1)}(M)\).

Proof

First retain \(L+1\) sites and apply Lemma 26.11.23. Trace the last of these retained sites, and then apply the same lemma while retaining \(L\) sites.

Definition 26.11.25 Rank-one trace factorization for neighboring operators
#

A rank-one trace factorization of neighboring matrices \(\eta _{q,h}\) consists of real numbers \(a_q,b_h\) such that

\begin{align} \operatorname{tr}(\eta _{q,h})& =a_qb_h, \notag \\ \sum _q a_qb_q& =1. \notag \end{align}

The factorization is an explicit assumption; it is not deduced from zero correlation length. It is the factorization invoked at [ CPGSV16 , Appendix C.2, line 1613 ] .

Lemma 26.11.26 Separation of the two-boundary edge contraction

Suppose \(\eta _{q,h}\) has a rank-one trace factorization. For fixed boundary sectors \(u,v\), set

\begin{align} R_{u,q}& =\operatorname{tr}_{H_{q,l}}(\eta _{u,q}), \notag \\ L_{h,v}& =\operatorname{tr}_{H_{h,r}}(\eta _{h,v}). \notag \end{align}

Then

\begin{align} \sum _{q,h}\operatorname{tr}(\eta _{q,h})(R_{u,q}\otimes L_{h,v}) & = \left(\sum _q a_qR_{u,q}\right)\otimes \left(\sum _h b_hL_{h,v}\right). \notag \end{align}

This is the corrected edge contraction at [ CPGSV16 , Appendix C.2, lines 1613–1617 ] .

Proof

Substitute \(\operatorname{tr}(\eta _{q,h})=a_qb_h\) and distribute the two finite sums.

Theorem 26.11.27 Conditional fourth-region boundary trace

Let \(\eta _{q,h}\) be arbitrary matrices on \(H_{q,r}\otimes H_{h,l}\) with a rank-one trace factorization. For a nonempty retained sector word \(k=(k_0,\ldots ,k_{L-1})\), write

\begin{align} P_k& =\bigotimes _{n=0}^{L-2}\eta _{k_n,k_{n+1}}, \notag \\ R_{u,q}& =\operatorname{tr}_{H_{q,l}}(\eta _{u,q}), \notag \\ L_{h,v}& =\operatorname{tr}_{H_{h,r}}(\eta _{h,v}). \notag \end{align}

The edge contraction corresponding to tracing the two boundary sites of the longer cyclic chain is

\begin{align} & \bigoplus _k P_k\otimes \sum _{q,h}\operatorname{tr}(\eta _{q,h}) (R_{k_{L-1},q}\otimes L_{h,k_0}) \notag \\ & \quad = \bigoplus _k P_k\otimes \left(\sum _q a_qR_{k_{L-1},q}\right)\otimes \left(\sum _h b_hL_{h,k_0}\right). \notag \end{align}

This is the edge-coordinate interpretation of the displayed fourth-region trace in [ CPGSV16 , Appendix C.2, lines 1606 and 1613–1617 ] .

Proof

Apply Lemma 26.11.26 for each retained sector word. Tensor with the unchanged product \(P_k\) and take the direct sum over \(k\).

Remark 26.11.28
#

The theorem applies, in particular, to the positive chain-independent neighboring family supplied by Theorem 26.11.12, once the rank-one trace factorization is given. It does not derive that factorization, identify this two-boundary contraction with a one-site marginal, or prove a Markov decomposition or saturation of the area law.

There is an injective normal tensor \(\mathcal K\), of physical dimension two and bond dimension one, which generates MPDOs and has source zero correlation length, together with one positive two-site bond \(B\) whose translates commute. For every \(N\geq 2\),

\begin{align} \sigma ^{(N)}(\mathcal K) & =\prod _{i=0}^{N-1}B_{i,i+1}, \notag \end{align}

while the trace matrix of a chosen two-sector Beigi factorization is

\begin{align} T& =\begin{pmatrix} 1 & 0 \\ 0 & 0 \end{pmatrix}. \notag \end{align}

In particular, \(T\) is not primitive.

This shows that primitivity cannot be inferred for an arbitrary selected factorization in the step suggested at [ CPGSV16 , Appendix C.2, line 1613 ] . The same tensor also has a one-sector factorization with positive semidefinite neighboring operator and primitive trace matrix. Hence the example does not exclude a source-faithful minimal or visible-sector selection, and it does not disprove the stated commuting-form-to-SAL implication.

Proof

Let \(\mathcal K^{0,0}=1\) and let all other physical entries vanish. The matrices \(\{ \mathcal K^{i,j}\} _{i,j=0}^1\) span \(M_1(\mathbb C)\). For every \(X\in M_1(\mathbb C)\), the doubled-index transfer \(\mathcal E_{\mathcal K}\) and the physical-trace transfer \(P_{\mathcal K}\) satisfy

\begin{align} \mathcal E_{\mathcal K}(X)& =X, \notag \\ P_{\mathcal K}& =I_1, \notag \\ P_{\mathcal K}^2& =P_{\mathcal K}. \notag \end{align}

Hence \(\mathcal K\) is injective and normal and has source zero correlation length. Decompose the physical space nonminimally as \(\mathbb C\oplus \mathbb C\). With \(w_0=1\) and \(w_1=0\), take both sector factors to be the scalar \(w_k\) in sector \(k\). The neighboring operators are

\begin{align} \eta _{k,h} & =w_kw_h I_1 =\delta _{k,0}\delta _{h,0}I_1 \succeq 0. \notag \end{align}

In the sector coordinates the corresponding physical bond is

\begin{align} B & =\sum _{k,h}\mathbb {1}_{H_L^{(k)}}\otimes \eta _{k,h}\otimes \mathbb {1}_{H_R^{(h)}} \notag \\ & =\mathbb {1}_{H_L^{(0)}}\otimes I_1\otimes \mathbb {1}_{H_R^{(0)}}. \notag \end{align}

Since only the all-zero physical-index word contributes, the factorization identity is

\begin{align} \sigma ^{(N)}(\mathcal K) & =\prod _{i=0}^{N-1}B_{i,i+1}. \notag \end{align}

Consequently,

\begin{align} T_{k,h} & =\operatorname{tr}(\eta _{k,h}) =\delta _{k,0}\delta _{h,0}, \notag \\ T& =\begin{pmatrix} 1 & 0 \\ 0 & 0 \end{pmatrix}. \notag \end{align}

For every \(n\geq 1\), \(T^n=\begin{pmatrix} 1 & 0 \\ 0 & 0 \end{pmatrix}\). Thus no positive power has all entries strictly positive, so \(T\) is not primitive. For the alternative factorization, take one sector \(B^L=\mathbb C^2\) and \(B^R=\mathbb C\), with

\begin{align} l& =\begin{pmatrix} 1 & 0 \\ 0 & 0 \end{pmatrix}, \notag \\ r& =(1). \notag \end{align}

Its sole neighboring operator is \(\widehat\eta _{0,0}=\operatorname{diag}(1,0)\succeq 0\), and hence its trace matrix is \(\widehat T=(\operatorname{tr}(\widehat\eta _{0,0}))=(1)\). Every positive power of \(\widehat T\) equals \((1)\), so this one-sector trace matrix is primitive.

For a physical-sector factorization with neighboring operators \(\eta _{k,h}\), retain a sector \(k\) when there is a sector \(h\) such that \(\eta _{k,h}\ne 0\) and \(h\leadsto k\), where \(\leadsto \) denotes reachability by nonzero neighboring operators. The first edge \(k\to h\) is explicit, so the resulting closed walk has positive length even when the return path is empty. The set \(C\) of retained sectors is therefore exactly the set of vertices occurring in positive-length directed cycles, in the sense of [ Bei12 , Section III ] . Define, for \(k,h\in C\),

\begin{align} T_{k,h}& =\operatorname{Re}\operatorname{tr}(\eta _{k,h}). \notag \end{align}

For positive semidefinite neighboring operators the trace is real, so \(T_{k,h}=\operatorname{tr}(\eta _{k,h})\), and \(T_{k,h}{\gt}0\) is equivalent to \(\eta _{k,h}\ne 0\).

Let \(N\geq 1\) and let \(k=(k_0,\ldots ,k_{N-1})\) be a cyclic sector configuration. If \(k_n\notin C\) for some \(n\), then \(\Omega _k=0\). Thus deleting the sectors outside \(C\) leaves every finite cyclic neighboring product unchanged. For every linear contraction \(\Phi \), including a composition of reindexings and partial traces, \(\Omega _k=0\) implies \(\Phi (\Omega _k)=0\).

Proof

If \(\Omega _k\ne 0\), each factor \(\eta _{k_n,k_{n+1}}\) is nonzero; otherwise every matrix entry of the product vanishes. Starting with the edge \(k_n\to k_{n+1}\) and following the remaining cyclic edges gives a return path to \(k_n\). Hence every \(k_n\) belongs to \(C\). The last assertion is the linear identity \(\Phi (0)=0\).

Proof

The virtual matrices of all physical sectors span the full matrix algebra. If \(A=A_k^{xy}\) is nonzero, nondegeneracy of the trace pairing gives a virtual matrix \(B=A_q^{uv}\) such that \(\operatorname{tr}(AB)\ne 0\). Cyclicity gives \(\operatorname{tr}(BA)=\operatorname{tr}(AB)\ne 0\), and therefore \(\eta _{k,q}\ne 0\) and \(\eta _{q,k}\ne 0\). Thus a sector containing a nonzero virtual matrix lies on a directed two-cycle. Hence every virtual matrix outside \(C\) vanishes, and the virtual matrices belonging to \(C\) still span the full algebra.

If a proper directed cut separated two nonempty subsets \(C_1,C_2\) of \(C\), let \(V_{C_i}\) denote the span of the virtual matrices in \(C_i\). Absence of an edge across the cut gives

\begin{align} V_{C_1}V_{C_2}& =\{ 0\} , \notag \\ V_{C_1}+V_{C_2}& =M_D(\mathbb C). \notag \end{align}

Both spaces contain a nonzero matrix. This contradicts the one-sided product obstruction for two nonzero subspaces whose sum is the full matrix algebra. Thus \(T\) is irreducible. The same trace pairing gives a two-edge return through each sector and closes every retained edge through a third retained sector. These yield the displayed positive diagonal entries of \(T^2\) and \(T^3\); the coprime return lengths imply primitivity.

Under the hypotheses of Theorem 26.11.32, suppose that the physical-trace transfer has source zero correlation length. There is a number \(\lambda {\gt}0\) such that, with \(\widehat T=\lambda ^{-1}T\),

\begin{align} \widehat T^2& =\widehat T^3, \notag \\ \operatorname{rank}(\widehat T^2)& =1, \notag \end{align}

and \(\operatorname{tr}(\widehat T^m)=\operatorname{tr}(\widehat T)\) for every \(m\geq 1\). By matrix multiplication, the two-step coefficient is \((\widehat T^2)_{k,h}=\sum _{q\in C}\widehat T_{k,q}\widehat T_{q,h}\). The assertion neither identifies \(\widehat T\) with \(\widehat T^2\) nor implies that the unreduced Beigi trace matrix is primitive or rank one.

Proof

Set the left sector tensor equal to zero outside \(C\). The preceding span argument shows that this does not change the physical tensor, and the neighboring operators with both indices in \(C\) are unchanged. The source zero-correlation-length relation, transported through this restricted factorization, gives \(\widehat T^2=\widehat T^3\) on the cyclic-active indices. By Theorem 26.11.32, \(\widehat T\) is primitive. Its square is therefore a strictly positive idempotent matrix and has rank one.

Let \(C\) be the set of cyclic-active sectors and suppose that every neighboring operator is positive semidefinite. For \(q,h\in C\),

\begin{align} \sum _{r\in C}\operatorname{tr}(\eta _{q,r})\operatorname{tr}(\eta _{r,h}) & =(T_C^2)_{q,h}. \notag \end{align}

More generally, if \(B_{q,h}(X)\) denotes the outer boundary operator in the three-site closure, then

\begin{align} \sum _{r\in C}\operatorname{tr}_{\mathrm{mid}} (B_{q,h}(X)\otimes \eta _{q,r}\otimes \eta _{r,h}) & =(T_C^2)_{q,h}B_{q,h}(X). \notag \end{align}

Here \(\operatorname{tr}_{\mathrm{mid}}\) traces both neighboring factors. No equality between \(T_C\) and \(T_C^2\) is asserted.

For every \(\lambda \in \mathbb {R}\), set \(\widehat T_C=\lambda ^{-1}T_C\). The same calculation with each fully traced edge multiplied by \(\lambda ^{-1}\) gives

\begin{align} \sum _{r\in C} \lambda ^{-1}\operatorname{tr}(\eta _{q,r}) \lambda ^{-1}\operatorname{tr}(\eta _{r,h}) & =(\widehat T_C^2)_{q,h}. \notag \end{align}
Proof

Positivity makes each \(\operatorname{tr}(\eta _{a,b})\) real. Expanding matrix multiplication gives

\begin{align} (T_C^2)_{q,h} & =\sum _{r\in C}(T_C)_{q,r}(T_C)_{r,h} =\sum _{r\in C}\operatorname{tr}(\eta _{q,r})\operatorname{tr}(\eta _{r,h}). \notag \end{align}

The partial trace of the fixed-sector three-site closure is \(\operatorname{tr}(\eta _{q,r})\operatorname{tr}(\eta _{r,h})B_{q,h}(X)\). Summing over \(r\in C\) proves the second identity. Multiplying each of the two trace factors by \(\lambda ^{-1}\) gives the normalized identity.

Theorem 26.11.35 Cyclic-active fourth-region factorization

Let \(\mathcal K\) be injective and have source zero correlation length, and suppose its neighboring operators are positive semidefinite. There are \(\lambda {\gt}0\) and strictly positive functions \(a,b\) on the cyclic-active sectors, normalized by \(a\mathbin {\boldsymbol \cdot }b=1\), such that every fourth-region marginal is a direct sum over retained sector words of the unchanged interior neighboring product tensored with the separated left and right boundary factors determined by \(a\) and \(b\).

Proof

The additional marginal replacement leaves the retained interior product unchanged and produces the two-step coefficient on the cyclic-active sectors. Its positive rank-one factorization separates the two surviving boundary sums. All sector words leaving the cyclic-active support vanish before the two outer partial traces are evaluated.

Theorem 26.11.36 Cyclic-active Markov decomposition at every cut

Under the hypotheses of Theorem 26.11.35, for arbitrary \(A,C\geq 0\), the fourth-region marginal on consecutive regions of lengths \(A\), \(1\), and \(C\) admits a Hayashi Markov decomposition. The middle site decomposes as the direct sum of its left and right sector factors. Each block is the tensor product of normalized positive left and right path states, and its probability is the product of their unnormalized traces divided by the positive periodic normalization.

Proof

Separate the retained chain at the distinguished middle site. The retained neighboring factors split into the left and right path products, while the two cyclic endpoint factors become their respective boundary matrices. Normalize each positive block by its trace, using an arbitrary trace-one positive matrix when the block vanishes. The trace-one identity for the full marginal shows that the resulting non-negative block weights sum to one.

Theorem 26.11.37 Physical-sector factorization and ZCL imply SAL

Let \(\mathcal K\) have positive bond dimension and be injective, and let \(F\) be a physical-sector factorization of \(\mathcal K\). Suppose every neighboring operator \(\eta ^F_{q,h}\) is positive semidefinite. If the physical-trace transfer of \(\mathcal K\) has source zero correlation length, then \(\mathcal K\) saturates the area law.

Proof

Positivity of the neighboring operators makes every nonempty sector-coordinate chain operator positive. Source zero correlation length makes its trace nonzero. Apply the preceding theorem with \(A=m-1\) and \(C=N-m-1\) at every admissible cut, then use the all-cut Markov criterion. Finally transport saturation through the physical isometry of \(F\).

Theorem 26.11.38 A translation-invariant commuting bond and ZCL imply SAL

Let \(\mathcal K\) be an injective normal tensor generating MPDOs. Suppose that there is one positive two-site bond \(B\) whose translates commute and, for every \(N\geq 2\), a constant \(c_N{\gt}0\) such that

\begin{align} \sigma ^{(N)}(\mathcal K) & =c_N\prod _{i=0}^{N-1}B_{i,i+1}. \notag \end{align}

If the physical-trace transfer of \(\mathcal K\) has zero correlation length, then \(\mathcal K\) saturates the area law.

This is the proposition at [ CPGSV16 , Appendix C.2, lines 1597–1619 ] .

Theorem 26.11.39 \(\eta \)-local structure gives the one-sector GSNNCH form

The single positive bond determined by the \(\eta \)-local structure gives the one-sector instance of the explicit GSNNCH decomposition.

Proof

Apply the one-sector construction to the single-bond product at every chain length.

Theorem 26.11.40 Injective SAL tensors generate GSNNCH states

Every injective MPO tensor satisfying SAL generates Gibbs states of a nearest-neighbor commuting Hamiltonian: the normalized finite-chain states are density operators with the explicit sector form of Definition 26.8.1, realized through one sector. The one-sector form is the commuting product form in which [ CPGSV16 , Proposition C.8 ] states its conclusion for an injective tensor, combined here with the density normalization of [ CPGSV16 , Definition 4.8 ] .

Proof

Corollary 26.10.3.48 gives the \(\eta \)-local structure, whose single positive bond gives the one-sector form by Theorem 26.11.39. SAL includes the nonvanishing of every positive-length trace, so Theorem 26.8.28 applies.

Remark 26.11.41 Positive physical-sector factorization
#

Suppose that \(K\) satisfies \(\mathrm{SAL}(K)\) and admits a physical-sector factorization whose neighboring operators \(\eta _{k,h}\) are simultaneously positive semidefinite. The associated two-site bond is

\begin{align} B& =\sum _{k,h} \mathbb {1}_{H_L^{(k)}}\otimes \eta _{k,h}\otimes \mathbb {1}_{H_R^{(h)}}, \label{eq:mpdo_eta_bond_assembly}\\ B& \geq 0, \notag \end{align}

and, for every \(N\geq 2\),

\begin{align} \sigma ^{(N)}(K) & =c_N\prod _{n=1}^{N}B_{n,n+1}, \label{eq:mpdo_eta_product_form}\\ c_N& {\gt}0, \notag \\[B_{i,i+1},B_{j,j+1}]& =0. \notag \end{align}

Under this hypothesis, Theorem 26.10.3.47 gives the \(\eta \)-local structure and proves (??)–(??) with \(c_N=1\). Theorem 26.11.6 then gives the commuting-form conclusion. Adjacent translates commute on every periodic chain of length at least three by Theorem 26.10.3.40, and the crossed two-site case is Theorem 26.10.3.41. Disjoint translates commute by Theorem 26.10.3.42. These cases give pairwise commutativity at every length \(N\geq 2\) by Theorem 26.10.3.43. Given the physical-sector factorization, the all-length product identity is Theorem 26.10.3.44. The doubled-index transfer condition enters only in the subsequent RFP and single-bond branch conclusions.